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Ex-4.6, Operations On Whole Numbers, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics PDF Download

Q1. Which one of the following is the smallest whole number?

(a) 1  (b)  2   (c) 0  (d) None of these

Solution: The set of whole numbers is { 0 , 1, 2, 3, 4, ...}.

So, the smallest whole number is 0.

Hence, the correct option is (c).

 

Q2. Which one of the following is the smallest even whole number?

(a) 0 (b) 1 (c) 2 (d) None of these

Solution: The natural numbers along with 0 form the collection of whole numbers.

So, the numbers 0, 1, 2, 3, 4, ... form the collection of whole numbers.

The number which is divisible by 2 is an even number.

So, in the collection "0, 1, 2, 3, 4, ...", 2 is the smallest even number.

Hence, the correct option is (c).

 

Q3. Which one of the following is the smallest odd whole number?

(a) 0 (b) 1 (c) 3 (d) 5

Solution: The natural numbers along with 0 form the collection of whole numbers.

So, the numbers 0, 1, 2, 3, 4, ... form the collection of whole numbers.

A natural number which is not divisible by 2 is called an odd whole number.

So, in the collection "0, 1, 2, 3, 4, ...", 1 is the smallest odd whole number.

Hence, the correct option is (b).

 

Q4. How many whole numbers are between 437 and 487?

(a) 50 (b) 49 (c) 51 (d) None of these

Solution: The whole numbers between 437 and 487 are 438, 439, 440, 441, ... , 484, 485 and 486. To find the required number of whole numbers,

We need to subtract 437 from 487 and then subtract again 1 from the result.

Thus, there are (487 - 437) - 1 whole numbers between 437 and 487.

Now, (487 - 437) - 1 = 50 - 1 = 49

Hence, the correct option is (b).

 

Q5. The product of the successor 999 and predecessor of 1001 is:

(a) one lakh (b) one billion (c) one million (d) one crore

Solution: Successor of 999 = 999 + 1 = 1000

Predecessor of 1001 = 1001 - 1 = 1000

Now,

Product = (Successor of 999) x (Predecessor of 1001)

= 1000 x 1000

= 1000000

= one million

Hence, the correct option is (c).

 

Q6. Which one of the following whole numbers does not have a predecessor?

(a) 1 (b) 0 (c) 2 (d) None of these

Solution: The numbers 0, 1, 2, 3, 4, .... form the collection of whole numbers.

The smallest whole number is 0.

So, 0 does not have a predecessor.

Hence, the correct option is (b).

 

Q7. The number of whole numbers between the smallest whole number and the greatest 2 digit number is:

(a) 101 (b) 100 (c)99 (d)98

Solution: Smallest whole number = 0

Greatest 2-digit whole number = 99

The whole numbers between 0 and 99 are 1, 2, 3, 4 …… 97, 98.

To find the number of whole numbers between 0 and 99,

Subtract 1 from the difference of 0 and 99.

Therefore, Number of whole numbers between 0 and 99 = (99 - 0) - 1

= 99 – 1

= 98

Hence, the correct option is (d).

 

Q8. If n is a whole number such that n + n = n, then n =?

(a) 1 (b)2 (c)3 (d) None of these

Solution: Here, 0 + 0 = 0, 1 + 1 = 2 , 2 + 2 = 4 …..

So, the statement n + n = n is true only when n = 0.

Hence, the correct option is (d).

 

Q9. The predecessor of the smallest 3 digit number is:

(a) 999 (b)99 (c) 100 (d)101

Solution: Smallest 3-digit number = 100

Predecessor of 3-digit number = 100 — 1 = 99

Hence, the correct option is (b).

 

Q10. The least number of 4 digits which is exactly divisible by 9 is:

(a)1008 (b)1009 (c)1026 (d)1018

Solution: Least 4-digit number = 1000

The least 4-digit number exactly divisible by 9 is 1000 + (9 - 1) = 1008.

Hence, the correct option is (a).

 

Q11. The number which when divided by 53 gives 8 as quotient and 5 as remainder is:

(a) 424 (b)419 (c)429 (d)None of these

Solution: Here, Divisor = 53, Quotient = 8 and Remainder = 5.

Now, using the relation Dividend = Divisor x Quotient + Remainder

We get

Dividend = 53 x 8 + 5

= 424 + 5

=429

Thus, the required number is 429.

Hence, the correct option is (c).

 

Q12. The whole number n satisfying n + 35 = 101 is:

(a)65 (b)67 (c)64 (d)66

Solution: Here, n+ 35 = 101.

Adding - 35 on both sides, we get

n + 35 + (- 35)= 101 + (- 35)

n + 0 = 66

n=66

Hence, the correct option is (d).

 

Q13. The value of 4 x 378 x 25 is :

(a)37800 (b)3780 (c)9450 (d)30078

Solution: By regrouping, we get

4 x 378 x 25 = 4 x 25 x 378

= 100 x 378

= 37800

Hence, the correct option is (a).

 

Q14. The value of 1735 x 1232 – 1735 x 232 is:

(a)17350 (b)173500 (c)1735000 (d)173505

Solution: Using distributive law of multiplication over subtraction, we get

1735 x 1232 – 1735 x 232 = 1735 (1232 – 232)

= 1735 x 1000

= 1735000

Hence, the correct option is (c).

 

Q15. The value of 47 x 99 is :

(a)4635 (b)4653 (c)4563 (d)6453

Solution: Since, 99 = 100 — 1

Therefore, 47 x 99 = 47 x (100 — 1)

= 47x 100 — 47

= 4700 — 47

= 4653

Thus, the value of 47 x 99 is 4653.

Hence, the correct option is (b).

The document Ex-4.6, Operations On Whole Numbers, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
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FAQs on Ex-4.6, Operations On Whole Numbers, Class 6, Maths RD Sharma Solutions - RD Sharma Solutions for Class 6 Mathematics

1. What are the different operations on whole numbers?
Ans. The different operations on whole numbers are addition, subtraction, multiplication, and division.
2. How do you perform addition of whole numbers?
Ans. To perform addition of whole numbers, we simply add the numbers together. For example, to add 3 and 5, we write 3 + 5 = 8.
3. What is the process of subtracting whole numbers?
Ans. The process of subtracting whole numbers involves subtracting one number from another. For example, to subtract 5 from 8, we write 8 - 5 = 3.
4. How do you multiply whole numbers?
Ans. To multiply whole numbers, we multiply the numbers together. For example, to multiply 3 and 4, we write 3 x 4 = 12.
5. What is the concept of division in whole numbers?
Ans. Division in whole numbers is the process of dividing one number by another to find out how many times the second number can be subtracted from the first number. For example, if we divide 12 by 3, we get 4 as the answer because 3 can be subtracted from 12 four times without any remainder.
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