SBI Clerk 2016: Mains Solutions Paper | SBI Clerk Mock Test Series & Past Year Papers 2024 - Bank Exams PDF Download

 Page 1


 
 
 
             
 
 
SBI Clerk Mains 2016 (Solutions) 
 
 
 
 
Direction (1-5): 
 
Floor Person Color 
8 U Pink 
7 Y Grey 
6 S Yellow 
5 Z Blue 
4 T Purple 
3 V Orange 
2 X Green 
1 W Red 
 
1. (c);  2. (d);  3. (a); 
 
4. (a);  5. (c); 
 
Direction (6-10): 
 
 
 
6. (e);  7.   (b);  8. (c); 
 
9. (c);  10. (c); 
 
Direction (11-15) : 
 
11. (b); Since the first letter is vowel and the last letter is 
consonant, so both are to be coded as code of 
consonant i.e. of B which is *.  
 
12. (c); Since first and last letters are consonants and in 
between there are two vowels, so both the vowels are 
to be coded as 8. So the code is7$8882. 
 
13. (e); Explanation: 
  Converting the letters into symbols the code is, 
  D K P R T B 
  % 6 5 2 $ * 
 
14. (d); Explanation: 
  Since 1st and last letters are vowels, so both are to be 
coded as +. So the code is +5#$2+ 
 
15. (a); Explanation: 
  Since 1st letter is a consonant and last is a vowel, so 
their codes are to be interchanged. So the code 
for HLEKBI is 13@6*9. 
Direction (16-20): Will ? ka 
Meet ? ja 
Us ? lu 
You ? hu 
Today ? la 
temperature ? ju 
the ? fu 
of ? na 
maximum ? fa 
 
16. (b);  17. (a);  18. (b); 
 
19. (b);  20. (c); 
 
Direction (21-25): © ? < 
@ ? = 
% ? > 
$ ? = 
? ? = 
 
21. (a); ?? < ?? = ?? > ?? 
  B<M (True) B<F (False) 
 
22. (b); ?? = ?? > ?? = ?? 
  K= ?? (False) K<M(True) 
 
23. (e); ?? < ?? = ?? = ?? 
  N= ?? (???????? ) W<N(True) 
 
24. (d); ?? = ?? = ?? < ?? 
  R=W(False) R>W(False) 
 
25. (d); ?? = ?? > ?? < ?? 
  N= ?? (?????????? ) N>J(False) 
 
26. (e); From statement I and II both : 
   
27. (b); From I: P is mother in law of R. or mother of R. 
  
  or 
   
  From II: P is father of R. 
REASONING ABILITY 
Page 2


 
 
 
             
 
 
SBI Clerk Mains 2016 (Solutions) 
 
 
 
 
Direction (1-5): 
 
Floor Person Color 
8 U Pink 
7 Y Grey 
6 S Yellow 
5 Z Blue 
4 T Purple 
3 V Orange 
2 X Green 
1 W Red 
 
1. (c);  2. (d);  3. (a); 
 
4. (a);  5. (c); 
 
Direction (6-10): 
 
 
 
6. (e);  7.   (b);  8. (c); 
 
9. (c);  10. (c); 
 
Direction (11-15) : 
 
11. (b); Since the first letter is vowel and the last letter is 
consonant, so both are to be coded as code of 
consonant i.e. of B which is *.  
 
12. (c); Since first and last letters are consonants and in 
between there are two vowels, so both the vowels are 
to be coded as 8. So the code is7$8882. 
 
13. (e); Explanation: 
  Converting the letters into symbols the code is, 
  D K P R T B 
  % 6 5 2 $ * 
 
14. (d); Explanation: 
  Since 1st and last letters are vowels, so both are to be 
coded as +. So the code is +5#$2+ 
 
15. (a); Explanation: 
  Since 1st letter is a consonant and last is a vowel, so 
their codes are to be interchanged. So the code 
for HLEKBI is 13@6*9. 
Direction (16-20): Will ? ka 
Meet ? ja 
Us ? lu 
You ? hu 
Today ? la 
temperature ? ju 
the ? fu 
of ? na 
maximum ? fa 
 
16. (b);  17. (a);  18. (b); 
 
19. (b);  20. (c); 
 
Direction (21-25): © ? < 
@ ? = 
% ? > 
$ ? = 
? ? = 
 
21. (a); ?? < ?? = ?? > ?? 
  B<M (True) B<F (False) 
 
22. (b); ?? = ?? > ?? = ?? 
  K= ?? (False) K<M(True) 
 
23. (e); ?? < ?? = ?? = ?? 
  N= ?? (???????? ) W<N(True) 
 
24. (d); ?? = ?? = ?? < ?? 
  R=W(False) R>W(False) 
 
25. (d); ?? = ?? > ?? < ?? 
  N= ?? (?????????? ) N>J(False) 
 
26. (e); From statement I and II both : 
   
27. (b); From I: P is mother in law of R. or mother of R. 
  
  or 
   
  From II: P is father of R. 
REASONING ABILITY 
 
 
 
             
 
   
 
 
28. (d);
 
29. (a); 
 
 
30. (b); Total 37 persons sitting in a row. 
 
Direction (31-35): 
Boys USPRQT 
Girls FEADBC 
 
31. (e);   32. (b);  33. (c); 
 
34. (e);    35. (a); 
 
Direction (36-37): 
 
36. (a) 
 
37. (d); 16+8+0+2+1=27 
 
Direction (38-40): 
38.  (b);
   
39. (d); 
 
40. (e); 
 
 
Direction (41-45): 
Input: Kite 19 54 Give 31 Right 72 87 Dream Ace. 
Step1: Ace Kite 19 54 Give 31 Right 72 Dream 87.  
Step2: Dream Ace Kite 19 54 Give 31 Right 87 72. 
Step3: Give Dream Ace Kite 19 31 Right 87 72 54. 
Step4: Kite Give Dream Ace 19 Right 87 72 54 31. 
Step5:  Right Kite Give Dream Ace 87 72 54 31 19. 
‘Step-5’ is the final step of this input. 
 
