The document RD Sharma Solutions -Page No.5.10, Negative Numbers And Integers, Class 6, Maths Class 6 Notes | EduRev is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.

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(i) âˆ’557 and 488

(ii) âˆ’522 and âˆ’160

(iii) 2567 and âˆ’325

(iv) âˆ’10025 and 139

(v) 2547 and âˆ’2548

(vi) 2884 and âˆ’2884

(âˆ’557)+488=âˆ’[|âˆ’557|âˆ’|488|] ( As, |âˆ’557|=557,|488|=488)

=âˆ’[557âˆ’488]

=âˆ’6

(ii) Here, we have to add integers that are both negative.

(âˆ’552)+(âˆ’160)=âˆ’[|âˆ’552|+|âˆ’160|] (As,|âˆ’552|=552,|âˆ’160|=160)

=âˆ’[552+160]

=âˆ’682

(iii) Here,we have to add integers of unlike signs ,therefore we find the difference of their absolute values & assign sign of the addend having greater absolute value .

(2567)+(âˆ’325)=[|2567|âˆ’|âˆ’325|] (As,|2567|=2567,|âˆ’325|=325)

=[2567âˆ’325]

=2242

(iv) Here, we have to add integers of unlike sign ,therefore we find the difference of their absolute values & assign the sign of the addend having greater absolute value .

(âˆ’10025)+139

=âˆ’[|âˆ’10025|âˆ’|139|] (As,|âˆ’10025|=10025,|139|=139)

=âˆ’[10025âˆ’139]

= âˆ’9886

(v) Here,we have to add integers of unlike signs ,therefore we find the difference of their absolute values & assign sign of the addend having greater absolute value .

(2547)+(âˆ’2548)=âˆ’[|2548|âˆ’|âˆ’2547|] (As,|2548|=2548,|âˆ’2547|=2547)

=âˆ’[2548âˆ’2547]

=âˆ’1

(vi) Here,we have to add integers of unlike signs ,therefore we find the difference of their absolute values & assign sign of the addend having greater absolute value .

(2884)+(âˆ’2884)

=[|2884|âˆ’|âˆ’2884|] (As,|2884|=2884,|âˆ’2884|=2884)

=[2884âˆ’2884]

=0