PPT: Ideal Transformer | Basic Electrical Technology - Electrical Engineering (EE) PDF Download

 Page 2


? Introduction of ideal transformer
? characteristics of ideal transformer
? Ideal transformer at no load condition
? Ideal transformer at on load condition
? Phasor diagrams
? Ideal transformer equations
Page 3


? Introduction of ideal transformer
? characteristics of ideal transformer
? Ideal transformer at no load condition
? Ideal transformer at on load condition
? Phasor diagrams
? Ideal transformer equations
? An ideal transformer is an imaginary
transformer which does not have any loss in
it, means no core losses, copper losses and
any other losses in transformer. Efficiency of
this transformer is considered as 100%.
Page 4


? Introduction of ideal transformer
? characteristics of ideal transformer
? Ideal transformer at no load condition
? Ideal transformer at on load condition
? Phasor diagrams
? Ideal transformer equations
? An ideal transformer is an imaginary
transformer which does not have any loss in
it, means no core losses, copper losses and
any other losses in transformer. Efficiency of
this transformer is considered as 100%.
1.Infinite permeability(u=infinite) which mean that
it doesn’t require any excitation current to establish
flux , but in practical the t/f draws magnetizing
current of 5% of full load current.
2.The core is linear , i.e avg. area under BH-curve is
zero . but in practical it is not possible due to non
linearity of core materiel.
3.coupling factor between primary and secondary is
unity , i.e all the flux should link with both primary
and secondary windings , but in practical there will
be a leakage flux of 5%.
4.The resistance of the windings should be zero i.e
copper loss should be zero . But there will exist
some amount of resistance.
Page 5


? Introduction of ideal transformer
? characteristics of ideal transformer
? Ideal transformer at no load condition
? Ideal transformer at on load condition
? Phasor diagrams
? Ideal transformer equations
? An ideal transformer is an imaginary
transformer which does not have any loss in
it, means no core losses, copper losses and
any other losses in transformer. Efficiency of
this transformer is considered as 100%.
1.Infinite permeability(u=infinite) which mean that
it doesn’t require any excitation current to establish
flux , but in practical the t/f draws magnetizing
current of 5% of full load current.
2.The core is linear , i.e avg. area under BH-curve is
zero . but in practical it is not possible due to non
linearity of core materiel.
3.coupling factor between primary and secondary is
unity , i.e all the flux should link with both primary
and secondary windings , but in practical there will
be a leakage flux of 5%.
4.The resistance of the windings should be zero i.e
copper loss should be zero . But there will exist
some amount of resistance.
? E
1
= 4.44 f N
1
F
m
? E
2
= 4.44 f N
2
F
m
? For an ideal transformer N
1
= N
2
E
1
= V
1
and E
2
= V
2
(transformation ratio K=1)