Physics Past Year Paper Theory (Delhi Set -2) - 2015, Class 12, CBSE Class 12 Notes | EduRev

 Page 1


55/1/2 1 [P.T.O. 
¸üÖê»Ö ®ÖÓ.
Roll No. 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70
Time allowed : 3 hours ] [ Maximum Marks : 70 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü … ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … 
(ii) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-†, ÜÖÞ›ü-²Ö, ÜÖÞ›ü-ÃÖ, ÜÖÞ›ü-¤ü †Öî¸ü ÜÖÞ›ü-µÖ … 
(iii) ÜÖÞ›ü-† ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú ÛúÖ 1 †ÓÛú Æîü … ÜÖÞ›ü-²Ö ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 2 †ÓÛú Æïü … ÜÖÞ›ü-ÃÖ ´Öë 
12 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 3 †ÓÛú Æïü … ÜÖÞ›ü-¤ü ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ÜÖÞ›ü-µÖ ´Öë 3 
¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 5 †ÓÛú Æïü … 
(iv) ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ŸÖ£ÖÖׯÖ, ¤üÖê †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú ¯ÖÏ¿®Ö ´Öë, ŸÖß®Ö †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú 
¯ÖÏ¿®Ö ´Öë †Öî¸ü ¯ÖÖÑ“Ö †ÓÛúÖë ¾ÖÖ»Öê ŸÖß®ÖÖë ¯ÖÏ¿®ÖÖë ´Öë †Ö®ŸÖ׸üÛú “ÖµÖ®Ö ¯ÖϤüÖ®Ö ×ÛúµÖÖ ÝÖµÖÖ Æîü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê 
פü‹ ÝÖ‹ “ÖµÖ®Ö ´Öë ÃÖê Ûêú¾Ö»Ö ‹Ûú ¯ÖÏ¿®Ö Æüß Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1/C 
55/1/2
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12  Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the
question paper only and will not write any answer on the answer-book during this period.
ÛúÖê›ü ®ÖÓ. 
Code No. 
   
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book.
SET – 2 
Page 2


55/1/2 1 [P.T.O. 
¸üÖê»Ö ®ÖÓ.
Roll No. 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70
Time allowed : 3 hours ] [ Maximum Marks : 70 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü … ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … 
(ii) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-†, ÜÖÞ›ü-²Ö, ÜÖÞ›ü-ÃÖ, ÜÖÞ›ü-¤ü †Öî¸ü ÜÖÞ›ü-µÖ … 
(iii) ÜÖÞ›ü-† ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú ÛúÖ 1 †ÓÛú Æîü … ÜÖÞ›ü-²Ö ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 2 †ÓÛú Æïü … ÜÖÞ›ü-ÃÖ ´Öë 
12 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 3 †ÓÛú Æïü … ÜÖÞ›ü-¤ü ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ÜÖÞ›ü-µÖ ´Öë 3 
¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 5 †ÓÛú Æïü … 
(iv) ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ŸÖ£ÖÖׯÖ, ¤üÖê †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú ¯ÖÏ¿®Ö ´Öë, ŸÖß®Ö †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú 
¯ÖÏ¿®Ö ´Öë †Öî¸ü ¯ÖÖÑ“Ö †ÓÛúÖë ¾ÖÖ»Öê ŸÖß®ÖÖë ¯ÖÏ¿®ÖÖë ´Öë †Ö®ŸÖ׸üÛú “ÖµÖ®Ö ¯ÖϤüÖ®Ö ×ÛúµÖÖ ÝÖµÖÖ Æîü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê 
פü‹ ÝÖ‹ “ÖµÖ®Ö ´Öë ÃÖê Ûêú¾Ö»Ö ‹Ûú ¯ÖÏ¿®Ö Æüß Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1/C 
55/1/2
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12  Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the
question paper only and will not write any answer on the answer-book during this period.
ÛúÖê›ü ®ÖÓ. 
Code No. 
   
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book.
SET – 2 
55/1/2 2 
(v) •ÖÆüÖÑ †Ö¾Ö¿µÖÛú ÆüÖê †Ö¯Ö ×®Ö´®Ö×»Ö×ÜÖŸÖ ³ÖÖîןÖÛ  ×®ÖµÖŸÖÖÓÛúÖë Ûêú ´ÖÖ®ÖÖë ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü :
c = 3 × 10
8
 m/s 
h = 6.63 × 10
–34
 Js 
e = 1.6 × 10
–19
 C 
µ
0
 = 4p × 10
–7
 T m A
–1
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2
m
e
 = 9.1 × 10
–31
 kg
®µÖæ™ÒüÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.675 × 10
–27
 kg
¯ÖÏÖê™üÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.673 × 10
–27
 kg
†Ö¾ÖÖêÝÖÖ¦üÖê ÃÖÓܵÖÖ = 6.023 × 10
23
 ¯ÖÏ×ŸÖ ÝÖÏÖ´Ö ´ÖÖê»Ö 
²ÖÖê»™Ëü•ÖÌ´ÖÖ®Ö ×®ÖµÖŸÖÖÓÛú = 1.38 × 10
–23
 JK
–1
General Instructions : 
(i) All questions are compulsory. There are 26 questions in all. 
(ii) This question paper has five sections : Section A, Section B, Section C, Section D 
and Section E. 
(iii) Section A contains five questions of one mark each, Section B contains five 
questions of two marks each, Section C contains twelve questions of three marks 
each, Section D contains one value based question of four marks and Section E 
contains three questions of five marks each. 
(iv) There is no overall choice. However, an internal choice has been provided in one 
question of two marks, one question of three marks and all the three questions of 
five marks weightage. You have to attempt only one of the choices in such 
questions. 
(v) You may use the following values of physical constants wherever necessary : 
c = 3 × 10
8
 m/s 
h = 6.63 × 10
–34
 Js 
e = 1.6 × 10
–19
 C 
µ
0
 = 4p × 10
–7
 T m A
–1
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2
m
e
 = 9.1 × 10
–31
 kg
Mass of neutron = 1.675 × 10
–27
 kg 
Mass of proton = 1.673 × 10
–27
 kg 
Avogadro’s number = 6.023 × 10
23
 per gram mole 
Boltzmann constant = 1.38 × 10
–23
 JK
–1
 
