All Courses
Get the App Signup / Login
Sign in Open App
Commerce Exam  >  Commerce Notes  >  Mathematics (Maths) Class 11  >  RD Sharma Class 11 Solutions Chapter - Statistics

RD Sharma Class 11 Solutions Chapter - Statistics | Mathematics (Maths) Class 11 - Commerce PDF Download

Download, print and study this document offline
Please wait while the PDF view is loading
 Page 1


32. Statistics
Exercise 32.1
1 A. Question
Calculate the mean deviation about the median of the following observation :
3011, 2780, 3020, 2354, 3541, 4150, 5000
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 3011, 2780, 3020, 2354, 3541, 4150, 5000 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
2354, 2780, 3011, 3020, 3541, 4150, 5000
Therefore, The Median = 3020
Deviation |d| = |x-Median|
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 649.42
1 B. Question
Calculate the mean deviation about the median of the following observation :
38, 70, 48, 34, 42, 55, 63, 46, 54, 44
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 38, 70, 48, 34, 42, 55, 63, 46, 54, 44 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
34, 38,42,44,46,48,54,55,63,70
Here the Number of observations are Even then Median = 
Page 2


32. Statistics
Exercise 32.1
1 A. Question
Calculate the mean deviation about the median of the following observation :
3011, 2780, 3020, 2354, 3541, 4150, 5000
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 3011, 2780, 3020, 2354, 3541, 4150, 5000 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
2354, 2780, 3011, 3020, 3541, 4150, 5000
Therefore, The Median = 3020
Deviation |d| = |x-Median|
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 649.42
1 B. Question
Calculate the mean deviation about the median of the following observation :
38, 70, 48, 34, 42, 55, 63, 46, 54, 44
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 38, 70, 48, 34, 42, 55, 63, 46, 54, 44 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
34, 38,42,44,46,48,54,55,63,70
Here the Number of observations are Even then Median = 
Therefore, The Median = 47
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.6
1 C. Question
Calculate the mean deviation about the median of the following observation :
34, 66, 30, 38, 44, 50, 40, 60, 42, 51
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 34, 66, 30, 38, 44, 50, 40, 60, 42, 51 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
30, 34, 38, 40, 42, 44, 50,51, 60, 66
Here the Number of observations are Even then the middle terms are 42 and 44
Therefore, The Median =  = 43
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Page 3


32. Statistics
Exercise 32.1
1 A. Question
Calculate the mean deviation about the median of the following observation :
3011, 2780, 3020, 2354, 3541, 4150, 5000
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 3011, 2780, 3020, 2354, 3541, 4150, 5000 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
2354, 2780, 3011, 3020, 3541, 4150, 5000
Therefore, The Median = 3020
Deviation |d| = |x-Median|
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 649.42
1 B. Question
Calculate the mean deviation about the median of the following observation :
38, 70, 48, 34, 42, 55, 63, 46, 54, 44
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 38, 70, 48, 34, 42, 55, 63, 46, 54, 44 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
34, 38,42,44,46,48,54,55,63,70
Here the Number of observations are Even then Median = 
Therefore, The Median = 47
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.6
1 C. Question
Calculate the mean deviation about the median of the following observation :
34, 66, 30, 38, 44, 50, 40, 60, 42, 51
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 34, 66, 30, 38, 44, 50, 40, 60, 42, 51 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
30, 34, 38, 40, 42, 44, 50,51, 60, 66
Here the Number of observations are Even then the middle terms are 42 and 44
Therefore, The Median =  = 43
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.7
1 D. Question
Calculate the mean deviation about the median of the following observation :
22, 24, 30, 27, 29, 31, 25, 28, 41, 42
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 22, 24, 30, 27, 29, 31, 25, 28, 41, 42are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
22, 24, 25, 27, 28, 29, 30, 31, 41, 42
Here the Number of observations are Even then the middle terms are 28 and 29
Therefore, The Median =  = 28.5
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.7
Page 4