41. (a);  42. (b);  43. (d); 
 
44. (c);  45. (e); 
 
Direction (46-50): Height ? R>Q>S>V>T>P 
Weight ? S>P>R>Q>T>V 
 
46. (e);  47. (b);  48. (d); 
 
49. (c);  50. (a);
 
 
 
 
51. (c); Pattern is — 
   
  ? ? = 286  
 
52. (b);
  
 
  ? ? = 36.6  
 
53. (b); Pattern is  
  5 × 1 – 1 = 4  
  4 × 2 – 2 = 6 
  6 × 3 – 3 = 15 
  15 × 4 – 4 = 56 
  56 × 5 – 5 = 275 
 
54. (d); Pattern is — 
   
  ?  ? = 252 
 
55. (e); Pattern is,  
  5 × 1 – 2 = 3 
  3 × 2 – 2 = 4 
  4 × 3 – 2 = 10 
  10 × 4 – 2 = 38   ?  ? = 10 
56. (e); Let speed of stream be x km/hr. 
  ? speed of boat in still water is 3x km/hr 
  ? ATQ, 
  
24
3?? +?? +
24
3?? –?? = 6   
  
24
4?? +
24
2?? = 6   ?   
6
?? +
12
?? = 6   
  ?? =
18
6
= 3 ???? h?? /  
  ? Speed of boat in still water = 9 km/hr 
 
57. (d);  
QUANTITATIVE APTITUDE 
Page 3


 
 
 
             
 
 
SBI Clerk Mains 2016 (Solutions) 
 
 
 
 
Direction (1-5): 
 
Floor Person Color 
8 U Pink 
7 Y Grey 
6 S Yellow 
5 Z Blue 
4 T Purple 
3 V Orange 
2 X Green 
1 W Red 
 
1. (c);  2. (d);  3. (a); 
 
4. (a);  5. (c); 
 
Direction (6-10): 
 
 
 
6. (e);  7.   (b);  8. (c); 
 
9. (c);  10. (c); 
 
Direction (11-15) : 
 
11. (b); Since the first letter is vowel and the last letter is 
consonant, so both are to be coded as code of 
consonant i.e. of B which is *.  
 
12. (c); Since first and last letters are consonants and in 
between there are two vowels, so both the vowels are 
to be coded as 8. So the code is7$8882. 
 
13. (e); Explanation: 
  Converting the letters into symbols the code is, 
  D K P R T B 
  % 6 5 2 $ * 
 
14. (d); Explanation: 
  Since 1st and last letters are vowels, so both are to be 
coded as +. So the code is +5#$2+ 
 
15. (a); Explanation: 
  Since 1st letter is a consonant and last is a vowel, so 
their codes are to be interchanged. So the code 
for HLEKBI is 13@6*9. 
Direction (16-20): Will ? ka 
Meet ? ja 
Us ? lu 
You ? hu 
Today ? la 
temperature ? ju 
the ? fu 
of ? na 
maximum ? fa 
 
16. (b);  17. (a);  18. (b); 
 
19. (b);  20. (c); 
 
Direction (21-25): © ? < 
@ ? = 
% ? > 
$ ? = 
? ? = 
 
21. (a); ?? < ?? = ?? > ?? 
  B<M (True) B<F (False) 
 
22. (b); ?? = ?? > ?? = ?? 
  K= ?? (False) K<M(True) 
 
23. (e); ?? < ?? = ?? = ?? 
  N= ?? (???????? ) W<N(True) 
 
24. (d); ?? = ?? = ?? < ?? 
  R=W(False) R>W(False) 
 
25. (d); ?? = ?? > ?? < ?? 
  N= ?? (?????????? ) N>J(False) 
 
26. (e); From statement I and II both : 
   
27. (b); From I: P is mother in law of R. or mother of R. 
  
  or 
   
  From II: P is father of R. 
REASONING ABILITY 
 
 
 
             
 
   
 
 
28. (d);
 
29. (a); 
 
 
30. (b); Total 37 persons sitting in a row. 
 
Direction (31-35): 
Boys USPRQT 
Girls FEADBC 
 
31. (e);   32. (b);  33. (c); 
 
34. (e);    35. (a); 
 
Direction (36-37): 
 
36. (a) 
 
37. (d); 16+8+0+2+1=27 
 
Direction (38-40): 
38.  (b);
   
39. (d); 
 
40. (e); 
 
 
Direction (41-45): 
Input: Kite 19 54 Give 31 Right 72 87 Dream Ace. 
Step1: Ace Kite 19 54 Give 31 Right 72 Dream 87.  
Step2: Dream Ace Kite 19 54 Give 31 Right 87 72. 
Step3: Give Dream Ace Kite 19 31 Right 87 72 54. 
Step4: Kite Give Dream Ace 19 Right 87 72 54 31. 
Step5:  Right Kite Give Dream Ace 87 72 54 31 19. 
‘Step-5’ is the final step of this input. 
 