Page 3


55/1/2 1 [P.T.O. 
¸üÖê»Ö ®ÖÓ.
Roll No. 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70
Time allowed : 3 hours ] [ Maximum Marks : 70 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü … ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … 
(ii) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-†, ÜÖÞ›ü-²Ö, ÜÖÞ›ü-ÃÖ, ÜÖÞ›ü-¤ü †Öî¸ü ÜÖÞ›ü-µÖ … 
(iii) ÜÖÞ›ü-† ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú ÛúÖ 1 †ÓÛú Æîü … ÜÖÞ›ü-²Ö ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 2 †ÓÛú Æïü … ÜÖÞ›ü-ÃÖ ´Öë 
12 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 3 †ÓÛú Æïü … ÜÖÞ›ü-¤ü ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ÜÖÞ›ü-µÖ ´Öë 3 
¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 5 †ÓÛú Æïü … 
(iv) ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ŸÖ£ÖÖׯÖ, ¤üÖê †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú ¯ÖÏ¿®Ö ´Öë, ŸÖß®Ö †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú 
¯ÖÏ¿®Ö ´Öë †Öî¸ü ¯ÖÖÑ“Ö †ÓÛúÖë ¾ÖÖ»Öê ŸÖß®ÖÖë ¯ÖÏ¿®ÖÖë ´Öë †Ö®ŸÖ׸üÛú “ÖµÖ®Ö ¯ÖϤüÖ®Ö ×ÛúµÖÖ ÝÖµÖÖ Æîü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê 
פü‹ ÝÖ‹ “ÖµÖ®Ö ´Öë ÃÖê Ûêú¾Ö»Ö ‹Ûú ¯ÖÏ¿®Ö Æüß Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1/C 
55/1/2
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12  Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the
question paper only and will not write any answer on the answer-book during this period.
ÛúÖê›ü ®ÖÓ. 
Code No. 
   
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book.
SET – 2 
55/1/2 2 
(v) •ÖÆüÖÑ †Ö¾Ö¿µÖÛú ÆüÖê †Ö¯Ö ×®Ö´®Ö×»Ö×ÜÖŸÖ ³ÖÖîןÖÛ  ×®ÖµÖŸÖÖÓÛúÖë Ûêú ´ÖÖ®ÖÖë ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü :
c = 3 × 10
8
 m/s 
h = 6.63 × 10
–34
 Js 
e = 1.6 × 10
–19
 C 
µ
0
 = 4p × 10
–7
 T m A
–1
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2
m
e
 = 9.1 × 10
–31
 kg
®µÖæ™ÒüÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.675 × 10
–27
 kg
¯ÖÏÖê™üÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.673 × 10
–27
 kg
†Ö¾ÖÖêÝÖÖ¦üÖê ÃÖÓܵÖÖ = 6.023 × 10
23
 ¯ÖÏ×ŸÖ ÝÖÏÖ´Ö ´ÖÖê»Ö 
²ÖÖê»™Ëü•ÖÌ´ÖÖ®Ö ×®ÖµÖŸÖÖÓÛú = 1.38 × 10
–23
 JK
–1
General Instructions : 
(i) All questions are compulsory. There are 26 questions in all. 
(ii) This question paper has five sections : Section A, Section B, Section C, Section D 
and Section E. 
(iii) Section A contains five questions of one mark each, Section B contains five 
questions of two marks each, Section C contains twelve questions of three marks 
each, Section D contains one value based question of four marks and Section E 
contains three questions of five marks each. 
(iv) There is no overall choice. However, an internal choice has been provided in one 
question of two marks, one question of three marks and all the three questions of 
five marks weightage. You have to attempt only one of the choices in such 
questions. 
(v) You may use the following values of physical constants wherever necessary : 
c = 3 × 10
8
 m/s 
h = 6.63 × 10
–34
 Js 
e = 1.6 × 10
–19
 C 
µ
0
 = 4p × 10
–7
 T m A
–1
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2
m
e
 = 9.1 × 10
–31
 kg
Mass of neutron = 1.675 × 10
–27
 kg 
Mass of proton = 1.673 × 10
–27
 kg 
Avogadro’s number = 6.023 × 10
23
 per gram mole 
Boltzmann constant = 1.38 × 10
–23
 JK
–1
 
