Past Year Paper, Chemistry (Set - 3 ), Delhi, 2015, Class 12, Chemistry Class 12 Notes | EduRev

Chemistry Class 12

Class 12 : Past Year Paper, Chemistry (Set - 3 ), Delhi, 2015, Class 12, Chemistry Class 12 Notes | EduRev

 Page 1


56/1/1/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/1/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 1 
Page 2


56/1/1/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/1/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 1 
56/1/1/D 2  
General Instructions : 
 (i) All questions are compulsory. 
 (ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each. 
 (iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each. 
 (iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each. 
 (v) Q. no. 23 is a value based question and carry 4 marks. 
 (vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each. 
 (vii) Use log tables if necessary, use of calculators is not allowed. 
 
1. H
3
PO
4
 Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1 
 What is the basicity of H
3
PO
4
 ? 
 
2. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1 
    
 Write the IUPAC name of the given compound : 
    
  
3. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1 
  CH
3
 – CH
2
 – Br ŸÖ£ÖÖ CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 Which would undergo S
N
2 reaction faster in the following pair and why ? 
  CH
3
 – CH
2
 – Br and CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
Page 3


56/1/1/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/1/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 1 
56/1/1/D 2  
General Instructions : 
 (i) All questions are compulsory. 
 (ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each. 
 (iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each. 
 (iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each. 
 (v) Q. no. 23 is a value based question and carry 4 marks. 
 (vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each. 
 (vii) Use log tables if necessary, use of calculators is not allowed. 
 
1. H
3
PO
4
 Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1 
 What is the basicity of H
3
PO
4
 ? 
 
2. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1 
    
 Write the IUPAC name of the given compound : 
    
  
3. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1 
  CH
3
 – CH
2
 – Br ŸÖ£ÖÖ CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 Which would undergo S
N
2 reaction faster in the following pair and why ? 
  CH
3
 – CH
2
 – Br and CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
56/1/1/D 3 [P.T.O. 
4. BaCl
2
 †Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê 
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1 
 Out of BaCl
2
 and KCl, which one is more effective in causing coagulation of a 
negatively charged colloidal Sol ? Give reason. 
 
5. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ 
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü  ?  1 
 What is the formula of a compound in which the element Y forms ccp lattice and 
atoms of X occupy 1/3
rd
 of tetrahedral voids ? 
 
6. ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾Ö ŒµÖÖ Æïü ? ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾ÖÖë Ûúß ¤üÖê ×¾Ö¿ÖêÂÖŸÖÖ†Öë ÛúÖê ×»Ö×ÜÖ‹ …  2 
 What are the transition elements ? Write two characteristics of the transition elements. 
 
7. (i) ÛúÖò´¯»ÖêŒÃÖ [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö    
×»Ö×ÜÖµÖê …  
 (ii) ×®Ö´®Ö ÛúÖò´¯»ÖêŒÃÖ ÛúÖ ÃÖæ¡Ö ×»Ö×ÜÖ‹ :  
  ¯Öê®™üÖ‹ê´ÖÖ‡®Ö®ÖÖ‡™ÒüÖ‡™üÖê-o-ÛúÖê²ÖÖ»™ü (III). 2 
 (i) Write down the IUPAC name of the following complex :  
  [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) 
 (ii) Write the formula for the following complex :  
  Pentaamminenitrito-o-Cobalt (III). 
 
8. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2 
 Name the reagents used in the following reactions : 
 (i) CH
3
 – CO – CH
3
 
?
??? CH
3
 – C
|
O
H
H
 – CH
3
 
 (ii) C
6
H
5
 – CH
2
 – CH
3 
?
??? C
6
H
5
 – COO
–
K
+ 
 
9. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê  
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2 
 What is meant by positive deviations from Raoult’s law ? Give an example. What is 
the sign of ?
mix
H for positive deviation ? 
†£Ö¾ÖÖ/OR 
Page 4


56/1/1/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/1/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 1 
56/1/1/D 2  
General Instructions : 
 (i) All questions are compulsory. 
 (ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each. 
 (iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each. 
 (iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each. 
 (v) Q. no. 23 is a value based question and carry 4 marks. 
 (vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each. 
 (vii) Use log tables if necessary, use of calculators is not allowed. 
 
