Class 9 Exam > Class 9 Notes > Mathematics (Maths) Class 9 > RD Sharma (Very Short Answer Questions): Linear Equations in Two Variables
Class 9 Maths Chapter 4 Question Answers - Linear Equations in Two Variables
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Page 1
Question:37
Write the equation representing x-axis.
Solution:
The equation of line representing x axis is given by
Question:38
Write the equation representing y-axis.
Solution:
The equation of line representing y axis is given by
Question:39
Write the equation of a line passing through the point 0, 4
and parallel to x-axis.
Solution:
We are given the co-ordinates of the Cartesian plane at 0, 4
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 4.
We get the equation as
Question:40
Write the equation of a line passing through the point 3, 5
and parallel to x-axis.
Solution:
We are given the co-ordinates of the Cartesian plane at 3, 5
.
Page 2
Question:37
Write the equation representing x-axis.
Solution:
The equation of line representing x axis is given by
Question:38
Write the equation representing y-axis.
Solution:
The equation of line representing y axis is given by
Question:39
Write the equation of a line passing through the point 0, 4
and parallel to x-axis.
Solution:
We are given the co-ordinates of the Cartesian plane at 0, 4
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 4.
We get the equation as
Question:40
Write the equation of a line passing through the point 3, 5
and parallel to x-axis.
Solution:
We are given the co-ordinates of the Cartesian plane at 3, 5
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 5.
We get the equation as
Question:41
Write the equation of a line parallel to y-axis and passing through the point -3, -7
.
Solution:
We are given the co-ordinates of the Cartesian plane at – 3, – 7
.
For the equation of the line parallel to y axis, we assume the equation as a one variable equation independent of y
containing x equal to –3.
We get the equation as
Question:42
A line passes through the point -4, 6
and is parallel to x-axis. Find its equation.
Solution:
We are given the co-ordinates of the Cartesian plane at – 4, 6
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 6.
We get the equation as
Question:43
Solve the equation 3x - 2 = 2x + 3 and represent the solution on the number line.
Solution:
We are given,
we get,
The representation of the solution on the number line, when given equation is treated as an equation in one
variable.
Page 3
Question:37
Write the equation representing x-axis.
Solution:
The equation of line representing x axis is given by
Question:38
Write the equation representing y-axis.
Solution:
The equation of line representing y axis is given by
Question:39
Write the equation of a line passing through the point 0, 4
and parallel to x-axis.
Solution:
We are given the co-ordinates of the Cartesian plane at 0, 4
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 4.
We get the equation as
Question:40
Write the equation of a line passing through the point 3, 5
and parallel to x-axis.
Solution:
We are given the co-ordinates of the Cartesian plane at 3, 5
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 5.
We get the equation as
Question:41
Write the equation of a line parallel to y-axis and passing through the point -3, -7
.
Solution:
We are given the co-ordinates of the Cartesian plane at – 3, – 7
.
For the equation of the line parallel to y axis, we assume the equation as a one variable equation independent of y
containing x equal to –3.
We get the equation as
Question:42
A line passes through the point -4, 6
and is parallel to x-axis. Find its equation.
Solution:
We are given the co-ordinates of the Cartesian plane at – 4, 6
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 6.
We get the equation as
Question:43
Solve the equation 3x - 2 = 2x + 3 and represent the solution on the number line.
Solution:
We are given,
we get,
The representation of the solution on the number line, when given equation is treated as an equation in one
variable.
Question:44
Solve the equation 2y - 1 = y + 1 and represent it graphically on the coordinate plane.
Solution:
We are given,
we get,
The representation of the solution on the Cartesian plane, it is a line parallel to y axis passing through the point
is shown below
Question:45
If the point (a, 2) lies on the graph of the linear equation 2x - 3y + 8 = 0, find the value of a.
Solution:
We are given lies on the graph of linear equation .
So, the given co-ordinates are the solution of the equation .
Therefore, we can calculate the value of a by substituting the value of given co-ordinates in equation .
Substituting in equation , we get
Question:46
Page 4
Question:37
Write the equation representing x-axis.
Solution:
The equation of line representing x axis is given by
Question:38
Write the equation representing y-axis.
Solution:
The equation of line representing y axis is given by
Question:39
Write the equation of a line passing through the point 0, 4
and parallel to x-axis.
Solution:
We are given the co-ordinates of the Cartesian plane at 0, 4
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 4.
We get the equation as
Question:40
Write the equation of a line passing through the point 3, 5
and parallel to x-axis.
Solution:
We are given the co-ordinates of the Cartesian plane at 3, 5
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 5.
We get the equation as
Question:41
Write the equation of a line parallel to y-axis and passing through the point -3, -7
.
Solution:
We are given the co-ordinates of the Cartesian plane at – 3, – 7
.
For the equation of the line parallel to y axis, we assume the equation as a one variable equation independent of y
containing x equal to –3.
We get the equation as
Question:42
A line passes through the point -4, 6
and is parallel to x-axis. Find its equation.
Solution:
We are given the co-ordinates of the Cartesian plane at – 4, 6
.
For the equation of the line parallel to x axis, we assume the equation as a one variable equation independent of x
containing y equal to 6.
We get the equation as
Question:43
Solve the equation 3x - 2 = 2x + 3 and represent the solution on the number line.
Solution:
We are given,
we get,
The representation of the solution on the number line, when given equation is treated as an equation in one
variable.
Question:44
Solve the equation 2y - 1 = y + 1 and represent it graphically on the coordinate plane.
Solution:
We are given,
we get,
The representation of the solution on the Cartesian plane, it is a line parallel to y axis passing through the point
is shown below
Question:45
If the point (a, 2) lies on the graph of the linear equation 2x - 3y + 8 = 0, find the value of a.
Solution:
We are given lies on the graph of linear equation .
So, the given co-ordinates are the solution of the equation .
Therefore, we can calculate the value of a by substituting the value of given co-ordinates in equation .
Substituting in equation , we get
Question:46
Find the value of k for which the point 1, -2
lies on the graph of the linear equation x - 2y + k = 0.
Solution:
We are given lies on the graph of linear equation .
So, the given co-ordinates are the solution of the equation .
Therefore, we can calculate the value of k by substituting the value of given co-ordinates in equation .
Substituting in equation , we get
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