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Question 1:In a surface broaching process, a broach having 5 mm pitch and cut per teeth 0.05 mm is used for reducing the thickness by 6 mm. If the length of the workpiece is 50 mm and the cutting speed is 0.5 m/s, the time required/pass in second is

[PI 2006]

Question 2:In deep drawing of sheet metal, spring loaded stripper clamps the work until:

[PI 2004]

Question 3:The function of draw bead in the deep drawing operation is to

[PI 1994]

Question 4:In a bending operation, if the modulus of elasticity E is increased keeping all other parameters unehanged, the spring back will

[PI 1994]

Question 5:Wall thickness of drawn cup is controlled by

[PI 1992]

Question 6:A cup of 10 cm height and 5 cm diameter is to be made from a sheet metal of 2 mm thickness.The number of deductions necessary will be

[PI 1991]

Question 7:In progressive die (for sheet metal), spring loaded stripper plate is used to clamp the stock until

[PI 1991]

Question 8:Consider a linear elastic rectangular thin sheet of metal, subjected to uniform uniaxial tensile stress of 100 MPa along the length direction. Assume plane stress condition in the plane normal to the thickness. The Young’s modulus E = 200 MPa and Poisson’s ratio μ = 0.3 are given. The principal strains in the plane of the sheet are

[ME 2019,Set-2]

Question 9: The value of true strain produced in compressing a cylinder to half its original length is

[ME 2016,Set-2]

Question 10:In the deep drawing of cups, blanks show a tendency to wrinkle up around the periphery (flange). The most likely cause and remedy of the phenomenon are, respectively.

[ME 2008]

Question 11:A shell of 100 mm diameter and 100 mm height with the corner radius of 0.4 mm is to be produced by cup drawing. The required blank diameter is

[ME 2003]

Question 12:Identify the stress strain in flange portion of a partially drawn cylindrical cup when deep drawing without a blank holder

[ME 1999]

Question 13:In deep drawing of sheets, the values of limiting drawing ratio depends on

[ME 1994]

Question 14:Wrinkling is a common defect found is

[ME 1991]

Question 15:Circular blanks of 10 mm diameter are punched from an aluminum sheet of 2 mm thickness.The shear strength of aluminum is 80 MPa.The minimum punching force required in kN is

[PI 2013]

Question 16:A disc of 200 mm diameter is blanked from a strip of an aluminum alloy of thickness 3.2 mm.The material shear strength to fracture is 150 MPa.The blanking force (in kN) is

[PI 2009]

Question 17:A blank of 50 mm diameter is to be sheared from a sheet of 2.5 mm thickness. The required radial clearance between the die and the punch is 6% of sheet thickness. The punch and die diameter (mm) for this blanking operation respectively are

[PI 2008]

Question 18:Circular blanks of 35 mm dia are punched from a steel sheet of 2 mm thickness. If the clearance per side between the punch and die is to be kept as 40 microns. The sizes of punch and die should respectively be

[PI 2007]

Question 19: It is required to punch a hole of diameter 10 mm on a sheet of thickness 3 mm. The shear strength of the work material is 420 MPa.The required punch force is

[PI 2006]

Question 20:It is require to punch a hole of diameter 10 mm on a sheet of thickness 3 mm. The shear strength of the work material is 420 MPa. The required punch force is

[PI 2006]

Question 21:A ϕ 25 mm hole is pierced in a t = 2.5 mm thick steel sheet having shear strength τ = 350 MPa.If the diametral clearance is given by the expression c = 0.0064 √τ, the die diameter (in mm), punch diameter (in mm) and punch force in (kN) respectively are

[PI 2005]

Question 22:Determine the load required to punch a 20 mm diameter hole in 2 mm thick sheet. The properties of the material of the sheet are: Tensile strength – 580 MPa

Yield strength in tension – 410

MPa Shear strength – 350 MPa

Yield strength in shear – 250 MPa

Yield strength in tension – 410

MPa Shear strength – 350 MPa

Yield strength in shear – 250 MPa

The load in kN is

[PI 2004]

Question 23:A hole of 40 mm diameter is pierced in a steel sheet of 4 mm thickness without shear on the tool. Shear strength of steel is 400 N/mm2 and penetration is 25%. What is the expected percentage load reduction if a shear of 1 mm is provided on the punch?

[PI 2004]

Question 24:A cylindrical cup of 48.5 mm diameter and 52 mm height has a corner radius of 1.5 mm.Cold rolled steel sheet of thickness 1.5 mm is used to produce the cup. Assume trim allowance as 2 mm per 25 mm of cup diameter.What is the blank size in mm?

[PI 2004]

Question 25:Consider the following statements related piercing and blanking

1. Shear on the punch reduces the maximum cutting force

2. Shear increases the capacity of the press needed

3. Shear increases the life of the punch

4. Total energy needed to make the cut remains unaltered due to provision of shear.

1. Shear on the punch reduces the maximum cutting force

2. Shear increases the capacity of the press needed

3. Shear increases the life of the punch

4. Total energy needed to make the cut remains unaltered due to provision of shear.

Which of the above statements are correct?

[PI 2003]

Question 26:A hydraulic press is used to produce circular blanks of 10 mm diameter from a sheet of 2 mm thickness. If the shear strength of the sheet material is 400 N/mm^{2}, the force required for producing a circular blank is

[PI 2003]

Question 27:Which one is not a method of reducing cutting forces to prevent the overloading of press?

[PI 2003]

Question 28:For 50% penetration of work material, a punch with single shear equal to thickness will

[PI 2001]

Question 29:In blanking operation, the best way to improve the smoothness and secureness of the edges is to

[PI 1994]

Question 30:Calculate the smallest punch diameter that can be designed for piercing sheet metal strip with the following data. Crushing strength of the punch material is 1500 MPa. Thickness of the sheet is 2 mm, factor of safety is 3, shear strength of the sheet material 500 MPa is

[PI 1990]

Question 31:Internal gears are manufactured by

[ME 2014,Set-2]

Question 32:A rectangular hole of size 100 mm × 50 mm is to be made on a 5 mm thick sheet of steel having ultimate tensile strength and shear strength of 500 MPa and 300 MPa, respectively. The hole is made by punching process. Neglecting the effect of clearance, the punching force (in kN) is

[ME 2014,Set-2]

Question 33:Calculate the punch size in mm, for a circular blanking operation for which details are given below.

Size of the blank - 25 mm

Thickness of the sheet - 2 mm

Radial clearance between punch and die 0.06 mm Die allowance 0.05 mm

[ME 2012]

Question 34:The shear strength of a sheet metal is 300 MPa.The blanking force required to produce a blank of 100 mm diameter from a 1.5 mm thick sheet is close to

[ME 2011]

Question 35:10 mm diameter holes are to be punched in a steel sheet of 3 mm thickness. Shear strength of the material is 400 N/mm^{2} and penetration is 40%. Shear provided on the punch is 2 mm.The blanking force during the operation will be

[ME 2004]

Question 36:A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the dia clearance is 3%. The required punch diameter is

[ME 2003]

Question 37:In blanking operation the clearance is provided on

[ME 2002]

Question 38:The cutting force in punching and blanking operations mainly depends on

[ME 2001]

Question 39:A 50 mm diameter disc is to be punched out from a carbon steel sheet 1.0 mm thick. The diameter of the die should be (Take clearance as 3% of sheet thickness) _______.

[ME 1996]

Question 40:The thickness of the blank needed to produce, by power spinning a missile cone of thickness 1.5 mm and half cone angle 30°

[ME 1992]

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