Percentages Questions for CAT with Answers PDF

Let p = 100
q = 100 + 20% of 100 = 120
r = 120 - 25% of 120 = 120 - 30 = 90
s = 90 + 40% of 90 = 90 + 36 = 126
s - p = 126 - 100 = 26
So, s is 26 higher than p.
Required percentage = (26/100) × 100% = 26%

Increased amount = 9100
Let N be number of chocolates 1 month ago.
9100 = 1.3N
N = 7000 milk chocolates

B - A = P (given)
B = P + A


AP = 100 P
A = 100

Price of the object after 1 year = 3 + 2000% of 3 = Rs. 63
Price of the object after 2 years = 63 + 2000% of 63 = 21 × 63 = Rs. 1323

Let the maximum marks be x.
According to the given condition,
0.58x - 0.2x = 38
0.38x = 38
x = 100

Let x be the price of the item.
After increasing 25%, it becomes 1.25x.
After decreasing 20%, it becomes x. (1.25x × 0.8 = x)
So, for every value of x, it is true.

Let the fraction X be x/y.

Hence, option (2) is the correct answer.

He had to buy X kg such that 81% of X = 37 kg.

⇒ He had to buy 46 kg (multiple of 2 kg), i.e. 23 packets of sweets.
⇒ Total cost = Rs. 150 × 23 = Rs. 3450

SP = 1.1 CP
New cost price = 0.9 CP
New selling price = SP - 132
According to the given condition,

0.2 CP - 132 = 0.09 CP
0.11 CP = 132
CP = Rs. 1200

Let the maximum marks be 100.
Marks of A = 40% of 100 = 40
Marks of B = 80% of 40 = 32
Marks of C = 60% of (40 + 32) = 43.2
Marks of D = 45% of (40 + 43.2) = 37.44
Marks required for passing the examination = 36 out of 100
All, except B, passed the examination.