55/1/2 3 [P.T.O. 
ÜÖÞ›ü – †
Section – A 
1. •Ö²Ö ×ÛúÃÖß ×²Ö´²Ö ÛúÖê ×ÛúÃÖß †¾ÖŸÖ»Ö ¤ü¯ÖÔÞÖ Ûêú f †Öî¸ü 2f Ûêú ²Öß“Ö ¸üÜÖÖ •ÖÖŸÖÖ Æîü, ŸÖ²Ö ²Ö®Ö®Öê ¾ÖÖ»ÖÖ ¯ÖÏןÖײִ²Ö ÛîúÃÖÖ 
ÆüÖêŸÖÖ Æîü – (i) ¾ÖÖßÖ×¾ÖÛú †£Ö¾ÖÖ †Ö³ÖÖÃÖß †Öî¸ü (ii) ”ûÖê™üÖ †£Ö¾ÖÖ ×¾Ö¾ÖÙ¬ÖŸÖ ? 1 
When an object is placed between f and 2f of a concave mirror, would the image 
formed be (i) real or virtual and (ii) diminished or magnified ? 
2. ‡»ÖꌙÒüÖò®Ö Ûúß ÝÖ×ŸÖ•Ö ‰ú•ÖÖÔ Ûêú ±ú»Ö®Ö Ûêú ºþ¯Ö ´Öë ‡ÃÖÛúß ¤êü-²ÖÎÖÝ»Öß ŸÖ¸ÓüÝÖ¤îü¬µÖÔ Ûêú ×¾Ö“Ö¸üÞÖ ÛúÖê ÝÖÏÖ±ú ÜÖà“ÖÛú¸ü
¤ü¿ÖÖÔ‡‹ … 1 
Draw a plot showing the variation of de Broglie wavelength of electron as a function
of its K. E.
3. ´ÖÖê²ÖÖ‡»Ö ±úÖê®Ö ´Öë †ÖÝÖ´Öß ×ÃÖݮֻÖÖë †Öî¸ü ×®ÖÝÖÔ´Öß ×ÃÖݮֻÖÖë Ûúß †Ö¾Öé×¢ÖµÖÖÑ ×³Ö®®Ö ŒµÖÖë ÆüÖêŸÖß Æîü ? 1 
Why is the frequency of outgoing and incoming signals different in a mobile phone ?
4. ¦ü¾µÖ´ÖÖ®Ö ‘m’ †Öî¸ü †Ö¾Öê¿Ö ‘q’ ÛúÖ ÛúÖê‡Ô ÛúÞÖ ‘v’ ¾ÖêÝÖ ÃÖê ×ÛúÃÖß ‹ÛúÃÖ´ÖÖ®Ö “Öã´²ÖÛúßµÖ õÖê¡Ö, •ÖÖê ÛúÞÖ Ûúß ÝÖ×ŸÖ Ûúß
פü¿ÖÖ Ûêú »Ö´²Ö¾ÖŸÖ Æîü, ´Öë ¯ÖϾÖê¿Ö Ûú¸üŸÖÖ Æîü, ˆÃÖÛúß ÝÖ×ŸÖ•Ö ‰ú•ÖÖÔ ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ¯ÖϳÖÖ×¾ÖŸÖ ÆüÖêŸÖß Æîü ? 1 
A particle of mass ‘m’ and charge ‘q’ moving with velocity ‘v’ enters the region of
uniform magnetic field at right angle to the direction of its motion. How does its
kinetic energy get affected ?
5. ×“Ö¡Ö ´Öë ×ÛúÃÖß ¬ÖÖ¸üÖ¾ÖÖÆüß ¯Ö׸ü®ÖÖ×»ÖÛúÖ ÛúÖê ×ÛúÃÖß “ÖÖ»ÖÛú »Öæ¯Ö (¯ÖÖ¿Ö) Ûúß †Öê¸ü ÝÖןִÖÖ®Ö ¤ü¿ÖÖÔµÖÖ ÝÖµÖÖ Æîü … »Öæ¯Ö ´Öë
¯ÖÏê׸üŸÖ ¬ÖÖ¸üÖ Ûúß ×¤ü¿ÖÖ ²ÖŸÖÖ‡‹ … 1 
Figure shows a current carrying solenoid moving towards a conducting loop. Find the 
direction of the current induced in the loop. 
Page 4


55/1/2 1 [P.T.O. 
¸üÖê»Ö ®ÖÓ.
Roll No. 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70
Time allowed : 3 hours ] [ Maximum Marks : 70 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü … ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … 
(ii) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-†, ÜÖÞ›ü-²Ö, ÜÖÞ›ü-ÃÖ, ÜÖÞ›ü-¤ü †Öî¸ü ÜÖÞ›ü-µÖ … 
(iii) ÜÖÞ›ü-† ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú ÛúÖ 1 †ÓÛú Æîü … ÜÖÞ›ü-²Ö ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 2 †ÓÛú Æïü … ÜÖÞ›ü-ÃÖ ´Öë 
12 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 3 †ÓÛú Æïü … ÜÖÞ›ü-¤ü ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ÜÖÞ›ü-µÖ ´Öë 3 
¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 5 †ÓÛú Æïü … 
(iv) ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ŸÖ£ÖÖׯÖ, ¤üÖê †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú ¯ÖÏ¿®Ö ´Öë, ŸÖß®Ö †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú 
¯ÖÏ¿®Ö ´Öë †Öî¸ü ¯ÖÖÑ“Ö †ÓÛúÖë ¾ÖÖ»Öê ŸÖß®ÖÖë ¯ÖÏ¿®ÖÖë ´Öë †Ö®ŸÖ׸üÛú “ÖµÖ®Ö ¯ÖϤüÖ®Ö ×ÛúµÖÖ ÝÖµÖÖ Æîü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê 
פü‹ ÝÖ‹ “ÖµÖ®Ö ´Öë ÃÖê Ûêú¾Ö»Ö ‹Ûú ¯ÖÏ¿®Ö Æüß Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1/C 
55/1/2
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12  Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the
question paper only and will not write any answer on the answer-book during this period.
ÛúÖê›ü ®ÖÓ. 
Code No. 
   
