Commerce Exam > Commerce Notes > Mathematics (Maths) Class 11 > Past Year Paper, Maths(Set - 1), 2019, Class 11
Past Year Paper, Maths(Set - 1), 2019, Class 11 | Mathematics (Maths) Class 11 - Commerce PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
C l a s s – X I
M A T H E M A T I C S
T i m e a l l o w e d : 3 h o u r s , M a x i m u m M a r k s : 1 0 0
G e n e r a l I n s t r u c t i o n s :
a ) A l l q u e s t i o n s a r e c o m p u l s o r y .
b ) T h e q u e s t i o n p a p e r c o n s i s t s o f 2 6 q u e s t i o n s d i v i d e d i n t o t h r e e s e c t i o n s A , B a n d C . S e c t i o n
A c o m p r i s e s o f 6 q u e s t i o n s o f o n e m a r k e a c h , S e c t i o n B c o m p r i s e s o f 1 3 q u e s t i o n s o f f o u r
m a r k s e a c h a n d S e c t i o n C c o m p r i s e s o f 7 q u e s t i o n s o f s i x m a r k s e a c h .
c ) A l l q u e s t i o n s i n S e c t i o n A a r e t o b e a n s w e r e d i n o n e w o r d , o n e s e n t e n c e o r a s p e r t h e e x a c t
r e q u i r e m e n t o f t h e q u e s t i o n .
d ) U s e o f c a l c u l a t o r s i s n o t p e r m i t t e d .
S e c t i o n A
1 . I d e n t i f y a f u n c t i o n s o t h a t
S o l :
2 . I f A = { ( x , y ) : y = a x , x R } a n d B = { ( x , y ) : y = a - x , x R } t h e n w h a t i s
S o l : W h e n i n b o t h c a s e s . H e n c e
3 . I f R i s a r e l a t i o n f r o m a s e t A c o n t a i n i n g e l e m e n t s t o a s e t B c o n t a i n i n g e l e m e n t s
t h e f i n d t h e n u m b e r o f s u b s e t s o f
S o l :
4 . C h e c k w h e t h e r t h e g i v e n l i n e s a r e p a r a l l e l o r p e r p e n d i c u l a r .
S o l : T h e y a r e p a r a l l e l s i n c e
Page 2
C l a s s – X I
M A T H E M A T I C S
T i m e a l l o w e d : 3 h o u r s , M a x i m u m M a r k s : 1 0 0
G e n e r a l I n s t r u c t i o n s :
a ) A l l q u e s t i o n s a r e c o m p u l s o r y .
b ) T h e q u e s t i o n p a p e r c o n s i s t s o f 2 6 q u e s t i o n s d i v i d e d i n t o t h r e e s e c t i o n s A , B a n d C . S e c t i o n
A c o m p r i s e s o f 6 q u e s t i o n s o f o n e m a r k e a c h , S e c t i o n B c o m p r i s e s o f 1 3 q u e s t i o n s o f f o u r
m a r k s e a c h a n d S e c t i o n C c o m p r i s e s o f 7 q u e s t i o n s o f s i x m a r k s e a c h .
c ) A l l q u e s t i o n s i n S e c t i o n A a r e t o b e a n s w e r e d i n o n e w o r d , o n e s e n t e n c e o r a s p e r t h e e x a c t
r e q u i r e m e n t o f t h e q u e s t i o n .
d ) U s e o f c a l c u l a t o r s i s n o t p e r m i t t e d .
S e c t i o n A
1 . I d e n t i f y a f u n c t i o n s o t h a t
S o l :
2 . I f A = { ( x , y ) : y = a x , x R } a n d B = { ( x , y ) : y = a - x , x R } t h e n w h a t i s
S o l : W h e n i n b o t h c a s e s . H e n c e
3 . I f R i s a r e l a t i o n f r o m a s e t A c o n t a i n i n g e l e m e n t s t o a s e t B c o n t a i n i n g e l e m e n t s
t h e f i n d t h e n u m b e r o f s u b s e t s o f
S o l :
4 . C h e c k w h e t h e r t h e g i v e n l i n e s a r e p a r a l l e l o r p e r p e n d i c u l a r .