41. (a);  42. (b);  43. (d); 
 
44. (c);  45. (e); 
 
Direction (46-50): Height ? R>Q>S>V>T>P 
Weight ? S>P>R>Q>T>V 
 
46. (e);  47. (b);  48. (d); 
 
49. (c);  50. (a);
 
 
 
 
51. (c); Pattern is — 
   
  ? ? = 286  
 
52. (b);
  
 
  ? ? = 36.6  
 
53. (b); Pattern is  
  5 × 1 – 1 = 4  
  4 × 2 – 2 = 6 
  6 × 3 – 3 = 15 
  15 × 4 – 4 = 56 
  56 × 5 – 5 = 275 
 
54. (d); Pattern is — 
   
  ?  ? = 252 
 
55. (e); Pattern is,  
  5 × 1 – 2 = 3 
  3 × 2 – 2 = 4 
  4 × 3 – 2 = 10 
  10 × 4 – 2 = 38   ?  ? = 10 
56. (e); Let speed of stream be x km/hr. 
  ? speed of boat in still water is 3x km/hr 
  ? ATQ, 
  
24
3?? +?? +
24
3?? –?? = 6   
  
24
4?? +
24
2?? = 6   ?   
6
?? +
12
?? = 6   
  ?? =
18
6
= 3 ???? h?? /  
  ? Speed of boat in still water = 9 km/hr 
 
57. (d);  
QUANTITATIVE APTITUDE 
 
 
 
             
 
   
? ???????????????? ???????? = [112× 78 – 107 × 73] × 2 
= ???? . 1850 
 
58. (b); Length of BD by pythagores theorem 
   ???? = v8
2
+ 6
2
 
   = v64 + 36 = 10 
  ? Length of BC 
   = v(24)
2
+ (10)
2
 
   = v576 + 100 
   = v676 
  = 26  
 
59. (a); Let radius of circle be r meter  
  ? 2pr = 44 
   2 ×
22
7
× ?? = 44 
  r = 7cm 
  ? BC = 14 m 
  ? AB = AC = 7 v2 m 
  ? Area of ?ABC 
   =
1
2
× 7v2 × 7v2 = 49 ?? 2
 
 
60. (a); Radius of bigger semicircle = 14 
  & radius of smaller semicircle = 7  
  ? Required area 
   =
1
2
[?? (14)
2
– 2 × ?? (7)
2
] 
   =
1
2
[196?? – 98?? ]  =
1
2
× 98?? = 154  
61. (a); There are four cases ? 3R, (1R, 2G), (2R, 1G), 3G 
  ? Required probability  
   =
?? 3 
4
+ ?? 1 
4
× ?? 2 
6
+ ?? 2 
4
× ?? 1 
6
+ ?? 3 
6
?? 3 
15
 
   =
4+4×15+6×6+20
91×5
 
   =
4+60+36+20
91×5
 =
120
91×5
=
24
91
 
 
62. (a); 4x + 7y = 42  …(i)  
  3x – 11y = – 1  …(ii) 
  Multiplying (i) by 3 and (ii) by 4 
  12x + 21y = 126 …(iii) 
  12x – 44y = – 4 …(iv)  
  Solving (iii) & (iv)  
  x = 7 & y = 2 
  ? x > y  
 
63. (c); I. 9x² – 29x + 22 = 0  
  9x² – 18x – 11x + 22 = 0  
  9x (x – 2) – 11 (x – 2) = 0  
   ? ?? = 2  ????
11
9
 
  II. y² –7y + 12 = 0  
  y² – 3y – 4y + 12 = 0  
  y (y – 3) – 4 (y – 3) = 0  
  y = 3, 4  
  ? y > x  
 
64. (d); I. 3x² – 12x + 8x – 32 = 0  
  3x (x – 4) + 8 (x – 4) = 0  
   ? ?? = 4,
–8
3
 
  II. 2y² – 17y + 36 = 0  
  2y² – 9y – 8y + 36 = 0  
  y (2y – 9) – 4 (2y – 9) = 0   
   ? ?? = 4,
9
2
 
  ? y = x 
 
65. (a); I. 3x² – 19x – 14 = 0  
  3x² – 21x + 2x – 14 = 0 
  3x (x – 7) + 2 (x – 7) = 0  
   ? ?? = 7 ????
–2
3
 
  II. 2y² + 5y + 3 = 0  
  2y² +2y + 3y + 3 = 0  
  2y (y + 1) + 3 (y + 1) = 0   
   ?? = – 1 ????
–3
2
 
  ? x > y  
 
66. (e); I. x² + 2 × 7 × x + (7)² = 0  
  ? (x + 7)² = 0  
  ?  x = – 7  
  II. y (y + 9) = 0  
  ? y = 0 or –9 
  ? No relation.  
 
67.  (e); Average salary = 
1000×43000
1600
 = 26875 
 
68. (b); Number of employees in : 
  PNB = 1600 
  OBC = 1700 
  SBI = 2100 
 
69. (e); Required ratio = 15000×600 : 35000 × 900        
  = 2 : 7 
 
70. (e); Required percentage = 
400
600
× 100 
  = 66
2
3
%   
 
71. (b); Required percentage = 
20000×900
25000×800
× 100 = 90% 
 
72. (b); Required No. =
280+354+343+535+433
5
= 389  
 
73. (d); Required difference = (235 + 567 ) - 134 = 668 
74. (e); Required % =
320+346+436
255+343+545+546+453
× 100 
  =
1102
2142
× 100 ˜ 51%  
 
75. (d); Required animals  
   =
65
100
× (411 + 535+ 534 ) = 962 
 
76. (c); Required No. of lions = 
3
4
(135 + 325+ 345+ 267 )  
   = 804  
 
77. (c); Let their salaries be 100, 300 and 400 
  Their new salaries = 105 : 330 : 460  
  = 21 : 66 : 92   
 
Page 4


 
 
 
             
 
 
SBI Clerk Mains 2016 (Solutions) 
 
 
 
 
Direction (1-5): 
 
Floor Person Color 
8 U Pink 
7 Y Grey 
6 S Yellow 
5 Z Blue 
4 T Purple 
3 V Orange 
2 X Green 
1 W Red 
 
1. (c);  2. (d);  3. (a); 
 
4. (a);  5. (c); 
 
Direction (6-10): 
 
 
 
6. (e);  7.   (b);  8. (c); 
 
9. (c);  10. (c); 
 
Direction (11-15) : 
 
11. (b); Since the first letter is vowel and the last letter is 
consonant, so both are to be coded as code of 
consonant i.e. of B which is *.  
 
12. (c); Since first and last letters are consonants and in 
between there are two vowels, so both the vowels are 
to be coded as 8. So the code is7$8882. 
 
13. (e); Explanation: 
  Converting the letters into symbols the code is, 
  D K P R T B 
  % 6 5 2 $ * 
 
14. (d); Explanation: 
  Since 1st and last letters are vowels, so both are to be 
coded as +. So the code is +5#$2+ 
 
15. (a); Explanation: 
  Since 1st letter is a consonant and last is a vowel, so 
their codes are to be interchanged. So the code 
for HLEKBI is 13@6*9. 
Direction (16-20): Will ? ka 
Meet ? ja 
Us ? lu 
You ? hu 
Today ? la 
temperature ? ju 
the ? fu 
of ? na 
maximum ? fa 
 
16. (b);  17. (a);  18. (b); 
 
19. (b);  20. (c); 
 
Direction (21-25): © ? < 
@ ? = 
% ? > 
$ ? = 
? ? = 
 
21. (a); ?? < ?? = ?? > ?? 
  B<M (True) B<F (False) 
 
22. (b); ?? = ?? > ?? = ?? 
  K= ?? (False) K<M(True) 
 
23. (e); ?? < ?? = ?? = ?? 
  N= ?? (???????? ) W<N(True) 
 
24. (d); ?? = ?? = ?? < ?? 
  R=W(False) R>W(False) 
 
25. (d); ?? = ?? > ?? < ?? 
  N= ?? (?????????? ) N>J(False) 
 
26. (e); From statement I and II both : 
   
27. (b); From I: P is mother in law of R. or mother of R. 
  
  or 
   
  From II: P is father of R. 
REASONING ABILITY 
 
 
 
             
 
   
 
 
28. (d);
 
29. (a); 
 
 
30. (b); Total 37 persons sitting in a row. 
 
Direction (31-35): 
Boys USPRQT 
Girls FEADBC 
 
31. (e);   32. (b);  33. (c); 
 
34. (e);    35. (a); 
 
Direction (36-37): 
 
36. (a) 
 
37. (d); 16+8+0+2+1=27 
 
Direction (38-40): 
38.  (b);
   
39. (d); 
 
40. (e); 
 
 
Direction (41-45): 
Input: Kite 19 54 Give 31 Right 72 87 Dream Ace. 
Step1: Ace Kite 19 54 Give 31 Right 72 Dream 87.  
Step2: Dream Ace Kite 19 54 Give 31 Right 87 72. 
Step3: Give Dream Ace Kite 19 31 Right 87 72 54. 
Step4: Kite Give Dream Ace 19 Right 87 72 54 31. 
Step5:  Right Kite Give Dream Ace 87 72 54 31 19. 
‘Step-5’ is the final step of this input. 
 
41. (a);  42. (b);  43. (d); 
 
44. (c);  45. (e); 
 
Direction (46-50): Height ? R>Q>S>V>T>P 
Weight ? S>P>R>Q>T>V 
 
46. (e);  47. (b);  48. (d); 
 
49. (c);  50. (a);
 
 
 
 
51. (c); Pattern is — 
   
  ? ? = 286  
 
52. (b);
  
 
  ? ? = 36.6  
 
53. (b); Pattern is  
  5 × 1 – 1 = 4  
  4 × 2 – 2 = 6 
  6 × 3 – 3 = 15 
  15 × 4 – 4 = 56 
  56 × 5 – 5 = 275 
 
54. (d); Pattern is — 
   
  ?  ? = 252 
 
55. (e); Pattern is,  
  5 × 1 – 2 = 3 
  3 × 2 – 2 = 4 
  4 × 3 – 2 = 10 
  10 × 4 – 2 = 38   ?  ? = 10 
56. (e); Let speed of stream be x km/hr. 
  ? speed of boat in still water is 3x km/hr 
  ? ATQ, 
  
24
3?? +?? +
24
3?? –?? = 6   
  
24
4?? +
24
2?? = 6   ?   
6
?? +
12
?? = 6   
  ?? =
18
6
= 3 ???? h?? /  
  ? Speed of boat in still water = 9 km/hr 
 
57. (d);  
QUANTITATIVE APTITUDE 
 
 
 
             
 
   
? ???????????????? ???????? = [112× 78 – 107 × 73] × 2 
= ???? . 1850 
 
58. (b); Length of BD by pythagores theorem 
   ???? = v8
2
+ 6
2
 
   = v64 + 36 = 10 
  ? Length of BC 
   = v(24)
2
+ (10)
2
 
   = v576 + 100 
   = v676 
  = 26  
 
59. (a); Let radius of circle be r meter  
  ? 2pr = 44 
   2 ×
22
7
× ?? = 44 
  r = 7cm 
  ? BC = 14 m 
  ? AB = AC = 7 v2 m 
  ? Area of ?ABC 
   =
1
2
× 7v2 × 7v2 = 49 ?? 2
 
 
60. (a); Radius of bigger semicircle = 14 
  & radius of smaller semicircle = 7  
  ? Required area 
   =
1
2
[?? (14)
2
– 2 × ?? (7)
2
] 
   =
1
2
[196?? – 98?? ]  =
1
2
× 98?? = 154  
61. (a); There are four cases ? 3R, (1R, 2G), (2R, 1G), 3G 
  ? Required probability  
   =
?? 3 
4
+ ?? 1 
4
× ?? 2 
6
+ ?? 2 
4
× ?? 1 
6
+ ?? 3 
6
?? 3 
15
 
   =
4+4×15+6×6+20
91×5
 
   =
4+60+36+20
91×5
 =
120
91×5
=
24
91
 
 
62. (a); 4x + 7y = 42  …(i)  
  3x – 11y = – 1  …(ii) 
  Multiplying (i) by 3 and (ii) by 4 
  12x + 21y = 126 …(iii) 
  12x – 44y = – 4 …(iv)  
  Solving (iii) & (iv)  
  x = 7 & y = 2 
  ? x > y  
 