1. H
3
PO
4
 Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1 
 What is the basicity of H
3
PO
4
 ? 
 
2. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1 
    
 Write the IUPAC name of the given compound : 
    
  
3. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1 
  CH
3
 – CH
2
 – Br ŸÖ£ÖÖ CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 Which would undergo S
N
2 reaction faster in the following pair and why ? 
  CH
3
 – CH
2
 – Br and CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
56/1/1/D 3 [P.T.O. 
4. BaCl
2
 †Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê 
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1 
 Out of BaCl
2
 and KCl, which one is more effective in causing coagulation of a 
negatively charged colloidal Sol ? Give reason. 
 
5. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ 
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü  ?  1 
 What is the formula of a compound in which the element Y forms ccp lattice and 
atoms of X occupy 1/3
rd
 of tetrahedral voids ? 
 
6. ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾Ö ŒµÖÖ Æïü ? ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾ÖÖë Ûúß ¤üÖê ×¾Ö¿ÖêÂÖŸÖÖ†Öë ÛúÖê ×»Ö×ÜÖ‹ …  2 
 What are the transition elements ? Write two characteristics of the transition elements. 
 
7. (i) ÛúÖò´¯»ÖêŒÃÖ [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö    
×»Ö×ÜÖµÖê …  
 (ii) ×®Ö´®Ö ÛúÖò´¯»ÖêŒÃÖ ÛúÖ ÃÖæ¡Ö ×»Ö×ÜÖ‹ :  
  ¯Öê®™üÖ‹ê´ÖÖ‡®Ö®ÖÖ‡™ÒüÖ‡™üÖê-o-ÛúÖê²ÖÖ»™ü (III). 2 
 (i) Write down the IUPAC name of the following complex :  
  [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) 
 (ii) Write the formula for the following complex :  
  Pentaamminenitrito-o-Cobalt (III). 
 
8. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2 
 Name the reagents used in the following reactions : 
 (i) CH
3
 – CO – CH
3
 
?
??? CH
3
 – C
|
O
H
H
 – CH
3
 
 (ii) C
6
H
5
 – CH
2
 – CH
3 
?
??? C
6
H
5
 – COO
–
K
+ 
 
9. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê  
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2 
 What is meant by positive deviations from Raoult’s law ? Give an example. What is 
the sign of ?
mix
H for positive deviation ? 
†£Ö¾ÖÖ/OR 
56/1/1/D 4  
9. ‹×•ÖµÖÖê™ÒüÖê¯ÃÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ¯ÖÏÖ¯ŸÖ ‹×•ÖµÖÖê™ÒüÖê¯Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ÛúÖ 
ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ …  2 
 Define azeotropes. What type of azeotrope is formed by positive deviation from 
Raoult’s law ? Give an example. 
 
