Class 6 Exam  >  Class 6 Notes  >  RD Sharma Solutions for Class 6 Mathematics  >  RD Sharma Solutions -Ex-20.3, Mensuration, Class 6, Maths

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics PDF Download

Question 1. The following figures are drawn on a squared paper. Count the number of squares enclosed by each figure and find its area, taking the area of each square as 1 cm2.

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

Solution:

(i) There are 16 complete squares in the given shape.

Since, Area of one square = 1 cm2

Therefore, Area of this shape = 16 × 1 = 16 cm2

(ii) There are 36 complete squares in the given shape.

Since, Area of one square = 1 cm2

Therefore, Area of 36 squares = 36 × 1 = 36 cm2

(iii) There are 15 complete and 6 half squares in the given shape.

Since, Area of one square = 1 cm2

Therefore, Area of this shape = (15 + 6 × 12) = 18 cm2

(iv) There are 20 complete and 8 half squares in the given shape.

Since, Area of one square = 1 cm2

Therefore, Area of this shape = (20 + 8 × 12) = 24 cm2

(v) There are 13 complete squares, 8 more than half squares and 7 less than half squares in the given shape.

Area of one square = 1 cm2

Area of this shape = (13 + 8 × 1) = 21 cm2

(vi) There are 8 complete squares, 6 more than half squares and 4 less than half squares in the given shape.

Area of one square = 1 cm2

Area of this shape = (8 + 6 × 1) = 14 cm2

 

Question 2. On a squared paper, draw (i) a rectangle, (ii) a triangle, (iii) any irregular closed figure, Find approximate area of each by counting the number of squares complete, more than half and exactly half.

Solution: (i) A rectangle: This contains 18 complete squares.

If we assume that the area of one complete square is 1 cm2,

Then the area o this rectangle will be 18 cm2.

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

(ii) A triangle: This triangle contains 4 complete squares, 6 more than half squares and 6 less than half squares.

If we assume that the area of one complete square is 1 cm2,

Then the area of this shape = (4 + 6 x 1) = 10 cm2

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

(iii) Any irregular figure: This figure consists of 10 complete squares, 1 exactly half square, 7 more than half squares and 6 less than half squares.

If we assume that the area of one complete square is 1 cm2,

Then the area of this shape = (10 + 1 x12 + 7 x 1) = 17.5 cm2

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

 

Question 3. Draw any circle on the graph paper, Count the squares and use them to estimate the area the area of the circular region.

Solution:

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

This circle on the squared paper consists of 21 complete squares, 15 more than half squares and 8 less than half squares.

Let us assume that the area of 1 square is 1 cm2.

If we neglect the less than half squares while approximating more than half square as equal to a complete square, we get:

Area of this shape = (21 + 15) = 36 cm2

 

Question 4. Using tracing paper and centimeter graph paper to compare the areas of the following pairs of figures:

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

Solution:

Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 MathematicsEx-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

Using tracing paper, we traced both the figures on a graph paper.

This figure contains 4 complete squares, 9 more than half squares and 9 less than half squares. Let us assume that the area of one square is 1 cm2

If we neglect the less than half squares and consider the area of more than half squares as equal to area of complete square, we get:

Area of this shape = (4 + 9) = 13 cm2

This figure contains 8 complete squares, 11 more than half squares and 10 less than half squares.

Let us assume that the area of one square is 1 cm2.

If we neglect the less than half squares and consider the area of more than half squares as equal to area of complete square, we get:

Area of this shape = (8 + 11) = 19 cm2

On comparing the areas of these two shapes, we get that the area of Fig. (ii) is more than that of Fig. (i).

The document Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
All you need of Class 6 at this link: Class 6
99 docs

Top Courses for Class 6

FAQs on Ex-20.3, Mensuration, Class 6, Maths RD Sharma Solutions - RD Sharma Solutions for Class 6 Mathematics

1. What is RD Sharma Solutions?
Ans. RD Sharma Solutions is a comprehensive guidebook or textbook that provides step-by-step solutions to all the questions and exercises present in the RD Sharma textbook. It is widely used by students to understand and practice mathematical concepts.
2. What is Ex-20.3 in RD Sharma Solutions?
Ans. Ex-20.3 in RD Sharma Solutions refers to Exercise 20.3, which is a section or set of questions in the textbook related to the topic of Mensuration. It contains a series of problems that students need to solve to understand and master the concepts of Mensuration.
3. What is Mensuration?
Ans. Mensuration is a branch of mathematics that deals with the measurement of geometric figures such as lengths, areas, volumes, and angles. It involves calculations and formulas to determine the size, shape, and quantity of objects in both two-dimensional and three-dimensional space.
4. How can RD Sharma Solutions help in preparing for the Class 6 Maths exam?
Ans. RD Sharma Solutions can be extremely helpful in preparing for the Class 6 Maths exam. It provides clear and detailed solutions to all the exercises and questions in the textbook, allowing students to understand the concepts thoroughly. By practicing these solutions, students can gain confidence in solving similar problems and improve their problem-solving skills, which are crucial for the exam.
5. Are RD Sharma Solutions available in multiple languages?
Ans. RD Sharma Solutions are primarily available in English, as the textbook is widely used in English medium schools. However, depending on the region and demand, there might be versions available in other regional languages as well. It is recommended to check with local bookstores or online platforms for the availability of RD Sharma Solutions in specific languages.
99 docs
Download as PDF
Explore Courses for Class 6 exam

Top Courses for Class 6

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Semester Notes

,

Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

,

Extra Questions

,

Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

,

Mensuration

,

Objective type Questions

,

Ex-20.3

,

MCQs

,

Class 6

,

Important questions

,

Ex-20.3

,

Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

,

shortcuts and tricks

,

Previous Year Questions with Solutions

,

Class 6

,

Mensuration

,

video lectures

,

Class 6

,

Sample Paper

,

Exam

,

ppt

,

Mensuration

,

mock tests for examination

,

study material

,

Summary

,

Free

,

practice quizzes

,

Viva Questions

,

past year papers

,

Ex-20.3

,

pdf

;