63. (c); I. 9x² – 29x + 22 = 0  
  9x² – 18x – 11x + 22 = 0  
  9x (x – 2) – 11 (x – 2) = 0  
   ? ?? = 2  ????
11
9
 
  II. y² –7y + 12 = 0  
  y² – 3y – 4y + 12 = 0  
  y (y – 3) – 4 (y – 3) = 0  
  y = 3, 4  
  ? y > x  
 
64. (d); I. 3x² – 12x + 8x – 32 = 0  
  3x (x – 4) + 8 (x – 4) = 0  
   ? ?? = 4,
–8
3
 
  II. 2y² – 17y + 36 = 0  
  2y² – 9y – 8y + 36 = 0  
  y (2y – 9) – 4 (2y – 9) = 0   
   ? ?? = 4,
9
2
 
  ? y = x 
 
65. (a); I. 3x² – 19x – 14 = 0  
  3x² – 21x + 2x – 14 = 0 
  3x (x – 7) + 2 (x – 7) = 0  
   ? ?? = 7 ????
–2
3
 
  II. 2y² + 5y + 3 = 0  
  2y² +2y + 3y + 3 = 0  
  2y (y + 1) + 3 (y + 1) = 0   
   ?? = – 1 ????
–3
2
 
  ? x > y  
 
66. (e); I. x² + 2 × 7 × x + (7)² = 0  
  ? (x + 7)² = 0  
  ?  x = – 7  
  II. y (y + 9) = 0  
  ? y = 0 or –9 
  ? No relation.  
 
67.  (e); Average salary = 
1000×43000
1600
 = 26875 
 
68. (b); Number of employees in : 
  PNB = 1600 
  OBC = 1700 
  SBI = 2100 
 
69. (e); Required ratio = 15000×600 : 35000 × 900        
  = 2 : 7 
 
70. (e); Required percentage = 
400
600
× 100 
  = 66
2
3
%   
 
71. (b); Required percentage = 
20000×900
25000×800
× 100 = 90% 
 
72. (b); Required No. =
280+354+343+535+433
5
= 389  
 
73. (d); Required difference = (235 + 567 ) - 134 = 668 
74. (e); Required % =
320+346+436
255+343+545+546+453
× 100 
  =
1102
2142
× 100 ˜ 51%  
 
75. (d); Required animals  
   =
65
100
× (411 + 535+ 534 ) = 962 
 
76. (c); Required No. of lions = 
3
4
(135 + 325+ 345+ 267 )  
   = 804  
 
77. (c); Let their salaries be 100, 300 and 400 
  Their new salaries = 105 : 330 : 460  
  = 21 : 66 : 92   
 
 
 
 
             
 
78. (b); Work done by the third pipe in 1 min. 
= (1/50) – [(1/60) + (1/75)] = [(1/50) (3/100)]  
  = (1/100) 
  ?The third pipe can alone fill the tank in 100 minutes. 
 
79. (e); Both the statements together is not sufficient.  
 
80. (d); Both statements alone is sufficient.  
   Let age of A is x and age of B is y. 
  ? 3x = y   ... (i) 
  From statement I: 
10 3
10 7
x
y
+
=
+
... (ii) 
  Solving equations (i) and (ii), x = 20, y = 60 
  From statement II: 
  = 
10 1
10 5
x
y
-
=
-
 
  =>5x – 50 = y – 10 
  =>5x – y = 40 (iii) 
  From equations (i) and (iii), x = 20, y = 60 
 
81. (c); Let length the train be x. 
   From statement I: 
   Speed = 
8
x
  
   From statement II: 
   Speed = 
50
20
x +
  
   Solving this, x = 
400
12
  = 
100
3
  meter
 
 
82.  (e); From I and II we find a + b = 2z 
     we can not find a + b from I and II together. 
 
83. (e); Let age of A, B and C be x year, y year and z year 
respectively  
   Data is not sufficient. 
  From statement I: 
   x =  
80
100
z ? 
  From statement II: 
   y =  
60
100
z ? 
  From these two equations 
4
3
x
y
=  but cannot find x 
and y separately. 
 
84. (d); Let the present age of Ranjana and Rakhi be 15x and 
17x 
15?? + 6
17?? + 6
=
9
10
 
  x = 2 
  ? Age of Ranjana after 6 years 
  = 15 × 2 + 6 =36 years. 
 
85. (b); S.I. =7200 
  R=
?? .?? ×100
?? ×?? =
7200×100
20,000×3
= 12% 
  C.I = 20000[(1+
12
100
)
3
- 1] 
  = 8098.56 
 
86. (a); Here volume of water emptied by the second pipe 
will be 4 times to that of first Hence, Time take will be 
1/4 of the first pipe. When both the pipes are open 
the part of the tank emptied in 1 minute= 1/8 Hence 
the tank will be emptied in 8 minutes. 
 
87. (b); Total CP = 2000 + 750 = 2750 
  Total ???? =
120
100
× 2000+
95
100
× 750  
  = 2400 + 712.5 
  = 3112.5 
  ? Total gain = 3112.5 – 2750 = 362.5 Rs.  
 
88. (a); Let Man = ?? 
  Woman = 2??  
  ? 
8
?? +
4
2?? =
1
6
  
   
20
2?? =
1
6
  
  ?? = 60  
  ?  Man = 60, woman = 120  
  Required No. of days =
2
3
4
60
+
8
120
 
  =
2×120
3(16)
  
  = 5 days 
 
89. (c); Let their investment be ?? , 2??  and 4??  
  ? A ? 6?? + 6 × (?? +
?? 2
) = 6?? + 9?? = 15?? 
  ?? ? 6 × 2?? + 6 × 4?? = 36??  
  ?? ? 6 × 4?? + 6 × (4?? -
1
4
× 4?? ) = 24?? + 18?? =
42 ??  
  ?  Required Ratio = 15 : 36 : 42  
  = 5 : 12 : 14   
 
90. (b); Number of questions attempted correctly = 
  70% of 10 + 50% of 30 + 60% of 45  
  = 7 + 15 + 27 = 49 
  Passing grade = (60/100 )* 85 = 51 
  Reqd. Ans = 51 - 49 = 2 
 
91. (c); Age of new man = 28 + 28 = 56 years 
 
92. (b); 11% ? 5236  
  1% ? 476   
  ? (11 + 19 + 7) = 37% ? 17612 Rs.  
 
93. (c); Probability =
2?? 1
×3?? 2
+2?? 2
×3?? 1
5?? 3
    
  =
2×3+1×3
10
 =
9
10
  
 
94. (d); ?? =
1
1
12
-
1
20
=
1
5-3
60
  
  B = 30 days 
  ? Required No. of days =
1
1
20
+
1
60
 =
60
4
= 15 days 
Page 5


 
 
 
             
 
 
SBI Clerk Mains 2016 (Solutions) 
 
 
 
 
Direction (1-5): 
 
Floor Person Color 
8 U Pink 
7 Y Grey 
6 S Yellow 
5 Z Blue 
4 T Purple 
3 V Orange 
2 X Green 
1 W Red 
 
1. (c);  2. (d);  3. (a); 
 
4. (a);  5. (c); 
 
Direction (6-10): 
 
 
 
6. (e);  7.   (b);  8. (c); 
 
9. (c);  10. (c); 
 
Direction (11-15) : 
 
11. (b); Since the first letter is vowel and the last letter is 
consonant, so both are to be coded as code of 
consonant i.e. of B which is *.  
 
12. (c); Since first and last letters are consonants and in 
between there are two vowels, so both the vowels are 
to be coded as 8. So the code is7$8882. 
 
13. (e); Explanation: 
  Converting the letters into symbols the code is, 
  D K P R T B 
  % 6 5 2 $ * 
 
14. (d); Explanation: 
  Since 1st and last letters are vowels, so both are to be 
coded as +. So the code is +5#$2+ 
 
15. (a); Explanation: 
  Since 1st letter is a consonant and last is a vowel, so 
their codes are to be interchanged. So the code 
for HLEKBI is 13@6*9. 
Direction (16-20): Will ? ka 
Meet ? ja 
Us ? lu 
You ? hu 
Today ? la 
temperature ? ju 
the ? fu 
of ? na 
maximum ? fa 
 
16. (b);  17. (a);  18. (b); 
 
19. (b);  20. (c); 
 
Direction (21-25): © ? < 
@ ? = 
% ? > 
$ ? = 
? ? = 
 
21. (a); ?? < ?? = ?? > ?? 
  B<M (True) B<F (False) 
 
22. (b); ?? = ?? > ?? = ?? 
  K= ?? (False) K<M(True) 
 
23. (e); ?? < ?? = ?? = ?? 
  N= ?? (???????? ) W<N(True) 
 
24. (d); ?? = ?? = ?? < ?? 
  R=W(False) R>W(False) 
 
25. (d); ?? = ?? > ?? < ?? 
  N= ?? (?????????? ) N>J(False) 
 
26. (e); From statement I and II both : 
   
27. (b); From I: P is mother in law of R. or mother of R. 
  
  or 
   
  From II: P is father of R. 
REASONING ABILITY 
 
 
 
             
 
   
 
 
28. (d);
 
29. (a); 
 
 
30. (b); Total 37 persons sitting in a row. 
 
Direction (31-35): 
Boys USPRQT 
Girls FEADBC 
 
31. (e);   32. (b);  33. (c); 
 
34. (e);    35. (a); 
 
Direction (36-37): 
 
36. (a) 
 
37. (d); 16+8+0+2+1=27 
 
Direction (38-40): 
38.  (b);
   
39. (d); 
 
40. (e); 
 
 
Direction (41-45): 
Input: Kite 19 54 Give 31 Right 72 87 Dream Ace. 
Step1: Ace Kite 19 54 Give 31 Right 72 Dream 87.  
Step2: Dream Ace Kite 19 54 Give 31 Right 87 72. 
Step3: Give Dream Ace Kite 19 31 Right 87 72 54. 
Step4: Kite Give Dream Ace 19 Right 87 72 54 31. 
Step5:  Right Kite Give Dream Ace 87 72 54 31 19. 
‘Step-5’ is the final step of this input. 
 
41. (a);  42. (b);  43. (d); 
 
44. (c);  45. (e); 
 
Direction (46-50): Height ? R>Q>S>V>T>P 
Weight ? S>P>R>Q>T>V 
 
46. (e);  47. (b);  48. (d); 
 
49. (c);  50. (a);
 
 
 
 
51. (c); Pattern is — 
   
  ? ? = 286  
 
52. (b);
  
 
  ? ? = 36.6  
 
53. (b); Pattern is  
  5 × 1 – 1 = 4  
  4 × 2 – 2 = 6 
  6 × 3 – 3 = 15 
  15 × 4 – 4 = 56 
  56 × 5 – 5 = 275 
 
54. (d); Pattern is — 
   
  ?  ? = 252 
 
55. (e); Pattern is,  
  5 × 1 – 2 = 3 
  3 × 2 – 2 = 4 
  4 × 3 – 2 = 10 
  10 × 4 – 2 = 38   ?  ? = 10 
56. (e); Let speed of stream be x km/hr. 
  ? speed of boat in still water is 3x km/hr 
  ? ATQ, 
  
24
3?? +?? +
24
3?? –?? = 6   
  
24
4?? +
24
2?? = 6   ?   
6
?? +
12
?? = 6   
  ?? =
18
6
= 3 ???? h?? /  
  ? Speed of boat in still water = 9 km/hr 
 
57. (d);  
QUANTITATIVE APTITUDE 
 
 
 
             
 
   
? ???????????????? ???????? = [112× 78 – 107 × 73] × 2 
= ???? . 1850 
 
58. (b); Length of BD by pythagores theorem 
   ???? = v8
2
+ 6
2
 
   = v64 + 36 = 10 
  ? Length of BC 
   = v(24)
2
+ (10)
2
 
   = v576 + 100 
   = v676 
  = 26  
 
59. (a); Let radius of circle be r meter  
  ? 2pr = 44 
   2 ×
22
7
× ?? = 44 
  r = 7cm 
  ? BC = 14 m 
  ? AB = AC = 7 v2 m 
  ? Area of ?ABC 
   =
1
2
× 7v2 × 7v2 = 49 ?? 2
 
 
60. (a); Radius of bigger semicircle = 14 
  & radius of smaller semicircle = 7  
  ? Required area 
   =
1
2
[?? (14)
2
– 2 × ?? (7)
2
] 
   =
1
2
[196?? – 98?? ]  =
1
2
× 98?? = 154  
61. (a); There are four cases ? 3R, (1R, 2G), (2R, 1G), 3G 
  ? Required probability  
   =
?? 3 
4
+ ?? 1 
4
× ?? 2 
6
+ ?? 2 
4
× ?? 1 
6
+ ?? 3 
6
?? 3 
15
 
   =
4+4×15+6×6+20
91×5
 
   =
4+60+36+20
91×5
 =
120
91×5
=
24
91
 
 
62. (a); 4x + 7y = 42  …(i)  
  3x – 11y = – 1  …(ii) 
  Multiplying (i) by 3 and (ii) by 4 
  12x + 21y = 126 …(iii) 
  12x – 44y = – 4 …(iv)  
  Solving (iii) & (iv)  
  x = 7 & y = 2 
  ? x > y  
 
63. (c); I. 9x² – 29x + 22 = 0  
  9x² – 18x – 11x + 22 = 0  
  9x (x – 2) – 11 (x – 2) = 0  
   ? ?? = 2  ????
11
9
 
  II. y² –7y + 12 = 0  
  y² – 3y – 4y + 12 = 0  
  y (y – 3) – 4 (y – 3) = 0  
  y = 3, 4  
  ? y > x  
 
64. (d); I. 3x² – 12x + 8x – 32 = 0  
  3x (x – 4) + 8 (x – 4) = 0  
   ? ?? = 4,
–8
3
 
  II. 2y² – 17y + 36 = 0  
  2y² – 9y – 8y + 36 = 0  
  y (2y – 9) – 4 (2y – 9) = 0   
   ? ?? = 4,
9
2
 
  ? y = x 
 
65. (a); I. 3x² – 19x – 14 = 0  
  3x² – 21x + 2x – 14 = 0 
  3x (x – 7) + 2 (x – 7) = 0  
   ? ?? = 7 ????
–2
3
 
  II. 2y² + 5y + 3 = 0  
  2y² +2y + 3y + 3 = 0  
  2y (y + 1) + 3 (y + 1) = 0   
   ?? = – 1 ????
–3
2
 
  ? x > y  
 
66. (e); I. x² + 2 × 7 × x + (7)² = 0  
  ? (x + 7)² = 0  
  ?  x = – 7  
  II. y (y + 9) = 0  
  ? y = 0 or –9 
  ? No relation.  
 
67.  (e); Average salary = 
1000×43000
1600
 = 26875 
 
68. (b); Number of employees in : 
  PNB = 1600 
  OBC = 1700 
  SBI = 2100 
 
69. (e); Required ratio = 15000×600 : 35000 × 900        
  = 2 : 7 
 
70. (e); Required percentage = 
400
600
× 100 
  = 66
2
3
%   
 
71. (b); Required percentage = 
20000×900
25000×800
× 100 = 90% 
 
72. (b); Required No. =
280+354+343+535+433
5
= 389  
 
73. (d); Required difference = (235 + 567 ) - 134 = 668 
74. (e); Required % =
320+346+436
255+343+545+546+453
× 100 
  =
1102
2142
× 100 ˜ 51%  
 
75. (d); Required animals  
   =
65
100
× (411 + 535+ 534 ) = 962 
 
76. (c); Required No. of lions = 
3
4
(135 + 325+ 345+ 267 )  
   = 804  
 
77. (c); Let their salaries be 100, 300 and 400 
  Their new salaries = 105 : 330 : 460  
  = 21 : 66 : 92   
 
 
 
 
             
 
78. (b); Work done by the third pipe in 1 min. 
= (1/50) – [(1/60) + (1/75)] = [(1/50) (3/100)]  
  = (1/100) 
  ?The third pipe can alone fill the tank in 100 minutes. 
 
79. (e); Both the statements together is not sufficient.  
 
80. (d); Both statements alone is sufficient.  
   Let age of A is x and age of B is y. 
  ? 3x = y   ... (i) 
  From statement I: 
10 3
10 7
x
y
+
=
+
... (ii) 
  Solving equations (i) and (ii), x = 20, y = 60 
  From statement II: 
  = 
10 1
10 5
x
y
-
=
-
 
  =>5x – 50 = y – 10 
  =>5x – y = 40 (iii) 
  From equations (i) and (iii), x = 20, y = 60 
 
81. (c); Let length the train be x. 
   From statement I: 
   Speed = 
8
x
  
   From statement II: 
   Speed = 
50
20
x +
  
   Solving this, x = 
400
12
  = 
100
3
  meter
 
 
82.  (e); From I and II we find a + b = 2z 
     we can not find a + b from I and II together. 
 
83. (e); Let age of A, B and C be x year, y year and z year 
respectively  
   Data is not sufficient. 
  From statement I: 
   x =  
80
100
z ? 
  From statement II: 
   y =  
60
100
z ? 
  From these two equations 
4
3
x
y
=  but cannot find x 
and y separately. 
 