10. (a) ×ÃÖ»¾Ö¸ü Œ»ÖÖê¸üÖ‡›ü Ûêú •Ö»ÖßµÖ ×¾Ö»ÖµÖ®Ö Ûêú ×¾ÖªãŸÖ †¯Ö‘Ö™ü®Ö ´Öë Ûîú£ÖÖê›ü ¯Ö¸ü ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ‹Ñ ÆüÖêŸÖß Æïü :   
   Ag
+
(aq) + e
–
 ?? Ag(s) E° = +0.80 V 
   H
+
(aq) + e
–
 ?? 
1
2
H
2
(g) E° = 0.00 V 
  ˆ®ÖÛêú ´ÖÖ®ÖÛú †¯Ö“ÖµÖ®Ö ‡»ÖꌙÒüÖê›ü ×¾Ö³Ö¾Ö (E°) Ûêú ´ÖÖ®ÖÖë Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü Ûîú£ÖÖê›ü ¯Ö¸ü ×ÛúÃÖ †×³Ö×ÛÎúµÖÖ Ûúß 
ÃÖÓ³ÖÖ¾Ö®ÖÖ Æîü †Öî¸ü ŒµÖÖë ? 
 (b) ÃÖß´ÖÖÓŸÖ ´ÖÖê»Ö¸ü “ÖÖ»ÖÛúŸÖÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ×¾ÖªãŸÖË †¯Ö‘Ö™ËüµÖ Ûúß “ÖÖ»ÖÛúŸÖÖ ÃÖÖÓ¦üÞÖ Ûêú ‘Ö™ü®Öê Ûêú ÃÖÖ£Ö 
ŒµÖÖë Ûú´Ö ÆüÖê®Öê »ÖÝÖŸÖß Æîü ?  2 
 (a) Following reactions occur at cathode during the electrolysis of aqueous silver 
chloride solution : 
   Ag
+
(aq) + e
–
 ?? Ag(s) E° = +0.80 V 
   H
+
(aq) + e
–
 ?? 
1
2
H
2
(g) E° = 0.00 V 
  On the basis of their standard reduction electrode potential (E°) values, which 
reaction is feasible at the cathode and why ? 
 (b) Define limiting molar conductivity. Why conductivity of an electrolyte solution 
decreases with the decrease in concentration ? 
 
11. ²ÖꮕÖß®Ö Ûêú 49 g ´Öë ²ÖꮕÖÖê‡Ûú †´»Ö ÛúÖ 3.9 g ‘Öã»Ö®Öê ¯Ö¸ü ×Æü´ÖÖÓÛú ´Öë 1.62 K ÛúÖ †¾Ö®Ö´Ö®Ö ÆüÖê •ÖÖŸÖÖ Æîü … ¾Öî®™ü 
ÆüÖ±ú ÛúÖ¸üÛú ÛúÖê ¯Ö׸üÛú×»ÖŸÖ Ûúßו֋ †Öî¸ü ×¾Ö»ÖêµÖ Ûêú þֳÖÖ¾Ö Ûúß ¯ÖÏÖÝÖã׌ŸÖ Ûúßו֋ (ÃÖÓÝÖã×ÞÖŸÖ µÖÖ ×¾Ö‘Ö×™üŸÖ)  3 
 (פüµÖÖ ÝÖµÖÖ : ²ÖꮕÖÖê‡Ûú ‹×ÃÖ›ü ÛúÖ ´ÖÖê»Ö ¦ü¾µÖ´ÖÖ®Ö = 122 g mol
–1
, ²ÖꮕÖß®Ö Ûêú ×»ÖµÖê K
f
 = 4.9 K kg mol
–1
) 
 3.9 g of benzoic acid dissolved in 49 g of benzene shows a depression in freezing point 
of 1.62 K. Calculate the van’t Hoff factor and predict the nature of solute (associated 
or dissociated). 
 (Given : Molar mass of benzoic acid = 122 g mol
–1
, K
f
 for benzene = 4.9 K kg mol
–1
) 
Page 5


56/1/1/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/1/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 1 
56/1/1/D 2  
General Instructions : 
 (i) All questions are compulsory. 
 (ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each. 
 (iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each. 
 (iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each. 
 (v) Q. no. 23 is a value based question and carry 4 marks. 
 (vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each. 
 (vii) Use log tables if necessary, use of calculators is not allowed. 
 
