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**Q.1. Which of the following acts as a circuit protection device? (2019)A: ConductorB: InductorC: SwitchD: FuseAns: **D

Solution:

Fuse wire has less melting point so when excess current flows, due to heat produced in it, it melts.

A: Zero, 60 Î¼A

B: 60 Î¼A, 60 Î¼A

C: 60 Î¼A, zero

D: Zero, zero

Ans:

Solution:

Capacitance of capacitor C = 20 mF

= 20 Ã— 10

Rate of change of potential

i

= 60 Ã— 10

= 60 Î¼A

As we know that i

A: 0.138 H

B: 138.88 H

C: 1.389 H

D: 13.89 H

Ans:

Solution:

Energy stored in the inductor

Energy stored in the inductor

A: I

B: I

C: I

D: I

Ans:

Solution:

**Q.5. ****An inductor 20 mH, a capacitor 100 Î¼F and a resistor 50 Î© are connected in series across a source of emf, V = 10 sin 314 t. The power loss in the circuit is (2018)A: 0.79 WB: 0.43 WC: 2.74 WD: 1.13 WAns: **A

Solution:

**A: 0.2 AB: 2 AC: 0 ampereD: 2 mAAns:** B

Solution:

**Q.7. ****An inductor 20 mH, a capacitor 50 Î¼F and a resistor. 40Î© are connected in series across a source of emf V = 10 sin 340 t. The power loss in A.C. circuit is (2016)A: 0.89WB: 0.51WC: 0.67WD: 0.76WAns: **B

Solution:

**Q.8. ****A small signal voltage V(t) = V _{0} sinÏ‰t is applied across an ideal capacitor C : (2016)A: Current I(t), leads voltage V(t) by 180 degreeB: Current I(t), lags voltage V(t) by 90 degreeC: Over a full cycle the capacitor C does not consume any energy from the voltage source.D: Current I(t) is in phase with voltage V(t)Ans: **C

Solution:

Capacitor does not consume energy effectively over full cycles

A: P

B:

C:

D:

Ans: B

Solution:

A resistance R draws power P when connected to an AC source.

The magnitude of voltage of the AC source is

V^{2} = RP

âˆ´ V=

An inductor of inductance L and reactance Ï‰L is now placed in series with the resistance

**Q.10. ****A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6A, the voltage across the secondary coil and the current in the primary coil respectively are : (2014)A: 450 V, 13.5 AB: 600 V, 15 AC: 300 V, 15 AD: 450 V, 15 A**

Initial power = 3000 W

As the efficiency is 90%, then final power

That is,

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