S o l : T h e y a r e p a r a l l e l s i n c e
5 . F i n d t h e a r e a o f t h e t r i a n g l e w h o s e v e r t i c e s a r e ( 2 , 0 ) , ( 5 , 3 ) , ( 2 , 6 )
S o l : A r e a o f a t r i a n g l e
=
6 . W r i t e t h e e q u a t i o n o f a c i r c l e w i t h c e n t e r ( 0 , 0 ) a n d r a d i u s 5 .
S o l :
S e c t i o n B
7 . S o l v e
S o l :
8 . P r o v e b y m a t h e m a t i c a l i n d u c t i o n t h a t .
S o l : L e t b e t h e s t a t e m e n t g i v e n b y
= 1 , T r u e
L e t i t b e t r u e f o r n = m
1 + 2 + 3 + . . . . + m =
1 + 2 + 3 + . . . . + m + ( m + 1 ) = + ( m + 1 )
Page 3
C l a s s – X I
M A T H E M A T I C S
T i m e a l l o w e d : 3 h o u r s , M a x i m u m M a r k s : 1 0 0
G e n e r a l I n s t r u c t i o n s :
a ) A l l q u e s t i o n s a r e c o m p u l s o r y .
b ) T h e q u e s t i o n p a p e r c o n s i s t s o f 2 6 q u e s t i o n s d i v i d e d i n t o t h r e e s e c t i o n s A , B a n d C . S e c t i o n
A c o m p r i s e s o f 6 q u e s t i o n s o f o n e m a r k e a c h , S e c t i o n B c o m p r i s e s o f 1 3 q u e s t i o n s o f f o u r
m a r k s e a c h a n d S e c t i o n C c o m p r i s e s o f 7 q u e s t i o n s o f s i x m a r k s e a c h .
c ) A l l q u e s t i o n s i n S e c t i o n A a r e t o b e a n s w e r e d i n o n e w o r d , o n e s e n t e n c e o r a s p e r t h e e x a c t
r e q u i r e m e n t o f t h e q u e s t i o n .
d ) U s e o f c a l c u l a t o r s i s n o t p e r m i t t e d .
S e c t i o n A
1 . I d e n t i f y a f u n c t i o n s o t h a t
S o l :
2 . I f A = { ( x , y ) : y = a x , x R } a n d B = { ( x , y ) : y = a - x , x R } t h e n w h a t i s
S o l : W h e n i n b o t h c a s e s . H e n c e
3 . I f R i s a r e l a t i o n f r o m a s e t A c o n t a i n i n g e l e m e n t s t o a s e t B c o n t a i n i n g e l e m e n t s
t h e f i n d t h e n u m b e r o f s u b s e t s o f
S o l :
4 . C h e c k w h e t h e r t h e g i v e n l i n e s a r e p a r a l l e l o r p e r p e n d i c u l a r .
S o l : T h e y a r e p a r a l l e l s i n c e
5 . F i n d t h e a r e a o f t h e t r i a n g l e w h o s e v e r t i c e s a r e ( 2 , 0 ) , ( 5 , 3 ) , ( 2 , 6 )
S o l : A r e a o f a t r i a n g l e
=
6 . W r i t e t h e e q u a t i o n o f a c i r c l e w i t h c e n t e r ( 0 , 0 ) a n d r a d i u s 5 .
S o l :
S e c t i o n B
7 . S o l v e
S o l :
8 . P r o v e b y m a t h e m a t i c a l i n d u c t i o n t h a t .