1. H
3
PO
4
 Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1 
 What is the basicity of H
3
PO
4
 ? 
 
2. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1 
    
 Write the IUPAC name of the given compound : 
    
  
3. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1 
  CH
3
 – CH
2
 – Br ŸÖ£ÖÖ CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 Which would undergo S
N
2 reaction faster in the following pair and why ? 
  CH
3
 – CH
2
 – Br and CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
56/1/1/D 3 [P.T.O. 
4. BaCl
2
 †Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê 
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1 
 Out of BaCl
2
 and KCl, which one is more effective in causing coagulation of a 
negatively charged colloidal Sol ? Give reason. 
 
5. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ 
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü  ?  1 
 What is the formula of a compound in which the element Y forms ccp lattice and 
atoms of X occupy 1/3
rd
 of tetrahedral voids ? 
 
6. ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾Ö ŒµÖÖ Æïü ? ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾ÖÖë Ûúß ¤üÖê ×¾Ö¿ÖêÂÖŸÖÖ†Öë ÛúÖê ×»Ö×ÜÖ‹ …  2 
 What are the transition elements ? Write two characteristics of the transition elements. 
 
7. (i) ÛúÖò´¯»ÖêŒÃÖ [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö    
×»Ö×ÜÖµÖê …  
 (ii) ×®Ö´®Ö ÛúÖò´¯»ÖêŒÃÖ ÛúÖ ÃÖæ¡Ö ×»Ö×ÜÖ‹ :  
  ¯Öê®™üÖ‹ê´ÖÖ‡®Ö®ÖÖ‡™ÒüÖ‡™üÖê-o-ÛúÖê²ÖÖ»™ü (III). 2 
 (i) Write down the IUPAC name of the following complex :  
  [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) 
 (ii) Write the formula for the following complex :  
  Pentaamminenitrito-o-Cobalt (III). 
 
8. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2 
 Name the reagents used in the following reactions : 
 (i) CH
3
 – CO – CH
3
 
?
??? CH
3
 – C
|
O
H
H
 – CH
3
 
 (ii) C
6
H
5
 – CH
2
 – CH
3 
?
??? C
6
H
5
 – COO
–
K
+ 
 
9. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê  
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2 
 What is meant by positive deviations from Raoult’s law ? Give an example. What is 
the sign of ?
mix
H for positive deviation ? 
†£Ö¾ÖÖ/OR 
56/1/1/D 4  
9. ‹×•ÖµÖÖê™ÒüÖê¯ÃÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ¯ÖÏÖ¯ŸÖ ‹×•ÖµÖÖê™ÒüÖê¯Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ÛúÖ 
ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ …  2 
 Define azeotropes. What type of azeotrope is formed by positive deviation from 
Raoult’s law ? Give an example. 
 
10. (a) ×ÃÖ»¾Ö¸ü Œ»ÖÖê¸üÖ‡›ü Ûêú •Ö»ÖßµÖ ×¾Ö»ÖµÖ®Ö Ûêú ×¾ÖªãŸÖ †¯Ö‘Ö™ü®Ö ´Öë Ûîú£ÖÖê›ü ¯Ö¸ü ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ‹Ñ ÆüÖêŸÖß Æïü :   
   Ag
+
(aq) + e
–
 ?? Ag(s) E° = +0.80 V 
   H
+
(aq) + e
–
 ?? 
1
2
H
2
(g) E° = 0.00 V 
  ˆ®ÖÛêú ´ÖÖ®ÖÛú †¯Ö“ÖµÖ®Ö ‡»ÖꌙÒüÖê›ü ×¾Ö³Ö¾Ö (E°) Ûêú ´ÖÖ®ÖÖë Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü Ûîú£ÖÖê›ü ¯Ö¸ü ×ÛúÃÖ †×³Ö×ÛÎúµÖÖ Ûúß 
ÃÖÓ³ÖÖ¾Ö®ÖÖ Æîü †Öî¸ü ŒµÖÖë ? 
 (b) ÃÖß´ÖÖÓŸÖ ´ÖÖê»Ö¸ü “ÖÖ»ÖÛúŸÖÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ×¾ÖªãŸÖË †¯Ö‘Ö™ËüµÖ Ûúß “ÖÖ»ÖÛúŸÖÖ ÃÖÖÓ¦üÞÖ Ûêú ‘Ö™ü®Öê Ûêú ÃÖÖ£Ö 
ŒµÖÖë Ûú´Ö ÆüÖê®Öê »ÖÝÖŸÖß Æîü ?  2 
 (a) Following reactions occur at cathode during the electrolysis of aqueous silver 
chloride solution : 
   Ag
+
(aq) + e
–
 ?? Ag(s) E° = +0.80 V 
   H
+
(aq) + e
–
 ?? 
1
2
H
2
(g) E° = 0.00 V 
  On the basis of their standard reduction electrode potential (E°) values, which 
reaction is feasible at the cathode and why ? 
 (b) Define limiting molar conductivity. Why conductivity of an electrolyte solution 
decreases with the decrease in concentration ? 
 
