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Page 1
SBI Clerk Mains 2016 (Solutions)
Direction (1-5):
Floor Person Color
8 U Pink
7 Y Grey
6 S Yellow
5 Z Blue
4 T Purple
3 V Orange
2 X Green
1 W Red
1. (c); 2. (d); 3. (a);
4. (a); 5. (c);
Direction (6-10):
6. (e); 7. (b); 8. (c);
9. (c); 10. (c);
Direction (11-15) :
11. (b); Since the first letter is vowel and the last letter is
consonant, so both are to be coded as code of
consonant i.e. of B which is *.
12. (c); Since first and last letters are consonants and in
between there are two vowels, so both the vowels are
to be coded as 8. So the code is7$8882.
13. (e); Explanation:
Converting the letters into symbols the code is,
D K P R T B
% 6 5 2 $ *
14. (d); Explanation:
Since 1st and last letters are vowels, so both are to be
coded as +. So the code is +5#$2+
15. (a); Explanation:
Since 1st letter is a consonant and last is a vowel, so
their codes are to be interchanged. So the code
for HLEKBI is 13@6*9.
Direction (16-20): Will ? ka
Meet ? ja
Us ? lu
You ? hu
Today ? la
temperature ? ju
the ? fu
of ? na
maximum ? fa
16. (b); 17. (a); 18. (b);
19. (b); 20. (c);
Direction (21-25): © ? <
@ ? =
% ? >
$ ? =
? ? =
21. (a); ?? < ?? = ?? > ??
B<M (True) B<F (False)
22. (b); ?? = ?? > ?? = ??
K= ?? (False) K<M(True)
23. (e); ?? < ?? = ?? = ??
N= ?? (???????? ) W<N(True)
24. (d); ?? = ?? = ?? < ??
R=W(False) R>W(False)
25. (d); ?? = ?? > ?? < ??
N= ?? (?????????? ) N>J(False)
26. (e); From statement I and II both :
27. (b); From I: P is mother in law of R. or mother of R.
or
From II: P is father of R.
REASONING ABILITY
Page 2
SBI Clerk Mains 2016 (Solutions)
Direction (1-5):
Floor Person Color
8 U Pink
7 Y Grey
6 S Yellow
5 Z Blue
4 T Purple
3 V Orange
2 X Green
1 W Red
1. (c); 2. (d); 3. (a);
4. (a); 5. (c);
Direction (6-10):
6. (e); 7. (b); 8. (c);
9. (c); 10. (c);
Direction (11-15) :
11. (b); Since the first letter is vowel and the last letter is
consonant, so both are to be coded as code of
consonant i.e. of B which is *.
12. (c); Since first and last letters are consonants and in
between there are two vowels, so both the vowels are
to be coded as 8. So the code is7$8882.
13. (e); Explanation:
Converting the letters into symbols the code is,
D K P R T B
% 6 5 2 $ *
14. (d); Explanation:
Since 1st and last letters are vowels, so both are to be
coded as +. So the code is +5#$2+
15. (a); Explanation:
Since 1st letter is a consonant and last is a vowel, so
their codes are to be interchanged. So the code
for HLEKBI is 13@6*9.
Direction (16-20): Will ? ka
Meet ? ja
Us ? lu
You ? hu
Today ? la
temperature ? ju
the ? fu
of ? na
maximum ? fa
16. (b); 17. (a); 18. (b);
19. (b); 20. (c);
Direction (21-25): © ? <
@ ? =
% ? >
$ ? =
? ? =
21. (a); ?? < ?? = ?? > ??
B<M (True) B<F (False)
22. (b); ?? = ?? > ?? = ??
K= ?? (False) K<M(True)
23. (e); ?? < ?? = ?? = ??
N= ?? (???????? ) W<N(True)
24. (d); ?? = ?? = ?? < ??
R=W(False) R>W(False)
25. (d); ?? = ?? > ?? < ??
N= ?? (?????????? ) N>J(False)
26. (e); From statement I and II both :
27. (b); From I: P is mother in law of R. or mother of R.
or
From II: P is father of R.
REASONING ABILITY
28. (d);
29. (a);
30. (b); Total 37 persons sitting in a row.
Direction (31-35):
Boys USPRQT
Girls FEADBC
31. (e); 32. (b); 33. (c);
34. (e); 35. (a);
Direction (36-37):
36. (a)
37. (d); 16+8+0+2+1=27
Direction (38-40):
38. (b);
39. (d);
40. (e);
Direction (41-45):
Input: Kite 19 54 Give 31 Right 72 87 Dream Ace.
Step1: Ace Kite 19 54 Give 31 Right 72 Dream 87.
Step2: Dream Ace Kite 19 54 Give 31 Right 87 72.
Step3: Give Dream Ace Kite 19 31 Right 87 72 54.
Step4: Kite Give Dream Ace 19 Right 87 72 54 31.
Step5: Right Kite Give Dream Ace 87 72 54 31 19.
‘Step-5’ is the final step of this input.
