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Practise Question - 18 Video Lecture | Crash Course for EmSAT Achieve
FAQs on Practise Question - 18 Video Lecture - Crash Course for EmSAT Achieve
| 1. What is the formula to calculate the energy of a photon in electron volts (eV)? |  |
Ans. The formula to calculate the energy of a photon in electron volts (eV) is E = hc/λ, where E is the energy in eV, h is the Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the photon in meters.
| 2. How can I convert the energy of a photon from eV to joules? | |
Ans. To convert the energy of a photon from electron volts (eV) to joules, you can use the conversion factor 1 eV = 1.6 x 10^-19 J. Simply multiply the energy in eV by this conversion factor to obtain the energy in joules.
| 3. What is the significance of the energy of a photon in eV? | |
Ans. The energy of a photon in electron volts (eV) is a common unit used to describe the energy of individual photons in the field of physics and photonics. It allows for convenient comparisons and calculations involving the energy levels of photons, as it directly relates to the electronic structure of materials and their interaction with light.
| 4. How does the energy of a photon relate to its wavelength? | |
Ans. According to the formula E = hc/λ, the energy of a photon is inversely proportional to its wavelength. This means that photons with shorter wavelengths have higher energy, while photons with longer wavelengths have lower energy.
| 5. Can the energy of a photon be negative? | |
Ans. No, the energy of a photon cannot be negative. The energy of a photon is always positive and is determined by its frequency or wavelength. A negative energy value would not have any physical meaning in the context of photons.
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Dec 26, 2024 Last updated |
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