11. ²ÖꮕÖß®Ö Ûêú 49 g ´Öë ²ÖꮕÖÖê‡Ûú †´»Ö ÛúÖ 3.9 g ‘Öã»Ö®Öê ¯Ö¸ü ×Æü´ÖÖÓÛú ´Öë 1.62 K ÛúÖ †¾Ö®Ö´Ö®Ö ÆüÖê •ÖÖŸÖÖ Æîü … ¾Öî®™ü 
ÆüÖ±ú ÛúÖ¸üÛú ÛúÖê ¯Ö׸üÛú×»ÖŸÖ Ûúßו֋ †Öî¸ü ×¾Ö»ÖêµÖ Ûêú þֳÖÖ¾Ö Ûúß ¯ÖÏÖÝÖã׌ŸÖ Ûúßו֋ (ÃÖÓÝÖã×ÞÖŸÖ µÖÖ ×¾Ö‘Ö×™üŸÖ)  3 
 (פüµÖÖ ÝÖµÖÖ : ²ÖꮕÖÖê‡Ûú ‹×ÃÖ›ü ÛúÖ ´ÖÖê»Ö ¦ü¾µÖ´ÖÖ®Ö = 122 g mol
–1
, ²ÖꮕÖß®Ö Ûêú ×»ÖµÖê K
f
 = 4.9 K kg mol
–1
) 
 3.9 g of benzoic acid dissolved in 49 g of benzene shows a depression in freezing point 
of 1.62 K. Calculate the van’t Hoff factor and predict the nature of solute (associated 
or dissociated). 
 (Given : Molar mass of benzoic acid = 122 g mol
–1
, K
f
 for benzene = 4.9 K kg mol
–1
) 
56/1/1/D 5 [P.T.O. 
12. (i) Ø•ÖÛú Ûêú ¯Ö׸üÂÛú¸üÞÖ Ûú¸ü®Öê Ûúß ×¾Ö×¬Ö Ûêú ¯Öß”êû •ÖÖê ×ÃÖ¨üÖ®ŸÖ ÆüÖêŸÖÖ Æîü ˆÃÖÛúÖ ÃÖÓÛêúŸÖ Ûúßו֋ …  
 (ii) ÛúÖò¯Ö¸ü Ûêú ×®ÖÂÛúÂÖÔÞÖ ´Öë ×ÃÖ×»ÖÛúÖ Ûúß ŒµÖÖ ³Öæ×´ÖÛúÖ ÆüÖêŸÖß Æîü ? 
 (iii) ¾µÖÖ¯ÖÖ¸üß »ÖÖêÆü ÛúÖ ×¾Ö¿Öã¨ü ºþ¯Ö »ÖÖêÆü ÛúÖ ÛúÖî®Ö ºþ¯Ö Æîü ? 3 
 (i) Indicate the principle behind the method used for the refining of zinc. 
 (ii) What is the role of silica in the extraction of copper ? 
 (iii) Which form of the iron is the purest form of commercial iron ? 
 
