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# Notes | EduRev

## Physics 28 Years Past year papers for NEET/AIPMT Class 11

Created by: Shiksha Academy

## NEET : Notes | EduRev

The document Notes | EduRev is a part of the NEET Course Physics 28 Years Past year papers for NEET/AIPMT Class 11.
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Q 1. Increase in temperature of a gas filled in a container would lead to:    [2019]
A: Increase in its mass
B: Increase in its kinetic energy
C: Decrease in its pressure
D: Decrease in intermolecular distance
Ans:
B
Solution: Increase in temperature would lead to the increase in kinetic energy of gas (assuming far as to be ideal) as

Q 2. At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere ? (Given: Mass of oxygen molecule (m) = 2.76 Ã— 10â€“26 kg Boltzmann's constant kB = 1.38 Ã— 10â€“23 J Kâ€“1):-    [2018]
A: 2.508 Ã— 104 K
B: 8.360 Ã— 104 K
C: 5.016 Ã— 104 K
D: 1.254 Ã— 104 K
Ans:
B
Solution:

Q 3. The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T(Kelvin) and mass m, is:-    [2017]
A:
B:
C:
D:
Ans:
A
Solution: Kinetic energy of thermal neutron with equilibrium

Q 4. A gas mixture consists of 2 moles of O2 and 4 moles of Ar at temperature T. Neglecting all vibrational modes, the total internal energy of the system is:-    [2017]
A: 15 RT
B: 9 RT
C: 11 RT
D: 4 RT
Ans:
C
Solution:

Q 5. The molecules of a given mass of a gas have r.m.s. velocity of 200 ms-1 at 27Â°C and 1.0 x 10-5 Nm-2 pressure. When the temperature and pressure of the gas are respectively, 127Â°C and 0.05 x 105Nm2, the r.m.s. velocity of velocity of its molecules in ms-1 is;    [2016]
A: 100 / 3
B: 100 âˆš2
C: 400 / âˆš3
D: 100âˆš2 / 3
Ans:
C
Solution:
It is given that,
vrms = 200 m/s
T1 = 300 K
P1 = 105 N/m2
rms velocity of gas molecules,
For two different cases,

It is given that,
vrms = 200 m/s
T1 = 300 K
P1 = 105 N/m2
rms velocity of gas molecules,
For two different cases,

Q 6. The ratio of the specific heats  in terms of degrees of freedom (n) is given by:    [2015]
A:
B:
C:
D:
Ans:
D
Solution:

This fits into the pattern    , where n is the number of the degrees of freedom

Q 7. The mean free path of molecules of a gas,(radius â€˜râ€™) is inversely proportional to:    [2014]
A: r
B: âˆšr
C: r3
D: r2
Ans: D

Solution:

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