PPT: RC - RL Circuits Notes | EduRev

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Electrical Engineering (EE) : PPT: RC - RL Circuits Notes | EduRev

 Page 1


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
Page 2


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Circuits
The steps involved in solving
simple circuits containing dc
sources, resistances, and one
energy-storage element
(inductance or capacitance) are:
Page 3


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Circuits
The steps involved in solving
simple circuits containing dc
sources, resistances, and one
energy-storage element
(inductance or capacitance) are:
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
1. Apply Kirchhoff’s current and voltage
laws to write the circuit equation.
2. If the equation contains integrals,
differentiate each term in the equation
to produce a pure differential equation.
3. Assume a solution of the form K
1
+
K
2
e
st
.
Page 4


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Circuits
The steps involved in solving
simple circuits containing dc
sources, resistances, and one
energy-storage element
(inductance or capacitance) are:
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
1. Apply Kirchhoff’s current and voltage
laws to write the circuit equation.
2. If the equation contains integrals,
differentiate each term in the equation
to produce a pure differential equation.
3. Assume a solution of the form K
1
+
K
2
e
st
.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
4. Substitute the solution into the
differential equation to determine the
values of K
1
and s . (Alternatively, we
can determine K
1
by solving the circuit
in steady state)
5. Use the initial conditions to
determine the value of K
2
.
6. Write the final solution.
Page 5


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Circuits
The steps involved in solving
simple circuits containing dc
sources, resistances, and one
energy-storage element
(inductance or capacitance) are:
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
1. Apply Kirchhoff’s current and voltage
laws to write the circuit equation.
2. If the equation contains integrals,
differentiate each term in the equation
to produce a pure differential equation.
3. Assume a solution of the form K
1
+
K
2
e
st
.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
4. Substitute the solution into the
differential equation to determine the
values of K
1
and s . (Alternatively, we
can determine K
1
by solving the circuit
in steady state)
5. Use the initial conditions to
determine the value of K
2
.
6. Write the final solution.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Transient Analysis
Find i(t) and the voltage v(t)
Apply KVL around the loop:
0 ) ( ) ( = + + - t v R t i V
S
i(t)= 0 for t < 0 since the switch is open prior to t = 0
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