RD Sharma Solutions for Class 8 Math Chapter 7 - Factorization (Part-6) Class 8 Notes | EduRev

RD Sharma Solutions for Class 8 Mathematics

Created by: Abhishek Kapoor

Class 8 : RD Sharma Solutions for Class 8 Math Chapter 7 - Factorization (Part-6) Class 8 Notes | EduRev

The document RD Sharma Solutions for Class 8 Math Chapter 7 - Factorization (Part-6) Class 8 Notes | EduRev is a part of the Class 8 Course RD Sharma Solutions for Class 8 Mathematics.
All you need of Class 8 at this link: Class 8

Question 1: Factorize each of the following algebraic expression:
4x2 + 12xy +9y2
Answer 1: 4x2+12xy+9y2 

=(2x)2+2×2x×3y+(3y)2 
=(2x+3y)2 
=(2x+3y)(2x+3y) 
Question 2: Factorize each of the following algebraic expression:
9a2 − 24ab + 16b2
Answer 2: 9a224ab+16b2 

=(3a)22×3a×4b+(4b)2 
=(3a4b)2 
=(3a4b)(3a4b) 
Question 3: Factorize each of the following algebraic expression:
p2q2 − 6pqr + 9r2
Answer 3:
p2q2−6pqr+9r2 
=(pq)22×pq×3r+(3r)2 
=(pq3r)2 
=(pq3r)(pq3r) 
Question 4: Factorize each of the following algebraic expression:
36a2 + 36a + 9
Answer 4: 36a2+36a+9 

=9(4a2+4a+1) 
=9{(2a)2+2×2a×1+12} 
=9(2a+1)2 
=9(2a+1)(2a+1) 
Question 5: Factorize each of the following algebraic expression:
a2 + 2ab + b2 − 16
Answer 5: a2+2ab+b216 

=a2+2×a×b+b216 
=(a+b)242 
=(a+b4)(a+b+4) 
Question 6: Factorize each of the following algebraic expression:
9z2x2 + 4xy − 4y2
Answer 6: 9z2x2+4xy4y2 

=9z2(x24xy+4y2) 
=9z2[x22×x×2y+(2y)2] 
=(3z)2(x2y)2 
=[3z−(x−2y)][3z+(x−2y)]
=(3zx+2y)(3z+x2y)=(x2y+3z)(x+2y+3z)
Question 7: Factorize each of the following algebraic expression:
9a4 − 24a2b2 + 16b4 − 256
Answer 7: 9a424a2b2+16b4256 

=(9a424a2b2+16b4)256 
=[(3a2)22×3a2×4b2+(4b2)2]162 
=(3a24b2)2162 
=[(3a24b2)16][(3a24b2)+16] 
=(3a24b216)(3a24b2+16) 
Question 8: Factorize each of the following algebraic expression:
16 − a6 + 4a3b3 − 4b6
Answer 8: 16a6+4a3b34b6 

=16(a64a3b3+4b6) 
=42[(a3)22×a3×2b3+(2b3)2] 
=42(a32b3)2 
=[4(a32b3)][4+(