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book.
SET – 2 
55/1/2 2 
(v) •ÖÆüÖÑ †Ö¾Ö¿µÖÛú ÆüÖê †Ö¯Ö ×®Ö´®Ö×»Ö×ÜÖŸÖ ³ÖÖîןÖÛ  ×®ÖµÖŸÖÖÓÛúÖë Ûêú ´ÖÖ®ÖÖë ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü :
c = 3 × 10
8
 m/s 
h = 6.63 × 10
–34
 Js 
e = 1.6 × 10
–19
 C 
µ
0
 = 4p × 10
–7
 T m A
–1
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2
m
e
 = 9.1 × 10
–31
 kg
®µÖæ™ÒüÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.675 × 10
–27
 kg
¯ÖÏÖê™üÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.673 × 10
–27
 kg
†Ö¾ÖÖêÝÖÖ¦üÖê ÃÖÓܵÖÖ = 6.023 × 10
23
 ¯ÖÏ×ŸÖ ÝÖÏÖ´Ö ´ÖÖê»Ö 
²ÖÖê»™Ëü•ÖÌ´ÖÖ®Ö ×®ÖµÖŸÖÖÓÛú = 1.38 × 10
–23
 JK
–1
General Instructions : 
(i) All questions are compulsory. There are 26 questions in all. 
(ii) This question paper has five sections : Section A, Section B, Section C, Section D 
and Section E. 
(iii) Section A contains five questions of one mark each, Section B contains five 
questions of two marks each, Section C contains twelve questions of three marks 
each, Section D contains one value based question of four marks and Section E 
contains three questions of five marks each. 
(iv) There is no overall choice. However, an internal choice has been provided in one 
question of two marks, one question of three marks and all the three questions of 
five marks weightage. You have to attempt only one of the choices in such 
questions. 
(v) You may use the following values of physical constants wherever necessary : 
c = 3 × 10
8
 m/s 
h = 6.63 × 10
–34
 Js 
e = 1.6 × 10
–19
 C 
µ
0
 = 4p × 10
–7
 T m A
–1
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2
m
e
 = 9.1 × 10
–31
 kg
Mass of neutron = 1.675 × 10
–27
 kg 
Mass of proton = 1.673 × 10
–27
 kg 
Avogadro’s number = 6.023 × 10
23
 per gram mole 
Boltzmann constant = 1.38 × 10
–23
 JK
–1
 