41. (a); 42. (b); 43. (d);
44. (c); 45. (e);
Direction (46-50): Height ? R>Q>S>V>T>P
Weight ? S>P>R>Q>T>V
46. (e); 47. (b); 48. (d);
49. (c); 50. (a);
51. (c); Pattern is —
? ? = 286
52. (b);
? ? = 36.6
53. (b); Pattern is
5 × 1 – 1 = 4
4 × 2 – 2 = 6
6 × 3 – 3 = 15
15 × 4 – 4 = 56
56 × 5 – 5 = 275
54. (d); Pattern is —
? ? = 252
55. (e); Pattern is,
5 × 1 – 2 = 3
3 × 2 – 2 = 4
4 × 3 – 2 = 10
10 × 4 – 2 = 38 ? ? = 10
56. (e); Let speed of stream be x km/hr.
? speed of boat in still water is 3x km/hr
? ATQ,
24
3?? +?? +
24
3?? –?? = 6
24
4?? +
24
2?? = 6 ?
6
?? +
12
?? = 6
?? =
18
6
= 3 ???? h?? /
? Speed of boat in still water = 9 km/hr
57. (d);
QUANTITATIVE APTITUDE
Page 3
SBI Clerk Mains 2016 (Solutions)
Direction (1-5):
Floor Person Color
8 U Pink
7 Y Grey
6 S Yellow
5 Z Blue
4 T Purple
3 V Orange
2 X Green
1 W Red
1. (c); 2. (d); 3. (a);
4. (a); 5. (c);
Direction (6-10):
6. (e); 7. (b); 8. (c);
9. (c); 10. (c);
Direction (11-15) :
11. (b); Since the first letter is vowel and the last letter is
consonant, so both are to be coded as code of
consonant i.e. of B which is *.
12. (c); Since first and last letters are consonants and in
between there are two vowels, so both the vowels are
to be coded as 8. So the code is7$8882.
13. (e); Explanation:
Converting the letters into symbols the code is,
D K P R T B
% 6 5 2 $ *
14. (d); Explanation:
Since 1st and last letters are vowels, so both are to be
coded as +. So the code is +5#$2+
15. (a); Explanation:
Since 1st letter is a consonant and last is a vowel, so
their codes are to be interchanged. So the code
for HLEKBI is 13@6*9.
Direction (16-20): Will ? ka
Meet ? ja
Us ? lu
You ? hu
Today ? la
temperature ? ju
the ? fu
of ? na
maximum ? fa
16. (b); 17. (a); 18. (b);
19. (b); 20. (c);
Direction (21-25): © ? <
@ ? =
% ? >
$ ? =
? ? =
21. (a); ?? < ?? = ?? > ??
B<M (True) B<F (False)
22. (b); ?? = ?? > ?? = ??
K= ?? (False) K<M(True)
23. (e); ?? < ?? = ?? = ??
N= ?? (???????? ) W<N(True)
24. (d); ?? = ?? = ?? < ??
R=W(False) R>W(False)
25. (d); ?? = ?? > ?? < ??
N= ?? (?????????? ) N>J(False)
26. (e); From statement I and II both :
27. (b); From I: P is mother in law of R. or mother of R.
or
From II: P is father of R.
REASONING ABILITY
28. (d);
29. (a);
30. (b); Total 37 persons sitting in a row.
Direction (31-35):
Boys USPRQT
Girls FEADBC
31. (e); 32. (b); 33. (c);
34. (e); 35. (a);
Direction (36-37):
36. (a)
37. (d); 16+8+0+2+1=27
Direction (38-40):
38. (b);
39. (d);
40. (e);
Direction (41-45):
Input: Kite 19 54 Give 31 Right 72 87 Dream Ace.
Step1: Ace Kite 19 54 Give 31 Right 72 Dream 87.
Step2: Dream Ace Kite 19 54 Give 31 Right 87 72.
Step3: Give Dream Ace Kite 19 31 Right 87 72 54.
Step4: Kite Give Dream Ace 19 Right 87 72 54 31.
Step5: Right Kite Give Dream Ace 87 72 54 31 19.
‘Step-5’ is the final step of this input.
41. (a); 42. (b); 43. (d);
44. (c); 45. (e);
Direction (46-50): Height ? R>Q>S>V>T>P
Weight ? S>P>R>Q>T>V
46. (e); 47. (b); 48. (d);
49. (c); 50. (a);
51. (c); Pattern is —
? ? = 286
52. (b);
? ? = 36.6
53. (b); Pattern is
5 × 1 – 1 = 4
4 × 2 – 2 = 6
6 × 3 – 3 = 15
15 × 4 – 4 = 56
56 × 5 – 5 = 275
54. (d); Pattern is —
? ? = 252
55. (e); Pattern is,
5 × 1 – 2 = 3
3 × 2 – 2 = 4
4 × 3 – 2 = 10
10 × 4 – 2 = 38 ? ? = 10
56. (e); Let speed of stream be x km/hr.
