Page No.5.10, Negative Numbers And Integers, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics PDF Download

PAGE NO 5.10:

Question 2: Find the sum of:
(i) −557 and 488
(ii) −522 and −160
(iii) 2567 and −325
(iv) −10025 and 139
(v) 2547 and −2548
(vi) 2884 and −2884
ANSWER: (i) Here, we have to add integers of unlike sign ,therefore we find the difference of their absolute values & assign the sign of the addend having greater absolute value
(−557)+488=−[|−557|−|488|]                   ( As, |−557|=557,|488|=488)
=−[557−488]
=−6
(ii) Here, we have to add integers that are both negative.
(−552)+(−160)=−[|−552|+|−160|]                  (As,|−552|=552,|−160|=160)
=−[552+160]
=−682
(iii) Here,we have to add integers of unlike signs ,therefore we find the difference of their absolute values & assign sign of the addend having greater absolute value .
(2567)+(−325)=[|2567|−|−325|]               (As,|2567|=2567,|−325|=325)
 =[2567−325]
=2242
(iv)  Here, we have to add integers of unlike sign ,therefore we find the difference of their absolute values & assign the sign of the addend having greater absolute value .
(−10025)+139
=−[|−10025|−|139|]                 (As,|−10025|=10025,|139|=139)
=−[10025−139]
= −9886
(v) Here,we have to add integers of unlike signs ,therefore we find the difference of their absolute values & assign sign of the addend having greater absolute value .
(2547)+(−2548)=−[|2548|−|−2547|]               (As,|2548|=2548,|−2547|=2547)
=−[2548−2547]
=−1
(vi) Here,we have to add integers of unlike signs ,therefore we find the difference of their absolute values & assign sign of the addend having greater absolute value .
(2884)+(−2884)
=[|2884|−|−2884|]               (As,|2884|=2884,|−2884|=2884)
=[2884−2884]
=0