The document RS Aggarwal Solutions: Whole Numbers Exercise - 3C Notes | EduRev is a part of the Class 6 Course Mathematics (Maths) Class 6.

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**Q.1. Perform the following subtractions. ****Check your results by the****corresponding ****additions :****(i) 6237 – 694****(ii) 21205 – 10899****(iii) 100000 – 78987****(iv) 1010101 – 656565****Ans.****(i)****(ii)****(iii)****(iv)****Q.2. Replace each * by the correct digit in each of the following :****(i)****(ii)****(iii)****(iv)****Ans.****(i)****(ii)****(iii)****(iv)****Q.3. Find the difference :****(i) 463 – 9****(ii) 5632 – 99****(iii) 8640 – 999****(iv) 13006 – 9999****Ans. ****(i)** 463 – 9 = 464 – 1 – 9 = 464 – 10

= 454**(ii) **5632 – 99 = 5632 – 100 + 1

= 5633 – 100 = 5533**(iii)** 8640 – 999 = 8640 – 1000 + 1

= 8641 – 1000 = 7641**(iv)** 13006 – 9999 = 13006 – 10000 + 1

= 13007 – 10000 = 12007**Q.4. Find the difference between the smallest number of 7 digits and the largest number of 4 digits.****Ans. **Smallest number of 7-digits = 1000000

Largest number of 4-digits = 9999

Required difference = (1000000 – 9999)

= 990001**Q.5. Ravi opened his account in a bank by depositing Rs. 136000. Next day he**

**withdrew Rs. 73129 from it. How much money was let in his account ?****Ans.** Deposit in the beginning = Rs. 136000

Next day withdrew = Rs. 73129

∴ Amount left in the bank account

= Rs. 136000 – 73129 = Rs. 62871**Q.6. Mrs Saxena withdrew Rs. 100000 from her bank account. She purchased a TV**

**set for Rs. 38750, a refrigerator for Rs. 23890 and jewellery worth Rs. 35560. How much money was left with her ?****Ans.** Amount withdrawn from the bank

= Rs. 1,00,000

Cost of TV set = Rs. 38750

Cost of refrigerator = Rs. 23890

Cost of jewellery = Rs. 35560

Total amount spent on her purchase

= Rs. (38750 + 23890 + 35560)

= Rs. 98200

Amount left with her = Rs. 1,00,000 –

Rs. 98200 = Rs. 1800**Q.7. The population of a town was 110500. In one year it increased by 3608 due to new births. However 8973 persons died or left the town during the year. What was the ****population at the end of the year?****Ans. **Population of a town = 110500

Increase in 1 year = 3608

Persons left or died = 8973

∴ The population at the end of year

= 110500 + 3608 – 8973

= 114108 – 8973 = 105135**Q.8. Find the whole number n when :****(i) n + 4 = 9**

**(ii) n + 35 = 101****(iii) n – 18 = 39****(iv) n – 20568 = 21403****Ans.** (i) We have n + 4 = 9

n = 9 – 4 = 5

∴ n = 5**(ii)** n + 35 = 101

Subtracting 35 from both sides

n + 35 – 35 = 101 – 35 ⇒ n = 66

∴ n = 66**(iii)** n – 18 = 39

Adding 18 to both sides

n – 18 + 18 = 39 + 18

⇒ n = 57

∴ n = 57

**(iv)** n – 20568 = 21403

Adding 20568 to both sides

n – 20568 + 20568 = 21403 + 20568

n = 41971

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