? speed of boat in still water is 3x km/hr
? ATQ,
24
3?? +?? +
24
3?? –?? = 6
24
4?? +
24
2?? = 6 ?
6
?? +
12
?? = 6
?? =
18
6
= 3 ???? h?? /
? Speed of boat in still water = 9 km/hr
57. (d);
QUANTITATIVE APTITUDE
? ???????????????? ???????? = [112× 78 – 107 × 73] × 2
= ???? . 1850
58. (b); Length of BD by pythagores theorem
???? = v8
2
+ 6
2
= v64 + 36 = 10
? Length of BC
= v(24)
2
+ (10)
2
= v576 + 100
= v676
= 26
59. (a); Let radius of circle be r meter
? 2pr = 44
2 ×
22
7
× ?? = 44
r = 7cm
? BC = 14 m
? AB = AC = 7 v2 m
? Area of ?ABC
=
1
2
× 7v2 × 7v2 = 49 ?? 2
60. (a); Radius of bigger semicircle = 14
& radius of smaller semicircle = 7
? Required area
=
1
2
[?? (14)
2
– 2 × ?? (7)
2
]
=
1
2
[196?? – 98?? ] =
1
2
× 98?? = 154
61. (a); There are four cases ? 3R, (1R, 2G), (2R, 1G), 3G
? Required probability
=
?? 3
4
+ ?? 1
4
× ?? 2
6
+ ?? 2
4
× ?? 1
6
+ ?? 3
6
?? 3
15
=
4+4×15+6×6+20
91×5
=
4+60+36+20
91×5
=
120
91×5
=
24
91
62. (a); 4x + 7y = 42 …(i)
3x – 11y = – 1 …(ii)
Multiplying (i) by 3 and (ii) by 4
12x + 21y = 126 …(iii)
12x – 44y = – 4 …(iv)
Solving (iii) & (iv)
x = 7 & y = 2
? x > y
63. (c); I. 9x² – 29x + 22 = 0
9x² – 18x – 11x + 22 = 0
9x (x – 2) – 11 (x – 2) = 0
? ?? = 2 ????
11
9
II. y² –7y + 12 = 0
y² – 3y – 4y + 12 = 0
y (y – 3) – 4 (y – 3) = 0
y = 3, 4
? y > x
64. (d); I. 3x² – 12x + 8x – 32 = 0
3x (x – 4) + 8 (x – 4) = 0
? ?? = 4,
–8
3
II. 2y² – 17y + 36 = 0
2y² – 9y – 8y + 36 = 0
y (2y – 9) – 4 (2y – 9) = 0
? ?? = 4,
9
2
? y = x
65. (a); I. 3x² – 19x – 14 = 0
3x² – 21x + 2x – 14 = 0
3x (x – 7) + 2 (x – 7) = 0
? ?? = 7 ????
–2
3
II. 2y² + 5y + 3 = 0
2y² +2y + 3y + 3 = 0
2y (y + 1) + 3 (y + 1) = 0
?? = – 1 ????
–3
2
? x > y
66. (e); I. x² + 2 × 7 × x + (7)² = 0
? (x + 7)² = 0
? x = – 7
II. y (y + 9) = 0
? y = 0 or –9
? No relation.
67. (e); Average salary =
1000×43000
1600
= 26875
68. (b); Number of employees in :
PNB = 1600
OBC = 1700
SBI = 2100
69. (e); Required ratio = 15000×600 : 35000 × 900
= 2 : 7
70. (e); Required percentage =
400
600
× 100
= 66
2
3
%
71. (b); Required percentage =
20000×900
25000×800
× 100 = 90%
72. (b); Required No. =
280+354+343+535+433
5
= 389
73. (d); Required difference = (235 + 567 ) - 134 = 668
74. (e); Required % =
320+346+436
255+343+545+546+453
× 100
=
1102
2142
× 100 ˜ 51%
75. (d); Required animals
=
65
100
× (411 + 535+ 534 ) = 962
76. (c); Required No. of lions =
3
4
(135 + 325+ 345+ 267 )
= 804
77. (c); Let their salaries be 100, 300 and 400
Their new salaries = 105 : 330 : 460
= 21 : 66 : 92
Page 4
SBI Clerk Mains 2016 (Solutions)
Direction (1-5):
Floor Person Color
8 U Pink
7 Y Grey
6 S Yellow
5 Z Blue
4 T Purple
3 V Orange
2 X Green
1 W Red
1. (c); 2. (d); 3. (a);
4. (a); 5. (c);
Direction (6-10):
6. (e); 7. (b); 8. (c);
9. (c); 10. (c);
Direction (11-15) :
11. (b); Since the first letter is vowel and the last letter is
consonant, so both are to be coded as code of
consonant i.e. of B which is *.
12. (c); Since first and last letters are consonants and in
between there are two vowels, so both the vowels are
to be coded as 8. So the code is7$8882.