32. Statistics
Exercise 32.1
1 A. Question
Calculate the mean deviation about the median of the following observation :
3011, 2780, 3020, 2354, 3541, 4150, 5000
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 3011, 2780, 3020, 2354, 3541, 4150, 5000 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
2354, 2780, 3011, 3020, 3541, 4150, 5000
Therefore, The Median = 3020
Deviation |d| = |x-Median|
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 649.42
1 B. Question
Calculate the mean deviation about the median of the following observation :
38, 70, 48, 34, 42, 55, 63, 46, 54, 44
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 38, 70, 48, 34, 42, 55, 63, 46, 54, 44 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
34, 38,42,44,46,48,54,55,63,70
Here the Number of observations are Even then Median = 
Therefore, The Median = 47
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.6
1 C. Question
Calculate the mean deviation about the median of the following observation :
34, 66, 30, 38, 44, 50, 40, 60, 42, 51
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 34, 66, 30, 38, 44, 50, 40, 60, 42, 51 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
30, 34, 38, 40, 42, 44, 50,51, 60, 66
Here the Number of observations are Even then the middle terms are 42 and 44
Therefore, The Median =  = 43
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.7
1 D. Question
Calculate the mean deviation about the median of the following observation :
22, 24, 30, 27, 29, 31, 25, 28, 41, 42
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 22, 24, 30, 27, 29, 31, 25, 28, 41, 42are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
22, 24, 25, 27, 28, 29, 30, 31, 41, 42
Here the Number of observations are Even then the middle terms are 28 and 29
Therefore, The Median =  = 28.5
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.7
1 E. Question
Calculate the mean deviation about the median of the following observation :
38, 70, 48, 34, 63, 42, 55, 44, 53, 47
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 38, 70, 48, 34, 63, 42, 55, 44, 53, 47 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
34, 38, 43, 44, 47, 48, 53, 55, 63, 70
Here the Number of observations are Even then the middle terms are 47 and 48.
Therefore, The Median =  = 47.5
Deviation |d| = |x-Median|
And, The number of observations are 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.4
2 A. Question
Calculate the mean deviation from the mean for the following data :
4, 7, 8, 9, 10, 12, 13, 17
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation from mean.
Formula Used:
Explanation: Here, Observations 4, 7, 8, 9, 10, 12, 13, 17 are Given.
Deviation |d| = |x-Mean|
Page 5


32. Statistics
Exercise 32.1
1 A. Question
Calculate the mean deviation about the median of the following observation :
3011, 2780, 3020, 2354, 3541, 4150, 5000
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 3011, 2780, 3020, 2354, 3541, 4150, 5000 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
2354, 2780, 3011, 3020, 3541, 4150, 5000
Therefore, The Median = 3020
Deviation |d| = |x-Median|
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 649.42
1 B. Question
Calculate the mean deviation about the median of the following observation :
38, 70, 48, 34, 42, 55, 63, 46, 54, 44
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 38, 70, 48, 34, 42, 55, 63, 46, 54, 44 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
34, 38,42,44,46,48,54,55,63,70
Here the Number of observations are Even then Median = 
Therefore, The Median = 47
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.6
1 C. Question
Calculate the mean deviation about the median of the following observation :
34, 66, 30, 38, 44, 50, 40, 60, 42, 51
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 34, 66, 30, 38, 44, 50, 40, 60, 42, 51 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
30, 34, 38, 40, 42, 44, 50,51, 60, 66
Here the Number of observations are Even then the middle terms are 42 and 44
Therefore, The Median =  = 43
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.7
1 D. Question
Calculate the mean deviation about the median of the following observation :
22, 24, 30, 27, 29, 31, 25, 28, 41, 42
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 22, 24, 30, 27, 29, 31, 25, 28, 41, 42are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
22, 24, 25, 27, 28, 29, 30, 31, 41, 42
Here the Number of observations are Even then the middle terms are 28 and 29
Therefore, The Median =  = 28.5
Deviation |d| = |x-Median|
And, The number of observations is 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.7
1 E. Question
Calculate the mean deviation about the median of the following observation :
38, 70, 48, 34, 63, 42, 55, 44, 53, 47
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 38, 70, 48, 34, 63, 42, 55, 44, 53, 47 are Given.
Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the numbers in Ascending order, we get
34, 38, 43, 44, 47, 48, 53, 55, 63, 70
Here the Number of observations are Even then the middle terms are 47 and 48.
Therefore, The Median =  = 47.5
Deviation |d| = |x-Median|
And, The number of observations are 10.
Now, The Mean Deviation is
Mean Deviation = 
Hence, The Mean Deviation is 8.4
2 A. Question
Calculate the mean deviation from the mean for the following data :
4, 7, 8, 9, 10, 12, 13, 17
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation from mean.
Formula Used:
Explanation: Here, Observations 4, 7, 8, 9, 10, 12, 13, 17 are Given.
Deviation |d| = |x-Mean|
Mean = 
Mean of the Given Observations = 
And, The number of observations is 8.
Now, The Mean Deviation is
Mean Deviation = 
Mean Deviation of the given Observations = 
Hence, The Mean Deviation is 3
2 B. Question
Calculate the mean deviation from the mean for the following data :
13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17
Answer
Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation from Mean.
Formula Used: Mean Deviation = 
Explanation: Here, Observations 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 are Given.
Deviation |d| = |x-Mean|
Mean = 
Mean of the Given Observations = 
And, The number of observations is 12.
Now, The Mean Deviation is
Read More
75 videos|238 docs|91 tests
Join Course for Free

