The document RD Sharma Solutions -Ex-19.4, Geometrical Constructions, Class 6, Maths Class 6 Notes | EduRev is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.

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**Q.1 Construct the following angles with the help of protractor :**

**45 ^{0}, 67^{0}, 38^{0}, 110^{0}, 179^{0}, 98^{0}, 84^{0}.**

**Sol.1 : **45^{0}

We draw a ray OA.

We place the protractor on OA such that its center coincides with the point 0 and the diameter of the protractor coincides with OA.

We mark a point B against the mark of 45Â° on the protractor.

We remove the protractor and draw OB. âˆ AOB is the required angle of 45Â°.

Similarly, we draw the angles 67^{0}, 38^{0}, 110^{0}, 179^{0}, 98^{0} and 84^{0}.

**Q.2 Draw two rays PQ and RS as shown in figure. Using the protractor, construct angles of 15 ^{0} and 138^{0 }with one arm PQ and RS respectively.**

**Sol.2 : **(i) Draw a ray PQ as given in the question.

Place the protractor on the ray PQ such that its center coincides with the point P and the diameter of the protractor coincides with PQ.

Mark a point B against the mark of 15Â° on the protractor.

Remove the protractor and draw PB. âˆ QPB is the required angle of 15Â°.

(ii) Draw a ray RS as given in the question.

Place the protractor on ray RS such that its centre coincides with the point R and diameter of the protractor coincides with RS.

Mark a point T against the mark of 138^{0} on the protractor.

Remove the protractor and draw RJ.

âˆ SRTIIs the required angle of 138^{0}.