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Oxidising & Reducing Agents

Oxidising agent

  • An oxidising agent is a substance that oxidises another atom or ion by causing it to lose electrons
  • An oxidising agent itself gets reduced – gains electrons
  • Therefore, the ox. no. of the oxidising agent decreases
    Redox | Chemistry for Grade 12
Example of an oxidising agent in a chemical reaction

Reducing agent

  • A reducing agent is a substance that reduces another atom or ion by causing it to gain electrons
  • A reducing agent itself gets oxidised – loses/donates electrons
  • Therefore, the ox. no. of the reducing agent increases
    Redox | Chemistry for Grade 12
Example of a reducing agent in a chemical reaction
  • For a reaction to be recognised as a redox reaction, there must be both an oxidising and reducing agent
  • Some substances can act both as oxidising and reducing agents
  • Their nature is dependent upon what they are reacting with and the reaction conditions

Oxidising & Reducing Agents Table

Redox | Chemistry for Grade 12

Redox Equations

  • Balancing equations using redox principles is a useful skill and is best illustrated by following an example
  • It is important to follow a methodical step-by-step approach so that you don't get lost:

Example: Writing overall redox reactions
Manganate(VII) ions (MnO4- ) react with Fe2+ ions in the presence of acid (H+) to form Mn2+ ions, Fe3+ ions and water
Write the overall redox equation for this reaction

Step 1: Write the unbalanced equation and identify the atoms which change in oxidation state

  • Redox | Chemistry for Grade 12

Step 2: Deduce the oxidation state changes

  • Redox | Chemistry for Grade 12

Step 3: Balance the oxidation state changes

  • Redox | Chemistry for Grade 12

Step 4: Balance the charges

  • Redox | Chemistry for Grade 12

Step 5: Finally, balance the atoms

  • Redox | Chemistry for Grade 12

Interpreting & Predicting Redox Reactions

  • All of the species involved in a chemical reaction might not be known
  • You can be asked to interpret the information given to you and predict any other chemicals involved in the reaction
    • You can use the method shown in the Redox Equations section above
    • The worked example below is a method that works for balancing ionic half equations but can also be used to help predict redox equations

Example: Write complete equations for the following reactions:

(i) Hydrogen iodide reacting with sulfuric acid to form hydrogen sulfide, iodine and one other product

Step 1: Start with what you know:

  • HI + H2SO→ H2S + I2 

Step 2: Consider any unaccounted for elements

  • The only element that is not currently considered is oxygen

Step 3: Make a common and appropriate suggestion for the missing product

  • Most of these questions are in solution so there is always H2O, H+ and OH- available
    Missing product suggestion = 4H2O
    HI + H2SO4 → H2S + I2 + 4H2O

Step 4: Balance the remaining chemicals
8HI + H2SO4 → H2S + 4I2 + 4H2O

(ii) Lead(II) chloride, chlorine and one other product being formed from the reaction of concentrated hydrochloric acid with lead(IV) oxide

Step 1: Start with what you know:

  • PbO2 + HCl → PbCl2 + Cl2 

Step 2: Consider any unaccounted elements

  • The only element that is not currently considered is oxygen

Step 3: Make a common and appropriate suggestion for the missing product

  • Missing product suggestion = 2H2O
    PbO2 + HCl → PbCl2 + Cl2 + 2H2O

Step 4: Balance the remaining chemicals

  • PbO2 + 4HCl → PbCl2 + Cl2 + 2H2O
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