# Practice Questions with Solutions: Addition and Subtraction Notes | Study Mathematics for Class 4 - Class 4

## Class 4: Practice Questions with Solutions: Addition and Subtraction Notes | Study Mathematics for Class 4 - Class 4

The document Practice Questions with Solutions: Addition and Subtraction Notes | Study Mathematics for Class 4 - Class 4 is a part of the Class 4 Course Mathematics for Class 4.
All you need of Class 4 at this link: Class 4

Question 1: Add 4,032 and 1, 74 6.
Solution :

Step 1. Arrange the numbers in columns. Step 2. Adding ones, we have Step 3. Adding tens, we have Step 4. Adding hundreds, we have Step 5. Adding thousands, we have Hence, 4,032 + 1, 74 6 = 5, 778.
(Five thousand, seven hundred seventy-eight).

Question 2: Add 5,386 and 3,927.
Solution:
Step 1. Arrange the numbers in columns. Step 2. Adding ones, we have 6 ones + 7 ones = 13 ones = 1 ten + 3 ones. Carry over 1 to tens column and write 3 under ones column. Step 3. Adding tens, we have
1 ten (carried) + 8 tens + 2 tens = 11 tens = 1 hundred + 1 ten.
Carry over 1 to hundreds column and write 1 under tens column. Step 4. Adding hundreds, we have 1 hundred (carried) + 3 hundreds + 9 hundreds = 13 hundreds = 1 thousand + 3 hundreds. Carry over 1 to thousands column and write 3 under hundreds column. Step 5. Adding thousands, we have 1 thousand (carried) + 5 thousands + 3 thousands = 9 thousands. Hence,
5,386 + 3,927 = 9,313
(Nine thousand, three hundred thirteen).

Question 3: The population of town A is 2,301, the population of town B is 4,875, the population of town C is 1, 835. What is the total population of the three towns?
Solution : Population of town A = 2,301
Population of town B = 4,875
Population of town C = 1,835
Total population of the three towns
= 2,301 + 4,875 + 1, 835 = 9,011.
Hence, the total population of the three towns = 9,011.

Question 4: Add 7,521; 1 ,025 and 1 ,352.
Solution :

Step 1. Arrange the numbers in columns. Step 2. Adding ones, we have Step 3. Adding tens, we have Step 4. Adding hundreds, we have Step 5. Adding thousands, we have Hence, 7,521 + 1,025 + 1,352 = 9,898
(nine thousand, eight hundred ninety-eight).

Question 5: Add 2,908, 6,123 and 254
Solution :

Step 1. Step 2. Step 3. Step 4. Step 5. Hence,
2,908 + 6,123 + 254 = 9,285

(Nine thousand, two hundred eighty-five).

Question 6: Which number is 528 more than 7,874?
Solution : The required number = 7,874 + 528 = 8,402. Hence, the required number is 8,402.

Question 7: Simplify : 7,530 + 1, 817 - 5,173
Solution : Hence, 7,530 + 1,817- 5,173 = 4,174.

Question 8: 3,856 - 2,385 + 6,389 - 987
Solution : Hence, 3,856 - 2,385 + 6,389 - 987 = 6,873

Question 9: Subtract 5,013 from 8,347.
Solution :

Step 1. Arrange the numbers in columns. Step 2. Subtracting ones, we have Step 3. Subtracting tens, we have Step 4. Subtracting hundreds, we have Step 5. Subtracting thousands, we have Hence, 8,347 - 5,013 = 3,334
(Three thousand, three hundred thirty-four).

Question 10: A factory produced 3,263 mercury lamps in 2012. In 2013, it produced 4,450 mercury lamps. By how much did the factory's production increase?
Solution : Production in 2013 = 4,450
Production in 2012 = 3,263
Increase in production = 4,450 - 3,263
= 11187.
Hence, the production increased by 1,187.

Question 11: Subtract 2,856 from 8, 153.
Solution :

Step 1. Arrange the numbers in columns. Step 2. Subtract the ones. Here 3 < 6, so regroup 5 tens 3 ones as 4 tens and 13 ones. Step 3. Subtract the tens. Here, 4 < 5, so, regroup 1 hundred 4 tens as 0 hundreds and 14 tens. Step 4. Subtract the hundreds. Here, 0 < 8. so regroup 8 thousands 0 hundreds as 7 thousand and 10  hundreds. Step 5. Subtract the thousands. Hence, 8,153 - 2,856 = 5,297
(Five thousand, two hundred ninety-seven).

Question 12: What must be added to 4,213 to get 7,631?
Solution : The sum of two numbers = 7,631.
One number= 4,213
The other number= 7,631 - 4,213
= 3,418
Hence, the required number = 3,418.

Question 13: Subtract: 9,000 - 6.124.
Solution:

Step 1. Arrange the numbers in columns. Step 2. Regroup 9 thousands.
9 thousands = 8 thousands + 10 hundreds
10 hundreds = 9 hundreds + 10 tens
10 tens = 9 tens + 10 ones Step 3. Subtract the ones. Step 4. Subtract the tens. Step 5. Subtract the hundreds. Step 6. Subtract the thousands. Hence, 9,000 - 6,124 = 2,876.

The document Practice Questions with Solutions: Addition and Subtraction Notes | Study Mathematics for Class 4 - Class 4 is a part of the Class 4 Course Mathematics for Class 4.
All you need of Class 4 at this link: Class 4 Use Code STAYHOME200 and get INR 200 additional OFF

## Mathematics for Class 4

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