RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev

RD Sharma Solutions for Class 6 Mathematics

Created by: Abhishek Kapoor

Class 6 : RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev

The document RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
All you need of Class 6 at this link: Class 6

Question 1. Which of the following are closed curves? Which of them are simple?

(i)

RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev

(ii)

RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev

(iii)

(iv)

RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev

(v)

RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev

Answer:

Figure (ii), (iii), (iv), (vi), and (vii) are closed curves, whereas Figure (ii), (iii), (iv) and (vi) are simple closed curves.

 

Question 2. Define perimeter of a closed figure.

Answer: The length of the boundary of a closed figure is known as its permieter.

 

Question 3. Find the perimeter of each of the following shapes:

RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev
RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev RD Sharma Solutions -Ex-20.1, Mensuration, Class 6, Maths Class 6 Notes | EduRev

Answer: Perimeter = Sum of lengths of all sides os a closed figure

(i) Perimeter = ( 4 + 2 + 1 + 5) cm = 12 cm

(ii) Perimeter = (23 + 35 + 40 + 35) cm = 133 cm

(iii) Perimeter = (15 + 15 + 15 + 15) cm = 60 cm

(iv) Perimeter = (3 + 3 + 3 + 3 + 3) cm = 15 cm

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