Class 9 Exam > Class 9 Notes > Mathematics (Maths) Class 9 > RD Sharma MCQs: Factorization of Polynomials
RD Sharma MCQs: Factorization of Polynomials | Mathematics (Maths) Class 9 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
Q u e s t i o n : 7 7
Mark the correct alternative in each of the following:
If x - 2 is a factor of x
2
+ 3ax - 2a, then a =
a
2
b
- 2
c
1
d
-1
S o l u t i o n :
As is a factor of
i.e.
Hence, correct option is
d.
Q u e s t i o n : 7 8
If x
3
+ 6x
2
+ 4x + k is exactly divisible by x + 2, then k =
a
-6
Page 2
Q u e s t i o n : 7 7
Mark the correct alternative in each of the following:
If x - 2 is a factor of x
2
+ 3ax - 2a, then a =
a
2
b
- 2
c
1
d
-1
S o l u t i o n :
As is a factor of
i.e.
Hence, correct option is
d.
Q u e s t i o n : 7 8
If x
3
+ 6x
2
+ 4x + k is exactly divisible by x + 2, then k =
a
-6
b
-7
c
-8
d
-10
S o l u t i o n :
As is exactly divisible by
i.e., is a factor of f(x).
Therefore,
Hence, the correct option is
c.
Q u e s t i o n : 7 9
If x - a is a factor of x
3
-3x
2
a + 2a
2
x + b, then the value of b is
a
0
b
2
c
1
d
3
S o l u t i o n :
As is a factor of
i.e.
Thus, b = 0
Thus, the correct option is
a.
Q u e s t i o n : 8 0
If x
140
+ 2x
151
+ k is divisible by x + 1, then the value of k is
a
1
b
-3
c
2
d
-2
S o l u t i o n :
As is divisible by
i.e., is a factor of f(x).
Therefore,
Hence, the correct option is
a.
Q u e s t i o n : 8 1
If x + 2 is a factor of x
2
+ mx + 14, then m =
a
7
b
2
c
9
d
14
S o l u t i o n :
Page 3
Q u e s t i o n : 7 7
Mark the correct alternative in each of the following:
If x - 2 is a factor of x
2
+ 3ax - 2a, then a =
a
2
b
- 2
c
1
d
-1
S o l u t i o n :
As is a factor of
i.e.
Hence, correct option is
d.
Q u e s t i o n : 7 8
If x
3
+ 6x
2
+ 4x + k is exactly divisible by x + 2, then k =
a
-6
b
-7
c
-8
d
-10
S o l u t i o n :
As is exactly divisible by
i.e., is a factor of f(x).
Therefore,
Hence, the correct option is
c.
Q u e s t i o n : 7 9
If x - a is a factor of x
3
-3x
2
a + 2a
2
x + b, then the value of b is
a
0
b
2
c
1
d
3
S o l u t i o n :
As is a factor of
i.e.
Thus, b = 0
Thus, the correct option is
a.
Q u e s t i o n : 8 0
If x
140
+ 2x
151
+ k is divisible by x + 1, then the value of k is
a
1
b
-3
c
2
d
-2
S o l u t i o n :
As is divisible by
i.e., is a factor of f(x).
Therefore,
Hence, the correct option is
a.
Q u e s t i o n : 8 1
If x + 2 is a factor of x
2
+ mx + 14, then m =
a
7
b
2
c
9
d
14
S o l u t i o n :
As is a factor of
Therefore,
Hence, the correct option is
c.
Q u e s t i o n : 8 2
If x - 3 is a factor of x
2
- ax - 15, then a =
a
-2
b
5
c
-5
d
3
S o l u t i o n :
As is a factor of polynomial
i.e.
Therefore,
Hence, the correct option is
a
Q u e s t i o n : 8 3
If x
51
+ 51 is divided by x + 1, the remainder is
a
0
b
1
c
49
d
50
S o l u t i o n :
As is divided by
The remainder will be
Hence, the correct option is
d.
