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**Q.1 For a plane stress problem, the state of stress at a point P is represented by the stress element as shown in figure.By how much angle (Î¸) in degrees the stress element should be rotated in order to get the planes of maximum shear stress? [2019 : 2 Marks, Set-II](a) 31.7(b) 13.3(c) 26.6(d) 48.3Ans.** (A)

Angle of plane of max shear

âˆ´

(a) Zero

(b) 0.0050

(c) 0.0010

(d) 0.0025

Ans.

Normal strain in the plane of maximum shear strain

The shear stress Ï„ is [2016 : 2 Marks, Set-II]

(a) 10.0 MPa

(b) 5.0 MPa

(c) 2.5 MPa

(d) 0.0 MPa

Ans.

Now,

âˆ´

â‡’

âˆ´ **Q.4 For the plane stress situation shown in the figure, the maximum shear stress and the plane on which it acts are [2015 : 1 Mark, Set-II](a) -50 MPa, on a plane 45** (D)

Under hydrostatic loading condition, stresses at a point in all directions are equal and hence no shear stress.

Alternatively,

Thus, Mohrâ€™s circle reduces to a point. Hence shear stress at all orientations is zero.

As plane ABand BCare principle planes, therefore Mohrâ€™s circle for the given condition is,

Here, normal stress is zero at 45

â‡’ at 45

The maximum shear stress in MPa is [2013 : 2 Marks]

(a) 50

(b) 75

(c) 100

(d) 110

Ans.

But SS is not the option so taken (Ï„

(a) 0

(b) p/2

(c) p

(d) 2p

Ans.

Maximum shear stress,

(a) zero

(b) 3 MPa

(c) 6 MPa

(d) 9 MP

Ans.

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