RD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRev

RD Sharma Solutions for Class 6 Mathematics

Created by: Abhishek Kapoor

Class 6 : RD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRev

The document RD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRev is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
All you need of Class 6 at this link: Class 6

Q.1 Construct the following angles with the help of protractor :

450, 670, 380, 1100, 1790, 980, 840.

Sol.1 : 450

We draw a ray OA.

We place the protractor on OA such that its center coincides with the point 0 and the diameter of the protractor coincides with OA.

We mark a point B against the mark of 45° on the protractor.

We remove the protractor and draw OB. ∠AOB is the required angle of 45°.

Similarly, we draw the angles 670, 380, 1100, 1790, 980 and 840.

RD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRevRD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRev
RD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRevRD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRev
RD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRevRD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRev

 

Q.2 Draw two rays PQ and RS as shown in figure. Using the protractor, construct angles of 150 and 138with one arm PQ and RS respectively.

Sol.2 : (i) Draw a ray PQ as given in the question.

Place the protractor on the ray PQ such that its center coincides with the point P and the diameter of the protractor coincides with PQ.

Mark a point B against the mark of 15° on the protractor.

Remove the protractor and draw PB. ∠QPB is the required angle of 15°.

(ii) Draw a ray RS as given in the question.

Place the protractor on ray RS such that its centre coincides with the point R and diameter of the protractor coincides with RS.

Mark a point T against the mark of 1380 on the protractor.

Remove the protractor and draw RJ.

∠SRTIIs the required angle of 1380.

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