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Scientific Calculations - Simple Compound Measures of Rate

Example Results
For the potato cylinder placed in distilled water - a sucrose concentration of 0 mol dm-3 - the following results were obtained.
Osmosis Numericals | Biology for Grade 10

The increase in mass is the result of water being taken up by osmosis.

The rate of water uptake

  • In this experiment, 0.59 grams of water were taken up by the potato cylinder.
  • This took place over 40 minutes, so the water uptake in an hour, assuming that the rate was constant, would be:

Water uptake in 1 hour =
Osmosis Numericals | Biology for Grade 10
Water uptake in 1 hour =
Osmosis Numericals | Biology for Grade 10

The rate of water uptake is therefore 0.89 g/hour.

Percentage change in mass

  • There is some variation in mass between the potato cylinders at the beginning of the experiment as it would be impractical to prepare the cylinders so that they were identical in mass.
  • To compare changes in mass of different potato cylinders, calculate the percentage change in mass.
    Osmosis Numericals | Biology for Grade 10
  • Some of the values obtained for percentage change in mass will be positive, some will be negative.
  • For the potato cylinder in the distilled water:
    Osmosis Numericals | Biology for Grade 10
  • The changes in mass, as percentages, must be calculated for each potato cylinder.

Example: For the potato cylinder placed in a sucrose concentration of 0.2 mol dm-3, the following results were obtained:
Osmosis Numericals | Biology for Grade 10Calculate the change in mass as a percentage to the nearest whole number.

Osmosis Numericals | Biology for Grade 10

Analysing Results and Using Percentiles


The investigation cannot be based on changes in mass from just one potato cylinder.

In scientific tests, ensure a number of measurements are made to allow for uncertainty and error in data and anomalous results.

  • Percentage changes in mass must be calculated for each cylinder. A mean value for the change in mass of potato cylinders at each concentration – measured in moles of sucrose per dm3 of solution, or mol dm-3 – should be calculated.
  • A graph is plotted of change in mass, in per cent, against concentration of sucrose.
  • Where potato cylinders have gained in mass, the change will be positive.
  • Where potato cylinders have decreased in mass, the change will be negative.

Osmosis Numericals | Biology for Grade 10Osmosis Numericals | Biology for Grade 10

  • Where the plotted line crosses the horizontal axis at 0 per cent change in mass, the sucrose concentration is equal to the concentration of dissolved substances in the potato cells.
  • This can be identified on the graph as the point which shows no change in mass, and therefore represents no net movement of water by osmosis.

Example: What is the concentration of solutes in the cells of the potato in this investigation?

0.27 mol dm-3.
This value is where the line crosses the x-axis.

Percentile

The concentration of dissolved solutes in the cells of different potatoes will vary slightly from potato to potato. A set of data for a range in concentrations can look at the range, and the mean, but these do not show whether data is evenly spread or whether it is clustered together within a certain range.

  • Scientists use percentiles to divide a set of data into 100, and look to see where the data lie within these divisions.
  • The median – the point in a set of data where 50 per cent of the data fall above this value, and 50 per cent below it – is the 50th percentile.
  • The 75th percentile is where 75 percent of the data fall below this value.
  • There are several methods of finding a percentile. The simplest is the nearest rank method.

Begin by putting the data into order. For a range of values for the concentration of potato cell sap:
Osmosis Numericals | Biology for Grade 10

Arranged in order:
Osmosis Numericals | Biology for Grade 10To find, for example the 50th percentile, first find the rank:
Osmosis Numericals | Biology for Grade 10
So the 50th percentile will be the 16th number in the ordered data set, starting from the left.
The 50th percentile is 0.27.
Osmosis Numericals | Biology for Grade 10Where the ordered rank is not a whole number, round the number up.

Example: Find the 90th percentile for the same set of data.

0.32 mol dm-3
Osmosis Numericals | Biology for Grade 10
Osmosis Numericals | Biology for Grade 10

Percentile Rank

The percentile rank will show the position of a value within a range.
To find the percentile rank of a value, x:
Osmosis Numericals | Biology for Grade 10
Where:
B = number of values below x
E = number of values equal to x
N = number of values
So, for the student's value of 0.27 mol dm-3.
Osmosis Numericals | Biology for Grade 10

Example: For another student's value of 0.29 mol dm-3, find the percentile rank.

70th percentile.
percentile rank =
Osmosis Numericals | Biology for Grade 10

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