Q u e s t i o n : 8 4
If x + 1 is a factor of the polynomial 2x
2
+ kx, then k =
a
-2
b
-3
c
4
d
2
S o l u t i o n :
As is a factor of polynomial Therefore,
So,
Hence, the correct option is
d.
Page 4
Q u e s t i o n : 7 7
Mark the correct alternative in each of the following:
If x - 2 is a factor of x
2
+ 3ax - 2a, then a =
a
2
b
- 2
c
1
d
-1
S o l u t i o n :
As is a factor of
i.e.
Hence, correct option is
d.
Q u e s t i o n : 7 8
If x
3
+ 6x
2
+ 4x + k is exactly divisible by x + 2, then k =
a
-6
b
-7
c
-8
d
-10
S o l u t i o n :
As is exactly divisible by
i.e., is a factor of f(x).
Therefore,
Hence, the correct option is
c.
Q u e s t i o n : 7 9
If x - a is a factor of x
3
-3x
2
a + 2a
2
x + b, then the value of b is
a
0
b
2
c
1
d
3
S o l u t i o n :
As is a factor of
i.e.
Thus, b = 0
Thus, the correct option is
a.
Q u e s t i o n : 8 0
If x
140
+ 2x
151
+ k is divisible by x + 1, then the value of k is
a
1
b
-3
c
2
d
-2
S o l u t i o n :
As is divisible by
i.e., is a factor of f(x).
Therefore,
Hence, the correct option is
a.
Q u e s t i o n : 8 1
If x + 2 is a factor of x
2
+ mx + 14, then m =
a
7
b
2
c
9
d
14
S o l u t i o n :
As is a factor of
Therefore,
Hence, the correct option is
c.
Q u e s t i o n : 8 2
If x - 3 is a factor of x
2
- ax - 15, then a =
a
-2
b
5
c
-5
d
3
S o l u t i o n :
As is a factor of polynomial
i.e.
Therefore,
Hence, the correct option is
a
Q u e s t i o n : 8 3
If x
51
+ 51 is divided by x + 1, the remainder is
a
0
b
1
c
49
d
50
S o l u t i o n :
As is divided by
The remainder will be
Hence, the correct option is
d.
Q u e s t i o n : 8 4
If x + 1 is a factor of the polynomial 2x
2
+ kx, then k =
a
-2
b
-3
c
4
d
2
S o l u t i o n :
As is a factor of polynomial Therefore,
So,
Hence, the correct option is
d.
Q u e s t i o n : 8 5
If x + a is a factor of x
4
- a
2
x
2
+ 3x - 6a, then a =
a
0
b
-1
c
1
d
2
S o l u t i o n :
As is a factor of polynomial
Therefore,
Hence, the correct option is
a.
Q u e s t i o n : 8 6
The value of k for which x - 1 is a factor of 4x
3
+ 3x
2
- 4x + k, is
a
3
b
1
c
-2
d
-3
S o l u t i o n :
As is a factor of polynomial f(x) = 4x
3
+ 3x
2
- 4x + k
Therefore,
Hence, the correct option is
d.
Q u e s t i o n : 8 7
If x + 2 and x - 1 are the factors of x
3
+ 10x
2
+ mx + n, then the values of m and n are respectively
a
5 and -3
b
17 and -8
c
7 and -18
d
23 and -19
S o l u t i o n :
It is given and are the factors of the polynomial
i.e., and
Now
-8 +40 -2m +n = 0 ? -2m +n = -32 ? 2m -n = 32 . . . (i)
And
Solving equation
i and
ii we get
Page 5
Q u e s t i o n : 7 7
Mark the correct alternative in each of the following:
If x - 2 is a factor of x
2
+ 3ax - 2a, then a =
a
2
b
- 2
c
1
d
-1
S o l u t i o n :
As is a factor of
i.e.
Hence, correct option is
d.