13. (e); Explanation:
Converting the letters into symbols the code is,
D K P R T B
% 6 5 2 $ *
14. (d); Explanation:
Since 1st and last letters are vowels, so both are to be
coded as +. So the code is +5#$2+
15. (a); Explanation:
Since 1st letter is a consonant and last is a vowel, so
their codes are to be interchanged. So the code
for HLEKBI is 13@6*9.
Direction (16-20): Will ? ka
Meet ? ja
Us ? lu
You ? hu
Today ? la
temperature ? ju
the ? fu
of ? na
maximum ? fa
16. (b); 17. (a); 18. (b);
19. (b); 20. (c);
Direction (21-25): © ? <
@ ? =
% ? >
$ ? =
? ? =
21. (a); ?? < ?? = ?? > ??
B<M (True) B<F (False)
22. (b); ?? = ?? > ?? = ??
K= ?? (False) K<M(True)
23. (e); ?? < ?? = ?? = ??
N= ?? (???????? ) W<N(True)
24. (d); ?? = ?? = ?? < ??
R=W(False) R>W(False)
25. (d); ?? = ?? > ?? < ??
N= ?? (?????????? ) N>J(False)
26. (e); From statement I and II both :
27. (b); From I: P is mother in law of R. or mother of R.
or
From II: P is father of R.
REASONING ABILITY
28. (d);
29. (a);
30. (b); Total 37 persons sitting in a row.
Direction (31-35):
Boys USPRQT
Girls FEADBC
31. (e); 32. (b); 33. (c);
34. (e); 35. (a);
Direction (36-37):
36. (a)
37. (d); 16+8+0+2+1=27
Direction (38-40):
38. (b);
39. (d);
40. (e);
Direction (41-45):
Input: Kite 19 54 Give 31 Right 72 87 Dream Ace.
Step1: Ace Kite 19 54 Give 31 Right 72 Dream 87.
Step2: Dream Ace Kite 19 54 Give 31 Right 87 72.
Step3: Give Dream Ace Kite 19 31 Right 87 72 54.
Step4: Kite Give Dream Ace 19 Right 87 72 54 31.
Step5: Right Kite Give Dream Ace 87 72 54 31 19.
‘Step-5’ is the final step of this input.
41. (a); 42. (b); 43. (d);
44. (c); 45. (e);
Direction (46-50): Height ? R>Q>S>V>T>P
Weight ? S>P>R>Q>T>V
46. (e); 47. (b); 48. (d);
49. (c); 50. (a);
51. (c); Pattern is —
? ? = 286
52. (b);
? ? = 36.6
53. (b); Pattern is
5 × 1 – 1 = 4
4 × 2 – 2 = 6
6 × 3 – 3 = 15
15 × 4 – 4 = 56
56 × 5 – 5 = 275
54. (d); Pattern is —
? ? = 252
55. (e); Pattern is,
5 × 1 – 2 = 3
3 × 2 – 2 = 4
4 × 3 – 2 = 10
10 × 4 – 2 = 38 ? ? = 10
56. (e); Let speed of stream be x km/hr.
? speed of boat in still water is 3x km/hr
? ATQ,
24
3?? +?? +
24
3?? –?? = 6
24
4?? +
24
2?? = 6 ?
6
?? +
12
?? = 6
?? =
18
6
= 3 ???? h?? /
? Speed of boat in still water = 9 km/hr
57. (d);
QUANTITATIVE APTITUDE
? ???????????????? ???????? = [112× 78 – 107 × 73] × 2
= ???? . 1850
58. (b); Length of BD by pythagores theorem
???? = v8
2
+ 6
2
= v64 + 36 = 10
? Length of BC
= v(24)
2
+ (10)
2
= v576 + 100
= v676
= 26
59. (a); Let radius of circle be r meter
? 2pr = 44
2 ×
22
7
× ?? = 44
r = 7cm
? BC = 14 m
? AB = AC = 7 v2 m
? Area of ?ABC
=
1
2
× 7v2 × 7v2 = 49 ?? 2
60. (a); Radius of bigger semicircle = 14
& radius of smaller semicircle = 7
? Required area
=
1
2
[?? (14)
2
– 2 × ?? (7)
2
]
=
1
2
[196?? – 98?? ] =
1
2
× 98?? = 154
61. (a); There are four cases ? 3R, (1R, 2G), (2R, 1G), 3G
? Required probability
=
?? 3
4
+ ?? 1
4
× ?? 2
6
+ ?? 2
4
× ?? 1
6
+ ?? 3
6
?? 3
15
=
4+4×15+6×6+20
91×5
=
4+60+36+20
91×5
=
120
91×5
=
24
91
62. (a); 4x + 7y = 42 …(i)
3x – 11y = – 1 …(ii)
Multiplying (i) by 3 and (ii) by 4
12x + 21y = 126 …(iii)
12x – 44y = – 4 …(iv)
Solving (iii) & (iv)
x = 7 & y = 2
? x > y
63. (c); I. 9x² – 29x + 22 = 0
9x² – 18x – 11x + 22 = 0
9x (x – 2) – 11 (x – 2) = 0
? ?? = 2 ????
11
9
II. y² –7y + 12 = 0
y² – 3y – 4y + 12 = 0
y (y – 3) – 4 (y – 3) = 0
y = 3, 4
? y > x
64. (d); I. 3x² – 12x + 8x – 32 = 0
3x (x – 4) + 8 (x – 4) = 0
? ?? = 4,
–8
3
II. 2y² – 17y + 36 = 0
2y² – 9y – 8y + 36 = 0
y (2y – 9) – 4 (2y – 9) = 0
? ?? = 4,
9
2
? y = x
65. (a); I. 3x² – 19x – 14 = 0
3x² – 21x + 2x – 14 = 0
3x (x – 7) + 2 (x – 7) = 0
? ?? = 7 ????
–2
3
II. 2y² + 5y + 3 = 0
2y² +2y + 3y + 3 = 0
2y (y + 1) + 3 (y + 1) = 0
?? = – 1 ????
–3
2
? x > y
66. (e); I. x² + 2 × 7 × x + (7)² = 0
? (x + 7)² = 0
? x = – 7
II. y (y + 9) = 0
? y = 0 or –9
? No relation.
67. (e); Average salary =
1000×43000
1600
= 26875
68. (b); Number of employees in :
PNB = 1600
OBC = 1700
SBI = 2100
69. (e); Required ratio = 15000×600 : 35000 × 900
= 2 : 7
70. (e); Required percentage =
400
600
× 100
= 66
2
3
%
71. (b); Required percentage =
20000×900
25000×800
× 100 = 90%
72. (b); Required No. =
280+354+343+535+433
5
= 389
73. (d); Required difference = (235 + 567 ) - 134 = 668
74. (e); Required % =
320+346+436
255+343+545+546+453
× 100
=
1102
2142
× 100 ˜ 51%
75. (d); Required animals
=
65
100
× (411 + 535+ 534 ) = 962
76. (c); Required No. of lions =
3
4
(135 + 325+ 345+ 267 )
= 804
77. (c); Let their salaries be 100, 300 and 400
Their new salaries = 105 : 330 : 460
= 21 : 66 : 92
78. (b); Work done by the third pipe in 1 min.
= (1/50) – [(1/60) + (1/75)] = [(1/50) (3/100)]
= (1/100)
?The third pipe can alone fill the tank in 100 minutes.
79. (e); Both the statements together is not sufficient.
80. (d); Both statements alone is sufficient.
Let age of A is x and age of B is y.
? 3x = y ... (i)
From statement I:
10 3
10 7
x
y
+
=
+
... (ii)
Solving equations (i) and (ii), x = 20, y = 60
From statement II:
=
10 1
10 5
x
y
-
=
-
=>5x – 50 = y – 10
=>5x – y = 40 (iii)
From equations (i) and (iii), x = 20, y = 60
81. (c); Let length the train be x.
From statement I:
Speed =
8
x
From statement II:
Speed =
50
20
x +
Solving this, x =
400
12
=
100
3
meter
82. (e); From I and II we find a + b = 2z
we can not find a + b from I and II together.
83. (e); Let age of A, B and C be x year, y year and z year
respectively
Data is not sufficient.
From statement I:
x =
80
100
z ?
From statement II:
y =
60
100
z ?
From these two equations
4
3
x
y
= but cannot find x
and y separately.
84. (d); Let the present age of Ranjana and Rakhi be 15x and
17x
15?? + 6
17?? + 6
=
9
10
x = 2
? Age of Ranjana after 6 years
= 15 × 2 + 6 =36 years.
85. (b); S.I. =7200
R=
?? .?? ×100
?? ×?? =
7200×100
20,000×3
= 12%
C.I = 20000[(1+
12
100
)
3
- 1]
= 8098.56
86. (a); Here volume of water emptied by the second pipe
will be 4 times to that of first Hence, Time take will be
1/4 of the first pipe. When both the pipes are open
the part of the tank emptied in 1 minute= 1/8 Hence
the tank will be emptied in 8 minutes.
87. (b); Total CP = 2000 + 750 = 2750
Total ???? =
120
100
× 2000+
95
100
× 750
= 2400 + 712.5
= 3112.5
? Total gain = 3112.5 – 2750 = 362.5 Rs.
88. (a); Let Man = ??
Woman = 2??
?
8
?? +
4
2?? =
1
6
20
2?? =
1
6
?? = 60
? Man = 60, woman = 120
Required No. of days =
2
3
4
60
+
8
120
=
2×120
3(16)
= 5 days
89. (c); Let their investment be ?? , 2?? and 4??
? A ? 6?? + 6 × (?? +
?? 2
) = 6?? + 9?? = 15??
?? ? 6 × 2?? + 6 × 4?? = 36??
?? ? 6 × 4?? + 6 × (4?? -
1
4
× 4?? ) = 24?? + 18?? =
42 ??
? Required Ratio = 15 : 36 : 42
= 5 : 12 : 14
90. (b); Number of questions attempted correctly =
70% of 10 + 50% of 30 + 60% of 45
= 7 + 15 + 27 = 49
Passing grade = (60/100 )* 85 = 51
Reqd. Ans = 51 - 49 = 2
91. (c); Age of new man = 28 + 28 = 56 years
92. (b); 11% ? 5236
1% ? 476
? (11 + 19 + 7) = 37% ? 17612 Rs.
93. (c); Probability =
2?? 1
×3?? 2
+2?? 2
×3?? 1
5?? 3
=
2×3+1×3
10
=
9
10
94. (d); ?? =
1
1
12
-
1
20
=
1
5-3
60
B = 30 days
? Required No. of days =
1
1
20
+
1
60
=
60
4
= 15 days
Page 5
SBI Clerk Mains 2016 (Solutions)
Direction (1-5):
Floor Person Color
8 U Pink
7 Y Grey
6 S Yellow
5 Z Blue
4 T Purple
3 V Orange
2 X Green
1 W Red
1. (c); 2. (d); 3. (a);
4. (a); 5. (c);
Direction (6-10):
6. (e); 7. (b); 8. (c);
9. (c); 10. (c);
Direction (11-15) :
11. (b); Since the first letter is vowel and the last letter is
consonant, so both are to be coded as code of
consonant i.e. of B which is *.
12. (c); Since first and last letters are consonants and in
between there are two vowels, so both the vowels are
to be coded as 8. So the code is7$8882.
13. (e); Explanation:
Converting the letters into symbols the code is,
D K P R T B
% 6 5 2 $ *
14. (d); Explanation:
Since 1st and last letters are vowels, so both are to be
coded as +. So the code is +5#$2+
15. (a); Explanation:
Since 1st letter is a consonant and last is a vowel, so
their codes are to be interchanged. So the code
for HLEKBI is 13@6*9.
Direction (16-20): Will ? ka
Meet ? ja
Us ? lu
You ? hu
Today ? la
temperature ? ju
the ? fu
of ? na
maximum ? fa
16. (b); 17. (a); 18. (b);
19. (b); 20. (c);
Direction (21-25): © ? <
@ ? =
% ? >
$ ? =
? ? =
21. (a); ?? < ?? = ?? > ??
B<M (True) B<F (False)
22. (b); ?? = ?? > ?? = ??
K= ?? (False) K<M(True)
23. (e); ?? < ?? = ?? = ??
N= ?? (???????? ) W<N(True)
24. (d); ?? = ?? = ?? < ??
R=W(False) R>W(False)
25. (d); ?? = ?? > ?? < ??
N= ?? (?????????? ) N>J(False)
26. (e); From statement I and II both :
27. (b); From I: P is mother in law of R. or mother of R.
or
From II: P is father of R.
REASONING ABILITY
28. (d);
29. (a);
30. (b); Total 37 persons sitting in a row.
Direction (31-35):
Boys USPRQT
Girls FEADBC
31. (e); 32. (b); 33. (c);
34. (e); 35. (a);
Direction (36-37):
36. (a)
37. (d); 16+8+0+2+1=27
Direction (38-40):
38. (b);
39. (d);
40. (e);
Direction (41-45):
Input: Kite 19 54 Give 31 Right 72 87 Dream Ace.
Step1: Ace Kite 19 54 Give 31 Right 72 Dream 87.
Step2: Dream Ace Kite 19 54 Give 31 Right 87 72.
Step3: Give Dream Ace Kite 19 31 Right 87 72 54.
Step4: Kite Give Dream Ace 19 Right 87 72 54 31.
Step5: Right Kite Give Dream Ace 87 72 54 31 19.
‘Step-5’ is the final step of this input.
41. (a); 42. (b); 43. (d);
44. (c); 45. (e);
Direction (46-50): Height ? R>Q>S>V>T>P
Weight ? S>P>R>Q>T>V
46. (e); 47. (b); 48. (d);
49. (c); 50. (a);
51. (c); Pattern is —
? ? = 286
52. (b);
? ? = 36.6
53. (b); Pattern is
5 × 1 – 1 = 4
4 × 2 – 2 = 6
6 × 3 – 3 = 15
15 × 4 – 4 = 56
56 × 5 – 5 = 275
54. (d); Pattern is —
? ? = 252
55. (e); Pattern is,
5 × 1 – 2 = 3
3 × 2 – 2 = 4
4 × 3 – 2 = 10
10 × 4 – 2 = 38 ? ? = 10
56. (e); Let speed of stream be x km/hr.
? speed of boat in still water is 3x km/hr
? ATQ,
24
3?? +?? +
24
3?? –?? = 6
24
4?? +
24
2?? = 6 ?
6
?? +
12
?? = 6
?? =
18
6
= 3 ???? h?? /
? Speed of boat in still water = 9 km/hr
57. (d);
QUANTITATIVE APTITUDE
? ???????????????? ???????? = [112× 78 – 107 × 73] × 2
= ???? . 1850
58. (b); Length of BD by pythagores theorem
???? = v8
2
+ 6
2
= v64 + 36 = 10
? Length of BC
= v(24)
2
+ (10)
2
= v576 + 100
= v676
= 26
59. (a); Let radius of circle be r meter
? 2pr = 44
2 ×
22
7
× ?? = 44
r = 7cm
? BC = 14 m
? AB = AC = 7 v2 m
? Area of ?ABC
=
1
2
× 7v2 × 7v2 = 49 ?? 2
60. (a); Radius of bigger semicircle = 14
& radius of smaller semicircle = 7
? Required area
=
1
2
[?? (14)
2
– 2 × ?? (7)
2
]
=
1
2
[196?? – 98?? ] =
1
2
× 98?? = 154
61. (a); There are four cases ? 3R, (1R, 2G), (2R, 1G), 3G
? Required probability
=
?? 3
4
+ ?? 1
4
× ?? 2
6
+ ?? 2
4
× ?? 1
6
+ ?? 3
6
?? 3
15
=
4+4×15+6×6+20
91×5
=
4+60+36+20
91×5
=
120
91×5
=
24
91
62. (a); 4x + 7y = 42 …(i)
3x – 11y = – 1 …(ii)
Multiplying (i) by 3 and (ii) by 4
12x + 21y = 126 …(iii)
12x – 44y = – 4 …(iv)
Solving (iii) & (iv)
x = 7 & y = 2
? x > y
63. (c); I. 9x² – 29x + 22 = 0
9x² – 18x – 11x + 22 = 0
9x (x – 2) – 11 (x – 2) = 0
? ?? = 2 ????
11
9
II. y² –7y + 12 = 0
y² – 3y – 4y + 12 = 0
y (y – 3) – 4 (y – 3) = 0
y = 3, 4
? y > x
64. (d); I. 3x² – 12x + 8x – 32 = 0
3x (x – 4) + 8 (x – 4) = 0
? ?? = 4,
–8
3
II. 2y² – 17y + 36 = 0
2y² – 9y – 8y + 36 = 0
y (2y – 9) – 4 (2y – 9) = 0
? ?? = 4,
9
2
? y = x
65. (a); I. 3x² – 19x – 14 = 0
3x² – 21x + 2x – 14 = 0
3x (x – 7) + 2 (x – 7) = 0
? ?? = 7 ????
–2
3
II. 2y² + 5y + 3 = 0
2y² +2y + 3y + 3 = 0
2y (y + 1) + 3 (y + 1) = 0
?? = – 1 ????
–3
2
? x > y
66. (e); I. x² + 2 × 7 × x + (7)² = 0
? (x + 7)² = 0
? x = – 7
II. y (y + 9) = 0
? y = 0 or –9
? No relation.
67. (e); Average salary =
1000×43000
1600
= 26875
68. (b); Number of employees in :
PNB = 1600
OBC = 1700
SBI = 2100
69. (e); Required ratio = 15000×600 : 35000 × 900
= 2 : 7
70. (e); Required percentage =
400
600
× 100
= 66
2
3
%
71. (b); Required percentage =
20000×900
25000×800
× 100 = 90%
72. (b); Required No. =
280+354+343+535+433
5
= 389
73. (d); Required difference = (235 + 567 ) - 134 = 668
74. (e); Required % =
320+346+436
255+343+545+546+453
× 100
=
1102
2142
× 100 ˜ 51%
75. (d); Required animals
=
65
100
× (411 + 535+ 534 ) = 962
76. (c); Required No. of lions =
3
4
(135 + 325+ 345+ 267 )
= 804
77. (c); Let their salaries be 100, 300 and 400
Their new salaries = 105 : 330 : 460
= 21 : 66 : 92
78. (b); Work done by the third pipe in 1 min.
= (1/50) – [(1/60) + (1/75)] = [(1/50) (3/100)]
= (1/100)
?The third pipe can alone fill the tank in 100 minutes.
79. (e); Both the statements together is not sufficient.
80. (d); Both statements alone is sufficient.
Let age of A is x and age of B is y.
? 3x = y ... (i)
From statement I:
10 3
10 7
x
y
+
=
+
... (ii)
Solving equations (i) and (ii), x = 20, y = 60
From statement II:
=
10 1
10 5
x
y
-
=
-
=>5x – 50 = y – 10
=>5x – y = 40 (iii)
From equations (i) and (iii), x = 20, y = 60
81. (c); Let length the train be x.
From statement I:
Speed =
8
x
From statement II:
Speed =
50
20
x +
Solving this, x =
400
12
=
100
3
meter
82. (e); From I and II we find a + b = 2z
we can not find a + b from I and II together.
83. (e); Let age of A, B and C be x year, y year and z year
respectively
Data is not sufficient.
From statement I:
x =
80
100
z ?
From statement II:
y =
60
100
z ?
From these two equations
4
3
x
y
= but cannot find x
and y separately.
