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Page 1 Q u e s t i o n : 1 If the height of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm respectively, find the mean height. S o l u t i o n : Given that the heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm, respectively. We have to find the mean of their heights. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean height of the 5 persons is Q u e s t i o n : 2 Find the mean of 994, 996, 998, 1002, 1000. S o l u t i o n : The given 5 numbers are 994, 996, 998, 1002 and 1000, respectively. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the given 5 numbers is Q u e s t i o n : 3 Find the mean of first five natural numbers. S o l u t i o n : The first 5 natural numbers are 1, 2, 3, 4 and 5. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 5 natural numbers is Page 2 Q u e s t i o n : 1 If the height of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm respectively, find the mean height. S o l u t i o n : Given that the heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm, respectively. We have to find the mean of their heights. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean height of the 5 persons is Q u e s t i o n : 2 Find the mean of 994, 996, 998, 1002, 1000. S o l u t i o n : The given 5 numbers are 994, 996, 998, 1002 and 1000, respectively. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the given 5 numbers is Q u e s t i o n : 3 Find the mean of first five natural numbers. S o l u t i o n : The first 5 natural numbers are 1, 2, 3, 4 and 5. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 5 natural numbers is Q u e s t i o n : 4 Find the mean of all factors of 10. S o l u t i o n : All the factors of 10 are 1, 2, 5, and 10. They are 4 in numbers. We have to find the mean of the all factors of 10. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the all factors of 10 is Q u e s t i o n : 5 Find the mean of first 10 even natural numbers. S o l u t i o n : The first 10 even natural numbers are 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20. They are 10 in numbers. We have to find the mean of the first 10 even natural numbers. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 10 even natural numbers is Q u e s t i o n : 6 Find the mean of x, x+2, x+4, x+6, x+8. S o l u t i o n : We have to find the mean of , and . They are 5 in numbers. Remember the definition of mean of n values x 1 , x 2 … x n is Page 3 Q u e s t i o n : 1 If the height of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm respectively, find the mean height. S o l u t i o n : Given that the heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm, respectively. We have to find the mean of their heights. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean height of the 5 persons is Q u e s t i o n : 2 Find the mean of 994, 996, 998, 1002, 1000. S o l u t i o n : The given 5 numbers are 994, 996, 998, 1002 and 1000, respectively. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the given 5 numbers is Q u e s t i o n : 3 Find the mean of first five natural numbers. S o l u t i o n : The first 5 natural numbers are 1, 2, 3, 4 and 5. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 5 natural numbers is Q u e s t i o n : 4 Find the mean of all factors of 10. S o l u t i o n : All the factors of 10 are 1, 2, 5, and 10. They are 4 in numbers. We have to find the mean of the all factors of 10. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the all factors of 10 is Q u e s t i o n : 5 Find the mean of first 10 even natural numbers. S o l u t i o n : The first 10 even natural numbers are 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20. They are 10 in numbers. We have to find the mean of the first 10 even natural numbers. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 10 even natural numbers is Q u e s t i o n : 6 Find the mean of x, x+2, x+4, x+6, x+8. S o l u t i o n : We have to find the mean of , and . They are 5 in numbers. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the required mean is Q u e s t i o n : 7 Find the mean of first five multiples of 3. S o l u t i o n : The first five multiples of 3 are 3, 6, 9, 12, and 15. They are 5 in numbers. We have to find the mean of first five multiples of 3. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of first five multiples of 3 is Q u e s t i o n : 8 Following are the weights inkg of 10 new born babies in a hospital on a particular day: 3.4, 3.6, 4.2, 4.5, 3.9, 4.1, 3.8, 4.5, 4.4, 3.6. Find the mean X. S o l u t i o n : The weights inkg of 10 new born babies are 3.4, 3.6, 4.2, 4.5, 3.9, 4.1, 3.8, 4.5, 4.4, and 3.6. These are 10 in numbers. We have to find the mean of their weights. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of their weights is Q u e s t i o n : 9 Page 4 Q u e s t i o n : 1 If the height of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm respectively, find the mean height. S o l u t i o n : Given that the heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm, respectively. We have to find the mean of their heights. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean height of the 5 persons is Q u e s t i o n : 2 Find the mean of 994, 996, 998, 1002, 1000. S o l u t i o n : The given 5 numbers are 994, 996, 998, 1002 and 1000, respectively. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the given 5 numbers is Q u e s t i o n : 3 Find the mean of first five natural numbers. S o l u t i o n : The first 5 natural numbers are 1, 2, 3, 4 and 5. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 5 natural numbers is Q u e s t i o n : 4 Find the mean of all factors of 10. S o l u t i o n : All the factors of 10 are 1, 2, 5, and 10. They are 4 in numbers. We have to find the mean of the all factors of 10. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the all factors of 10 is Q u e s t i o n : 5 Find the mean of first 10 even natural numbers. S o l u t i o n : The first 10 even natural numbers are 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20. They are 10 in numbers. We have to find the mean of the first 10 even natural numbers. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 10 even natural numbers is Q u e s t i o n : 6 Find the mean of x, x+2, x+4, x+6, x+8. S o l u t i o n : We have to find the mean of , and . They are 5 in numbers. