Class 8 Exam  >  Class 8 Notes  >  RD Sharma Solutions for Class 8 Mathematics  >  RD Sharma Solutions - Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics PDF Download

PAGE NO 9.5:

Question 1:

Solve each of the following equation and also verify your solution:

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = y−Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 37/4 + 4/3 = y

or y = 127/12

∴ y = 127/12 for the given equation.

Check:

L.H.S = Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S = 127/12−Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = 127/12−4/3 = (127−16)/12 = 111/12 =Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

So, L.H.S = R.H.S for y = 127/12

PAGE NO 9.5:

Question 2:

Solve each of the following equation and also verify your solution:
5x/3 + 2/5 = 1 

ANSWER:

5x/3 + 2/5 = 1

⇒ 5x/3 = 1−2/5

⇒ 5x/3 = 3/5

⇒ x = 3/5 × 3/5 = 9/25

Verification:

L.H.S. = 5/3 × 9/25 + 2/5 = 3/5 + 2/5 = 1

R.H.S. = 1

∴ L.H.S. = R.H.S. for x = 9/25

PAGE NO 9.5:

Question 3:

Solve each of the following equation and also verify your solution:
x/2 + x/3 + x/4 = 13 

ANSWER:

x/2 + x/3 + x/4 = 13

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

⇒ 13x/12 = 13

⇒ x = 13 × 12/13 = 12

Verification:

L.H.S. = 12/2 + 12/3 + 12/4 = 6 + 4 + 3 = 13 = R.H.S.

PAGE NO 9.5:

Question 4:

Solve each of the following equation and also verify your solution:
x/2 + x/8 = 1/8 

ANSWER:

x/2 + x/8 = 1/8

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 5x/8 = 1/8

or x = 1/8 × 8/5 = 1/5

Verification:

L.H.S. = 1/2 × 1/5 + 1/8 × 1/5 = 1/10 + 1/40 = 5/40 = 1/8 = R.H.S.

PAGE NO 9.5:

Question 5:

Solve each of the following equation and also verify your solution:

2x/3−3x/8 = 7/12

ANSWER:

2x/3−3x/8 = 7/12

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 7x/24 = 7/12

or x = 7/12 × 24/7 = 2

Verification:

L.H.S. = 4/3−6/8

=Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics 

R.H.S. = 7/12

∴ R.H.S. = L.H.S. for x = 2

PAGE NO 9.5:

Question 6:

Solve each of the following equation and also verify your solution:
(x  + 2)(x  + 3) + (x − 3)(x − 2) − 2x(x  + 1) = 0

ANSWER:

(x + 2)(x + 3) + (x−3)(x−2)−2x(x + 1) = 0

or x2 + 5x + 6 + x2−5x + 6−2x2−2x = 0

or 12−2x = 0

or x = 12/2 = 6

Verification:

L.H.S. = (6 + 2)(6 + 3) + (6−3)(6−2)−2 × 6(6 + 1)

= 72 + 12−84 = 0 = R.H.S.

AGE NO 9.5:

Question 7:

Solve each of the following equation and also verify your solution:

x/2−4/5 + x/5 + 3x/10 = 1/5

ANSWER:

x/2−4/5 + x/5 + 3x/10 = 1/5

or x/2 + x/5 + 3x/10 = 1/5 + 4/5

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 10x/10 = 1

or x = 1

Verification:

L.H.S. = 1/2−4/5 + 1/5 + 3/10

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

= 1/5 = R.H.S.

PAGE NO 9.5:

Question 8:

Solve each of the following equation and also verify your solution:
7/x + 35 = 1/10 

ANSWER:

7/x + 35 = 1/10

or 7/x = 1/10−35

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Verification:

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

= 349/−10 + 35 = 1/10 = R.H.S.

PAGE NO 9.5:

Question 9:

Solve each of the following equation and also verify your solution:

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or −24x + 3 = 15

or 24x = 3−15

or x = −12/24 = −1/2

Verification:

L.H.S. =

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

PAGE NO 9.5:

Question 10:

Solve each of the following equation and also verify your solution:
13(y − 4) − 3(y − 9) − 5(y  + 4) = 0

ANSWER:

13(y−4)−3(y−9)−5(y + 4) = 0

or 13y−52−3y + 27−5y−20 = 0

or 5y = 45

or y = 45/5 = 9

Verification:

L.H.S. = 13(9−4)−3(9−9)−5(9 + 4)

= 13 × 5−3 × 0−5 × 13

= 0 = R.H.S.

PAGE NO 9.5:

Question 11:

Solve each of the following equation and also verify your solution:
2/3(x−5)−1/4(x−2) = 9/2 

ANSWER:

2/3(x−5)−1/4(x−2) = 9/2 

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

 

or 10x−68 = 108

or 10x = 108 + 68

or x = 176/10 = 88/5

Verification:

L.H.S. = 23(885−5)−14(885−2)

= 2/3 × 63/5−1/4 × 78/5 = 9/2 = R.H.S.

The document Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics is a part of the Class 8 Course RD Sharma Solutions for Class 8 Mathematics.
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FAQs on Chapter 9 - Linear Equation in One Variable (Part - 1), Class 8, Maths RD Sharma Solutions - RD Sharma Solutions for Class 8 Mathematics

1. What is a linear equation in one variable?
Ans. A linear equation in one variable is an equation that can be written in the form ax + b = 0, where a and b are real numbers, and x is the variable. It represents a straight line on a graph and has a unique solution.
2. How do you solve a linear equation in one variable?
Ans. To solve a linear equation in one variable, we need to isolate the variable on one side of the equation. We can do this by performing operations such as addition, subtraction, multiplication, and division on both sides of the equation. The goal is to get the variable alone on one side and a constant on the other side.
3. What is the solution to a linear equation in one variable?
Ans. The solution to a linear equation in one variable is the value of the variable that satisfies the equation. It is the value that, when substituted into the equation, makes the equation true. A linear equation can have one solution, no solution, or infinitely many solutions, depending on the values of the coefficients.
4. Can a linear equation in one variable have more than one solution?
Ans. A linear equation in one variable can have one solution, no solution, or infinitely many solutions. If the equation has one solution, it means there is a unique value of the variable that satisfies the equation. If the equation has no solution, it means there is no value of the variable that satisfies the equation. If the equation has infinitely many solutions, it means any value of the variable will satisfy the equation.
5. What are the applications of linear equations in one variable in real life?
Ans. Linear equations in one variable have various applications in real life. They are used in solving problems related to finance, such as calculating interest rates and loan payments. They are also used in physics to model motion and in engineering to solve problems related to electrical circuits. Additionally, linear equations in one variable are used in everyday situations such as calculating distances, determining the cost of items, and solving problems involving proportions.
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