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(i) 3

(ii) 10

(iii) 5

(iv)

(v)

Answer 1:

(3x+10)

Therefore, quotient=3x+10 and remainder=25. (ii)

=(2xâˆ’1/5)+

Therefore,

quotient =2xâˆ’1/5 and remainder=47/5.

(iii)

=(y

Therefore,

Therefore, quotient = x3+5 and remainder = 5.

(v)

=(y

Therefore, quotient = y2+3 and remainder = 6.

(i)

(ii)

(iii) 4

(iv) 4 âˆ’

(v) 2

(vi) 4

Answer 2:

(i)

=(2x+3)

âˆµ Remainder=1

Therefore, (x+1) is not a factor of 2x2+5x+4

(ii)

=(3y2+11y+27)+ 56/y-2

âˆµ Remainder = 56

âˆ´ (yâˆ’2) is not a factor of 3y^{3}+5y^{2}+5y+2.

(iii)

=(x2+3

)

âˆµ Remainder = 30

Therefore, (4x^{2}âˆ’5) is not a factor of 4x^{4}+7x^{2}+15

(iv)

=1âˆ’3z

âˆµ Remainder = 0

âˆ´ (4âˆ’z) is a factor of 3z^{2}âˆ’13z+4.

(v)

=(5a+3)+

âˆµ Remainder = 4

âˆ´ ( 2aâˆ’3) is not a factor of 10a^{2}âˆ’9aâˆ’5.

(vi)

=(2yâˆ’1)

âˆµ Remainder = 2

âˆ´ (4y+1) is not a factor of 8y^{2}âˆ’2y+1.**Question 3: Divide:x^{2} âˆ’ 5x + 6 by x âˆ’ 3Answer 3: **

**= xâˆ’2 ****Question 4: Divide:ax^{2} âˆ’ ay^{2} by ax + ayAnswer 4:**

Answer 5:

Answer 6:

**= cx+d ****Question 7: Divide:(a^{2} + 2ab + b^{2}) âˆ’ (a^{2} + 2ac + c^{2}) by 2a + b + cAnswer 7: **

=bâˆ’c **Question 8: ****Divide:**** **

Answer 8: **=1/2 x+3**

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