13. ´ÖÖê»Ö¸ü ¦ü¾µÖ´ÖÖ®Ö 27 g mol
–1
 Ûêú ÃÖÖ£Ö ‹Ûú ŸÖŸ¾Ö ÛúÖê¸ü »Ö´²ÖÖ‡Ô 4.05 × 10
–8
 cm ¾ÖÖ»Öß ‹Ûú ŒµÖæײÖÛú µÖæ×®Ö™ü 
ÃÖê»Ö ²Ö®ÖÖŸÖÖ Æîü … µÖפü ‘Ö®ÖŸ¾Ö 2.7 g cm
–3
 ÆüÖê, ŸÖÖê ŒµÖæײÖÛú µÖæ×®Ö™ü ÃÖê»Ö ÛúÖ Ã¾Öºþ¯Ö ŒµÖÖ Æîü ? 3 
 An element with molar mass 27 g mol
–1
 forms a cubic unit cell with edge length                 
4.05 × 10
–8
 cm. If its density is 2.7 g cm
–3
, what is the nature of the cubic unit cell ? 
 
14. (a) †Ö¯Ö ×®Ö´®Ö ÛúÖê ÛîúÃÖê ÃÖ´Ö—ÖÖ‹ÑÝÖê ? 
  (i) »Öï£Öî®ÖÖêµÖ›ü ÃÖÓÛãú“Ö®Ö Ûúß †¯ÖêõÖÖ ‹ê׌™ü®ÖÖêµÖ›ü ÃÖÓÛãú“Ö®Ö †×¬ÖÛú Æîü …  
  (ii) ÃÖÓÛÎú´ÖÞÖ ¬ÖÖŸÖã‹Ñ ¸ÓüÝÖß®Ö µÖÖî×ÝÖÛú ²Ö®ÖÖŸÖß Æïü …  
 (b) ×®Ö´®Ö ÃÖ´ÖßÛú¸üÞÖ ÛúÖê ¯ÖæÞÖÔ Ûúßו֋  :  3 
   2MnO
–
4
 + 6H
+
 + 5NO
–
2
 ?? 
 (a) How would you account for the following : 
  (i) Actinoid contraction is greater than lanthanoid contraction. 
  (ii) Transition metals form coloured compounds. 
 (b) Complete the following equation : 
   2MnO
–
4
 + 6H
+
 + 5NO
–
2
 ?? 
 
15. (i) ÛúÖò´¯»ÖêŒÃÖ [Pt(NH
3
)
2
Cl
2
] Ûêú •µÖÖ×´ÖŸÖßµÖ ÃÖ´ÖÖ¾ÖµÖ¾Ö ÛúÖê †Ö¸êü×ÜÖŸÖ Ûúßו֋ …  
 (ii) ×ÛÎúÙü»Ö ±úß»›ü ×ÃÖ¨üÖ®ŸÖ Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü µÖפü ?
o
 < P ÆüÖê ŸÖÖê d
4
 ÛúÖ ‡»ÖꌙÒüÖò®Ö ×¾Ö®µÖÖÃÖ ×»Ö×ÜÖ‹ …  
 (iii) ÛúÖò´¯»ÖêŒÃÖ [Ni(CO)
4
] ÛúÖ ÃÖÓÛú¸üÞÖ †Öî¸ü “Öã´²ÖÛúßµÖ ¯ÖÏÛéú×ŸÖ ×»Ö×ÜÖ‹ … (¯Ö.ÃÖÓ. Ni = 28) 3 
 (i) Draw the geometrical isomers of complex [Pt(NH
3
)
2
Cl
2
]. 
 (ii) On the basis of crystal field theory, write the electronic configuration for d
4
 ion 
if ?
o
 < P. 
 (iii) Write the hybridization and magnetic behaviour of the complex [Ni(CO)
4
]. 
  (At.no. of Ni = 28) 
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