Top Courses for Commerce

Related Exams
About this Document
Oct 24, 2024 Last updated
Document Description: RD Sharma Class 11 Solutions Chapter - Statistics for Commerce 2024 is part of Mathematics (Maths) Class 11 preparation. The notes and questions for RD Sharma Class 11 Solutions Chapter - Statistics have been prepared according to the Commerce exam syllabus. Information about RD Sharma Class 11 Solutions Chapter - Statistics covers topics like and RD Sharma Class 11 Solutions Chapter - Statistics Example, for Commerce 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma Class 11 Solutions Chapter - Statistics.
Introduction of RD Sharma Class 11 Solutions Chapter - Statistics in English is available as part of our Mathematics (Maths) Class 11 for Commerce & RD Sharma Class 11 Solutions Chapter - Statistics in Hindi for Mathematics (Maths) Class 11 course. Download more important topics related with notes, lectures and mock test series for Commerce Exam by signing up for free. Commerce: RD Sharma Class 11 Solutions Chapter - Statistics | Mathematics (Maths) Class 11 - Commerce
Description
Full syllabus notes, lecture & questions for RD Sharma Class 11 Solutions Chapter - Statistics | Mathematics (Maths) Class 11 - Commerce - Commerce | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 11 | Best notes, free PDF download
Information about RD Sharma Class 11 Solutions Chapter - Statistics
In this doc you can find the meaning of RD Sharma Class 11 Solutions Chapter - Statistics defined & explained in the simplest way possible. Besides explaining types of RD Sharma Class 11 Solutions Chapter - Statistics theory, EduRev gives you an ample number of questions to practice RD Sharma Class 11 Solutions Chapter - Statistics tests, examples and also practice Commerce tests
75 videos|238 docs|91 tests
Join Course for Free
Download as PDF
Explore Courses for Commerce exam

Top Courses for Commerce

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

pdf

,

Exam

,

Summary

,

RD Sharma Class 11 Solutions Chapter - Statistics | Mathematics (Maths) Class 11 - Commerce

,

ppt

,

past year papers

,

Sample Paper

,

Free

,

study material

,

Extra Questions

,

Semester Notes

,

Previous Year Questions with Solutions

,

practice quizzes

,

MCQs

,

Viva Questions

,

mock tests for examination

,

Important questions

,

RD Sharma Class 11 Solutions Chapter - Statistics | Mathematics (Maths) Class 11 - Commerce

,

RD Sharma Class 11 Solutions Chapter - Statistics | Mathematics (Maths) Class 11 - Commerce

,

shortcuts and tricks

,

video lectures

,

Objective type Questions

;
Additional Information about RD Sharma Class 11 Solutions Chapter - Statistics for Commerce Preparation

RD Sharma Class 11 Solutions Chapter - Statistics Free PDF Download

The RD Sharma Class 11 Solutions Chapter - Statistics is an invaluable resource that delves deep into the core of the Commerce exam. These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective. With the help of these notes, you can grasp complex subjects quickly, revise important points easily, and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner, allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material, or toppers' notes, this PDF has got you covered. Download the RD Sharma Class 11 Solutions Chapter - Statistics now and kickstart your journey towards success in the Commerce exam.

Importance of RD Sharma Class 11 Solutions Chapter - Statistics

The importance of RD Sharma Class 11 Solutions Chapter - Statistics cannot be overstated, especially for Commerce aspirants. This document holds the key to success in the Commerce exam. It offers a detailed understanding of the concept, providing invaluable insights into the topic. By knowing the concepts well in advance, students can plan their preparation effectively. Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.

RD Sharma Class 11 Solutions Chapter - Statistics Notes

RD Sharma Class 11 Solutions Chapter - Statistics Notes offer in-depth insights into the specific topic to help you master it with ease. This comprehensive document covers all aspects related to RD Sharma Class 11 Solutions Chapter - Statistics. It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation. Practice papers and question papers enable you to assess your progress effectively. Additionally, the paper analysis provides valuable tips for tackling the exam strategically. Access to Toppers' notes gives you an edge in understanding complex concepts. Whether you're a beginner or aiming for advanced proficiency, RD Sharma Class 11 Solutions Chapter - Statistics Notes on EduRev are your ultimate resource for success.

RD Sharma Class 11 Solutions Chapter - Statistics Commerce Questions

The "RD Sharma Class 11 Solutions Chapter - Statistics Commerce Questions" guide is a valuable resource for all aspiring students preparing for the Commerce exam. It focuses on providing a wide range of practice questions to help students gauge their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation. The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level. Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.

Study RD Sharma Class 11 Solutions Chapter - Statistics on the App

Students of Commerce can study RD Sharma Class 11 Solutions Chapter - Statistics alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. Apart from the RD Sharma Class 11 Solutions Chapter - Statistics, students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc. The EduRev App will make your learning easier as you can access it from anywhere you want. The content of RD Sharma Class 11 Solutions Chapter - Statistics is prepared as per the latest Commerce syllabus.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup