Class 6 Exam > Class 6 Notes > RD Sharma Solutions for Class 6 Mathematics > RD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths
Ex-19.4, Geometrical Constructions, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics PDF Download
Q.1 Construct the following angles with the help of protractor :
450, 670, 380, 1100, 1790, 980, 840.
Sol.1 : 450
We draw a ray OA.
We place the protractor on OA such that its center coincides with the point 0 and the diameter of the protractor coincides with OA.
We mark a point B against the mark of 45° on the protractor.
We remove the protractor and draw OB. ∠AOB is the required angle of 45°.
Similarly, we draw the angles 670, 380, 1100, 1790, 980 and 840.
Q.2 Draw two rays PQ and RS as shown in figure. Using the protractor, construct angles of 150 and 1380 with one arm PQ and RS respectively.
Sol.2 : (i) Draw a ray PQ as given in the question.
Place the protractor on the ray PQ such that its center coincides with the point P and the diameter of the protractor coincides with PQ.
Mark a point B against the mark of 15° on the protractor.
Remove the protractor and draw PB. ∠QPB is the required angle of 15°.
(ii) Draw a ray RS as given in the question.
Place the protractor on ray RS such that its centre coincides with the point R and diameter of the protractor coincides with RS.
Mark a point T against the mark of 1380 on the protractor.
Remove the protractor and draw RJ.
∠SRTIIs the required angle of 1380.
The document Ex-19.4, Geometrical Constructions, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
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FAQs on Ex-19.4, Geometrical Constructions, Class 6, Maths RD Sharma Solutions - RD Sharma Solutions for Class 6 Mathematics
| 1. What are geometrical constructions in mathematics? |  |
Ans. Geometrical constructions in mathematics refer to the process of creating various geometric figures using only a compass and a straightedge. These constructions involve drawing lines, angles, triangles, and other shapes without measuring or using any numerical data.
| 2. How can I construct an equilateral triangle using geometrical constructions? | |
Ans. To construct an equilateral triangle using geometrical constructions, follow these steps:
1. Draw a line segment using a straightedge.
2. Place the compass at one endpoint of the line segment and draw an arc.
3. Without changing the compass width, place the compass at the other endpoint of the line segment and draw another arc.
4. The intersection point of the two arcs will be the third vertex of the equilateral triangle.
5. Connect the three vertices to complete the construction.
| 3. Can geometrical constructions be done using only a compass? | |
Ans. No, geometrical constructions cannot be done using only a compass. Geometrical constructions require the use of both a compass and a straightedge. While the compass is used to draw circles and arcs, the straightedge is used to draw straight lines and measure distances.
| 4. What are some common geometrical constructions in mathematics? | |
Ans. Some common geometrical constructions in mathematics include constructing perpendicular bisectors, angle bisectors, parallel lines, triangles, squares, rectangles, and many more. These constructions are important in various mathematical concepts and problem-solving.
| 5. Are geometrical constructions only used in mathematics? | |
Ans. No, geometrical constructions are not only used in mathematics but also have practical applications in various fields like architecture, engineering, and design. Geometrical constructions help in accurately creating and visualizing geometric shapes and structures, which are essential in these fields.
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