S o l : L e t b e t h e s t a t e m e n t g i v e n b y
= 1 , T r u e
L e t i t b e t r u e f o r n = m
1 + 2 + 3 + . . . . + m =
1 + 2 + 3 + . . . . + m + ( m + 1 ) = + ( m + 1 )
P ( m + 1 ) = + ( m + 1 )
P ( m + 1 ) =
P ( m + 1 ) =
T h u s P ( m ) i s t r u e P ( m + 1 ) i s T r u e
9 . F i n d t h e s q u a r e r o o t o f .
S o l : L e t =
1 0 . S o l v e t h e i n e q u a l i t y .
S o l :
1 1 . F i n d t h e v a l u e o f i f 1 2 C x = 1 2 C x + 4 .
S o l : x + x + 4 = 1 2
2 x = 8
x = 4
1 2 . T h r e e c a r s a r e t h e r e i n a r a c e . C a r A i s 3 t i m e s a s l i k e l y t o w i n a s c a r B . C a r B i s t w i c e
a s l i k e l y t o w i n a s c a r C . W h a t i s t h e p r o b a b i l i t y o f w i n n i n g e a c h c a r .
S o l : L e t b e t h e p r o b a b i l i t y o f w i n n i n g C a r C ,
P ( C ) = p
P ( B ) = 2 p
P ( A ) = 6 p
P ( A ) + P ( B ) + P ( C ) = 1
Page 4
C l a s s – X I
M A T H E M A T I C S
T i m e a l l o w e d : 3 h o u r s , M a x i m u m M a r k s : 1 0 0
G e n e r a l I n s t r u c t i o n s :
a ) A l l q u e s t i o n s a r e c o m p u l s o r y .
b ) T h e q u e s t i o n p a p e r c o n s i s t s o f 2 6 q u e s t i o n s d i v i d e d i n t o t h r e e s e c t i o n s A , B a n d C . S e c t i o n
A c o m p r i s e s o f 6 q u e s t i o n s o f o n e m a r k e a c h , S e c t i o n B c o m p r i s e s o f 1 3 q u e s t i o n s o f f o u r
m a r k s e a c h a n d S e c t i o n C c o m p r i s e s o f 7 q u e s t i o n s o f s i x m a r k s e a c h .
c ) A l l q u e s t i o n s i n S e c t i o n A a r e t o b e a n s w e r e d i n o n e w o r d , o n e s e n t e n c e o r a s p e r t h e e x a c t
r e q u i r e m e n t o f t h e q u e s t i o n .
d ) U s e o f c a l c u l a t o r s i s n o t p e r m i t t e d .
S e c t i o n A
1 . I d e n t i f y a f u n c t i o n s o t h a t
S o l :
2 . I f A = { ( x , y ) : y = a x , x R } a n d B = { ( x , y ) : y = a - x , x R } t h e n w h a t i s
S o l : W h e n i n b o t h c a s e s . H e n c e
3 . I f R i s a r e l a t i o n f r o m a s e t A c o n t a i n i n g e l e m e n t s t o a s e t B c o n t a i n i n g e l e m e n t s
t h e f i n d t h e n u m b e r o f s u b s e t s o f
S o l :
4 . C h e c k w h e t h e r t h e g i v e n l i n e s a r e p a r a l l e l o r p e r p e n d i c u l a r .
S o l : T h e y a r e p a r a l l e l s i n c e
5 . F i n d t h e a r e a o f t h e t r i a n g l e w h o s e v e r t i c e s a r e ( 2 , 0 ) , ( 5 , 3 ) , ( 2 , 6 )
S o l : A r e a o f a t r i a n g l e
=
6 . W r i t e t h e e q u a t i o n o f a c i r c l e w i t h c e n t e r ( 0 , 0 ) a n d r a d i u s 5 .
S o l :
S e c t i o n B
7 . S o l v e
S o l :
8 . P r o v e b y m a t h e m a t i c a l i n d u c t i o n t h a t .
S o l : L e t b e t h e s t a t e m e n t g i v e n b y
= 1 , T r u e
L e t i t b e t r u e f o r n = m
1 + 2 + 3 + . . . . + m =
1 + 2 + 3 + . . . . + m + ( m + 1 ) = + ( m + 1 )
P ( m + 1 ) = + ( m + 1 )
P ( m + 1 ) =
P ( m + 1 ) =
T h u s P ( m ) i s t r u e P ( m + 1 ) i s T r u e
9 . F i n d t h e s q u a r e r o o t o f .
S o l : L e t =
1 0 . S o l v e t h e i n e q u a l i t y .
S o l :
1 1 . F i n d t h e v a l u e o f i f 1 2 C x = 1 2 C x + 4 .
S o l : x + x + 4 = 1 2
2 x = 8
x = 4
1 2 . T h r e e c a r s a r e t h e r e i n a r a c e . C a r A i s 3 t i m e s a s l i k e l y t o w i n a s c a r B . C a r B i s t w i c e
a s l i k e l y t o w i n a s c a r C . W h a t i s t h e p r o b a b i l i t y o f w i n n i n g e a c h c a r .
S o l : L e t b e t h e p r o b a b i l i t y o f w i n n i n g C a r C ,
P ( C ) = p
P ( B ) = 2 p
P ( A ) = 6 p
P ( A ) + P ( B ) + P ( C ) = 1
p + 2 p + 6 p = 1
9 p = 1
p =
P ( C ) =
P ( B ) =
P ( A ) =
1 3 . I f i s a f u n c t i o n t h a t c o n t a i n s 3 i n i t s d o m a i n a n d r a n g e a n d s a t i s f y t h e r e l a t i o n
f i n d f ( 3 )
S o l : L e t s a t i s f y t h e r e l a t i o n
f ( f ( a ) ) . ( 1 + f ( a ) ) = - f ( a )
f ( 3 ) . ( 4 ) = - 3
f ( 3 ) = -
1 4 . I f p r o v e t h a t .
S o l :
1 5 . F i n d t w o n u m b e r s s u c h t h a t t h e i r a r i t h m e t i c m e a n i s 1 5 a n d G e o m e t r i c m e a n i s 9
w i t h o u t u s i n g t h e i d e n t i t y
S o l : F o r m a q u a d r a t i c e q u a t i o n s u m o f w h o s e r o o t s a r e 3 0 a n d p r o d u c t o f t h e r o o t s i s 8 1
- x ( 3 0 ) + 8 1 = 0
- 3 x - 2 7 x + 8 1 = 0
x ( x - 3 ) - 2 7 ( x - 3 )
Page 5
C l a s s – X I
M A T H E M A T I C S
T i m e a l l o w e d : 3 h o u r s , M a x i m u m M a r k s : 1 0 0
G e n e r a l I n s t r u c t i o n s :
a ) A l l q u e s t i o n s a r e c o m p u l s o r y .
b ) T h e q u e s t i o n p a p e r c o n s i s t s o f 2 6 q u e s t i o n s d i v i d e d i n t o t h r e e s e c t i o n s A , B a n d C . S e c t i o n
A c o m p r i s e s o f 6 q u e s t i o n s o f o n e m a r k e a c h , S e c t i o n B c o m p r i s e s o f 1 3 q u e s t i o n s o f f o u r
m a r k s e a c h a n d S e c t i o n C c o m p r i s e s o f 7 q u e s t i o n s o f s i x m a r k s e a c h .
c ) A l l q u e s t i o n s i n S e c t i o n A a r e t o b e a n s w e r e d i n o n e w o r d , o n e s e n t e n c e o r a s p e r t h e e x a c t
r e q u i r e m e n t o f t h e q u e s t i o n .
d ) U s e o f c a l c u l a t o r s i s n o t p e r m i t t e d .
S e c t i o n A
1 . I d e n t i f y a f u n c t i o n s o t h a t
S o l :
2 . I f A = { ( x , y ) : y = a x , x R } a n d B = { ( x , y ) : y = a - x , x R } t h e n w h a t i s
S o l : W h e n i n b o t h c a s e s . H e n c e
3 . I f R i s a r e l a t i o n f r o m a s e t A c o n t a i n i n g e l e m e n t s t o a s e t B c o n t a i n i n g e l e m e n t s
t h e f i n d t h e n u m b e r o f s u b s e t s o f
S o l :
4 . C h e c k w h e t h e r t h e g i v e n l i n e s a r e p a r a l l e l o r p e r p e n d i c u l a r .
S o l : T h e y a r e p a r a l l e l s i n c e
5 . F i n d t h e a r e a o f t h e t r i a n g l e w h o s e v e r t i c e s a r e ( 2 , 0 ) , ( 5 , 3 ) , ( 2 , 6 )
S o l : A r e a o f a t r i a n g l e
=
6 . W r i t e t h e e q u a t i o n o f a c i r c l e w i t h c e n t e r ( 0 , 0 ) a n d r a d i u s 5 .
S o l :
S e c t i o n B
7 . S o l v e
S o l :
8 . P r o v e b y m a t h e m a t i c a l i n d u c t i o n t h a t .
S o l : L e t b e t h e s t a t e m e n t g i v e n b y
= 1 , T r u e
L e t i t b e t r u e f o r n = m
1 + 2 + 3 + . . . . + m =
1 + 2 + 3 + . . . . + m + ( m + 1 ) = + ( m + 1 )
P ( m + 1 ) = + ( m + 1 )
P ( m + 1 ) =
P ( m + 1 ) =
T h u s P ( m ) i s t r u e P ( m + 1 ) i s T r u e
9 . F i n d t h e s q u a r e r o o t o f .
S o l : L e t =
1 0 . S o l v e t h e i n e q u a l i t y .
S o l :
1 1 . F i n d t h e v a l u e o f i f 1 2 C x = 1 2 C x + 4 .
S o l : x + x + 4 = 1 2
2 x = 8
x = 4
1 2 . T h r e e c a r s a r e t h e r e i n a r a c e . C a r A i s 3 t i m e s a s l i k e l y t o w i n a s c a r B . C a r B i s t w i c e
a s l i k e l y t o w i n a s c a r C . W h a t i s t h e p r o b a b i l i t y o f w i n n i n g e a c h c a r .
S o l : L e t b e t h e p r o b a b i l i t y o f w i n n i n g C a r C ,
P ( C ) = p
P ( B ) = 2 p
P ( A ) = 6 p
P ( A ) + P ( B ) + P ( C ) = 1
p + 2 p + 6 p = 1
9 p = 1
p =
P ( C ) =
P ( B ) =
P ( A ) =
1 3 . I f i s a f u n c t i o n t h a t c o n t a i n s 3 i n i t s d o m a i n a n d r a n g e a n d s a t i s f y t h e r e l a t i o n
f i n d f ( 3 )
S o l : L e t s a t i s f y t h e r e l a t i o n
f ( f ( a ) ) . ( 1 + f ( a ) ) = - f ( a )
f ( 3 ) . ( 4 ) = - 3
f ( 3 ) = -
1 4 . I f p r o v e t h a t .
S o l :
1 5 . F i n d t w o n u m b e r s s u c h t h a t t h e i r a r i t h m e t i c m e a n i s 1 5 a n d G e o m e t r i c m e a n i s 9
w i t h o u t u s i n g t h e i d e n t i t y
S o l : F o r m a q u a d r a t i c e q u a t i o n s u m o f w h o s e r o o t s a r e 3 0 a n d p r o d u c t o f t h e r o o t s i s 8 1
- x ( 3 0 ) + 8 1 = 0
- 3 x - 2 7 x + 8 1 = 0
x ( x - 3 ) - 2 7 ( x - 3 )
( x - 3 ) ( x - 2 7 ) = 0
H e n c e t h e n u m b e r s a r e 3 a n d 2 7
1 6 . L e t b e a f u n c t i o n g i v e n b y f ( x ) = + 2 f i n d f - 1 ( 2 7 )
S o l : L e t b e a f u n c t i o n g i v e n b y f ( x ) = + 2 f i n d f - 1 ( 2 7 )
f ( x ) = + 2
+ 2 = 2 7
= 2 5
x = 5
f - 1 ( 2 7 ) = { - 5 , 5 }
1 7 . F i n d t h e d o m a i n a n d r a n g e o f t h e f u n c t i o n w h e r e a i s a p o s i t i v e
i n t e g e r .
