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# RD Sharma Solutions -Ex-6.9, Fractions, Class 6, Maths Class 6 Notes | EduRev

## RD Sharma Solutions for Class 6 Mathematics

Created by: Abhishek Kapoor

## Class 6 : RD Sharma Solutions -Ex-6.9, Fractions, Class 6, Maths Class 6 Notes | EduRev

The document RD Sharma Solutions -Ex-6.9, Fractions, Class 6, Maths Class 6 Notes | EduRev is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
All you need of Class 6 at this link: Class 6

Q 1. Add : i)  and  ii)  and  iii)  and  iv)  and
sol: i) Given :  and  LCM of 4 and 6 is 12 , so we will convert each fraction into an equivalent fraction with denominator 12.
ii) Given :  and  LCM of 10 and 15 is 30 , so we will convert each fraction into an equivalent fraction with denominator 30.
iii) Given :  and  LCM of 13 and 3 is 39 , so we will convert each fraction into an equivalent fraction with denominator 39.
iv) Given : and  LCM of 5 and 15 is 15 , so we will convert each fraction into an equivalent fraction with denominator 15.

Q 2. Subtract : i)  from  ii)  from  iii)  from  iv)  from
sol: i) Given :  and  LCM of 21 and 7 is 21, so we will convert each fraction into an equivalent fraction with denominator 21.
ii) Given :  and  LCM of 20 and 25 is 100 , so we will convert each fraction into an equivalent fraction with denominator 100.
iii) Given :  and  LCM of 1 and 16 is 16 , so we will convert each fraction into an equivalent fraction with denominator 16.
iv) Given :  and 4 LCM of 5 and 15 is 15 , so we will convert each fraction into an equivalent fraction with denominator 15.

Q 3. Find the difference of : i)  and  i)  and  i)  and  i)  and
sol: i) Given :  and ( because LCM of 24 and 16 is 48 )
ii) Given :  and  ( because LCM of 18 and 15 is 90 ) =
iii) Given :  and  ( because LCM of 4 and 12 is 12 )
iv) Given : and  ( because LCM of 7 and 3 is 21 )

Q 4. Subtract as indicated : i)  ii)  iii)  iv)
sol: i) Given :  and  ( because LCM of 3 and 9 is 9 ) =
ii) Given : and
iii) Given :  and     =  ( because LCM of 7 and 3 is 21 )
iv) Given :  and      ( because LCM of 4 and 6 is 12 )

Q 5. simplify :
i)  ii)  iii)  iv)  v)  vi)  vii)  viii)  ix)
sol:
i) given :  ( because LCM of 3, 4 and 2 is 12 )
ii) given : ( because LCM of 8, 5 and 4 is 40 )
iii) given :  ( because LCM of 8, 5 and 4 is 40 )
iv) given : ( because LCM of 4, 16 and 8 is 16 )
v) given :  ( because LCM of 3, 4 and 2 is 12 ) =
vi) given :( because LCM of 3, 4 and 6 is 12 )  ( HCF of numerator and denominator is 12 )
vii) given :  ( because LCM of 1, 4 and 6 is 12 ) =
viii) given :  ( because LCM of 6, 1 and 4 is 12 ) =
ix) given :

Q 6. Replace * with a correct number : i) ii) iii)
sol: i)  Therefore,
ii)
iii)  ( because LCM of 2 and 6 is 6 )

Q 7. Savita bought  m of ribbon and kavita  m of ribbon. What was the total length of the ribbon they bought ?
Sol: length of the ribbon bought by savita =  metres Length of the ribbon bought by kavita = metres
Total length of the ribbon bought by them:  metres +  metres  metres +  metres ( because LCM of 5 and 4 is 20 )
metres +  metres = metres =  metres

Q 8. Ravish takes  minutes to walk across the school ground. Rahul takesminutes to do the same. Who takes less time and by what fraction ?
Sol: Time taken by ravish =  =  minutes
Time taken by rahul =  minutes Comparing  minutes and  minutes, we get :  minutes ,  minutes ( LCM of 4 and 5 is 20, so will we convert each fraction into an equivalent fraction with denominator 20 )
Rahul takes less time , i.e,  minutes.

Q 9. A piece of a wire  metres long broke into two pieces. One piece was  meter long. How long is the other piece ?
Ans:
Length of the wire =  metres Length of one piece of wire =  metres Let the length of the second piece of wire be x m.
Therefore, Length of the wire = length of one piece + length of the second piece metres =  metres + x X =  metres - metres X
metres - metres =  metres -  metres =  metres X =  metres
Therefore, the length of the second piece is  metres

Q 10. Shikha and priya have bookshelves of the same size shikha’s shelf is  full of book and priya’s shelf is full. Whose bookshelf is more full ? By what fraction ?
Sol: Fraction of shikha’s filled bookshelf =  Fraction of Priya’s filled bookshelf =  Comparing  and , we get :
LCM of 5 and 6 is 30, so will convert each fraction into an equivalent fraction with denominator 30. =  metres,  metres  Shikha’s shelf is more full.
Therefore,

Q 11. Ravish’s house is Km from his school. He walked some distance and then took a bus for  Km. How far did he walk?
Sol: Total distance between the house and the school = Km Distance covered in the bus = Km Distance covered by walking + distance covered in the bus
= total distance between the house and the school Distance covered by walking
= total distance between the house and the school – Distance covered in the bus Distance covered by walking:Km - Km
LCM of 10 and 2 is 10, so we convert each fraction into an equivalent fraction with denominator   ( HCF of numerator and denominator is 2 )

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