Page 1 CBSE VI | Mathematics Sample Paper 1 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 1 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A 1.35 = 2. Correct answer: A Data collected from a group of 40 students is an example of primary data. 3. Correct answer: D Maximum marks = 47, Minimum marks = 21 Difference = Maximum – Minimum = 47 – 21 = 26 4. Correct answer: D Perimeter of a square = 4 × length of a side 5. Correct answer: A Area of a square = side × side = p × p = p 2 6. Correct answer: B 15 : 19 is not equivalent to 50 : 90. 7. Correct answer: C An isosceles triangle has exactly one line of symmetry. 8. Correct answer: A Protractor is used to draw and measure angles. 9. Correct answer: C Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest value. 10. Correct answer: B n 8 5 ? is the correct expression. 11. Correct answer: A Letter H has a horizontal line of symmetry. Page 2 CBSE VI | Mathematics Sample Paper 1 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 1 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A 1.35 = 2. Correct answer: A Data collected from a group of 40 students is an example of primary data. 3. Correct answer: D Maximum marks = 47, Minimum marks = 21 Difference = Maximum – Minimum = 47 – 21 = 26 4. Correct answer: D Perimeter of a square = 4 × length of a side 5. Correct answer: A Area of a square = side × side = p × p = p 2 6. Correct answer: B 15 : 19 is not equivalent to 50 : 90. 7. Correct answer: C An isosceles triangle has exactly one line of symmetry. 8. Correct answer: A Protractor is used to draw and measure angles. 9. Correct answer: C Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest value. 10. Correct answer: B n 8 5 ? is the correct expression. 11. Correct answer: A Letter H has a horizontal line of symmetry. CBSE VI | Mathematics Sample Paper 1 – Solution 12. Correct answer: B = 5 + 5 + 5 + 5 + 5 + 3 = 28 Section B 13. Cost of a book = Rs. 165.35 Cost of a pen = Rs. 72.00 Cost of a notebook = Rs. 14.85 Total Cost is given by, Total money to be paid by Preeta = Rs. 252.20 14. (a) Secondary (b) Primary 15. We know that a regular pentagon has 5 sides, so we can divide the perimeter by 5 to get the measure of one side. One side of pentagon = 25 cm ÷ 5 cm = 5 cm 16. Let the number of rows be 'n'. Since there are 11 students in a row and number of rows are n, the Rule is given as, Number of students in the parade = 11n. 17. Three symmetrical objects are (i) An electric tube-light (ii) A water glass (iii) A fan 18. Steps of construction: (1) Draw a line l. Mark a point A on a line l. (2) Place the compass ’ pointer on the 0 mark of the ruler. Open it to place the pencil point up to the 4.5 cm mark. (3) Taking caution that the opening of the compass has not changed, place the pointer on A and swing an arc to cut l at B. (4) AB is a line segment of required length. Page 3 CBSE VI | Mathematics Sample Paper 1 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 1 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A 1.35 = 2. Correct answer: A Data collected from a group of 40 students is an example of primary data. 3. Correct answer: D Maximum marks = 47, Minimum marks = 21 Difference = Maximum – Minimum = 47 – 21 = 26 4. Correct answer: D Perimeter of a square = 4 × length of a side 5. Correct answer: A Area of a square = side × side = p × p = p 2 6. Correct answer: B 15 : 19 is not equivalent to 50 : 90. 7. Correct answer: C An isosceles triangle has exactly one line of symmetry. 8. Correct answer: A Protractor is used to draw and measure angles. 9. Correct answer: C Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest value. 10. Correct answer: B n 8 5 ? is the correct expression. 11. Correct answer: A Letter H has a horizontal line of symmetry. CBSE VI | Mathematics Sample Paper 1 – Solution 12. Correct answer: B = 5 + 5 + 5 + 5 + 5 + 3 = 28 Section B 13. Cost of a book = Rs. 165.35 Cost of a pen = Rs. 72.00 Cost of a notebook = Rs. 14.85 Total Cost is given by, Total money to be paid by Preeta = Rs. 252.20 14. (a) Secondary (b) Primary 15. We know that a regular pentagon has 5 sides, so we can divide the perimeter by 5 to get the measure of one side. One side of pentagon = 25 cm ÷ 5 cm = 5 cm 16. Let the number of rows be 'n'. Since there are 11 students in a row and number of rows are n, the Rule is given as, Number of students in the parade = 11n. 17. Three symmetrical objects are (i) An electric tube-light (ii) A water glass (iii) A fan 18. Steps of construction: (1) Draw a line l. Mark a point A on a line l. (2) Place the compass ’ pointer on the 0 mark of the ruler. Open it to place the pencil point up to the 4.5 cm mark. (3) Taking caution that the opening of the compass has not changed, place the pointer on A and swing an arc to cut l at B. (4) AB is a line segment of required length. CBSE VI | Mathematics Sample Paper 1 – Solution 19. Ratio of 30 cm to 4 m Ratio of 20 sec to 6 minutes Since, , Therefore the given ratio do not form a proportion. 20. To get this answer subtract 27.84 from 84.5 Hence, 56.66 must be subtracted from 84.5 to get 27.84 21. The shaded portion is made up of line segments. It is covered by full and half squares. We have to calculate the number of fully filled and half filled squares. ? Fully filled squares = 6 ? Half-filled squares = 2 Area covered by fully filled square = 6 × 1 = 6 sq. units. Area covered by half-filled square = 2 × 1 2 = 1 Therefore, total area = 6 + 1 = 7 sq. units 22. Drawing the relational part the images become as follows: 23. (a) Butterscotch is liked by 5 + 5 + 2 = 12 students. (b) Chocolate flavor is less favourite. Page 4 CBSE VI | Mathematics Sample Paper 1 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 1 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A 1.35 = 2. Correct answer: A Data collected from a group of 40 students is an example of primary data. 3. Correct answer: D Maximum marks = 47, Minimum marks = 21 Difference = Maximum – Minimum = 47 – 21 = 26 4. Correct answer: D Perimeter of a square = 4 × length of a side 5. Correct answer: A Area of a square = side × side = p × p = p 2 6. Correct answer: B 15 : 19 is not equivalent to 50 : 90. 7. Correct answer: C An isosceles triangle has exactly one line of symmetry. 8. Correct answer: A Protractor is used to draw and measure angles. 9. Correct answer: C Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest value. 10. Correct answer: B n 8 5 ? is the correct expression. 11. Correct answer: A Letter H has a horizontal line of symmetry. CBSE VI | Mathematics Sample Paper 1 – Solution 12. Correct answer: B = 5 + 5 + 5 + 5 + 5 + 3 = 28 Section B 13. Cost of a book = Rs. 165.35 Cost of a pen = Rs. 72.00 Cost of a notebook = Rs. 14.85 Total Cost is given by, Total money to be paid by Preeta = Rs. 252.20 14. (a) Secondary (b) Primary 15. We know that a regular pentagon has 5 sides, so we can divide the perimeter by 5 to get the measure of one side. One side of pentagon = 25 cm ÷ 5 cm = 5 cm 16. Let the number of rows be 'n'. Since there are 11 students in a row and number of rows are n, the Rule is given as, Number of students in the parade = 11n. 17. Three symmetrical objects are (i) An electric tube-light (ii) A water glass (iii) A fan 18. Steps of construction: (1) Draw a line l. Mark a point A on a line l. (2) Place the compass ’ pointer on the 0 mark of the ruler. Open it to place the pencil point up to the 4.5 cm mark. (3) Taking caution that the opening of the compass has not changed, place the pointer on A and swing an arc to cut l at B. (4) AB is a line segment of required length. CBSE VI | Mathematics Sample Paper 1 – Solution 19. Ratio of 30 cm to 4 m Ratio of 20 sec to 6 minutes Since, , Therefore the given ratio do not form a proportion. 20. To get this answer subtract 27.84 from 84.5 Hence, 56.66 must be subtracted from 84.5 to get 27.84 21. The shaded portion is made up of line segments. It is covered by full and half squares. We have to calculate the number of fully filled and half filled squares. ? Fully filled squares = 6 ? Half-filled squares = 2 Area covered by fully filled square = 6 × 1 = 6 sq. units. Area covered by half-filled square = 2 × 1 2 = 1 Therefore, total area = 6 + 1 = 7 sq. units 22. Drawing the relational part the images become as follows: 23. (a) Butterscotch is liked by 5 + 5 + 2 = 12 students. (b) Chocolate flavor is less favourite. CBSE VI | Mathematics Sample Paper 1 – Solution 24. Let the isosceles triangle be ABC, in which AB = AC = 18 cm. Also perimeter is given 50 cm, we need to find BC. Perimeter of triangle = 50 cm AB + AC + BC = 50 cm ? 18 + 18 + x = 50 cm ? 36 + x = 50 cm ? x = 50 – 36 = 14 cm Therefore, length of third side is 14 cm. Section C 25. Let the marks of Rohit, Ajay and Vipul be 4x, 5x and 6x respectively. Given that Ajay's marks = 75 ? 5x = 75 75 x 15 5 ? ? ? Hence, marks of Rohit = 4x = 4 × 15 = 60 marks Marks of Vipul = 6x = 6 × 15 = 90 marks 26. (a) Economics has the most students enrolled. (b) From lowest to highest: Physics, Chemistry, Psychology, Political Science, Economics. (c) From ratio of the number of students enrolled in Economics to the number enrolled in Chemistry we can state that enrollment in Economics is 2 times larger than in Chemistry. 27. Steps of construction: (1) Given AB whose length is not known. (2) Fix the compasses pointer on A and the pencil end on B. The opening of the instrument now gives the length of AB . (3) Draw any line l. Choose a point C on l. Without changing the compasses setting, place the pointer on C. (4) Swing an arc that cuts l at a point, say D. Now CD is a copy of AB . Page 5 CBSE VI | Mathematics Sample Paper 1 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 1 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A 1.35 = 2. Correct answer: A Data collected from a group of 40 students is an example of primary data. 3. Correct answer: D Maximum marks = 47, Minimum marks = 21 Difference = Maximum – Minimum = 47 – 21 = 26 4. Correct answer: D Perimeter of a square = 4 × length of a side 5. Correct answer: A Area of a square = side × side = p × p = p 2 6. Correct answer: B 15 : 19 is not equivalent to 50 : 90. 7. Correct answer: C An isosceles triangle has exactly one line of symmetry. 8. Correct answer: A Protractor is used to draw and measure angles. 9. Correct answer: C Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest value. 10. Correct answer: B n 8 5 ? is the correct expression. 11. Correct answer: A Letter H has a horizontal line of symmetry. CBSE VI | Mathematics Sample Paper 1 – Solution 12. Correct answer: B = 5 + 5 + 5 + 5 + 5 + 3 = 28 Section B 13. Cost of a book = Rs. 165.35 Cost of a pen = Rs. 72.00 Cost of a notebook = Rs. 14.85 Total Cost is given by, Total money to be paid by Preeta = Rs. 252.20 14. (a) Secondary (b) Primary 15. We know that a regular pentagon has 5 sides, so we can divide the perimeter by 5 to get the measure of one side. One side of pentagon = 25 cm ÷ 5 cm = 5 cm 16. Let the number of rows be 'n'. Since there are 11 students in a row and number of rows are n, the Rule is given as, Number of students in the parade = 11n. 17. Three symmetrical objects are (i) An electric tube-light (ii) A water glass (iii) A fan 18. Steps of construction: (1) Draw a line l. Mark a point A on a line l. (2) Place the compass ’ pointer on the 0 mark of the ruler. Open it to place the pencil point up to the 4.5 cm mark. (3) Taking caution that the opening of the compass has not changed, place the pointer on A and swing an arc to cut l at B. (4) AB is a line segment of required length. CBSE VI | Mathematics Sample Paper 1 – Solution 19. Ratio of 30 cm to 4 m Ratio of 20 sec to 6 minutes Since, , Therefore the given ratio do not form a proportion. 20. To get this answer subtract 27.84 from 84.5 Hence, 56.66 must be subtracted from 84.5 to get 27.84 21. The shaded portion is made up of line segments. It is covered by full and half squares. We have to calculate the number of fully filled and half filled squares. ? Fully filled squares = 6 ? Half-filled squares = 2 Area covered by fully filled square = 6 × 1 = 6 sq. units. Area covered by half-filled square = 2 × 1 2 = 1 Therefore, total area = 6 + 1 = 7 sq. units 22. Drawing the relational part the images become as follows: 23. (a) Butterscotch is liked by 5 + 5 + 2 = 12 students. (b) Chocolate flavor is less favourite. CBSE VI | Mathematics Sample Paper 1 – Solution 24. Let the isosceles triangle be ABC, in which AB = AC = 18 cm. Also perimeter is given 50 cm, we need to find BC. Perimeter of triangle = 50 cm AB + AC + BC = 50 cm ? 18 + 18 + x = 50 cm ? 36 + x = 50 cm ? x = 50 – 36 = 14 cm Therefore, length of third side is 14 cm. Section C 25. Let the marks of Rohit, Ajay and Vipul be 4x, 5x and 6x respectively. Given that Ajay's marks = 75 ? 5x = 75 75 x 15 5 ? ? ? Hence, marks of Rohit = 4x = 4 × 15 = 60 marks Marks of Vipul = 6x = 6 × 15 = 90 marks 26. (a) Economics has the most students enrolled. (b) From lowest to highest: Physics, Chemistry, Psychology, Political Science, Economics. (c) From ratio of the number of students enrolled in Economics to the number enrolled in Chemistry we can state that enrollment in Economics is 2 times larger than in Chemistry. 27. Steps of construction: (1) Given AB whose length is not known. (2) Fix the compasses pointer on A and the pencil end on B. The opening of the instrument now gives the length of AB . (3) Draw any line l. Choose a point C on l. Without changing the compasses setting, place the pointer on C. (4) Swing an arc that cuts l at a point, say D. Now CD is a copy of AB . CBSE VI | Mathematics Sample Paper 1 – Solution 28. From the figure the smaller rectangles are equal. Therefore, Area of one smaller rectangle = length × breadth = 3 × 4 = 12 sq. m Area of 3 smaller rectangles = 3 × 12 = 36 sq. m Area of bigger rectangle = length × breadth = 10 × 8 = 80 sq. m Therefore, area of remaining part = 80 – 36 = 44 sq. m 29. Rate percent per annum is interest given on Rs. 100 for a year. Let the interest for Rs. 100 per annum be Rs. x. Principal : Principal :: Interest : Interest 5250 : 100 :: 420 : x Product of extreme terms = 5250x Product of the middle terms = 100 × 420 = 42000 5250x 100 420 42000 x8 5250 ?? ? ? ? 30. (a) In this case time is unknown and distance is known. Therefore, we proceed as follows: 6 hours = 6 × 60 minutes = 360 minutes 300 km is covered in 360 minutes Time required to cover 1 km distance = 360 6 min 300 5 ? Therefore, 280 km can be covered in 6 280 336 minutes 5 hours 36 minutes 5 ? ? ? (b) In this case distance is unknown and time is known. Therefore, we proceed as follows: Distance covered in 6 hours = 300 km Distance covered in 1 hour = 300 50 km 6 ? Therefore, distance covered in 10 hours = 50 × 10 = 500 km. 31. Area of a square wall = side × side = 10 × 10 = 100 sq. m Area of four square walls = 4 × 100 = 400 sq. m Cost of painting 1 sq. m of wall = Rs. 20 Therefore, total cost of painting = Rs. 20 × 400 = Rs. 8000 32. (a) In 2009-April, May and in 2010-May, June. (b) In 2009-May and in 2010-May. (c) In 2009-June and in 2010-March and MayRead More

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