RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev

RD Sharma Solutions for Class 8 Mathematics

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Class 8 : RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev

The document RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev is a part of the Class 8 Course RD Sharma Solutions for Class 8 Mathematics.
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Question 8: By what number should (−5) −1 be multiplied so that the product is (−8) −1

Answer 8:
Let the number be x.
According to the question, 
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev

Question 9: By what number should (15) −1 be multiplied so that the product may be equal to (−5) −1 ?

Answer 9: 
Let the required number be x.
Therefore,
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
x=−3
Hence, the required number is 3. 

Question 10:

By what number should (−15)−1 be divided so that the quotient may be equal to (−5)−1?

Answer 10:

Expressing in fractional form, we get:
(−15)−1 = −1/15,      ---> (a−1 = 1/a)
and
(−5)−1 = −1/5           ---> (a−1 = 1/a)
We have to find a number x such that
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRevSolving this equation, we get:RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev          RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev          RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRevRD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRevHence, (−15)−1 should be divided by 1/3 to obtain (−5)−1.


Question 11:

By what number should (5/3)−2  be multiplied so that the product may be (73)−1?

Answer 11:

Expressing as a positive exponent, we have:
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev        ---> (a−1 = 1/a)                RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev            ---> ((a/b)n = (an)/(bn))                RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRevand(7/3)−1 = 3/7.                ---> (a−1 = 1/a)
We have to find a number x such that
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRevMultiplying both sides by 25/9, we get:RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRevHence, (5/3)−2 should be multiplied by 25/21 to obtain (7/3)−1.

Question 12:

Find x, if
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
Answer 12:
(i) We have:

RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                 
   RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev(am×an = am+n)
  RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                                 
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
x = 3
(ii) We have:

RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                   
   RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev(am×an = am+n)
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                                 
 RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                                       
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
x = 6
(iii) We have:

RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                     
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                               
 RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                               
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev 
                             
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
x = 1/2
(iv) We have:

RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                   
 RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                             
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                             
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev 
                           
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
x = 10/3
(v) We have:

RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                 
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                     
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                             
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                                 
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
(vi) We have:

RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                 
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                       
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev                                 
 RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
Question 13:
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
Answer 13:
(i) First, we have to find x.
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRevx = 322×23-4  = Hence, x−2 is:
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
(ii) First, we have to find x.
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
Hence, the value of x−1 is:
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev

Question 14: Find the value of x for which 52x ÷ 5−3 = 55.
Answer 14:
We have:
RD Sharma Solutions - Chapter 2 - Powers (Ex-2.2) Part- 2 Class 8 Math Class 8 Notes | EduRev
hence, x is 1.

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