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**Euclid’s Division Algorithm** is a technique to compute the** Highest Common Factor (HCF)** of two given positive integers. HCF of two positive integers a and b is the largest positive integer d that divides both **a** and** b. **To understand** Euclid’s Division Algorithm** we first need to understand** Euclid’s Division Lemma**.

**Euclid’s Division Lemma**

**Euclid’s Division Lemma** gives the relation between all the components of** Division. **Let’s look at the statement of **Euclid’s Division Lemma:**

For any 2 positive integer a & b there exists a unique integers q & r, **Such that: a = b x (q + r), ** **where 0 <= r < b**

Let’s understand **Euclid’s Division** **Lemma** visually. In the below diagram, the Dividend 27 is** a** and the Divisor 8 is** b. **

The Quotient 3 is **q** and the Remainder 3 is **r **

As you can see in the below image:

Thus, the division lemma: a = b x (q + r) can be written as:

**Divident = (Divisor x Quotient) + Remainder**

**Euclid’s Division Lemma**has many Applications related to Divisibility of Integers- It can be used to find
**HCF**of two numbers. **HCF**Stands For**Highest Common Factor.**

**Using Division Lemma to Find the HCF of Two Numbers**

The process of finding the HCF of two numbers using EUCLID’S DIVISION LEMMA is called “EUCLID’S DIVISION ALGORITHM”.**Example 1: Let’s find the HCF of 135 and 255?****Solution: ****Step 1:** Apply the Division Lemma to the 255 and 135, by dividing 255 by 135.

**Step 2:** Now, the Remainder becomes the divisor and the previous divisor becomes the dividend

**Step 3:** Again Division Lemma is Applied to this new pair of Dividend and Divisor

**Step 4:** Now 15 is our new Divisor and 120 is the new Dividend.

The Divisor which makes the Remainder Zero is the HCF of Two Numbers.

So 15 is the HCF of 255 and 135.

**Example 2: Use Euclid’s Division Algorithm to Find the HCF of 867 and 255?****Solution: ****Step 1: **Since 867 > 255, we apply the Division Lemma to 867 and 255, to get

867 = 255 x 3 + 102**Step 2: **Since the Remainder 102 ≠ 0, we apply the division lemma to 867 and 255, to get

255 = 102 x 2 + 51**Step 3: **We consider the new divisor 102 and the new Remainder 51 and apply the division lemma to get

102 = 51 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 51, the HCF of 255 and 867 is 51 .**Example 3: Use Euclid’s Division Algorithm to Find the HCF of 4052 and 12576?****Solution:****Step 1: **Since 12576 > 4052 , we apply the Division Lemma to 867 and 255, to get

12576 = 4052 x 3 + 420**Step 2:** Since the Remainder 420 ≠ 0, we apply the division lemma to 12576 and 4052, to get

4052 = 420 x 9 + 272**Step 3:** We consider the new divisor 420 and the new Remainder 272 and apply the division lemma to get

420 = 272 x 1 + 148

We consider the new divisor 272 and the new Remainder 148 and apply the division lemma to get

272 = 148 x 1 +124

We consider the new divisor 148 and the new Remainder 124 and apply the division lemma to get

148 = 124 x 1 + 24

We consider the new divisor 124 and the new Remainder 24 and apply the division lemma to get

124 = 24 x 5 + 4

We consider the new divisor 24 and the new Remainder 4 and apply the division lemma to get

24 = 4 x 6 + 0

The remainder has now become zero, so our procedure stops . Since the divisor at this stage is 4, the HCF of 4052 and 12576 is 4.

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