Page 1 CBSE VII | Mathematics Sample Paper 1 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 1 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A According to the distributive property of integers, we have a ? (b + c) = a ? b + a ? c 2. Correct answer: B A number is chosen from numbers 1 to 5. Odd numbers are 1, 3, 5. Required probability = number of ways to choose an odd number /total number of numbers = 3/5 3. Correct answer: A 3x + 4 = 25 Transposing 4 to R.H.S, we get 3x = 25 - 4 3x = 21 Dividing both sides by 3, we get x = 7 4. Correct answer: D Since, the angle measuring 150 o and y are corresponding angles. Therefore, y = 150 o . (As the lines are parallel, corresponding angles are equal) 5. Correct answer: D We know that the measure of an exterior angle of a triangle is equal to the sum of its two opposite interior angles. So, x + 90 o = 125 o Therefore, x = 35 o 6. Correct answer: B Negative of a negative integer is a positive integer. So, - (-5) = +5 So, -2 - (-5) = -2 + 5 Page 2 CBSE VII | Mathematics Sample Paper 1 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 1 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A According to the distributive property of integers, we have a ? (b + c) = a ? b + a ? c 2. Correct answer: B A number is chosen from numbers 1 to 5. Odd numbers are 1, 3, 5. Required probability = number of ways to choose an odd number /total number of numbers = 3/5 3. Correct answer: A 3x + 4 = 25 Transposing 4 to R.H.S, we get 3x = 25 - 4 3x = 21 Dividing both sides by 3, we get x = 7 4. Correct answer: D Since, the angle measuring 150 o and y are corresponding angles. Therefore, y = 150 o . (As the lines are parallel, corresponding angles are equal) 5. Correct answer: D We know that the measure of an exterior angle of a triangle is equal to the sum of its two opposite interior angles. So, x + 90 o = 125 o Therefore, x = 35 o 6. Correct answer: B Negative of a negative integer is a positive integer. So, - (-5) = +5 So, -2 - (-5) = -2 + 5 CBSE VII | Mathematics Sample Paper 1 - Solution 7. Correct answer: C Since, the measure of an exterior angle of a triangle is equal to the sum of measures of its two opposite interior angles. 8. Correct answer: C The given observations are 11, 10, 12, 12, 9, 10, 14, 12, 9. 9. Correct answer: A 10. Correct answer: C Angle x is alternate angle to angle 30 o . And, since alternate interior angles are equal, x = 30 o . 11. Correct answer: C Since, given triangle is a right angled triangle, we have x 2 = 3 2 + 4 2 = 9 + 16 = 25 = 5 2 Therefore, x = 5 cm 12. Correct answer: B Given, AB = RQ, AC = RP, ?BAC = ?QRP Hence, ?ABC ? ?RQP Page 3 CBSE VII | Mathematics Sample Paper 1 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 1 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A According to the distributive property of integers, we have a ? (b + c) = a ? b + a ? c 2. Correct answer: B A number is chosen from numbers 1 to 5. Odd numbers are 1, 3, 5. Required probability = number of ways to choose an odd number /total number of numbers = 3/5 3. Correct answer: A 3x + 4 = 25 Transposing 4 to R.H.S, we get 3x = 25 - 4 3x = 21 Dividing both sides by 3, we get x = 7 4. Correct answer: D Since, the angle measuring 150 o and y are corresponding angles. Therefore, y = 150 o . (As the lines are parallel, corresponding angles are equal) 5. Correct answer: D We know that the measure of an exterior angle of a triangle is equal to the sum of its two opposite interior angles. So, x + 90 o = 125 o Therefore, x = 35 o 6. Correct answer: B Negative of a negative integer is a positive integer. So, - (-5) = +5 So, -2 - (-5) = -2 + 5 CBSE VII | Mathematics Sample Paper 1 - Solution 7. Correct answer: C Since, the measure of an exterior angle of a triangle is equal to the sum of measures of its two opposite interior angles. 8. Correct answer: C The given observations are 11, 10, 12, 12, 9, 10, 14, 12, 9. 9. Correct answer: A 10. Correct answer: C Angle x is alternate angle to angle 30 o . And, since alternate interior angles are equal, x = 30 o . 11. Correct answer: C Since, given triangle is a right angled triangle, we have x 2 = 3 2 + 4 2 = 9 + 16 = 25 = 5 2 Therefore, x = 5 cm 12. Correct answer: B Given, AB = RQ, AC = RP, ?BAC = ?QRP Hence, ?ABC ? ?RQP CBSE VII | Mathematics Sample Paper 1 - Solution Section B 13. To find the complement of each of the given angle, we have to subtract them from 90 o , since the sum of two complementary angles is 90 o . (a) Complementary angle of 45 o = 90 o - 45 o = 45 o (b) Complementary angle of 54 o = 90 o - 54 o = 36 o (c) Complementary angle of 65 o = 90 o - 65 o = 25 o 14. (a) 6n + 4 = 10 Statement: For 6n, Six times of a number n For 6n + 4, Six times of a number n added to 4 Thus, for 6n + 4 = 10, the final statement is "Six times of a number n added to 4 gives 10". (b) y 7 - 3 = 9 Statement: For y 7 , one-seventh of a number y For y 7 - 3, 3 subtracted from one-seventh of a number y Thus, for y 7 - 3 = 9, the final statement is "3 subtracted from one-seventh of a number y gives 9". 15. part of the exercise is solved by Raju. When is converted into lowest form, we get which is same as part of exercise solved by Sameer. Thus, both have solved same part of the exercise. Page 4 CBSE VII | Mathematics Sample Paper 1 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 1 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A According to the distributive property of integers, we have a ? (b + c) = a ? b + a ? c 2. Correct answer: B A number is chosen from numbers 1 to 5. Odd numbers are 1, 3, 5. Required probability = number of ways to choose an odd number /total number of numbers = 3/5 3. Correct answer: A 3x + 4 = 25 Transposing 4 to R.H.S, we get 3x = 25 - 4 3x = 21 Dividing both sides by 3, we get x = 7 4. Correct answer: D Since, the angle measuring 150 o and y are corresponding angles. Therefore, y = 150 o . (As the lines are parallel, corresponding angles are equal) 5. Correct answer: D We know that the measure of an exterior angle of a triangle is equal to the sum of its two opposite interior angles. So, x + 90 o = 125 o Therefore, x = 35 o 6. Correct answer: B Negative of a negative integer is a positive integer. So, - (-5) = +5 So, -2 - (-5) = -2 + 5 CBSE VII | Mathematics Sample Paper 1 - Solution 7. Correct answer: C Since, the measure of an exterior angle of a triangle is equal to the sum of measures of its two opposite interior angles. 8. Correct answer: C The given observations are 11, 10, 12, 12, 9, 10, 14, 12, 9. 9. Correct answer: A 10. Correct answer: C Angle x is alternate angle to angle 30 o . And, since alternate interior angles are equal, x = 30 o . 11. Correct answer: C Since, given triangle is a right angled triangle, we have x 2 = 3 2 + 4 2 = 9 + 16 = 25 = 5 2 Therefore, x = 5 cm 12. Correct answer: B Given, AB = RQ, AC = RP, ?BAC = ?QRP Hence, ?ABC ? ?RQP CBSE VII | Mathematics Sample Paper 1 - Solution Section B 13. To find the complement of each of the given angle, we have to subtract them from 90 o , since the sum of two complementary angles is 90 o . (a) Complementary angle of 45 o = 90 o - 45 o = 45 o (b) Complementary angle of 54 o = 90 o - 54 o = 36 o (c) Complementary angle of 65 o = 90 o - 65 o = 25 o 14. (a) 6n + 4 = 10 Statement: For 6n, Six times of a number n For 6n + 4, Six times of a number n added to 4 Thus, for 6n + 4 = 10, the final statement is "Six times of a number n added to 4 gives 10". (b) y 7 - 3 = 9 Statement: For y 7 , one-seventh of a number y For y 7 - 3, 3 subtracted from one-seventh of a number y Thus, for y 7 - 3 = 9, the final statement is "3 subtracted from one-seventh of a number y gives 9". 15. part of the exercise is solved by Raju. When is converted into lowest form, we get which is same as part of exercise solved by Sameer. Thus, both have solved same part of the exercise. CBSE VII | Mathematics Sample Paper 1 - Solution 16. When two line intersect the following figure is formed. This shows that 4 angles are formed. 17. Divide the total length of ribbon by the length of each strip of ribbon that is cut from it to get the total number of ribbon strips. So, divide by = = = = = 6 Thus, 6 strips can be cut from the ribbon. 18. In the figure, we can see that POR and ROT are right angles. Thus, ?ROS + ?2 = 90 o ?ROS = 67 o So, ?2 = 90 o - 67 o = 23 o Also, ?POQ + ?1 = 90 o ?POQ = 52 o So, ?1 = 90 o - 52 o = 38 o 19. Multiply both sides by 6 (L.C.M of 3 and 2) 2 (2x -1) = 3 (x + 2) 4x - 2 = 3x + 6 Transpose 3x to L.H.S and -2 to R.H.S 4x -3x = 6 + 2 x = 8 Page 5 CBSE VII | Mathematics Sample Paper 1 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 1 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A According to the distributive property of integers, we have a ? (b + c) = a ? b + a ? c 2. Correct answer: B A number is chosen from numbers 1 to 5. Odd numbers are 1, 3, 5. Required probability = number of ways to choose an odd number /total number of numbers = 3/5 3. Correct answer: A 3x + 4 = 25 Transposing 4 to R.H.S, we get 3x = 25 - 4 3x = 21 Dividing both sides by 3, we get x = 7 4. Correct answer: D Since, the angle measuring 150 o and y are corresponding angles. Therefore, y = 150 o . (As the lines are parallel, corresponding angles are equal) 5. Correct answer: D We know that the measure of an exterior angle of a triangle is equal to the sum of its two opposite interior angles. So, x + 90 o = 125 o Therefore, x = 35 o 6. Correct answer: B Negative of a negative integer is a positive integer. So, - (-5) = +5 So, -2 - (-5) = -2 + 5 CBSE VII | Mathematics Sample Paper 1 - Solution 7. Correct answer: C Since, the measure of an exterior angle of a triangle is equal to the sum of measures of its two opposite interior angles. 8. Correct answer: C The given observations are 11, 10, 12, 12, 9, 10, 14, 12, 9. 9. Correct answer: A 10. Correct answer: C Angle x is alternate angle to angle 30 o . And, since alternate interior angles are equal, x = 30 o . 11. Correct answer: C Since, given triangle is a right angled triangle, we have x 2 = 3 2 + 4 2 = 9 + 16 = 25 = 5 2 Therefore, x = 5 cm 12. Correct answer: B Given, AB = RQ, AC = RP, ?BAC = ?QRP Hence, ?ABC ? ?RQP CBSE VII | Mathematics Sample Paper 1 - Solution Section B 13. To find the complement of each of the given angle, we have to subtract them from 90 o , since the sum of two complementary angles is 90 o . (a) Complementary angle of 45 o = 90 o - 45 o = 45 o (b) Complementary angle of 54 o = 90 o - 54 o = 36 o (c) Complementary angle of 65 o = 90 o - 65 o = 25 o 14. (a) 6n + 4 = 10 Statement: For 6n, Six times of a number n For 6n + 4, Six times of a number n added to 4 Thus, for 6n + 4 = 10, the final statement is "Six times of a number n added to 4 gives 10". (b) y 7 - 3 = 9 Statement: For y 7 , one-seventh of a number y For y 7 - 3, 3 subtracted from one-seventh of a number y Thus, for y 7 - 3 = 9, the final statement is "3 subtracted from one-seventh of a number y gives 9". 15. part of the exercise is solved by Raju. When is converted into lowest form, we get which is same as part of exercise solved by Sameer. Thus, both have solved same part of the exercise. CBSE VII | Mathematics Sample Paper 1 - Solution 16. When two line intersect the following figure is formed. This shows that 4 angles are formed. 17. Divide the total length of ribbon by the length of each strip of ribbon that is cut from it to get the total number of ribbon strips. So, divide by = = = = = 6 Thus, 6 strips can be cut from the ribbon. 18. In the figure, we can see that POR and ROT are right angles. Thus, ?ROS + ?2 = 90 o ?ROS = 67 o So, ?2 = 90 o - 67 o = 23 o Also, ?POQ + ?1 = 90 o ?POQ = 52 o So, ?1 = 90 o - 52 o = 38 o 19. Multiply both sides by 6 (L.C.M of 3 and 2) 2 (2x -1) = 3 (x + 2) 4x - 2 = 3x + 6 Transpose 3x to L.H.S and -2 to R.H.S 4x -3x = 6 + 2 x = 8 CBSE VII | Mathematics Sample Paper 1 - Solution 20. Eggs produced by the poultry farm = 600 Eggs delivered to each shop = 600 ? 10 = 60 Money earned by a particular shopkeeper = Rs. 276 Money earned if all eggs were good = 60 × 5 = Rs. 300 Money lost due to rotten eggs = 300 - 276 = Rs. 24 Cost that shopkeeper will give for one rotten egg = Rs. 2 Number of rotten eggs = 24 ? 2 = 12 Hence, 12 eggs were rotten. 21. Material required to make 1 shirt = yards Material required to make 6 shirts = Thus, to make 6 shirts, yards of material will be required. 22. Given, CDE QPR We have to find the angle in ?PQR that corresponds to ?D. Now, since corresponding parts of congruent triangles are congruent, ?D ?P. Hence, ?D = 60 o . 23. Average score = mean score MeanRead More

211 videos|109 docs|45 tests

### Sample Solution Paper 2 - Term- 1 Mathematics, Class 7

- Doc | 11 pages
### Sample Solution Paper 3 - Term- 1 Mathematics, Class 7

- Doc | 13 pages
### Sample Solution Paper 4 - Term- 1 Mathematics, Class 7

- Doc | 13 pages