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Problems on Trains - Concept 2, Quantitative Aptitude Video Lecture | General Test Preparation for CUET - CUET Commerce

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FAQs on Problems on Trains - Concept 2, Quantitative Aptitude Video Lecture - General Test Preparation for CUET - CUET Commerce

1. What are the different types of problems on trains that are commonly asked in quantitative aptitude exams?
Ans. The different types of problems on trains that are commonly asked in quantitative aptitude exams include finding the speed of a train, the time taken by a train to cross a stationary object or another train, and the distance covered by a train in a given time.
2. How can I calculate the speed of a train given the distance and time?
Ans. To calculate the speed of a train, you can use the formula: Speed = Distance/Time. Simply divide the distance covered by the train by the time taken, and you will get the speed of the train.
3. What is the concept of relative speed in train problems?
Ans. In train problems, relative speed refers to the speed at which one train appears to be moving with respect to another train or a stationary object. It is calculated by subtracting the speed of the stationary object or the slower train from the speed of the faster train.
4. How can I calculate the time taken by a train to cross a stationary object?
Ans. To calculate the time taken by a train to cross a stationary object, you can use the formula: Time = Distance/Relative Speed. Divide the distance between the train and the object by the relative speed of the train, and you will get the time taken to cross the object.
5. Can you provide an example of a problem on trains and how to solve it?
Ans. Sure, here is an example: A train traveling at a speed of 60 km/h takes 12 seconds to cross a pole. What is the length of the train? To solve this, we can use the formula: Speed = Distance/Time. Rearranging the formula, Distance = Speed * Time. Plugging in the values, Distance = 60 km/h * 12 seconds. Converting the time to hours (12 seconds = 12/3600 hours), Distance = 60 km/h * (12/3600) hours. Simplifying, Distance = 0.2 km. Therefore, the length of the train is 0.2 km.
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