55/1/2 3 [P.T.O. 
ÜÖÞ›ü – †
Section – A 
1. •Ö²Ö ×ÛúÃÖß ×²Ö´²Ö ÛúÖê ×ÛúÃÖß †¾ÖŸÖ»Ö ¤ü¯ÖÔÞÖ Ûêú f †Öî¸ü 2f Ûêú ²Öß“Ö ¸üÜÖÖ •ÖÖŸÖÖ Æîü, ŸÖ²Ö ²Ö®Ö®Öê ¾ÖÖ»ÖÖ ¯ÖÏןÖײִ²Ö ÛîúÃÖÖ 
ÆüÖêŸÖÖ Æîü – (i) ¾ÖÖßÖ×¾ÖÛú †£Ö¾ÖÖ †Ö³ÖÖÃÖß †Öî¸ü (ii) ”ûÖê™üÖ †£Ö¾ÖÖ ×¾Ö¾ÖÙ¬ÖŸÖ ? 1 
When an object is placed between f and 2f of a concave mirror, would the image 
formed be (i) real or virtual and (ii) diminished or magnified ? 
2. ‡»ÖꌙÒüÖò®Ö Ûúß ÝÖ×ŸÖ•Ö ‰ú•ÖÖÔ Ûêú ±ú»Ö®Ö Ûêú ºþ¯Ö ´Öë ‡ÃÖÛúß ¤êü-²ÖÎÖÝ»Öß ŸÖ¸ÓüÝÖ¤îü¬µÖÔ Ûêú ×¾Ö“Ö¸üÞÖ ÛúÖê ÝÖÏÖ±ú ÜÖà“ÖÛú¸ü
¤ü¿ÖÖÔ‡‹ … 1 
Draw a plot showing the variation of de Broglie wavelength of electron as a function
of its K. E.
3. ´ÖÖê²ÖÖ‡»Ö ±úÖê®Ö ´Öë †ÖÝÖ´Öß ×ÃÖݮֻÖÖë †Öî¸ü ×®ÖÝÖÔ´Öß ×ÃÖݮֻÖÖë Ûúß †Ö¾Öé×¢ÖµÖÖÑ ×³Ö®®Ö ŒµÖÖë ÆüÖêŸÖß Æîü ? 1 
Why is the frequency of outgoing and incoming signals different in a mobile phone ?
4. ¦ü¾µÖ´ÖÖ®Ö ‘m’ †Öî¸ü †Ö¾Öê¿Ö ‘q’ ÛúÖ ÛúÖê‡Ô ÛúÞÖ ‘v’ ¾ÖêÝÖ ÃÖê ×ÛúÃÖß ‹ÛúÃÖ´ÖÖ®Ö “Öã´²ÖÛúßµÖ õÖê¡Ö, •ÖÖê ÛúÞÖ Ûúß ÝÖ×ŸÖ Ûúß
פü¿ÖÖ Ûêú »Ö´²Ö¾ÖŸÖ Æîü, ´Öë ¯ÖϾÖê¿Ö Ûú¸üŸÖÖ Æîü, ˆÃÖÛúß ÝÖ×ŸÖ•Ö ‰ú•ÖÖÔ ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ¯ÖϳÖÖ×¾ÖŸÖ ÆüÖêŸÖß Æîü ? 1 
A particle of mass ‘m’ and charge ‘q’ moving with velocity ‘v’ enters the region of
uniform magnetic field at right angle to the direction of its motion. How does its
kinetic energy get affected ?
5. ×“Ö¡Ö ´Öë ×ÛúÃÖß ¬ÖÖ¸üÖ¾ÖÖÆüß ¯Ö׸ü®ÖÖ×»ÖÛúÖ ÛúÖê ×ÛúÃÖß “ÖÖ»ÖÛú »Öæ¯Ö (¯ÖÖ¿Ö) Ûúß †Öê¸ü ÝÖןִÖÖ®Ö ¤ü¿ÖÖÔµÖÖ ÝÖµÖÖ Æîü … »Öæ¯Ö ´Öë
¯ÖÏê׸üŸÖ ¬ÖÖ¸üÖ Ûúß ×¤ü¿ÖÖ ²ÖŸÖÖ‡‹ … 1 
Figure shows a current carrying solenoid moving towards a conducting loop. Find the 
direction of the current induced in the loop. 
55/1/2 4 
ÜÖÞ›ü – ²Ö
Section – B 
6. †¬ÖÐã×¾ÖŸÖ ¯ÖÏÛúÖ¿Ö †Öî¸ü ¸îü×ÜÖÛúŸÖ: ¬ÖÐã×¾ÖŸÖ ¯ÖÏÛúÖ¿Ö Ûêú ²Öß“Ö ×¾Ö³Öê¤ü®Ö Ûúßו֋ … †Ö¸êüÜÖ Ûúß ÃÖÆüÖµÖŸÖÖ ÃÖê ¾ÖÞÖÔ®Ö Ûúßו֋
×Ûú ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ¯ÖÏÛúßÞÖÔ®Ö «üÖ¸üÖ †¬ÖÐã×¾ÖŸÖ ¯ÖÏÛúÖ¿Ö ¸îü×ÜÖÛúŸÖ: ¬ÖÐã×¾ÖŸÖ ÆüÖê •ÖÖŸÖÖ Æîü … 2 
Distinguish between unpolarised and a linearly polarised light. Describe, with the help
of a diagram, how unpolarised light gets linearly polarised by scattering.
7. ¿¾ÖêŸÖ ¯ÖÏÛúÖ¿Ö ×ÛúÃÖß ÛúÖÑ“Ö Ûêú ׯÖÏ•ûÌ´Ö ÃÖê ÝÖã•Ö¸ü®Öê ¯Ö¸ü ¯Ö׸üõÖê×¯ÖŸÖ ÆüÖê •ÖÖŸÖÖ Æîü …
»ÖëÃÖ ´ÖîÛú¸ü ÃÖæ¡Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸üÛêú µÖÆü ¤ü¿ÖÖÔ‡‹ ×Ûú ×ÛúÃÖß ×¤ü‹ ÝÖ‹ »ÖëÃÖ Ûúß ±úÖêÛúÃÖ ¤æü¸üß ˆÃÖ ¯Ö¸ü †Ö¯Ö×ŸÖŸÖ 
¯ÖÏÛúÖ¿Ö Ûêú ¾ÖÞÖÔ (¸ÓüÝÖ) ¯Ö¸ü ×®Ö³ÖÔ¸ü Ûú¸üŸÖß Æîü … 2 
Why does white light disperse when passed through a glass prism ? 
Using lens maker’s formula, show how the focal length of a given lens depends upon 
the colour of light incident on it. 
8. ×“Ö¡Ö ´Öë ¤ü¿ÖÖÔ‹ ÝÖ‹ ×®Ö¸üÖê¬Öß ×¾Ö³Ö¾Ö †Öî¸ü ±úÖê™üÖò®Ö Ûúß †Ö¯ÖŸÖ®Ö †Ö¾Öé×¢Ö Ûêú ²Öß“Ö ÝÖÏÖ±ú ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸üÛêú ¯»ÖÖÓÛú
×®ÖµÖŸÖÖÓÛú ¯Ö׸üÛú×»ÖŸÖ Ûúßו֋ … 2 
Using the graph shown in the figure for stopping potential V/s the incident frequency 
of photons, calculate Planck’s constant. 
Page 5


55/1/2 1 [P.T.O. 
¸üÖê»Ö ®ÖÓ.
Roll No. 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70
Time allowed : 3 hours ] [ Maximum Marks : 70 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü … ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … 
(ii) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-†, ÜÖÞ›ü-²Ö, ÜÖÞ›ü-ÃÖ, ÜÖÞ›ü-¤ü †Öî¸ü ÜÖÞ›ü-µÖ … 
(iii) ÜÖÞ›ü-† ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú ÛúÖ 1 †ÓÛú Æîü … ÜÖÞ›ü-²Ö ´Öë 5 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 2 †ÓÛú Æïü … ÜÖÞ›ü-ÃÖ ´Öë 
12 ¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 3 †ÓÛú Æïü … ÜÖÞ›ü-¤ü ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ÜÖÞ›ü-µÖ ´Öë 3 
¯ÖÏ¿®Ö Æïü, ¯ÖÏŸµÖêÛú Ûêú 5 †ÓÛú Æïü … 
(iv) ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ŸÖ£ÖÖׯÖ, ¤üÖê †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú ¯ÖÏ¿®Ö ´Öë, ŸÖß®Ö †ÓÛúÖë ¾ÖÖ»Öê ‹Ûú 
¯ÖÏ¿®Ö ´Öë †Öî¸ü ¯ÖÖÑ“Ö †ÓÛúÖë ¾ÖÖ»Öê ŸÖß®ÖÖë ¯ÖÏ¿®ÖÖë ´Öë †Ö®ŸÖ׸üÛú “ÖµÖ®Ö ¯ÖϤüÖ®Ö ×ÛúµÖÖ ÝÖµÖÖ Æîü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê 
פü‹ ÝÖ‹ “ÖµÖ®Ö ´Öë ÃÖê Ûêú¾Ö»Ö ‹Ûú ¯ÖÏ¿®Ö Æüß Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1/C 
55/1/2
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12  Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the
question paper only and will not write any answer on the answer-book during this period.
ÛúÖê›ü ®ÖÓ. 
Code No. 
   