S o l : T h e f u n c t i o n i s d e f i n e d f o r a l l v a l u e s o f x w h e r e t h e d e n o m i n a t o r i s n o t e q u a l t o z e r o
H e n c e d o m a i n =
R a n g e o f
L e t
R a n g e o f
1 8 . F i n d t h e l i m i t o f
S o l : R a t i o n a l i z e t h e n u m e r a t o r
Read More
|
75 videos|238 docs|91 tests
|
FAQs on Past Year Paper, Maths(Set - 1), 2019, Class 11 - Mathematics (Maths) Class 11 - Commerce
| 1. How can I download the past year paper for Maths(Set - 1) of Class 11 for 2019? |  |
Ans. You can download the past year paper for Maths(Set - 1) of Class 11 for 2019 by searching for it on educational websites, online forums, or by visiting the official website of your respective educational board. Many websites provide free access to past year papers in PDF format that can be easily downloaded and used for exam preparation.
| 2. What is the difficulty level of the Maths(Set - 1) exam for Class 11 in 2019? | |
Ans. The difficulty level of the Maths(Set - 1) exam for Class 11 in 2019 can vary from board to board. However, generally, the exam is designed to test the fundamental concepts and problem-solving skills of students. It may include questions of varying complexity, ranging from basic concepts to more challenging problems. It is advisable to thoroughly understand the syllabus and practice solving different types of questions to prepare effectively for the exam.
| 3. Are the questions in the Maths(Set - 1) exam for Class 11 in 2019 from the textbook? | |
Ans. The questions in the Maths(Set - 1) exam for Class 11 in 2019 can be based on the textbook as well as other reference materials. While the textbook forms the primary source of study, the exam may also include additional questions to assess the depth of a student's understanding and application of concepts. It is important to study the textbook thoroughly and practice solving additional questions from various sources to be well-prepared for the exam.
| 4. How should I prepare for the Maths(Set - 1) exam for Class 11 in 2019? | |
Ans. To prepare for the Maths(Set - 1) exam for Class 11 in 2019, it is crucial to have a clear understanding of the syllabus and the topics covered. Start by organizing your study material, including textbooks, reference books, and past year papers. Create a study schedule and allocate dedicated time for each topic. Practice solving different types of questions, including numerical problems and conceptual questions. Additionally, work on improving your problem-solving skills by attempting previous year papers and sample papers.
| 5. Are there any online resources available for the Maths(Set - 1) exam preparation of Class 11 in 2019? | |
Ans. Yes, there are several online resources available for the Maths(Set - 1) exam preparation of Class 11 in 2019. You can find educational websites, online forums, and video tutorials that provide study materials, practice questions, and explanations for various topics. Additionally, there are online platforms that offer interactive quizzes and mock tests to help you assess your preparation level. Make use of these resources to supplement your study and enhance your understanding of the subject.
About this Document
|
1.5K Views |
|
4.89/5 Rating |
|
Dec 22, 2024 Last updated |
Document Description: Past Year Paper, Maths(Set - 1), 2019, Class 11 for Commerce 2024 is part of Mathematics (Maths) Class 11 preparation.