Q u e s t i o n : 7 8
If x
3
+ 6x
2
+ 4x + k is exactly divisible by x + 2, then k =
a
-6
b
-7
c
-8
d
-10
S o l u t i o n :
As is exactly divisible by
i.e., is a factor of f(x).
Therefore,
Hence, the correct option is
c.
Q u e s t i o n : 7 9
If x - a is a factor of x
3
-3x
2
a + 2a
2
x + b, then the value of b is
a
0
b
2
c
1
d
3
S o l u t i o n :
As is a factor of
i.e.
Thus, b = 0
Thus, the correct option is
a.
Q u e s t i o n : 8 0
If x
140
+ 2x
151
+ k is divisible by x + 1, then the value of k is
a
1
b
-3
c
2
d
-2
S o l u t i o n :
As is divisible by
i.e., is a factor of f(x).
Therefore,
Hence, the correct option is
a.
Q u e s t i o n : 8 1
If x + 2 is a factor of x
2
+ mx + 14, then m =
a
7
b
2
c
9
d
14
S o l u t i o n :
As is a factor of
Therefore,
Hence, the correct option is
c.
Q u e s t i o n : 8 2
If x - 3 is a factor of x
2
- ax - 15, then a =
a
-2
b
5
c
-5
d
3
S o l u t i o n :
As is a factor of polynomial
i.e.
Therefore,
Hence, the correct option is
a
Q u e s t i o n : 8 3
If x
51
+ 51 is divided by x + 1, the remainder is
a
0
b
1
c
49
d
50
S o l u t i o n :
As is divided by
The remainder will be
Hence, the correct option is
d.
Q u e s t i o n : 8 4
If x + 1 is a factor of the polynomial 2x
2
+ kx, then k =
a
-2
b
-3
c
4
d
2
S o l u t i o n :
As is a factor of polynomial Therefore,
So,
Hence, the correct option is
d.
Q u e s t i o n : 8 5
If x + a is a factor of x
4
- a
2
x
2
+ 3x - 6a, then a =
a
0
b
-1
c
1
d
2
S o l u t i o n :
As is a factor of polynomial
Therefore,
Hence, the correct option is
a.
Q u e s t i o n : 8 6
The value of k for which x - 1 is a factor of 4x
3
+ 3x
2
- 4x + k, is
a
3
b
1
c
-2
d
-3
S o l u t i o n :
As is a factor of polynomial f(x) = 4x
3
+ 3x
2
- 4x + k
Therefore,
Hence, the correct option is
d.
Q u e s t i o n : 8 7
If x + 2 and x - 1 are the factors of x
3
+ 10x
2
+ mx + n, then the values of m and n are respectively
a
5 and -3
b
17 and -8
c
7 and -18
d
23 and -19
S o l u t i o n :
It is given and are the factors of the polynomial
i.e., and
Now
-8 +40 -2m +n = 0 ? -2m +n = -32 ? 2m -n = 32 . . . (i)
And
Solving equation
i and
ii we get
m = 7 and n = - 18
Hence, the correct option is
c
Q u e s t i o n : 8 8
Let f(x) be a polynomial such that f -
1
2
= 0, then a factor of f(x) is
a
2x - 1
b
2x + 1
c
x - 1
d
x + 1
S o l u t i o n :
Let f(x) be a polynomial such that
i.e., is a factor.
On rearranging can be written as
Thus, is a factor of f(x).
Hence, the correct option is
b.
Q u e s t i o n : 8 9
When x
3
- 2x
2
+ ax - b is divided by x
2
- 2x - 3, the remainder is x - 6. The values of a and b are respectively
a
-2, -6
b
2 and -6
c
-2 and 6
d
2 and 6
S o l u t i o n :
If the reminder (x -6) is subtracted from the given polynomial then rest of part of this polynomial is exactly divisible by x
2
- 2x - 3.
Therefore,
Now,
Therefore, are factors of polynomial p(x).
Now,
And
and
Solving
i and
ii we get
Hence, the correct option is
c.
Q u e s t i o n : 9 0
One factor of x
4
+ x
2
- 20 is x
2
+ 5. The other factor is
a
( )
Read More
|
44 videos|412 docs|54 tests
|
Related Exams
About this Document
|
4.87/5 Rating |
|
Dec 27, 2024 Last updated |
Document Description: RD Sharma MCQs: Factorization of Polynomials for Class 9 2024 is part of Mathematics (Maths) Class 9 preparation.
The notes and questions for RD Sharma MCQs: Factorization of Polynomials have been prepared according to the Class 9 exam syllabus. Information about RD Sharma MCQs: Factorization of Polynomials covers topics
like and RD Sharma MCQs: Factorization of Polynomials Example, for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma MCQs: Factorization of Polynomials.
Introduction of RD Sharma MCQs: Factorization of Polynomials in English is available as part of our Mathematics (Maths) Class 9
for Class 9 & RD Sharma MCQs: Factorization of Polynomials in Hindi for Mathematics (Maths) Class 9 course.
Download more important topics related with notes, lectures and mock test series for Class 9
Exam by signing up for free. Class 9: RD Sharma MCQs: Factorization of Polynomials | Mathematics (Maths) Class 9
Description
Full syllabus notes, lecture & questions for RD Sharma MCQs: Factorization of Polynomials | Mathematics (Maths) Class 9 - Class 9 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 9 | Best notes, free PDF download
Information about RD Sharma MCQs: Factorization of Polynomials
In this doc you can find the meaning of RD Sharma MCQs: Factorization of Polynomials defined & explained in the simplest way possible. Besides explaining types of
RD Sharma MCQs: Factorization of Polynomials theory, EduRev gives you an ample number of questions to practice RD Sharma MCQs: Factorization of Polynomials tests, examples and also practice Class 9
tests
|
Explore Courses for Class 9 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Viva Questions
,Extra Questions
,past year papers
,Exam
,Summary
,RD Sharma MCQs: Factorization of Polynomials | Mathematics (Maths) Class 9
,RD Sharma MCQs: Factorization of Polynomials | Mathematics (Maths) Class 9
,ppt
,RD Sharma MCQs: Factorization of Polynomials | Mathematics (Maths) Class 9
,study material
,Important questions
,Free
,Previous Year Questions with Solutions
,shortcuts and tricks
,Semester Notes
,Sample Paper
,practice quizzes
,Objective type Questions
,mock tests for examination
,video lectures
,MCQs
;
Additional Information about RD Sharma MCQs: Factorization of Polynomials for Class 9 Preparation
RD Sharma MCQs: Factorization of Polynomials Free PDF Download
The RD Sharma MCQs: Factorization of Polynomials is an invaluable resource that delves deep into the core of the Class 9 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the RD Sharma MCQs: Factorization of Polynomials now and kickstart your journey towards success in the Class 9 exam.
Importance of RD Sharma MCQs: Factorization of Polynomials
The importance of RD Sharma MCQs: Factorization of Polynomials cannot be overstated, especially for Class 9 aspirants.
This document holds the key to success in the Class 9 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
RD Sharma MCQs: Factorization of Polynomials Notes
RD Sharma MCQs: Factorization of Polynomials Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to RD Sharma MCQs: Factorization of Polynomials.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, RD Sharma MCQs: Factorization of Polynomials Notes on EduRev are your ultimate resource for success.
RD Sharma MCQs: Factorization of Polynomials Class 9 Questions
The "RD Sharma MCQs: Factorization of Polynomials Class 9 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 9 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RD Sharma MCQs: Factorization of Polynomials on the App
Students of Class 9 can study RD Sharma MCQs: Factorization of Polynomials alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the RD Sharma MCQs: Factorization of Polynomials,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of RD Sharma MCQs: Factorization of Polynomials is prepared as per the latest Class 9 syllabus.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup