Practice Test Doc: Graphics Interpretation | Data Insights for GMAT PDF Download

Q1: 
In the chart, the outer circle represents the age distribution of subscribers to Beautiful Garden magazine, and the inner circle represents the age distribution of subscribers to Garden Joy magazine. Neither magazine has any subscribers less than 18 years old.
Select from the drop-down menus the options that complete the statement so that it is accurate based on the information provided.
It can be determined from the chart that the _____ of the ages of the subscribers to Beautiful Garden is between 44 and 55 years, whereas that for subscribers to Garden Joy is between ______ years.­
Ans: Dropdown 1: median
Dropdown 2: 34 and 45
Sol: The boundary between 65+(blue shaded) and 18-24 yr old(Grey shaded) is the start point.
So when we move from this boundary clockwise towards 18+category, we start from 0% of people and end again at this boundary completing one circle covering entire 100% of subscribers.
Now exactly opposite to this line will be 50% mark and there is a wide dotted portion there. So 50% would lie in this dotted portion.

Q2: Bright Star Incorporation is a company that makes stationery-related products. The company has a recent sale order of color markers. It has prepared the color paste, which will be mixed into the water to make color ink for the markers. The graph below shows how the solubility of different color pastes varies with temperature.
Assume the curves shown in the graph continue the same general pattern beyond the plotted area. Select the most appropriate answer based on the information in the graph.
1. The most soluble color paste with water at the 70 °C is ______.
2. The color paste which has a very steady effect of temperature on its solubility with water is ______.
Ans: Dropdown 1: Red
Dropdown 2: Yellow

Q3: 

The graph shows estimated annual user expenditures on pesticides by pesticide type in the United States between 1988 and 2007.
Based on the given information, fill in the blanks in each of the following statements.
1. The pesticide type that experienced the greatest percentage growth in user expenditures between 1988 and 2007 was ______.
2. In 1994, user expenditures on Insecticides accounted for _____ of total user expenditures on pesticides.
Ans: Dropdown 1: Insecticides
Dropdown 2: between 25% and 30%
Sol: 1. The pesticide type that experienced the greatest percentage growth in user expenditures between 1988 and 2007 was Insecticides.
This can be solved by using the percentage formula New-Old/Old * 100.
Percentage growth in user expenditure between 1988 and 2007 for Fungicides and others is 2000-1500/1500 * 100 = 25%
Percentage growth in user expenditure between 1988 and 2007 for Insecticides is 6500-3500/3000 * 100 = 84%
Percentage growth in user expenditure between 1988 and 2007 for Herbicides and plant growth is 12500-7500/7500 * 100 = 66%
2. In 1994, user expenditures on Insecticides accounted for between 25% and 30% of total user expenditures on pesticides.
In 1994, Insecticide Expenditure/Total Pesticide Expenditure * 100 = 4000/15500 * 100 = 25.8%

Q4: 

The graph shows the number of visits and the number of page views a certain website received each month last year.
Use the drop-down menus to fill in the blanks in each of the following statements based on the information given by the graph.
1. The month with the fewest visits per page view was ______.
2. The median number of monthly page views was closest to _______.
Ans: Dropdown 1: July
Dropdown 2: 200,000
Sol: 1: To calculate the month with the fewest visits per page
if we can maximize the denominator while keeping the numerator smallest , we can get the answer.
Visually, if you see July has the maximum gap between the visits and page views. 
Thus, it should be July.
2: To calculate the median number of page visits, we need to find the 6th and 7th page visits if we sort all the page visits in order.
For that, if you see we have Lowest below 150k. 
Now we have another 5 page visits between 150k and 200k. thus, 6th page visit would be the maximum of the page visits in this range which is around 180k in Feb or sept.
7th would be the next highest in this after the above range maximum, we could see the one at 220k(in march) is the next greater page visit. Thus median will be the mean of 6th and 7th largest page visits. or Median = 180k + 220k/2 = 200k. 
Thus, answer would be anything near this number.

Q5: Data from each of the countries presented was collected regarding proportions of the overall population that go through different types of plastic surgeries. Surgeries are segmented into non-invasive and invasive treatments and sub-segmentations are shown on the graph.
Select the most appropriate drop down text that fills in the sentence.
1. _______ has more invasive procedures per 1,000 population as a percentage of all types of procedures shown than any other country in the world. Fat surgeries account for the largest portion of this country's invasive surgeries and account for at least 2 procedures per 1,000 population.
2. The number of face and hair surgeries for each country is _______ to the overall number of surgeries for a given country in 2010.
Ans: Dropdown 1: Brazil
Dropdown 2: Highly proportional

Solution: For the 1st question : It is asked to calculate the following : #Invasive Procedures / Total Procedures.
South Korea : 8.2 / 16 * 100 = 51.25%
Brazil : 9.2 / 13 * 100 = 70.6%
Venezuela : 5.5 / 7.8 * 100 = 70.5%
Brazil wins -> Answer B.
For the 2nd question : We can see on the graph that there is a positive correlation between the number of hair and face surgeries and the overall number of surgeries : as one increases the other one increases.
Therefore, the best answer seem to be -> Answer A.