Page 1 CBSE VI | Mathematics Sample Paper 2 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 2 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: D Decimal number represented by point A on the number line is 1.9 2. Correct answer: D Number of students who like hockey = 14 Number of students who like football = 13 Difference = 14 – 13 = 1 3. Correct answer: C Perimeter of a square = 4 × side 70 = 4 × side Side = 70 4 = 17.5 m 4. Correct answer: B Cost of n such books will be 10n. 5. Correct answer: B 3 : 4 :: x : 8 3x 48 ? Gives, 4x = 24 ? x = 6 6. Correct answer: A A rectangle has two lines of symmetry. 7. Correct answer: A Cost of k chocolates = 6k Then, cost of 5 chocolates = 6 × 5 = Rs. 30 Page 2 CBSE VI | Mathematics Sample Paper 2 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 2 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: D Decimal number represented by point A on the number line is 1.9 2. Correct answer: D Number of students who like hockey = 14 Number of students who like football = 13 Difference = 14 – 13 = 1 3. Correct answer: C Perimeter of a square = 4 × side 70 = 4 × side Side = 70 4 = 17.5 m 4. Correct answer: B Cost of n such books will be 10n. 5. Correct answer: B 3 : 4 :: x : 8 3x 48 ? Gives, 4x = 24 ? x = 6 6. Correct answer: A A rectangle has two lines of symmetry. 7. Correct answer: A Cost of k chocolates = 6k Then, cost of 5 chocolates = 6 × 5 = Rs. 30 CBSE VI | Mathematics Sample Paper 2 – Solution 8. Correct answer: A The given number 8.6 can be written as 9. Correct answer: B Value at y = 1 is 4(1) + 12 = 16 10. Correct answer: A Alphabet H has 2 lines of symmetry 11. Correct answer: B 9 multiplied to k and then 1 is added. 12. Correct answer: B 0.1254 < 01257 < 0.1258 < 01259 Section B 13. Weight of an empty cylinder = 18.075 kg Weight of the gas filled in it = 12.350 kg Total weight = Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g 14. This data can be represented in a tabular form as shown below: Standard VI Girls Boys Total Div A 10 12 22 Div. B 6 20 26 Div. C 18 12 30 Div. D 16 24 40 Total 50 68 118 Page 3 CBSE VI | Mathematics Sample Paper 2 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 2 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: D Decimal number represented by point A on the number line is 1.9 2. Correct answer: D Number of students who like hockey = 14 Number of students who like football = 13 Difference = 14 – 13 = 1 3. Correct answer: C Perimeter of a square = 4 × side 70 = 4 × side Side = 70 4 = 17.5 m 4. Correct answer: B Cost of n such books will be 10n. 5. Correct answer: B 3 : 4 :: x : 8 3x 48 ? Gives, 4x = 24 ? x = 6 6. Correct answer: A A rectangle has two lines of symmetry. 7. Correct answer: A Cost of k chocolates = 6k Then, cost of 5 chocolates = 6 × 5 = Rs. 30 CBSE VI | Mathematics Sample Paper 2 – Solution 8. Correct answer: A The given number 8.6 can be written as 9. Correct answer: B Value at y = 1 is 4(1) + 12 = 16 10. Correct answer: A Alphabet H has 2 lines of symmetry 11. Correct answer: B 9 multiplied to k and then 1 is added. 12. Correct answer: B 0.1254 < 01257 < 0.1258 < 01259 Section B 13. Weight of an empty cylinder = 18.075 kg Weight of the gas filled in it = 12.350 kg Total weight = Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g 14. This data can be represented in a tabular form as shown below: Standard VI Girls Boys Total Div A 10 12 22 Div. B 6 20 26 Div. C 18 12 30 Div. D 16 24 40 Total 50 68 118 CBSE VI | Mathematics Sample Paper 2 – Solution 15. Let the length of the fourth side be x cm. Perimeter = 130 cm 30 + 40 + 25 + x = 130 cm 95 + x = 130 cm x = 130 – 95 x = 35 cm Therefore, length of the fourth side is 35 cm. 16. Number of ball in smaller boxes = x Number of balls in the larger box = 2 × number of balls in small Box + balls left over = 2x + 10 17. Point A represents 0.8 Point B represents 1.3 Point C represents 2.2 Point D represents 2.9 18. Length of rectangular field = 20 m Breadth of the rectangular field = 15 m The ratio of the breadth to the length is 15 : 20 Now, 15 15 5 3 15:20 3: 4 20 20 5 4 ? ? ? ? ? ? Thus, the required ratio is 3 : 4. 