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book.
SET – 2 
55/1/2 2 
(v) •ÖÆüÖÑ †Ö¾Ö¿µÖÛú ÆüÖê †Ö¯Ö ×®Ö´®Ö×»Ö×ÜÖŸÖ ³ÖÖîןÖÛ  ×®ÖµÖŸÖÖÓÛúÖë Ûêú ´ÖÖ®ÖÖë ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü :
c = 3 × 10
8
 m/s 
h = 6.63 × 10
–34
 Js 
e = 1.6 × 10
–19
 C 
µ
0
 = 4p × 10
–7
 T m A
–1
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2
m
e
 = 9.1 × 10
–31
 kg
®µÖæ™ÒüÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.675 × 10
–27
 kg
¯ÖÏÖê™üÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.673 × 10
–27
 kg
†Ö¾ÖÖêÝÖÖ¦üÖê ÃÖÓܵÖÖ = 6.023 × 10
23
 ¯ÖÏ×ŸÖ ÝÖÏÖ´Ö ´ÖÖê»Ö 
²ÖÖê»™Ëü•ÖÌ´ÖÖ®Ö ×®ÖµÖŸÖÖÓÛú = 1.38 × 10
–23
 JK
–1
General Instructions : 
(i) All questions are compulsory. There are 26 questions in all. 
(ii) This question paper has five sections : Section A, Section B, Section C, Section D 
and Section E. 
(iii) Section A contains five questions of one mark each, Section B contains five 
questions of two marks each, Section C contains twelve questions of three marks 
each, Section D contains one value based question of four marks and Section E 
contains three questions of five marks each. 
(iv) There is no overall choice. However, an internal choice has been provided in one 
question of two marks, one question of three marks and all the three questions of 
five marks weightage. You have to attempt only one of the choices in such 
questions. 
(v) You may use the following values of physical constants wherever necessary : 
c = 3 × 10
8
 m/s 
h = 6.63 × 10
–34
 Js 
e = 1.6 × 10
–19
 C 
µ
0
 = 4p × 10
–7
 T m A
–1
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2
m
e
 = 9.1 × 10
–31
 kg
Mass of neutron = 1.675 × 10
–27
 kg 
Mass of proton = 1.673 × 10
–27
 kg 
Avogadro’s number = 6.023 × 10
23
 per gram mole 
Boltzmann constant = 1.38 × 10
–23
 JK
–1
 