84. (d); Let the present age of Ranjana and Rakhi be 15x and
17x
15?? + 6
17?? + 6
=
9
10
x = 2
? Age of Ranjana after 6 years
= 15 × 2 + 6 =36 years.
85. (b); S.I. =7200
R=
?? .?? ×100
?? ×?? =
7200×100
20,000×3
= 12%
C.I = 20000[(1+
12
100
)
3
- 1]
= 8098.56
86. (a); Here volume of water emptied by the second pipe
will be 4 times to that of first Hence, Time take will be
1/4 of the first pipe. When both the pipes are open
the part of the tank emptied in 1 minute= 1/8 Hence
the tank will be emptied in 8 minutes.
87. (b); Total CP = 2000 + 750 = 2750
Total ???? =
120
100
× 2000+
95
100
× 750
= 2400 + 712.5
= 3112.5
? Total gain = 3112.5 – 2750 = 362.5 Rs.
88. (a); Let Man = ??
Woman = 2??
?
8
?? +
4
2?? =
1
6
20
2?? =
1
6
?? = 60
? Man = 60, woman = 120
Required No. of days =
2
3
4
60
+
8
120
=
2×120
3(16)
= 5 days
89. (c); Let their investment be ?? , 2?? and 4??
? A ? 6?? + 6 × (?? +
?? 2
) = 6?? + 9?? = 15??
?? ? 6 × 2?? + 6 × 4?? = 36??
?? ? 6 × 4?? + 6 × (4?? -
1
4
× 4?? ) = 24?? + 18?? =
42 ??
? Required Ratio = 15 : 36 : 42
= 5 : 12 : 14
90. (b); Number of questions attempted correctly =
70% of 10 + 50% of 30 + 60% of 45
= 7 + 15 + 27 = 49
Passing grade = (60/100 )* 85 = 51
Reqd. Ans = 51 - 49 = 2
91. (c); Age of new man = 28 + 28 = 56 years
92. (b); 11% ? 5236
1% ? 476
? (11 + 19 + 7) = 37% ? 17612 Rs.
93. (c); Probability =
2?? 1
×3?? 2
+2?? 2
×3?? 1
5?? 3
=
2×3+1×3
10
=
9
10
94. (d); ?? =
1
1
12
-
1
20
=
1
5-3
60
B = 30 days
? Required No. of days =
1
1
20
+
1
60
=
60
4
= 15 days
95. (b);
132×5
18
=
100+165
??
?? =
275×18
132×5
?? = 7.5 seconds
96. (b);
3?? 12?? +3
=
3?? 15??
? New ratio = 1 : 5
? Required % =
1
6
× 100%
=
50
3
% = 16
2
3
%
97. (d);
Let B turned off after T min
2T+3× 20 = 90
T=15 min
98. (a); (2?? + 3?? )10 = (3?? + 2?? )??
20?? + 30?? = 24?? + 16??
2?? = 7??
? 10?? = 10 days
? ?? =
1
100
days
? 2?? + 1?? = 7?? + ??
= 8??
=
8
100
=
2
25
? Required No. of days = 12
1
2
days
99. (a); Ratio of their speeds = v
28
5
: v
20
7
? v
28
5
? 14
? v
20
7
?
14
v28
× v5 ×
v20
v7
=
14
2v7
× v5 ×
2v5
v7
=
14×5
7
= 10 kmph
100. (a); Area = 2?? 2
m
2
? 2?? 2
× 2 = 256
?? 2
= 64
?? = 8
? Required length = 2 × 8 = 16 m
101. (c); 102. (e); 103. (c);
104. (c); 105. (b); 106. (b);
107. (d); 108. (e); 109. (e);
110. (d); 111. (e); 112. (d);
113. (e); 114. (e); 115. (e);
116. (c);
117. (c); ’Earn a decent living’ is the only suitable syntax to be
used. It means ‘to earn well’ that fulfils the sentence’s
context.
118. (c); After ‘to’ we should use ‘V1’ to show purpose.
119. (c); ‘Disowning’ is the improper usage. We have to use
‘disown’ here so that syntax gets correct
120. (b); ‘Art’ is singular subject, so it should agree with a
singular verb. Hence, ‘requires’ is suitable
expression.
121. (a); To express the subjunctive mood. Auxiliary ‘were’ is
used in the sentence.
122. (c); Accost means to approach someone with an
allegation or blame, so 3rd option is the most
appropriate one.
123. (c); Harmful-not good for health, so 3
rd
option is most
appropriate one
124. (b); downturns means- a decline in economic, knell
means -the sound of a bell
125. (c); survived means- continue to live or exist, unscathed
means- without suffering any injury, damage, or
harm.
126. (b); downturn, out “dole out” is the correct phrase which
means to help someone with money and gifts.
127. (d); 128. (a); 129. (c);
130. (a); 131. (e); 132. (c);
133. (d); 134. (b); 135. (e);
136. (b); For questions (136-140) THE CORRECT SEQUENCE
IS ECADBFG
137. (c); 138. (e); 139. (c);
140. (e);
ENGLISH LANGUAGE
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