84. (d); Let the present age of Ranjana and Rakhi be 15x and 
17x 
15?? + 6
17?? + 6
=
9
10
 
  x = 2 
  ? Age of Ranjana after 6 years 
  = 15 × 2 + 6 =36 years. 
 
85. (b); S.I. =7200 
  R=
?? .?? ×100
?? ×?? =
7200×100
20,000×3
= 12% 
  C.I = 20000[(1+
12
100
)
3
- 1] 
  = 8098.56 
 
86. (a); Here volume of water emptied by the second pipe 
will be 4 times to that of first Hence, Time take will be 
1/4 of the first pipe. When both the pipes are open 
the part of the tank emptied in 1 minute= 1/8 Hence 
the tank will be emptied in 8 minutes. 
 
87. (b); Total CP = 2000 + 750 = 2750 
  Total ???? =
120
100
× 2000+
95
100
× 750  
  = 2400 + 712.5 
  = 3112.5 
  ? Total gain = 3112.5 – 2750 = 362.5 Rs.  
 
88. (a); Let Man = ?? 
  Woman = 2??  
  ? 
8
?? +
4
2?? =
1
6
  
   
20
2?? =
1
6
  
  ?? = 60  
  ?  Man = 60, woman = 120  
  Required No. of days =
2
3
4
60
+
8
120
 
  =
2×120
3(16)
  
  = 5 days 
 
89. (c); Let their investment be ?? , 2??  and 4??  
  ? A ? 6?? + 6 × (?? +
?? 2
) = 6?? + 9?? = 15?? 
  ?? ? 6 × 2?? + 6 × 4?? = 36??  
  ?? ? 6 × 4?? + 6 × (4?? -
1
4
× 4?? ) = 24?? + 18?? =
42 ??  
  ?  Required Ratio = 15 : 36 : 42  
  = 5 : 12 : 14   
 
90. (b); Number of questions attempted correctly = 
  70% of 10 + 50% of 30 + 60% of 45  
  = 7 + 15 + 27 = 49 
  Passing grade = (60/100 )* 85 = 51 
  Reqd. Ans = 51 - 49 = 2 
 
91. (c); Age of new man = 28 + 28 = 56 years 
 
92. (b); 11% ? 5236  
  1% ? 476   
  ? (11 + 19 + 7) = 37% ? 17612 Rs.  
 
93. (c); Probability =
2?? 1
×3?? 2
+2?? 2
×3?? 1
5?? 3
    
  =
2×3+1×3
10
 =
9
10
  
 
94. (d); ?? =
1
1
12
-
1
20
=
1
5-3
60
  
  B = 30 days 
  ? Required No. of days =
1
1
20
+
1
60
 =
60
4
= 15 days 
 
 
 
             
 
 
95. (b); 
132×5
18
=
100+165
??  
  ?? =
275×18
132×5
  
  ?? = 7.5 seconds 
 
96. (b); 
3?? 12?? +3
=
3?? 15?? 
  ? New ratio = 1 : 5  
  ? Required % =
1
6
× 100% 
  =
50
3
% = 16
2
3
% 
 
97. (d);
   
  Let B turned off after T min 
  2T+3× 20 = 90 
  T=15 min  
 
98. (a); (2?? + 3?? )10 = (3?? + 2?? )??  
  20?? + 30?? = 24?? + 16??  
  2?? = 7??  
  ? 10?? = 10 days 
  ? ?? =
1
100
 days 
  ? 2?? + 1?? = 7?? + ??  
  = 8??  
  =
8
100
=
2
25
  
  ? Required No. of days = 12
1
2
 days 
 
99. (a); Ratio of their speeds = v
28
5
: v
20
7
 
   ? v
28
5
? 14  
  ? v
20
7
?
14
v28
× v5 ×
v20
v7
  
  =
14
2v7
× v5 ×
2v5
v7
  =
14×5
7
  = 10 kmph 
 
100. (a); Area = 2?? 2
 m
2
  
   
  ? 2?? 2
× 2 = 256  
  ?? 2
= 64  
  ?? = 8  
  ?  Required length = 2 × 8 = 16 m
 
 
 
 
101. (c);  102. (e); 103. (c); 
 
104. (c);  105. (b); 106. (b); 
 
107. (d);  108. (e); 109. (e); 
 
110. (d);  111. (e); 112. (d); 
 
113. (e);  114. (e); 115. (e); 
 
116. (c); 
 
117. (c); ’Earn a decent living’ is the only suitable syntax to be 
used. It means ‘to earn well’ that fulfils the sentence’s 
context. 
 
118. (c); After ‘to’ we should use ‘V1’ to show purpose. 
 
119. (c); ‘Disowning’ is the improper usage. We have to use 
‘disown’ here so that syntax gets correct 
120. (b); ‘Art’ is singular subject, so it should agree with a 
singular verb. Hence, ‘requires’ is suitable 
expression. 
 
121. (a); To express the subjunctive mood. Auxiliary ‘were’ is 
used in the sentence. 
122. (c); Accost means to approach someone with an 
allegation or blame, so 3rd option is the most 
appropriate one. 
 
123. (c); Harmful-not good for health, so 3
rd
 option is most 
appropriate one 
 
124. (b); downturns means- a decline in economic, knell 
means -the sound of a bell 
 
125. (c); survived means- continue to live or exist, unscathed 
means- without suffering any injury, damage, or 
harm. 
126. (b); downturn, out “dole out” is the correct phrase which 
means to help someone with money and gifts. 
 
127. (d);  128. (a); 129. (c); 
 
130. (a);  131. (e); 132. (c); 
 
133. (d);  134. (b); 135. (e); 
 
136. (b); For questions (136-140) THE CORRECT SEQUENCE 
IS ECADBFG 
 
137. (c);  138. (e); 139. (c); 
 
140. (e);
 
 
 
ENGLISH LANGUAGE