55/1/2 3 [P.T.O. 
ÜÖÞ›ü – †
Section – A 
1. •Ö²Ö ×ÛúÃÖß ×²Ö´²Ö ÛúÖê ×ÛúÃÖß †¾ÖŸÖ»Ö ¤ü¯ÖÔÞÖ Ûêú f †Öî¸ü 2f Ûêú ²Öß“Ö ¸üÜÖÖ •ÖÖŸÖÖ Æîü, ŸÖ²Ö ²Ö®Ö®Öê ¾ÖÖ»ÖÖ ¯ÖÏןÖײִ²Ö ÛîúÃÖÖ 
ÆüÖêŸÖÖ Æîü – (i) ¾ÖÖßÖ×¾ÖÛú †£Ö¾ÖÖ †Ö³ÖÖÃÖß †Öî¸ü (ii) ”ûÖê™üÖ †£Ö¾ÖÖ ×¾Ö¾ÖÙ¬ÖŸÖ ? 1 
When an object is placed between f and 2f of a concave mirror, would the image 
formed be (i) real or virtual and (ii) diminished or magnified ? 
2. ‡»ÖꌙÒüÖò®Ö Ûúß ÝÖ×ŸÖ•Ö ‰ú•ÖÖÔ Ûêú ±ú»Ö®Ö Ûêú ºþ¯Ö ´Öë ‡ÃÖÛúß ¤êü-²ÖÎÖÝ»Öß ŸÖ¸ÓüÝÖ¤îü¬µÖÔ Ûêú ×¾Ö“Ö¸üÞÖ ÛúÖê ÝÖÏÖ±ú ÜÖà“ÖÛú¸ü
¤ü¿ÖÖÔ‡‹ … 1 
Draw a plot showing the variation of de Broglie wavelength of electron as a function
of its K. E.
3. ´ÖÖê²ÖÖ‡»Ö ±úÖê®Ö ´Öë †ÖÝÖ´Öß ×ÃÖݮֻÖÖë †Öî¸ü ×®ÖÝÖÔ´Öß ×ÃÖݮֻÖÖë Ûúß †Ö¾Öé×¢ÖµÖÖÑ ×³Ö®®Ö ŒµÖÖë ÆüÖêŸÖß Æîü ? 1 
Why is the frequency of outgoing and incoming signals different in a mobile phone ?
4. ¦ü¾µÖ´ÖÖ®Ö ‘m’ †Öî¸ü †Ö¾Öê¿Ö ‘q’ ÛúÖ ÛúÖê‡Ô ÛúÞÖ ‘v’ ¾ÖêÝÖ ÃÖê ×ÛúÃÖß ‹ÛúÃÖ´ÖÖ®Ö “Öã´²ÖÛúßµÖ õÖê¡Ö, •ÖÖê ÛúÞÖ Ûúß ÝÖ×ŸÖ Ûúß
פü¿ÖÖ Ûêú »Ö´²Ö¾ÖŸÖ Æîü, ´Öë ¯ÖϾÖê¿Ö Ûú¸üŸÖÖ Æîü, ˆÃÖÛúß ÝÖ×ŸÖ•Ö ‰ú•ÖÖÔ ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ¯ÖϳÖÖ×¾ÖŸÖ ÆüÖêŸÖß Æîü ? 1 
A particle of mass ‘m’ and charge ‘q’ moving with velocity ‘v’ enters the region of
uniform magnetic field at right angle to the direction of its motion. How does its
kinetic energy get affected ?
5. ×“Ö¡Ö ´Öë ×ÛúÃÖß ¬ÖÖ¸üÖ¾ÖÖÆüß ¯Ö׸ü®ÖÖ×»ÖÛúÖ ÛúÖê ×ÛúÃÖß “ÖÖ»ÖÛú »Öæ¯Ö (¯ÖÖ¿Ö) Ûúß †Öê¸ü ÝÖןִÖÖ®Ö ¤ü¿ÖÖÔµÖÖ ÝÖµÖÖ Æîü … »Öæ¯Ö ´Öë
¯ÖÏê׸üŸÖ ¬ÖÖ¸üÖ Ûúß ×¤ü¿ÖÖ ²ÖŸÖÖ‡‹ … 1 
Figure shows a current carrying solenoid moving towards a conducting loop. Find the 
direction of the current induced in the loop. 
55/1/2 4 
ÜÖÞ›ü – ²Ö
Section – B 
6. †¬ÖÐã×¾ÖŸÖ ¯ÖÏÛúÖ¿Ö †Öî¸ü ¸îü×ÜÖÛúŸÖ: ¬ÖÐã×¾ÖŸÖ ¯ÖÏÛúÖ¿Ö Ûêú ²Öß“Ö ×¾Ö³Öê¤ü®Ö Ûúßו֋ … †Ö¸êüÜÖ Ûúß ÃÖÆüÖµÖŸÖÖ ÃÖê ¾ÖÞÖÔ®Ö Ûúßו֋
×Ûú ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ¯ÖÏÛúßÞÖÔ®Ö «üÖ¸üÖ †¬ÖÐã×¾ÖŸÖ ¯ÖÏÛúÖ¿Ö ¸îü×ÜÖÛúŸÖ: ¬ÖÐã×¾ÖŸÖ ÆüÖê •ÖÖŸÖÖ Æîü … 2 
Distinguish between unpolarised and a linearly polarised light. Describe, with the help
of a diagram, how unpolarised light gets linearly polarised by scattering.
7. ¿¾ÖêŸÖ ¯ÖÏÛúÖ¿Ö ×ÛúÃÖß ÛúÖÑ“Ö Ûêú ׯÖÏ•ûÌ´Ö ÃÖê ÝÖã•Ö¸ü®Öê ¯Ö¸ü ¯Ö׸üõÖê×¯ÖŸÖ ÆüÖê •ÖÖŸÖÖ Æîü …
»ÖëÃÖ ´ÖîÛú¸ü ÃÖæ¡Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸üÛêú µÖÆü ¤ü¿ÖÖÔ‡‹ ×Ûú ×ÛúÃÖß ×¤ü‹ ÝÖ‹ »ÖëÃÖ Ûúß ±úÖêÛúÃÖ ¤æü¸üß ˆÃÖ ¯Ö¸ü †Ö¯Ö×ŸÖŸÖ 
¯ÖÏÛúÖ¿Ö Ûêú ¾ÖÞÖÔ (¸ÓüÝÖ) ¯Ö¸ü ×®Ö³ÖÔ¸ü Ûú¸üŸÖß Æîü … 2 
Why does white light disperse when passed through a glass prism ? 
Using lens maker’s formula, show how the focal length of a given lens depends upon 
the colour of light incident on it. 
8. ×“Ö¡Ö ´Öë ¤ü¿ÖÖÔ‹ ÝÖ‹ ×®Ö¸üÖê¬Öß ×¾Ö³Ö¾Ö †Öî¸ü ±úÖê™üÖò®Ö Ûúß †Ö¯ÖŸÖ®Ö †Ö¾Öé×¢Ö Ûêú ²Öß“Ö ÝÖÏÖ±ú ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸üÛêú ¯»ÖÖÓÛú
×®ÖµÖŸÖÖÓÛú ¯Ö׸üÛú×»ÖŸÖ Ûúßו֋ … 2 
Using the graph shown in the figure for stopping potential V/s the incident frequency 
of photons, calculate Planck’s constant. 
55/1/2 5 [P.T.O. 
9. ®Öß“Öê ¤üß ÝÖµÖß ®ÖÖ׳ÖÛúßµÖ †×³Ö×ÛÎúµÖÖ ÛúÖê ¯Öæ¸üÖ Ûúßו֋ : 2 
(a)
10
5
B + 
1
0
n ?? 
4
2
He + ……
(b) 
94
42
Mo + 
2
1
H ?? 
95
43
Te + ……
†£Ö¾ÖÖ  
µÖפü ×ÛúÃÖß ®ÖÖ׳ÖÛúßµÖ †×³Ö×ÛÎúµÖÖ ´Öë ¯ÖÏÖê™üÖò®ÖÖë †Öî¸ü ®µÖæ™ÒüÖò®ÖÖë ¤üÖê®ÖÖë Ûúß ÃÖÓܵÖÖ ÃÖÓ¸ü×õÖŸÖ ¸üÆüŸÖß Æîü, ŸÖ²Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü 
¦ü¾µÖ´ÖÖ®Ö ÛúÖ ºþ¯ÖÖ®ŸÖ¸üÞÖ ‰ú•ÖÖÔ ´Öë (†£Ö¾ÖÖ ‡ÃÖÛúÖ ¾µÖãŸÛÎú´Ö) ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ÃÖ×ÆüŸÖ ¾µÖÖܵÖÖ Ûúßו֋ …  
Complete the following nuclear reactions : 
(a) 
10
5
B + 
1
0
n ?? 
4
2
He + ……
(b) 
94
42
Mo + 
2
1
H ?? 
95
43
Te + ……
OR 
If both the number of protons and neutrons in a nuclear reaction is conserved, in what 
way is mass converted into energy (or vice verse) ? Explain giving one example. 
10. ×ÛúÃÖß “ÖÖ»ÖÛú ´Öë †Ö¾Öê¿Ö ¾ÖÖÆüÛúÖë Ûêú †¯Ö¾ÖÖÆü ¾ÖêÝÖ Ûúß †¾Ö¬ÖÖ¸üÞÖÖ ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸üÛêú ˆÃÖ “ÖÖ»ÖÛú Ûúß ¯ÖÏןָüÖê¬ÖÛúŸÖÖ
†Öî¸ü ¬ÖÖ¸üÖ ‘Ö®ÖŸ¾Ö Ûêú ²Öß“Ö ÃÖÓ²ÖÓ¬Ö ¾µÖ㟯֮®Ö Ûúßו֋ … 2 
Using the concept of drift velocity of charge carriers in a conductor, deduce the
relationship between current density and resistivity of the conductor.
ÜÖÞ›ü – ÃÖ
Section – C 
11. ˆ¯ÖµÖãŒŸÖ †Ö¸êüÜÖ Ûúß ÃÖÆüÖµÖŸÖÖ ÃÖê (i) “Öã´²ÖÛúßµÖ ×¤üÛËú¯ÖÖŸÖ †Öî¸ü (ii) ®Ö×ŸÖ ÛúÖêÞÖ ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ …  µÖפü ×ÛúÃÖß
“Öã´²ÖÛúßµÖ ÃÖã‡Ô ÛúÖê (i) ¬ÖÐã¾ÖÖë, (ii) ×¾ÖÂÖã¾ÖŸÖË ¾Öé¢Ö ¯Ö¸ü ¸üÜÖë, ŸÖÖê ¾ÖÆü ×ÛúÃÖ ×¤ü¿ÖÖ ´Öë ÃÖÓÛêúŸÖ Ûú¸êüÝÖß ? 3 
Define the following using suitable diagrams : (i) magnetic declination and (ii) angle
of dip. In what direction will a compass needle point when kept at the (i) poles and (ii)
equator ?
12. ×ÛúÃÖß ¯Ö׸ü®ÖÖ×»ÖÛúÖ ×•ÖÃÖ´Öë ÛúÖê‡Ô ãÖÖµÖß ¬ÖÖ¸üÖ I ¯ÖϾÖÖ×ÆüŸÖ ÆüÖê ¸üÆüß Æîü, ´Öë ÃÖÓ×“ÖŸÖ “Öã´²ÖÛúßµÖ ‰ú•ÖÖÔ Ûêú ×»Ö‹, ¯Ö׸ü®ÖÖ×»ÖÛúÖ
Ûêú “Öã´²ÖÛúßµÖ õÖê¡Ö B, õÖê¡Ö±ú»Ö A ŸÖ£ÖÖ »Ö´²ÖÖ‡Ô l Ûêú ¯Ö¤üÖë ´Öë ¾µÖÓ•ÖÛú ¾µÖ㟯֮®Ö Ûúßו֋ …
¯ÖÏ×ŸÖ ‹ÛúÖÓÛú †ÖµÖŸÖ®Ö ‡ÃÖ “Öã´²ÖÛúßµÖ ‰ú•ÖÖÔ Ûúß ŸÖã»Ö®ÖÖ ×ÛúÃÖß ÃÖ´ÖÖ®ŸÖ¸ü ¯Ö×¼üÛúÖ ÃÖÓ¬ÖÖ׸ü¡Ö ´Öë ÃÖÓ×“ÖŸÖ ×ãָü ¾ÖîªãŸÖ ‰ú•ÖÖÔ
‘Ö®ÖŸ¾Ö ÃÖê ×ÛúÃÖ ¯ÖÏÛúÖ¸ü Ûúß •ÖÖŸÖß Æîü ? 3 
Derive the expression for the magnetic energy stored in a solenoid in terms of
magnetic field B, area A and length l of the solenoid carrying a steady current I.
How does this magnetic energy per unit volume compare with the electrostatic energy
density stored in a parallel plate capacitor ?