To show that the area of rhombus is half the product of its diagonals.
A rhombus is a simple (non-self-intersecting) quadrilateral whose all four sides are of same length.
If a parallelogram has two consecutive sides congruent, it is a rhombus.
If two triangles are congruent then their areas are equal.
Area of a triangle = 1/2 X base X height
Area of a rectangle = Length X Breadth
In above figure EHGF is rhombus with diagonal HF (length d1) and diagonal EG (length d2)
Area of rhombus EHGF = Area of triangle EFH + Area of triangle FH
= half of the product of the diagonals
Find the area of the following rhombus.
In the given figure,
PR = d1= 24 cm.
SQ = d2 = 18 cm.
So, the area of the rhombus PQRS is 216 cm2.
|1. What is the formula to calculate the area of a rhombus?|
|2. How do you find the length of the diagonals of a rhombus?|
|3. Can a rhombus have diagonals of different lengths?|
|4. How can I find the area of a rhombus if only one diagonal is given?|
|5. What are some real-life applications of the concept of rhombus area?|