19. Steps of construction: 1. Draw a line segment AB of any length and mark a point P on it. 2. Taking P as centre and any radius draw two arcs one on left side of P and other on right side of P, which cut AB at Q and R. 3. Taking Q and R as a centre draw two arcs and let them intersect at S. 4. Join PS. 5. PS is the required perpendicular of AB. Page 4 CBSE VI | Mathematics Sample Paper 2 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 2 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: D Decimal number represented by point A on the number line is 1.9 2. Correct answer: D Number of students who like hockey = 14 Number of students who like football = 13 Difference = 14 – 13 = 1 3. Correct answer: C Perimeter of a square = 4 × side 70 = 4 × side Side = 70 4 = 17.5 m 4. Correct answer: B Cost of n such books will be 10n. 5. Correct answer: B 3 : 4 :: x : 8 3x 48 ? Gives, 4x = 24 ? x = 6 6. Correct answer: A A rectangle has two lines of symmetry. 7. Correct answer: A Cost of k chocolates = 6k Then, cost of 5 chocolates = 6 × 5 = Rs. 30 CBSE VI | Mathematics Sample Paper 2 – Solution 8. Correct answer: A The given number 8.6 can be written as 9. Correct answer: B Value at y = 1 is 4(1) + 12 = 16 10. Correct answer: A Alphabet H has 2 lines of symmetry 11. Correct answer: B 9 multiplied to k and then 1 is added. 12. Correct answer: B 0.1254 < 01257 < 0.1258 < 01259 Section B 13. Weight of an empty cylinder = 18.075 kg Weight of the gas filled in it = 12.350 kg Total weight = Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g 14. This data can be represented in a tabular form as shown below: Standard VI Girls Boys Total Div A 10 12 22 Div. B 6 20 26 Div. C 18 12 30 Div. D 16 24 40 Total 50 68 118 CBSE VI | Mathematics Sample Paper 2 – Solution 15. Let the length of the fourth side be x cm. Perimeter = 130 cm 30 + 40 + 25 + x = 130 cm 95 + x = 130 cm x = 130 – 95 x = 35 cm Therefore, length of the fourth side is 35 cm. 16. Number of ball in smaller boxes = x Number of balls in the larger box = 2 × number of balls in small Box + balls left over = 2x + 10 17. Point A represents 0.8 Point B represents 1.3 Point C represents 2.2 Point D represents 2.9 18. Length of rectangular field = 20 m Breadth of the rectangular field = 15 m The ratio of the breadth to the length is 15 : 20 Now, 15 15 5 3 15:20 3: 4 20 20 5 4 ? ? ? ? ? ? Thus, the required ratio is 3 : 4. 19. Steps of construction: 1. Draw a line segment AB of any length and mark a point P on it. 2. Taking P as centre and any radius draw two arcs one on left side of P and other on right side of P, which cut AB at Q and R. 3. Taking Q and R as a centre draw two arcs and let them intersect at S. 4. Join PS. 5. PS is the required perpendicular of AB. CBSE VI | Mathematics Sample Paper 2 – Solution 20. Subtract 74.5 from 91 Hence, 16.5 should be added to 74.5 to get 91. 21. a. y + 7 b. a 23 22. The complete image is as below: 23. (a) Number of students whose favourite colour is blue = 30. (b) Number of students whose favourite colour is green = 45 Number of students whose favourite colour is red = 25 Thus, required number of students = 45 – 2 5 = 20 24. Speed of the bus = v km per hour Distance travelled by the bus in 10 hours = 10v km According to the question, Distance from Delhi to Mumbai = Distance travelled by bus in 10 hours + 80 km = 10v km + 80 km = (10v + 80) km Section C 25. Total balls = 55 Blue balls = 25 Remaining balls are = 55 – 25 = 30 Given that remaining balls are in the ratio of 2 : 1. Let these balls be 2x and 1x respectively. ? 2x + 1x = 30 ? 3x = 30 ? x = 10 Thus, number of other two balls are 2x = 2 × 10 = 20 and 1x = 1 × 10 = 10 Ratio of sum of other two balls to the blue balls 30 6 6:5 25 5 ? ? ? Page 5 CBSE VI | Mathematics Sample Paper 2 – Solution CBSE Board Class VI Mathematics Term II Sample Paper 2 – Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: D Decimal number represented by point A on the number line is 1.9 2. Correct answer: D Number of students who like hockey = 14 Number of students who like football = 13 Difference = 14 – 13 = 1 3. Correct answer: C Perimeter of a square = 4 × side 70 = 4 × side Side = 70 4 = 17.5 m 4. Correct answer: B Cost of n such books will be 10n. 5. Correct answer: B 3 : 4 :: x : 8 3x 48 ? Gives, 4x = 24 ? x = 6 6. Correct answer: A A rectangle has two lines of symmetry. 