Percentages CAT Previous Year Questions with Answer PDF

Let the total number of registered voters be 100x.
Number of votes casted = 80x

Votes for Candidate 1 = 30% of 80x = 24x
∴ Remaining three candidates will recieve = 80x - 24x = 56x votes.

Remaining 3 candidates get votes in the ratio of 1 : 2 : 3 of the remaining 56x votes.
⇒ Votes of Candidate 2 = 1/6 × 56x = 28x/3
⇒ Votes of Candidate 3 = 2/6 × 56x = 56x/3
⇒ Votes of Candidate 4 = 3/6 × 56x = 28x

Highest number of votes is received by Candidate 4 while second highest is by Candidate 1.
⇒ 28x – 24x = 2512
⇒ x = 2512/4 = 628

∴ total number of registered votes = 100x = 62800

Hence, option (d).

Let the selling price of the Large and Small boxes of chocolates be Rs.200 and Rs.100 respectively. Let us consider that the Large box has LL grams of chocolate while the Small box has SS grams of chocolate. 
The relation between the selling price per gram of chocolate can be represented as:

On solving we obtain the ratio of the amount of chocolate in each box as: L/S = 25/11
The percentage by which the weight of chocolate in the large box exceeds that in the small box
= 

Let the total number of people in the group be x

So, the total number of young members = (28/100) × x = 0.28x

Also, the total number of old members = x – 0.28x = 0.72x

It is also given that, 65% of all the members are literates,

Hence, total number of literate people = (65/100) × x = 0.65x

So, the total number of illiterate people = x – 0.65x = 0.35x

Besides, it is also given that 25% of the literates are young.

So, the number of young literates = (25/100) × 0.65x = 0.1625x

Hence, the number of young illiterates = 0.28x – 0.1625x = 0.1175x

Also, we get:

The number of illiterate old people = 0.35x – 0.1175x = 0.2325x

Hence, we can obtain the percentage of old people among the illiterates as:

(0.2325x/0.35x) × 100 = 66.423% ≈ 66%

Amount spent on rice in May = 450  x 1.2 = ? 540.
If the amount spent on wheat in April is w, then in May it would be 1.12w.
Given, (1.12w + 540) - ( w + 450) = 150
⇒ 12w = 60
⇒ w = 500
∴ The amount spent on wheat in May =1.12w i.e.,  560 

Let Bimala's income be B. Amala's income is 20% more than B.
So, A = 1.2 B
Similarly, Amala's income is 20% less than that of Kamala.
A = 0.8K
Therefore, 1.2B = 0.8K (or) K = (3/2)B
Now, Bimala's new income goes up by 10% = 1.1B
Kamala's income goes down by 4%
4% (1.5B) = 0.06B
Therefore, Kamala's new income is = 1.5B - 0.06B = 1.44B
So, K = 1.44B and B = 1.1 B
Percentage change = 0.34 B = (0.34/1.1) x 100 = 31%

Let total maximum marks in the examination = 100X

Meena’s score = 40% of 100X = 40X

Meena’s marks after review = 40X + 50% of 40X

⇒ 40X + 20X = 60X

With 60x score, she fails by 35 marks. So, passing marks = 60x + 35      ____(i)

Meena’s marks after post review = 60X + 20% of 60X

⇒ 60X + 12X = 72X

Now, passing score = 72X – 7      ____(ii)

Equating equation (i) and (ii) we get,

⇒ 72X – 7 = 60X + 35

⇒ 12X = 42

⇒ X = 7/2

Percentage of score needed to pass the examination is {(60X + 35)/100X × 100}

⇒ (245 × 100)/350 = 70

∴ Meena need to score 70% to pass the examination.

Increase in books = 12760 - 11500 = 1260
 +   x  (11500 - x) = 1260
10x + 12 x 11500 - 12x = 126000
x = 6000 books
So, Fiction books in 2015, 6000 + 600 = 6600 books

Given Max. mark = N and Pass mark = 45% of N
A scores 36 marks and falls short of the pass mark by 68%
This means the pass mark must be reduced by (100 - 68)% = 32%
So, A scored 32% (45% N) = 36
N = 250 marks
The only option whose range falls within the obtained value is (B) 243 ≤ N ≤ 252

Given that the number of girls appearing for an admission test is twice the number of boys.
Let x be the number of boys and 2x be the number of girls.
We have to find the % of candidates who do not get admission if 30% of the girls and 45% of the boys get admission.
Those who got admission is 1.05x and those who do not get admission is 1.95x.
So, 
The percentage of candidates who do not get admission is 65%.

Given that in a shirt factory , 15% of the shirts produced are defective so 85% are non defective.
From this remaining 85% non defective shirts, 20% are sold in domestic market and the remaining 80% are left for export which is equal to 8840 shirts i.e. 80% of 85% of x = 8840

⇒ x = 13000
The number of shirts produced in the factory is 13000

Given that the production of food grains increased by 40%.
Let initial production be y and after increase it becomes 1.4x
Per capita production of food grains increased by 27%.
Per capita income = 
⇒ let the initial Per capita income be (x/y).
After increase it becomes 1.27[x/y].


Hence there is an increase of 10% in the population of the village.