Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE) PDF Download

Q1: The number of junctions in the circuit is       (2024)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 6
(b) 7
(c) 8
(d) 9
Ans:
(a)
Sol:
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)A point at which more than two elements are joints together is called Junction.
A, B, C, D, E and F are junction.

Q2: For the circuit shown in the figure, V= 8 V, DC and I= 8A, DC. The voltage Vab in Volts is ___ (Round off to 1 decimal place).      (2023)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)

(a) 4.2
(b) 6
(c) 8
(d) 10.6
Ans:
(b)
Sol: Reraw the circuit:
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Now, using voltage division,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q3: In the circuit shown below, the magnitude of the voltage V1 in volts, across the 8kΩ resistor is ______________. (round off to nearest integer)      (2022)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 100
(b) 120
(c) 150
(d) 175
Ans:
(a)
Sol: Apply kVL :
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q4: In the given circuit, the value of capacitor C that makes current I = 0 is _________ μF.      (2021)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 15
(b) 50
(c) 5
(d) 20
Ans:
(d)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
⇒ Xc = 10Ω
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE) 
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q5: The current I flowing in the circuit shown below in amperes (round off to one decimal place) is ____      (2019)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 0.8
(b) 1.1
(c) 1.4
(d) 1.9
Ans: 
(c)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Applying nodal at node x,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Substituting (ii) in (i),
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q6:  The equivalent impedance Zeq for the infinite ladder circuit shown in the figure is      (2018)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)

(a) j12Ω
(b) -j12 Ω
(c) j13 Ω
(d) 13 Ω
Ans: 
(a)
Sol:
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)By solving above equation,
Zeq = j12

Q7: The power supplied by the 25 V source in the figure shown below is ________W.      (SET-1 (2017))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 25
(b) 250
(c) 2.5
(d) 100
Ans:
(b)
Sol: Using KCL at node , we get
 I + 0.4I = 14
 I = 10A
Now, power supplied,
P = 25×10 = 250W

Q8: The equivalent resistance between the terminals A and B is ______ Ω.     (SET-1 (2017))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 2.2
(b) 1.2
(c) 1
(d) 3
Ans:
(d)
Sol: Consider the following circuit diagram,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)After rearrangement we get
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Now, Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)

Q9: In the circuit shown below, the voltage and current sources are ideal. The voltage (Vout) across the current source, in volts, is       (SET-2 (2016))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 0
(b) 5
(c) 10
(d) 20
Ans:
(d)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)So, Vout = (5 x 2) + 10 = 20V

Q10: In the circuit shown below, the node voltage In the circuit shown below, the node voltage VA is ___________ V.      (SET-1 (2016))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 11.42
(b) 5.55
(c) 7.25
(d) 15.25
Ans:
(a)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Applying KCL at node A, we get
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q11: In the given circuit, the current supplied by the battery, in ampere, is _______.     (SET-1(2016))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 0.1
(b) 0.5
(c) 1
(d) 1.5
Ans:
(b)
Sol:
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Applying KCL at node A,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)and applying KVL in loop ABCD,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)From equation (i) and (ii),
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q12: In the portion of a circuit shown, if the heat generated in 5 Ω resistance is 10 calories per second, then heat generated by the 4 Ω  resistance, in calories per second, is _______.       (SET-1 (2016))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 1
(b) 2
(c) 3
(d) 4
Ans: 
(b)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q13: RA and RB are the input resistances of circuits as shown below. The circuits extend infinitely in the direction shown. Which one of the following statements is TRUE?       (SET-1 (2016))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) RA = RB
(b) RA = RB = 0
(c) RA < RB
(d) RB = RA/(1+RA)
Ans: 
(d)
Sol: If the equavalent resistance of first figure is RA then from the second figure, we can see that R= RA∣∣1Ω.
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q14: The current i (in Ampere) in the 2Ω resistor of the given network is ______.      (SET-2 (2015))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 0
(b) 1
(c) 2
(d) 4
Ans:
(a)
Sol: Redrawing the circuit,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Bridge is balance, so current flowing through 2Ω resistor is 0A.

Q15: In the given circuit, the parameter k is positive, and the power dissipated in the 2 Ω resistor is 12.5W. The value of k is _________.      (SET-1(2015))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 0.25
(b) 0.50
(c) 0.72
(d) 0.9
Ans: 
(b)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
 Q16: The voltages developed across the 3 Ω and 2 Ω resistors shown in the figure are 6 V and 2V respectively, with the polarity as marked. What is the power (in Watt) delivered by the 5V voltage source?     (SET-1(2015))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 5
(b) 7
(c) 10
(d) 14
Ans: 
(a)
Sol:
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Power = 5 x 1 = 5 Watt

Q17: The power delivered by the current source, in the figure, is ____.      (SET-3 (2014))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 1
(b) 2
(c) 3
(d) 4
Ans: 
(c)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Applying nodal analysis at node P, we have
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)∴ Power delivered by the current source
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q18: In the figure, the value of resistor R is (25 + I/2) ohms, where I is the current in amperes. The current I is _____.      (SET-1  (2014))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 25
(b) 15
(c) 12
(d) 10
Ans:
(d)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Applying KVL in given loop, we have
300 = IR
300 = (2R − 50) × R
we get, R = 30Ω or −5Ω
Since, resistance can't be negative. therefore, 
R = 30Ω
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q19: An incandescent lamp is marked 40 W, 240 V. If resistance at room temperature (26°C) is 120 Ω, and temperature coefficient of resistance is 4.5 × 10−3/°C, then its 'ON' state filament temperature in °C is approximately_____.       (SET-1 (2014))
(a) 1220.24
(b) 1860.36
(c) 2470.44
(d) 2960.96
Ans:
(c)
Sol: Let the resistance of incandescent lamp
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Let, RT be the resistance of the filament in ON state at temperature T.
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE) Therefore, ON state temperature of filament = 2470.44°C

Q20: The three circuit elements shown in the figure are part of an electric circuit. The total power absorbed by the three circuit elements in watts is _____.      (SET-1 (2014))
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 110
(b) 250
(c) 330
(d) 360
Ans: 
(c)
Sol: Given electrical circuit is shown below:
Applying KCL at node, current through 15V voltage source = 2 A
Power absorbed by 100 V voltage source = 10x100 = 1000 Watt.
Power absorbed by 80 V voltage source =-(80x8) = -640 Watts and power absorbed by 15 V voltage source = -(15x2) = -30 Watt.
Therefore, total power absorbed by the three circuit element = (100-640-30_ watts = 330 Watts

Q21: Three capacitors C1, Cand C3 whose values are 10μF, 5μF, and 2μF respectively, have breakdown voltages of 10 V, 5 V and 2 V respectively. For the interconnection shown below, the maximum safe voltage in Volts that can be applied across the combination, and the corresponding total charge in μC stored in the effective capacitance across the terminals are respectively,      (2013)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 2.8 and 36
(b) 7 and 119
(c) 2.8 and 32
(d) 7 and 80
Ans:
(c)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Capacitor C2 and C3 are in series.
In series charge is same.
So, maximum charge on C2 and C3 will be minimum of
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)In series the equivalent capacitance of C2 and C3 is  
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)In parallel, the voltage is same.
V1 = V23 = 2.8V
Change in capacitor C1
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)In parallel, the total charge
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q22: Consider a delta connection of resistors and its equivalent star connection as shown below. If all elements of the delta connection are scaled by a factor k, k > 0, the elements of the corresponding star equivalent will be scaled by a factor of      (2013)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) k2
(b) k
(c) 1/k
(d) √k
Ans:
(b)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q23: If VA−VB = 6V then VC−VD is     (2012)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) -5V
(b) 2V
(c) 3C
(d) 6V
Ans:
(a)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q24: In the circuit shown below, the current through the inductor is     (2012)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)

(b)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
(c)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
(d) 0A
Ans: 
(c)
Sol: 
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Apply KCL node at 'A'
so, current flowing through 1Ω is (1 − I2)
Applying KVL in ABCD loop,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q25: If the 12 Ω resistor draws a current of 1 A as shown in the figure, the value of resistance R is    (2010)
(a) 4Ω
(b) 6Ω
(c) 8Ω
(d) 18Ω
Ans:
(b)
Sol: Assuming voltage of the node Va
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q26: If the electrical circuit of figure (b) is an equivalent of the coupled tank system of figure (a), then       (2010)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) A, B are resistances and C, D capacitances
(b) A, C are resistances and B, D capacitances
(c) A, B are capacitances and C, D resistances
(d) A, C are capacitances and B, D resistances
Ans:
(d)
Sol: In such system, volumetric flow rate C is analogous to current and pressure is analogous to voltage
The hydraulic capacitance due to storage in gravity field is defined as
C = A/pg
where, A = Area of the tank
ρ = Density of the fluid
g = Acceleration due to gravity
The hydraulic capacitance is represented by A and C. Liquid trying to flow out of a container,can meet with resistance in several ways. If the outlet is a pipe, the friction between the liquid and the pile wall produces resistance to flow. Such resistance is represented by B and D.

Q27: As shown in the figure, a 1 Ω resistance is connected across a source that has a load line v+i=100. The current through the resistance is    (2010)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 25A
(b) 50A
(c) 100A
(d) 200A
Ans: 
(b)
Sol: A resistor has linear characteristics
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)current through resistance,
i = 100/2 = 50A

Q28: For the circuit shown, find out the current flowing through the 2 Ω resistance. Also identify the changes to be made to double the current through the 2 Ω resistance.      (2009)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) (5 A; Put V= 30 A)
(b) (2 A; Put VS = 8 A)
(c) (5 A; Put IS = 10 A)
(d) (7 A; Put IS = 12 A)
Ans:
(b)
Sol: Voltage across 2Ω resistance = Vs = 4 V
Current through 2Ω resistance Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Current cource has no effect, when connected across voltage source.
So, to double current through  2Ω resistance, voltage source is doubled i.e.
V - s = 8V

Q29: The equivalent capacitance of the input loop of the circuit shown is      (2009)
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)(a) 2 μF
(b) 100 μF
(c) 200 μF
(d) 4 μF
Ans:
(a)
Sol: Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Applying KVL,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)As imaginary part is negative, input impedance has equivalent capacitive reactance XC eq.
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)
Q30: How many 200 W/220 V incandescent lamps connected in series would consume the same total power as a single 100 W/220 V incandescent lamp ?      (2009)
(a) not possible
(b) 4
(c) 3
(d) 2
Ans:
(d)
Sol: Let resistance of a single incandescent lamp = R.
Power consumed by a single lamp, P = 200W.
When connected across voltage, V = 220V.
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)Let, n number of lamps are connected in series across voltage V = 200V.
So total resistance of lamps
Req.= nR = 242n
Total power consumed,
Previous Year Questions- Basics - 1 | Network Theory (Electric Circuits) - Electrical Engineering (EE)

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