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**Q.1 For a plane stress problem, the state of stress at a point P is represented by the stress element as shown in figure.By how much angle (θ) in degrees the stress element should be rotated in order to get the planes of maximum shear stress? [2019 : 2 Marks, Set-II](a) 31.7(b) 13.3(c) 26.6(d) 48.3Ans.** (A)

Angle of plane of max shear

∴

(a) Zero

(b) 0.0050

(c) 0.0010

(d) 0.0025

Ans.

Normal strain in the plane of maximum shear strain

The shear stress τ is [2016 : 2 Marks, Set-II]

(a) 10.0 MPa

(b) 5.0 MPa

(c) 2.5 MPa

(d) 0.0 MPa

Ans.

Now,

∴

⇒

∴ **Q.4 For the plane stress situation shown in the figure, the maximum shear stress and the plane on which it acts are [2015 : 1 Mark, Set-II](a) -50 MPa, on a plane 45** (D)

Under hydrostatic loading condition, stresses at a point in all directions are equal and hence no shear stress.

Alternatively,

Thus, Mohr’s circle reduces to a point. Hence shear stress at all orientations is zero.

As plane ABand BCare principle planes, therefore Mohr’s circle for the given condition is,

Here, normal stress is zero at 45

⇒ at 45

The maximum shear stress in MPa is [2013 : 2 Marks]

(a) 50

(b) 75

(c) 100

(d) 110

Ans.

But SS is not the option so taken (τ

(a) 0

(b) p/2

(c) p

(d) 2p

Ans.

Maximum shear stress,

(a) zero

(b) 3 MPa

(c) 6 MPa

(d) 9 MP

Ans.

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