The notes and questions for Past Year Paper, Maths(Set - 1), 2019, Class 11 have been prepared according to the Commerce exam syllabus. Information about Past Year Paper, Maths(Set - 1), 2019, Class 11 covers topics
like and Past Year Paper, Maths(Set - 1), 2019, Class 11 Example, for Commerce 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Past Year Paper, Maths(Set - 1), 2019, Class 11.
Introduction of Past Year Paper, Maths(Set - 1), 2019, Class 11 in English is available as part of our Mathematics (Maths) Class 11
for Commerce & Past Year Paper, Maths(Set - 1), 2019, Class 11 in Hindi for Mathematics (Maths) Class 11 course.
Download more important topics related with notes, lectures and mock test series for Commerce
Exam by signing up for free. Commerce: Past Year Paper, Maths(Set - 1), 2019, Class 11 | Mathematics (Maths) Class 11 - Commerce
Description
Full syllabus notes, lecture & questions for Past Year Paper, Maths(Set - 1), 2019, Class 11 | Mathematics (Maths) Class 11 - Commerce - Commerce | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 11 | Best notes, free PDF download
Information about Past Year Paper, Maths(Set - 1), 2019, Class 11
In this doc you can find the meaning of Past Year Paper, Maths(Set - 1), 2019, Class 11 defined & explained in the simplest way possible. Besides explaining types of
Past Year Paper, Maths(Set - 1), 2019, Class 11 theory, EduRev gives you an ample number of questions to practice Past Year Paper, Maths(Set - 1), 2019, Class 11 tests, examples and also practice Commerce
tests
|
Explore Courses for Commerce exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
past year papers
,Extra Questions
,2019
,Past Year Paper
,Previous Year Questions with Solutions
,Past Year Paper
,mock tests for examination
,Semester Notes
,2019
,Maths(Set - 1)
,Maths(Set - 1)
,study material
,2019
,Maths(Set - 1)
,Viva Questions
,Free
,ppt
,Class 11 | Mathematics (Maths) Class 11 - Commerce
,Class 11 | Mathematics (Maths) Class 11 - Commerce
,video lectures
,shortcuts and tricks
,Important questions
,Summary
,Sample Paper
,MCQs
,Objective type Questions
,Class 11 | Mathematics (Maths) Class 11 - Commerce
,practice quizzes
,Exam
,Past Year Paper
;
Additional Information about Past Year Paper, Maths(Set - 1), 2019, Class 11 for Commerce Preparation
Past Year Paper, Maths(Set - 1), 2019, Class 11 Free PDF Download
The Past Year Paper, Maths(Set - 1), 2019, Class 11 is an invaluable resource that delves deep into the core of the Commerce exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the Past Year Paper, Maths(Set - 1), 2019, Class 11 now and kickstart your journey towards success in the Commerce exam.
Importance of Past Year Paper, Maths(Set - 1), 2019, Class 11
The importance of Past Year Paper, Maths(Set - 1), 2019, Class 11 cannot be overstated, especially for Commerce aspirants.
This document holds the key to success in the Commerce exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
Past Year Paper, Maths(Set - 1), 2019, Class 11 Notes
Past Year Paper, Maths(Set - 1), 2019, Class 11 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to Past Year Paper, Maths(Set - 1), 2019, Class 11.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, Past Year Paper, Maths(Set - 1), 2019, Class 11 Notes on EduRev are your ultimate resource for success.
Past Year Paper, Maths(Set - 1), 2019, Class 11 Commerce Questions
The "Past Year Paper, Maths(Set - 1), 2019, Class 11 Commerce Questions" guide is a valuable resource for all aspiring students preparing for the
Commerce exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study Past Year Paper, Maths(Set - 1), 2019, Class 11 on the App
Students of Commerce can study Past Year Paper, Maths(Set - 1), 2019, Class 11 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the Past Year Paper, Maths(Set - 1), 2019, Class 11,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of Past Year Paper, Maths(Set - 1), 2019, Class 11 is prepared as per the latest Commerce syllabus.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup