Class 9 Exam > Class 9 Notes > Mathematics (Maths) Class 9 > RS Aggarwal MCQs: Lines and Angles
RS Aggarwal MCQs: Lines and Angles | Mathematics (Maths) Class 9 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
?
Question:53
If one angle of a triangle is equal to the sum of the other two angles, then the triangle is
a
an isosceles triangle
b
an obtuse triangle
c
an equilateral triangle
d
a right triangle
Solution:
Let ?ABC be such that ?A = ?B + ?C.
In ?ABC,
?A + ?B + ?C = 180º Anglesumproperty
? ?A + ?A = 180º ?A = ?B + ?C
? 2 ?A = 180º
? ?A = 90º
Therefore, ?ABC is a right triangle.
Thus, if one angle of a triangle is equal to the sum of the other two angles, then the triangle is a right triangle.
Hence, the correct answer is option d
.
Question:54
An exterior angle of a triangle is 110° and its two interior opposite angles are equal. Each of these equal angles is
a
70°
b
55°
c
35°
d
27
1°
2
Solution:
Let the measure of each of the two equal interior opposite angles of the triangle be x.
In a triangle, the exterior angle is equal to the sum of the two interior opposite angles.
? x + x = 110°
Page 2
?
Question:53
If one angle of a triangle is equal to the sum of the other two angles, then the triangle is
a
an isosceles triangle
b
an obtuse triangle
c
an equilateral triangle
d
a right triangle
Solution:
Let ?ABC be such that ?A = ?B + ?C.
In ?ABC,
?A + ?B + ?C = 180º Anglesumproperty
? ?A + ?A = 180º ?A = ?B + ?C
? 2 ?A = 180º
? ?A = 90º
Therefore, ?ABC is a right triangle.
Thus, if one angle of a triangle is equal to the sum of the other two angles, then the triangle is a right triangle.
Hence, the correct answer is option d
.
Question:54
An exterior angle of a triangle is 110° and its two interior opposite angles are equal. Each of these equal angles is
a
70°
b
55°
c
35°
d
27
1°
2
Solution:
Let the measure of each of the two equal interior opposite angles of the triangle be x.
In a triangle, the exterior angle is equal to the sum of the two interior opposite angles.
? x + x = 110°
? 2x = 110°
? x = 55°
Thus, the measure of each of these equal angles is 55°.
Hence, the correct answer is option b
.
Question:55
The angles of a triangle are in the ration 3 : 5 : 7. The triangle is
a acute-angled
b obtuse-angled
c right-angled
d an isosceles triangle
Solution:
a acute-angled
Let the angles measure (3x)°, (5x)° and (7x)°
.
Then,
3x +5x +7x = 180° ? 15x = 180° ? x = 12°
Therefore, the angles are 3(12)° = 36°, 5(12)° = 60° and 7(12)° = 84°
.
Hence, the triangle is acute-angled.
Question:56
If one of the angles of a triangle is 130° then the angle between the bisectors of the other two angles can be
a
50°
b
65°
c
90°
d
155°
Solution:
Let ?ABC be such that ?A = 130°.
Here, BP is the bisector of ?B and CP is the bisector of ?C.
? ?ABP = ?PBC =
1
2
?B .....1
Also, ?ACP = ?PCB =
1
2
?C .....2
In ?ABC,
?A + ?B + ?C = 180° Anglesumproperty
? 130° + ?B + ?C = 180°
? ?B + ?C = 180° - 130° = 50°
?
1
2
?B +
1
2
?C =
1
2
× 50° = 25°
? ?PBC + ?PCB = 25° .....3
Using(1)and(2)
In ?PBC,
?PBC + ?PCB + ?BPC = 180° Anglesumproperty
? 25° + ?BPC = 180°
Page 3
?
Question:53
If one angle of a triangle is equal to the sum of the other two angles, then the triangle is
a
an isosceles triangle
b
an obtuse triangle
c
an equilateral triangle
d
a right triangle
Solution:
Let ?ABC be such that ?A = ?B + ?C.
In ?ABC,
?A + ?B + ?C = 180º Anglesumproperty
? ?A + ?A = 180º ?A = ?B + ?C
? 2 ?A = 180º
? ?A = 90º
Therefore, ?ABC is a right triangle.
Thus, if one angle of a triangle is equal to the sum of the other two angles, then the triangle is a right triangle.
Hence, the correct answer is option d
.
Question:54
An exterior angle of a triangle is 110° and its two interior opposite angles are equal. Each of these equal angles is
a
70°
b
55°
c
35°
d
27
1°
2
Solution:
Let the measure of each of the two equal interior opposite angles of the triangle be x.
In a triangle, the exterior angle is equal to the sum of the two interior opposite angles.
? x + x = 110°
? 2x = 110°
? x = 55°
Thus, the measure of each of these equal angles is 55°.
Hence, the correct answer is option b
.
Question:55
The angles of a triangle are in the ration 3 : 5 : 7. The triangle is
a acute-angled
b obtuse-angled
c right-angled
d an isosceles triangle
Solution:
a acute-angled
Let the angles measure (3x)°, (5x)° and (7x)°
.
Then,
3x +5x +7x = 180° ? 15x = 180° ? x = 12°
Therefore, the angles are 3(12)° = 36°, 5(12)° = 60° and 7(12)° = 84°
.
Hence, the triangle is acute-angled.
Question:56
If one of the angles of a triangle is 130° then the angle between the bisectors of the other two angles can be
a
50°
b
65°
c
90°
d
155°
Solution:
Let ?ABC be such that ?A = 130°.
Here, BP is the bisector of ?B and CP is the bisector of ?C.
? ?ABP = ?PBC =
1
2
?B .....1
Also, ?ACP = ?PCB =
1
2
?C .....2
In ?ABC,
?A + ?B + ?C = 180° Anglesumproperty
? 130° + ?B + ?C = 180°
? ?B + ?C = 180° - 130° = 50°
?
1
2
?B +
1
2
?C =
1
2
× 50° = 25°
? ?PBC + ?PCB = 25° .....3
Using(1)and(2)
In ?PBC,
?PBC + ?PCB + ?BPC = 180° Anglesumproperty
? 25° + ?BPC = 180°
Using(3)
? ?BPC = 180° - 25° = 155°
Thus, if one of the angles of a triangle is 130° then the angle between the bisectors of the other two angles is 155°.
Hence, the correct answer is option d
.
Question:57
In the given figure, AOB is a straight line. The value of x is
a
12
b
15
c
20
d
25
Solution:
It is given that, AOB is a straight line.
? 60º + (5xº + 3xº) = 180º Linearpair
? 8xº = 180º - 60º = 120º
? xº = 15º
Thus, the value of x is 15.
Hence, the correct answer is option b
.
Question:58
The angles of a triangle are in the ratio 2 : 3 : 4. The largest angle of the triangle is
a
12°
b
100°
c
80°
d
60°
Solution:
Suppose ?ABC be such that ?A : ?B : ?C = 2 : 3 : 4.
Let ?A = 2k, ?B = 3k and ?C = 4k, where k is some constant.
In ?ABC,
?A + ?B + ?C = 180º Anglesumproperty
? 2k + 3k + 4k = 180º
? 9k = 180º
? k = 20º
? Measure of the largest angle = 4k = 4 × 20º = 80º
Hence, the correct answer is option c
.
Question:59
In the given figure, ?OAB = 110° and ?BCD = 130° then ?ABC is equal to
a
40°
b
50°
c
60°
Page 4
?
Question:53
If one angle of a triangle is equal to the sum of the other two angles, then the triangle is
a
an isosceles triangle
b
an obtuse triangle
c
an equilateral triangle
d
a right triangle
Solution:
Let ?ABC be such that ?A = ?B + ?C.
In ?ABC,
?A + ?B + ?C = 180º Anglesumproperty
? ?A + ?A = 180º ?A = ?B + ?C
? 2 ?A = 180º
? ?A = 90º
Therefore, ?ABC is a right triangle.
Thus, if one angle of a triangle is equal to the sum of the other two angles, then the triangle is a right triangle.
Hence, the correct answer is option d
.
Question:54
An exterior angle of a triangle is 110° and its two interior opposite angles are equal. Each of these equal angles is
a
70°
b
55°
c
35°
d
27
1°
2
Solution:
Let the measure of each of the two equal interior opposite angles of the triangle be x.
In a triangle, the exterior angle is equal to the sum of the two interior opposite angles.
? x + x = 110°
? 2x = 110°
? x = 55°
Thus, the measure of each of these equal angles is 55°.
Hence, the correct answer is option b
.
Question:55
The angles of a triangle are in the ration 3 : 5 : 7. The triangle is
a acute-angled
b obtuse-angled
c right-angled
d an isosceles triangle
Solution:
a acute-angled
Let the angles measure (3x)°, (5x)° and (7x)°
.
Then,
3x +5x +7x = 180° ? 15x = 180° ? x = 12°
Therefore, the angles are 3(12)° = 36°, 5(12)° = 60° and 7(12)° = 84°
.
Hence, the triangle is acute-angled.
Question:56
If one of the angles of a triangle is 130° then the angle between the bisectors of the other two angles can be
a
50°
b
65°
c
90°
d
155°
Solution:
Let ?ABC be such that ?A = 130°.
Here, BP is the bisector of ?B and CP is the bisector of ?C.
? ?ABP = ?PBC =
1
2
?B .....1
Also, ?ACP = ?PCB =
1
2
?C .....2
In ?ABC,
?A + ?B + ?C = 180° Anglesumproperty
? 130° + ?B + ?C = 180°
? ?B + ?C = 180° - 130° = 50°
?
1
2
?B +
1
2
?C =
1
2
× 50° = 25°
? ?PBC + ?PCB = 25° .....3
Using(1)and(2)
In ?PBC,
?PBC + ?PCB + ?BPC = 180° Anglesumproperty
? 25° + ?BPC = 180°
Using(3)
? ?BPC = 180° - 25° = 155°
Thus, if one of the angles of a triangle is 130° then the angle between the bisectors of the other two angles is 155°.
Hence, the correct answer is option d
.
Question:57
In the given figure, AOB is a straight line. The value of x is
a
12
b
15
c
20
d
25
Solution:
It is given that, AOB is a straight line.
? 60º + (5xº + 3xº) = 180º Linearpair
? 8xº = 180º - 60º = 120º
? xº = 15º
Thus, the value of x is 15.
Hence, the correct answer is option b
.
Question:58
The angles of a triangle are in the ratio 2 : 3 : 4. The largest angle of the triangle is
a
12°
b
100°
c
80°
d
60°
Solution:
Suppose ?ABC be such that ?A : ?B : ?C = 2 : 3 : 4.
Let ?A = 2k, ?B = 3k and ?C = 4k, where k is some constant.
In ?ABC,
?A + ?B + ?C = 180º Anglesumproperty
? 2k + 3k + 4k = 180º
? 9k = 180º
? k = 20º
? Measure of the largest angle = 4k = 4 × 20º = 80º
Hence, the correct answer is option c
.
Question:59
In the given figure, ?OAB = 110° and ?BCD = 130° then ?ABC is equal to
a
40°
b
50°
c
60°
d
70°
Solution:
In the given figure, OA || CD.
Construction: Extend OA such that it intersects BC at E.
Now, OE || CD and BC is a transversal.
? ?AEC = ?BCD = 130° Pairofcorrespondingangles
Also, ?OAB + ?BAE = 180° Linearpair
? 110° + ?BAE = 180°
? ?BAE = 180° - 110° = 70°
In ?ABE,
?AEC = ?BAE + ?ABE Inatriangle, exteriorangleisequaltothesumoftwooppositeinteriorangles
? 130° = 70° + x°
? x° = 130° - 70° = 60°
Thus, the measure of angle ?ABC is 60°.
Hence, the correct answer is option c
.
Question:60
If two angles are complements of each other, then each angle is
a
an acute angle
b
an obtuse angle
c
a right angle
d
a reflex angle
Solution:
a
an acute angle
If two angles are complements of each other, that is, the sum of their measures is 90°
, then each angle is an acute angle.
Question:61
An angle which measures more than 180° but less than 360°, is called
a
an acute angle
b
an obtuse angle
c
a straight angle
d
a reflex angle
Solution:
An angle which measures more than 180° but less than 360° is called a reflex angle.
Hence, the correct answer is option d
.
Question:62
The measure of an angle is five times its complement. The angle measures
a
25°
b
35°
c
65°
d
75°
Solution:
d
75°
Page 5
?
Question:53
If one angle of a triangle is equal to the sum of the other two angles, then the triangle is
a
an isosceles triangle
b
an obtuse triangle
c
an equilateral triangle
d
a right triangle
Solution:
Let ?ABC be such that ?A = ?B + ?C.
In ?ABC,
?A + ?B + ?C = 180º Anglesumproperty
? ?A + ?A = 180º ?A = ?B + ?C
? 2 ?A = 180º
? ?A = 90º
Therefore, ?ABC is a right triangle.
Thus, if one angle of a triangle is equal to the sum of the other two angles, then the triangle is a right triangle.
Hence, the correct answer is option d
.
Question:54
An exterior angle of a triangle is 110° and its two interior opposite angles are equal. Each of these equal angles is
a
70°
b
55°
c
35°
d
27
1°
2
Solution:
Let the measure of each of the two equal interior opposite angles of the triangle be x.
In a triangle, the exterior angle is equal to the sum of the two interior opposite angles.
? x + x = 110°
? 2x = 110°
? x = 55°
Thus, the measure of each of these equal angles is 55°.
Hence, the correct answer is option b
.
Question:55
The angles of a triangle are in the ration 3 : 5 : 7. The triangle is
a acute-angled
b obtuse-angled
c right-angled
d an isosceles triangle
Solution:
a acute-angled
Let the angles measure (3x)°, (5x)° and (7x)°
.
Then,
3x +5x +7x = 180° ? 15x = 180° ? x = 12°
Therefore, the angles are 3(12)° = 36°, 5(12)° = 60° and 7(12)° = 84°
.
Hence, the triangle is acute-angled.
Question:56
If one of the angles of a triangle is 130° then the angle between the bisectors of the other two angles can be
a
50°
b
65°
c
90°
d
155°
Solution:
Let ?ABC be such that ?A = 130°.
Here, BP is the bisector of ?B and CP is the bisector of ?C.
? ?ABP = ?PBC =
1
2
?B .....1
Also, ?ACP = ?PCB =
1
2
?C .....2
In ?ABC,
?A + ?B + ?C = 180° Anglesumproperty
? 130° + ?B + ?C = 180°
? ?B + ?C = 180° - 130° = 50°
?
1
2
?B +
1
2
?C =
1
2
× 50° = 25°
? ?PBC + ?PCB = 25° .....3
Using(1)and(2)
In ?PBC,
?PBC + ?PCB + ?BPC = 180° Anglesumproperty
? 25° + ?BPC = 180°
Using(3)
? ?BPC = 180° - 25° = 155°
Thus, if one of the angles of a triangle is 130° then the angle between the bisectors of the other two angles is 155°.
Hence, the correct answer is option d
.
Question:57
In the given figure, AOB is a straight line. The value of x is
a
12
b
15
c
20
d
25
Solution:
It is given that, AOB is a straight line.
? 60º + (5xº + 3xº) = 180º Linearpair
? 8xº = 180º - 60º = 120º
? xº = 15º
Thus, the value of x is 15.
Hence, the correct answer is option b
.
Question:58
The angles of a triangle are in the ratio 2 : 3 : 4. The largest angle of the triangle is
a
12°
b
100°
c
80°
d
60°
Solution:
Suppose ?ABC be such that ?A : ?B : ?C = 2 : 3 : 4.
Let ?A = 2k, ?B = 3k and ?C = 4k, where k is some constant.
In ?ABC,
?A + ?B + ?C = 180º Anglesumproperty
? 2k + 3k + 4k = 180º
? 9k = 180º
? k = 20º
? Measure of the largest angle = 4k = 4 × 20º = 80º
Hence, the correct answer is option c
.
Question:59
In the given figure, ?OAB = 110° and ?BCD = 130° then ?ABC is equal to
a
40°
b
50°
c
60°
d
70°
Solution:
In the given figure, OA || CD.
Construction: Extend OA such that it intersects BC at E.
Now, OE || CD and BC is a transversal.
? ?AEC = ?BCD = 130° Pairofcorrespondingangles
Also, ?OAB + ?BAE = 180° Linearpair
? 110° + ?BAE = 180°
? ?BAE = 180° - 110° = 70°
In ?ABE,
?AEC = ?BAE + ?ABE Inatriangle, exteriorangleisequaltothesumoftwooppositeinteriorangles
? 130° = 70° + x°
? x° = 130° - 70° = 60°
Thus, the measure of angle ?ABC is 60°.
Hence, the correct answer is option c
.
Question:60
If two angles are complements of each other, then each angle is
a
an acute angle
b
an obtuse angle
c
a right angle
d
a reflex angle
Solution:
a
an acute angle
If two angles are complements of each other, that is, the sum of their measures is 90°
, then each angle is an acute angle.
Question:61
An angle which measures more than 180° but less than 360°, is called
a
an acute angle
b
an obtuse angle
c
a straight angle
d
a reflex angle
Solution:
An angle which measures more than 180° but less than 360° is called a reflex angle.
Hence, the correct answer is option d
.
Question:62
The measure of an angle is five times its complement. The angle measures
a
25°
b
35°
c
65°
d
75°
Solution:
d
75°
Let the measure of the required angle be x°
.
Then, the measure of its complement will be (90 -x)°
.
? x = 5(90 -x) ? x = 450 -5x ? 6x = 450 ? x = 75
Question:63
Two complementary angles are such that twice the measure of one is equal to three times the measure of the other. The measure of larger angle is
a
72°
b
54°
c
63°
d
36°
Solution:
b
54°
Let the measure of the required angle be x°
.
Then, the measure of its complement will be(90 -x)°
.
? 2x = 3(90 -x) ? 2x = 270 -3x ? 5x = 270 ? x = 54
Question:64
In the given figure, AOB is a straight line. If ?AOC = 4x° and ?BOC = 5x°, then ?AOC = ?
a
40°
b
60°
c
80°
d
100°
Solution:
c
80°
We have :
?AOC + ?BOC = 180° [Since AOB is a straight line] ? 4x +5x = 180° ? 9x = 180° ? x = 20° ? ?AOC = 4 ×20° = 80°
Question:65
In the given figure, AOB is a straight line. If ?AOC = (3x + 10)° and ?BOC (4x - 26)°, then ?BOC = ?
a
96°
b
86°
c
76°
d
106°
Solution:
b
86°
We have :
?AOC + ?BOC = 180° [Since AOB is a straight line ] ? 3x +10 +4x -26 = 180° ? 7x = 196° ? x = 28°
? ?BOC = [4 ×28 -26]
°
Hence, ?BOC = 86°.
Question:66
In the given figure, AOB is a straight line. If ?AOC = (3x - 10)°, ?COD = 50° and ?BOD = (x + 20)°, then ?AOC = ?
a 40°
b 60°
c 80°
d 50°
Solution:
c 80°
We have :
?AOC + ?COD + ?BOD = 180° [Since AOB is a straight line ] ? 3x -10 +50 +x +20 = 180 ? 4x = 120 ? x = 30
Read More
|
44 videos|412 docs|55 tests
|
Related Exams
About this Document
|
4.93/5 Rating |
|
Nov 24, 2024 Last updated |
Document Description: RS Aggarwal MCQs: Lines and Angles for Class 9 2024 is part of Mathematics (Maths) Class 9 preparation.
The notes and questions for RS Aggarwal MCQs: Lines and Angles have been prepared according to the Class 9 exam syllabus. Information about RS Aggarwal MCQs: Lines and Angles covers topics
like and RS Aggarwal MCQs: Lines and Angles Example, for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RS Aggarwal MCQs: Lines and Angles.
Introduction of RS Aggarwal MCQs: Lines and Angles in English is available as part of our Mathematics (Maths) Class 9
for Class 9 & RS Aggarwal MCQs: Lines and Angles in Hindi for Mathematics (Maths) Class 9 course.
Download more important topics related with notes, lectures and mock test series for Class 9
Exam by signing up for free. Class 9: RS Aggarwal MCQs: Lines and Angles | Mathematics (Maths) Class 9
Description
Full syllabus notes, lecture & questions for RS Aggarwal MCQs: Lines and Angles | Mathematics (Maths) Class 9 - Class 9 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 9 | Best notes, free PDF download
Information about RS Aggarwal MCQs: Lines and Angles
In this doc you can find the meaning of RS Aggarwal MCQs: Lines and Angles defined & explained in the simplest way possible. Besides explaining types of
RS Aggarwal MCQs: Lines and Angles theory, EduRev gives you an ample number of questions to practice RS Aggarwal MCQs: Lines and Angles tests, examples and also practice Class 9
tests
|
Explore Courses for Class 9 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
mock tests for examination
,study material
,Semester Notes
,RS Aggarwal MCQs: Lines and Angles | Mathematics (Maths) Class 9
,practice quizzes
,ppt
,Free
,Objective type Questions
,video lectures
,Summary
,Sample Paper
,past year papers
,RS Aggarwal MCQs: Lines and Angles | Mathematics (Maths) Class 9
,shortcuts and tricks
,Exam
,MCQs
,Extra Questions
,Important questions
,RS Aggarwal MCQs: Lines and Angles | Mathematics (Maths) Class 9
,Viva Questions
,Previous Year Questions with Solutions
;
Additional Information about RS Aggarwal MCQs: Lines and Angles for Class 9 Preparation
RS Aggarwal MCQs: Lines and Angles Free PDF Download
The RS Aggarwal MCQs: Lines and Angles is an invaluable resource that delves deep into the core of the Class 9 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the RS Aggarwal MCQs: Lines and Angles now and kickstart your journey towards success in the Class 9 exam.
Importance of RS Aggarwal MCQs: Lines and Angles
The importance of RS Aggarwal MCQs: Lines and Angles cannot be overstated, especially for Class 9 aspirants.
This document holds the key to success in the Class 9 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
RS Aggarwal MCQs: Lines and Angles Notes
RS Aggarwal MCQs: Lines and Angles Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to RS Aggarwal MCQs: Lines and Angles.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, RS Aggarwal MCQs: Lines and Angles Notes on EduRev are your ultimate resource for success.
RS Aggarwal MCQs: Lines and Angles Class 9 Questions
The "RS Aggarwal MCQs: Lines and Angles Class 9 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 9 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RS Aggarwal MCQs: Lines and Angles on the App
Students of Class 9 can study RS Aggarwal MCQs: Lines and Angles alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the RS Aggarwal MCQs: Lines and Angles,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of RS Aggarwal MCQs: Lines and Angles is prepared as per the latest Class 9 syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup