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# Sample Solution Paper 2 - Term- 2 Math, Class 8 Class 8 Notes | EduRev

## Class 8 : Sample Solution Paper 2 - Term- 2 Math, Class 8 Class 8 Notes | EduRev

``` Page 1

CBSE VIII | Mathematics
Sample Paper 2 - Solution

CBSE Board
Class VIII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

(t
2
+ 3) (t + 3 ) (t - 3 ) = (t
2
+ 3) [t
2
- ( 3 )
2
]
= (t
2
+ 3) (t
2
- 3)
= (t
2
)
2
- (3)
2

= t
4
– 9
[(x - y) (x + y) = x
2
- y
2
]

The given shape has 6 vertices.

Let one number be x and the other number be (80 – x).
From the given information, we have
x3
80 x 5
5x 240 3x
5x 3x 240
8x 240
240
x 30
8
?
?
? ? ?
? ? ?
??
? ? ?

Thus, the two numbers are 30 and (80 – 30) = 50.
Hence, the greatest number amongst the two is 50.

Page 2

CBSE VIII | Mathematics
Sample Paper 2 - Solution

CBSE Board
Class VIII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

(t
2
+ 3) (t + 3 ) (t - 3 ) = (t
2
+ 3) [t
2
- ( 3 )
2
]
= (t
2
+ 3) (t
2
- 3)
= (t
2
)
2
- (3)
2

= t
4
– 9
[(x - y) (x + y) = x
2
- y
2
]

The given shape has 6 vertices.

Let one number be x and the other number be (80 – x).
From the given information, we have
x3
80 x 5
5x 240 3x
5x 3x 240
8x 240
240
x 30
8
?
?
? ? ?
? ? ?
??
? ? ?

Thus, the two numbers are 30 and (80 – 30) = 50.
Hence, the greatest number amongst the two is 50.

CBSE VIII | Mathematics
Sample Paper 2 - Solution

Here, 6 × a = 3 × 4
Therefore, a = 2.

A straight line

A rational number is a number of the form
p
q
where q ? 0. So in case of reciprocal
of 0, denominator will be 0.

Cuboid is a polyhedron because its faces are congruent and regular polygons. Also,
its vertices are formed by same number of faces.

Page 3

CBSE VIII | Mathematics
Sample Paper 2 - Solution

CBSE Board
Class VIII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

(t
2
+ 3) (t + 3 ) (t - 3 ) = (t
2
+ 3) [t
2
- ( 3 )
2
]
= (t
2
+ 3) (t
2
- 3)
= (t
2
)
2
- (3)
2

= t
4
– 9
[(x - y) (x + y) = x
2
- y
2
]

The given shape has 6 vertices.

Let one number be x and the other number be (80 – x).
From the given information, we have
x3
80 x 5
5x 240 3x
5x 3x 240
8x 240
240
x 30
8
?
?
? ? ?
? ? ?
??
? ? ?

Thus, the two numbers are 30 and (80 – 30) = 50.
Hence, the greatest number amongst the two is 50.

CBSE VIII | Mathematics
Sample Paper 2 - Solution

Here, 6 × a = 3 × 4
Therefore, a = 2.

A straight line

A rational number is a number of the form
p
q
where q ? 0. So in case of reciprocal
of 0, denominator will be 0.

Cuboid is a polyhedron because its faces are congruent and regular polygons. Also,
its vertices are formed by same number of faces.

CBSE VIII | Mathematics
Sample Paper 2 - Solution

1
3
= 1
Thus, the natural number 1 is equal to its cube.

Sales tax =
4
380 15.20
100
??

On cross-multiplying, we get
4x + 28 = 3x - 3
4x - 3x = -3 - 28
x = -31
x + 31 = 0

Section B

13.

14. 82
2
= (80 + 2)
2

In the property (a + b)
2
= a
2
+ b
2
+ 2ab, putting a = 80 and b = 2, we get
(80 + 2)
2
= 80
2
+ 2
2
+ 2 × 80 × 2
= 6400 + 4 + 320
= 6724

15.
(i) 100 × 7 + 10 × 9 + 1 × 8 = 700 + 90 + 8 = 798

(ii) 1000 × 3 + 100 × 1 + 10 × 5 + 1 × 9
= 3000 + 100 + 50 + 9
= 3159

Page 4

CBSE VIII | Mathematics
Sample Paper 2 - Solution

CBSE Board
Class VIII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

(t
2
+ 3) (t + 3 ) (t - 3 ) = (t
2
+ 3) [t
2
- ( 3 )
2
]
= (t
2
+ 3) (t
2
- 3)
= (t
2
)
2
- (3)
2

= t
4
– 9
[(x - y) (x + y) = x
2
- y
2
]

The given shape has 6 vertices.

Let one number be x and the other number be (80 – x).
From the given information, we have
x3
80 x 5
5x 240 3x
5x 3x 240
8x 240
240
x 30
8
?
?
? ? ?
? ? ?
??
? ? ?

Thus, the two numbers are 30 and (80 – 30) = 50.
Hence, the greatest number amongst the two is 50.

CBSE VIII | Mathematics
Sample Paper 2 - Solution

Here, 6 × a = 3 × 4
Therefore, a = 2.

A straight line

A rational number is a number of the form
p
q
where q ? 0. So in case of reciprocal
of 0, denominator will be 0.

Cuboid is a polyhedron because its faces are congruent and regular polygons. Also,
its vertices are formed by same number of faces.

CBSE VIII | Mathematics
Sample Paper 2 - Solution

1
3
= 1
Thus, the natural number 1 is equal to its cube.

Sales tax =
4
380 15.20
100
??

On cross-multiplying, we get
4x + 28 = 3x - 3
4x - 3x = -3 - 28
x = -31
x + 31 = 0

Section B

13.

14. 82
2
= (80 + 2)
2

In the property (a + b)
2
= a
2
+ b
2
+ 2ab, putting a = 80 and b = 2, we get
(80 + 2)
2
= 80
2
+ 2
2
+ 2 × 80 × 2
= 6400 + 4 + 320
= 6724

15.
(i) 100 × 7 + 10 × 9 + 1 × 8 = 700 + 90 + 8 = 798

(ii) 1000 × 3 + 100 × 1 + 10 × 5 + 1 × 9
= 3000 + 100 + 50 + 9
= 3159

CBSE VIII | Mathematics
Sample Paper 2 - Solution

16.

Hence, the area of 4 walls is 125 m
2
.

17.
By regrouping of terms, we have

Taking out common factor from underlined terms, we get

Again, taking out the underlined common factor, we have

18. Let the required number be x. Then,
26% of x = 65
26
x 65
100
100
x 65
26
x 250
??
??
? ? ?
??
??
??

Hence, the required number is 250.

19. Consider:

At one's place, A + 3 = _1
So think of a number which when added to 3 gives one's place as 1.
Such a number is 8 as 8 + 3 = 11
Taking, A = 8, we obtain the addition as below:

Page 5

CBSE VIII | Mathematics
Sample Paper 2 - Solution

CBSE Board
Class VIII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

(t
2
+ 3) (t + 3 ) (t - 3 ) = (t
2
+ 3) [t
2
- ( 3 )
2
]
= (t
2
+ 3) (t
2
- 3)
= (t
2
)
2
- (3)
2

= t
4
– 9
[(x - y) (x + y) = x
2
- y
2
]

The given shape has 6 vertices.

Let one number be x and the other number be (80 – x).
From the given information, we have
x3
80 x 5
5x 240 3x
5x 3x 240
8x 240
240
x 30
8
?
?
? ? ?
? ? ?
??
? ? ?

Thus, the two numbers are 30 and (80 – 30) = 50.
Hence, the greatest number amongst the two is 50.

CBSE VIII | Mathematics
Sample Paper 2 - Solution

Here, 6 × a = 3 × 4
Therefore, a = 2.

A straight line

A rational number is a number of the form
p
q
where q ? 0. So in case of reciprocal
of 0, denominator will be 0.

Cuboid is a polyhedron because its faces are congruent and regular polygons. Also,
its vertices are formed by same number of faces.

CBSE VIII | Mathematics
Sample Paper 2 - Solution

1
3
= 1
Thus, the natural number 1 is equal to its cube.

Sales tax =
4
380 15.20
100
??

On cross-multiplying, we get
4x + 28 = 3x - 3
4x - 3x = -3 - 28
x = -31
x + 31 = 0

Section B

13.

14. 82
2
= (80 + 2)
2

In the property (a + b)
2
= a
2
+ b
2
+ 2ab, putting a = 80 and b = 2, we get
(80 + 2)
2
= 80
2
+ 2
2
+ 2 × 80 × 2
= 6400 + 4 + 320
= 6724

15.
(i) 100 × 7 + 10 × 9 + 1 × 8 = 700 + 90 + 8 = 798

(ii) 1000 × 3 + 100 × 1 + 10 × 5 + 1 × 9
= 3000 + 100 + 50 + 9
= 3159

CBSE VIII | Mathematics
Sample Paper 2 - Solution

16.

Hence, the area of 4 walls is 125 m
2
.

17.
By regrouping of terms, we have

Taking out common factor from underlined terms, we get

Again, taking out the underlined common factor, we have

18. Let the required number be x. Then,
26% of x = 65
26
x 65
100
100
x 65
26
x 250
??
??
? ? ?
??
??
??

Hence, the required number is 250.

19. Consider:

At one's place, A + 3 = _1
So think of a number which when added to 3 gives one's place as 1.
Such a number is 8 as 8 + 3 = 11
Taking, A = 8, we obtain the addition as below:

CBSE VIII | Mathematics
Sample Paper 2 - Solution

20.
(i)

(ii)

21. A number is divisible by 4 if the number formed by its last two digits is divisible by
4.
(i) Consider 45748
Number formed by last two digits is 48.
Since, 48 is divisible by 4.
Hence, 45748 is also divisible by 4.

(ii) Consider 21404
Number formed by last two digits is 04.
Since, 04 is divisible by 4.
Hence, 21404 is also divisible by 4.

22. Here, F = 10, E = 20 and V = 15
We have
F + V - E = 10 + 15 - 20
= 25 - 20 = 5
Hence, F + V - E 2
Thus, such a polyhedron is not possible.

23. Distance = 1,433,500,000,000 m
= 14335 × 100000000 m
= 14335 × 10
8
m
= 1.4335 × 10
12
m

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## Mathematics (Maths) Class 8

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