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the required mean is Q u e s t i o n : 7 Find the mean of first five multiples of 3. S o l u t i o n : The first five multiples of 3 are 3, 6, 9, 12, and 15. They are 5 in numbers. We have to find the mean of first five multiples of 3. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of first five multiples of 3 is Q u e s t i o n : 8 Following are the weights inkg of 10 new born babies in a hospital on a particular day: 3.4, 3.6, 4.2, 4.5, 3.9, 4.1, 3.8, 4.5, 4.4, 3.6. Find the mean X. S o l u t i o n : The weights inkg of 10 new born babies are 3.4, 3.6, 4.2, 4.5, 3.9, 4.1, 3.8, 4.5, 4.4, and 3.6. These are 10 in numbers. We have to find the mean of their weights. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of their weights is Q u e s t i o n : 9 The percentage of marks obtained by students of a class in mathematics are : 64, 36, 47, 23, 0, 19, 81, 93, 72, 35, 3, 1. Find their mean. S o l u t i o n : Given that the percentage of marks obtained by students of a class of mathematics are 64, 36, 47, 23, 0, 19, 81, 93, 72, 35, 3, and 1. These are 12 in numbers. We have to find the mean of their percentage of marks. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of their weights is Q u e s t i o n : 1 0 The number of children in 10 families of a locality are: 2, 4, 3, 4, 2, 0, 3, 5, 1, 1, 5. Find the mean number of children per family. S o l u t i o n : Given that the numbers of children in 10 families are 2, 4, 3, 4, 2, 3, 5, 1, 1, and 5. We have to find the mean number of children per family. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean number of children per family is Q u e s t i o n : 1 1 Explain, by taking a suitable example, how the arithmetic mean alters by i adding a constant k to each term, ii subtracting a constant k from each them, iii multiplying each term by a constant k and iv dividing each term by a non-zero constant k. S o l u t i o n : Let us take n observations . If be the mean of the n observations, then we have Page 5 Q u e s t i o n : 1 If the height of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm respectively, find the mean height. S o l u t i o n : Given that the heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm, respectively. We have to find the mean of their heights. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean height of the 5 persons is Q u e s t i o n : 2 Find the mean of 994, 996, 998, 1002, 1000. S o l u t i o n : The given 5 numbers are 994, 996, 998, 1002 and 1000, respectively. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the given 5 numbers is Q u e s t i o n : 3 Find the mean of first five natural numbers. S o l u t i o n : The first 5 natural numbers are 1, 2, 3, 4 and 5. We have to find their mean. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 5 natural numbers is Q u e s t i o n : 4 Find the mean of all factors of 10. S o l u t i o n : All the factors of 10 are 1, 2, 5, and 10. They are 4 in numbers. We have to find the mean of the all factors of 10. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the all factors of 10 is Q u e s t i o n : 5 Find the mean of first 10 even natural numbers. S o l u t i o n : The first 10 even natural numbers are 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20. They are 10 in numbers. We have to find the mean of the first 10 even natural numbers. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of the first 10 even natural numbers is Q u e s t i o n : 6 Find the mean of x, x+2, x+4, x+6, x+8. S o l u t i o n : We have to find the mean of , and . They are 5 in numbers. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the required mean is Q u e s t i o n : 7 Find the mean of first five multiples of 3. S o l u t i o n : The first five multiples of 3 are 3, 6, 9, 12, and 15. They are 5 in numbers. We have to find the mean of first five multiples of 3. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of first five multiples of 3 is Q u e s t i o n : 8 Following are the weights inkg of 10 new born babies in a hospital on a particular day: 3.4, 3.6, 4.2, 4.5, 3.9, 4.1, 3.8, 4.5, 4.4, 3.6. Find the mean X. S o l u t i o n : The weights inkg of 10 new born babies are 3.4, 3.6, 4.2, 4.5, 3.9, 4.1, 3.8, 4.5, 4.4, and 3.6. These are 10 in numbers. We have to find the mean of their weights. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of their weights is Q u e s t i o n : 9 The percentage of marks obtained by students of a class in mathematics are : 64, 36, 47, 23, 0, 19, 81, 93, 72, 35, 3, 1. Find their mean. S o l u t i o n : Given that the percentage of marks obtained by students of a class of mathematics are 64, 36, 47, 23, 0, 19, 81, 93, 72, 35, 3, and 1. These are 12 in numbers. We have to find the mean of their percentage of marks. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean of their weights is Q u e s t i o n : 1 0 The number of children in 10 families of a locality are: 2, 4, 3, 4, 2, 0, 3, 5, 1, 1, 5. Find the mean number of children per family. S o l u t i o n : Given that the numbers of children in 10 families are 2, 4, 3, 4, 2, 3, 5, 1, 1, and 5. We have to find the mean number of children per family. Remember the definition of mean of n values x 1 , x 2 … x n is Therefore the mean number of children per family is Q u e s t i o n : 1 1 Explain, by taking a suitable example, how the arithmetic mean alters by i adding a constant k to each term, ii subtracting a constant k from each them, iii multiplying each term by a constant k and iv dividing each term by a non-zero constant k. S o l u t i o n : Let us take n observations . If be the mean of the n observations, then we have i Add a constant k to each of the observations. Then the observations becomes If be the mean of the new observations, then we have Let us take an example to understand the above fact. The first 5 natural numbers are 1, 2, 3, 4, and 5. Their mean is Add 2 to each of the numbers. Then the numbers becomes 3, 4, 5, 6, and 7. The new mean is Therefore adding a constant number to each observation the mean increased by that constant ii Subtract a constant k from each of the observations. Then the observations becomes If be the mean of the new observations, then we have Let us take an example to understand the above fact. The first 5 even natural numbers are 2, 4, 6, 8 and 10. Their mean is Subtract 1 from each of the numbers. Then the numbers becomes 1, 3, 5, 7, and 9. The new mean isRead More
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