7. Correct answer: A Cost of k chocolates = 6k Then, cost of 5 chocolates = 6 × 5 = Rs. 30 CBSE VI | Mathematics Sample Paper 2 – Solution 8. Correct answer: A The given number 8.6 can be written as 9. Correct answer: B Value at y = 1 is 4(1) + 12 = 16 10. Correct answer: A Alphabet H has 2 lines of symmetry 11. Correct answer: B 9 multiplied to k and then 1 is added. 12. Correct answer: B 0.1254 < 01257 < 0.1258 < 01259 Section B 13. Weight of an empty cylinder = 18.075 kg Weight of the gas filled in it = 12.350 kg Total weight = Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g 14. This data can be represented in a tabular form as shown below: Standard VI Girls Boys Total Div A 10 12 22 Div. B 6 20 26 Div. C 18 12 30 Div. D 16 24 40 Total 50 68 118 CBSE VI | Mathematics Sample Paper 2 – Solution 15. Let the length of the fourth side be x cm. Perimeter = 130 cm 30 + 40 + 25 + x = 130 cm 95 + x = 130 cm x = 130 – 95 x = 35 cm Therefore, length of the fourth side is 35 cm. 16. Number of ball in smaller boxes = x Number of balls in the larger box = 2 × number of balls in small Box + balls left over = 2x + 10 17. Point A represents 0.8 Point B represents 1.3 Point C represents 2.2 Point D represents 2.9 18. Length of rectangular field = 20 m Breadth of the rectangular field = 15 m The ratio of the breadth to the length is 15 : 20 Now, 15 15 5 3 15:20 3: 4 20 20 5 4 ? ? ? ? ? ? Thus, the required ratio is 3 : 4. 19. Steps of construction: 1. Draw a line segment AB of any length and mark a point P on it. 2. Taking P as centre and any radius draw two arcs one on left side of P and other on right side of P, which cut AB at Q and R. 3. Taking Q and R as a centre draw two arcs and let them intersect at S. 4. Join PS. 5. PS is the required perpendicular of AB. CBSE VI | Mathematics Sample Paper 2 – Solution 20. Subtract 74.5 from 91 Hence, 16.5 should be added to 74.5 to get 91. 21. a. y + 7 b. a 23 22. The complete image is as below: 23. (a) Number of students whose favourite colour is blue = 30. (b) Number of students whose favourite colour is green = 45 Number of students whose favourite colour is red = 25 Thus, required number of students = 45 – 2 5 = 20 24. Speed of the bus = v km per hour Distance travelled by the bus in 10 hours = 10v km According to the question, Distance from Delhi to Mumbai = Distance travelled by bus in 10 hours + 80 km = 10v km + 80 km = (10v + 80) km Section C 25. Total balls = 55 Blue balls = 25 Remaining balls are = 55 – 25 = 30 Given that remaining balls are in the ratio of 2 : 1. Let these balls be 2x and 1x respectively. ? 2x + 1x = 30 ? 3x = 30 ? x = 10 Thus, number of other two balls are 2x = 2 × 10 = 20 and 1x = 1 × 10 = 10 Ratio of sum of other two balls to the blue balls 30 6 6:5 25 5 ? ? ? CBSE VI | Mathematics Sample Paper 2 – Solution 26. 1. Maximum rainfall occurred in city B, i.e., 25 × 10 = 250 cm 2. Minimum rainfall was in city F that is 25 × 1 = 25 cm 3. Difference between rainfalls of city A and F = (7 – 1) × 25 = 150 cm 27. The steps of construction are as follows: 1. Draw right angle triangle ABC with right angle at B. 2. Construct perpendicular bisectors of sides AB and BC. 3. Let the point of intersection of the perpendiculars be P. 4. By observing this point P lies on hypotenuse AC. 28. Total area of tiles must be equal to the area of the floor of the room. Length = 15 m and Breadth = 16 m Area of the floor = length × breadth = 15 × 16 = 240 sq. m Area of one rectangular tile = length × breadth = 1.5 × 1 = 1.5 sq. m Area of floor 240 Number of tiles required 160 Area of one tile 1.5 ? ? ? ? 29. Number of girls in the class = 35 Number of boys in the class = 45 Total number of students = 35 + 45 = 80 Ratio of boys to girls = 45 : 35 = 9 : 7 (dividing by 5) Ratio of boys to total number of students = 45 : 80 = 9 : 16Read More

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