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# Sample Solution Paper 2 - Term- 2 Mathematics, Class 6 Class 6 Notes | EduRev

## Class 6 : Sample Solution Paper 2 - Term- 2 Mathematics, Class 6 Class 6 Notes | EduRev

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CBSE VI | Mathematics
Sample Paper 2 – Solution

CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

Decimal number represented by point A on the number line is 1.9

Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1

Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m

Cost of n such books will be 10n.

3 : 4 :: x : 8

3x
48
?
Gives, 4x = 24 ? x = 6

A rectangle has two lines of symmetry.

Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30

Page 2

CBSE VI | Mathematics
Sample Paper 2 – Solution

CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

Decimal number represented by point A on the number line is 1.9

Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1

Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m

Cost of n such books will be 10n.

3 : 4 :: x : 8

3x
48
?
Gives, 4x = 24 ? x = 6

A rectangle has two lines of symmetry.

Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30

CBSE VI | Mathematics
Sample Paper 2 – Solution

The given number 8.6 can be written as

Value at y = 1 is 4(1) + 12 = 16

Alphabet H has 2 lines of symmetry

9 multiplied to k and then 1 is added.

0.1254 < 01257 < 0.1258 < 01259

Section B

13. Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg
Total weight =

Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g

14. This data can be represented in a tabular form as shown below:
Standard VI Girls Boys Total
Div A 10 12 22
Div. B 6 20 26
Div. C 18 12 30
Div. D 16 24 40
Total 50 68 118

Page 3

CBSE VI | Mathematics
Sample Paper 2 – Solution

CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

Decimal number represented by point A on the number line is 1.9

Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1

Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m

Cost of n such books will be 10n.

3 : 4 :: x : 8

3x
48
?
Gives, 4x = 24 ? x = 6

A rectangle has two lines of symmetry.

Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30

CBSE VI | Mathematics
Sample Paper 2 – Solution

The given number 8.6 can be written as

Value at y = 1 is 4(1) + 12 = 16

Alphabet H has 2 lines of symmetry

9 multiplied to k and then 1 is added.

0.1254 < 01257 < 0.1258 < 01259

Section B

13. Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg
Total weight =

Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g

14. This data can be represented in a tabular form as shown below:
Standard VI Girls Boys Total
Div A 10 12 22
Div. B 6 20 26
Div. C 18 12 30
Div. D 16 24 40
Total 50 68 118

CBSE VI | Mathematics
Sample Paper 2 – Solution

15. Let the length of the fourth side be x cm.
Perimeter = 130 cm
30 + 40 + 25 + x = 130 cm
95 + x = 130 cm
x = 130 – 95
x = 35 cm
Therefore, length of the fourth side is 35 cm.

16. Number of ball in smaller boxes = x
Number of balls in the larger box = 2 × number of balls in small Box + balls left over
= 2x + 10

17. Point A represents 0.8
Point B represents 1.3
Point C represents 2.2
Point D represents 2.9

18. Length of rectangular field = 20 m
Breadth of the rectangular field = 15 m
The ratio of the breadth to the length is 15 : 20
Now,
15 15 5 3
15:20 3: 4
20 20 5 4
?
? ? ? ?
?

Thus, the required ratio is 3 : 4.

19. Steps of construction:
1. Draw a line segment AB of any length and mark a point P on it.
2. Taking P as centre and any radius draw two arcs one on left side of P and other
on right side of P, which cut AB at Q and R.
3. Taking Q and R as a centre draw two arcs and let them intersect at S.
4. Join PS.
5. PS is the required perpendicular of AB.

Page 4

CBSE VI | Mathematics
Sample Paper 2 – Solution

CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

Decimal number represented by point A on the number line is 1.9

Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1

Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m

Cost of n such books will be 10n.

3 : 4 :: x : 8

3x
48
?
Gives, 4x = 24 ? x = 6

A rectangle has two lines of symmetry.

Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30

CBSE VI | Mathematics
Sample Paper 2 – Solution

The given number 8.6 can be written as

Value at y = 1 is 4(1) + 12 = 16

Alphabet H has 2 lines of symmetry

9 multiplied to k and then 1 is added.

0.1254 < 01257 < 0.1258 < 01259

Section B

13. Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg
Total weight =

Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g

14. This data can be represented in a tabular form as shown below:
Standard VI Girls Boys Total
Div A 10 12 22
Div. B 6 20 26
Div. C 18 12 30
Div. D 16 24 40
Total 50 68 118

CBSE VI | Mathematics
Sample Paper 2 – Solution

15. Let the length of the fourth side be x cm.
Perimeter = 130 cm
30 + 40 + 25 + x = 130 cm
95 + x = 130 cm
x = 130 – 95
x = 35 cm
Therefore, length of the fourth side is 35 cm.

16. Number of ball in smaller boxes = x
Number of balls in the larger box = 2 × number of balls in small Box + balls left over
= 2x + 10

17. Point A represents 0.8
Point B represents 1.3
Point C represents 2.2
Point D represents 2.9

18. Length of rectangular field = 20 m
Breadth of the rectangular field = 15 m
The ratio of the breadth to the length is 15 : 20
Now,
15 15 5 3
15:20 3: 4
20 20 5 4
?
? ? ? ?
?

Thus, the required ratio is 3 : 4.

19. Steps of construction:
1. Draw a line segment AB of any length and mark a point P on it.
2. Taking P as centre and any radius draw two arcs one on left side of P and other
on right side of P, which cut AB at Q and R.
3. Taking Q and R as a centre draw two arcs and let them intersect at S.
4. Join PS.
5. PS is the required perpendicular of AB.

CBSE VI | Mathematics
Sample Paper 2 – Solution

20. Subtract 74.5 from 91

Hence, 16.5 should be added to 74.5 to get 91.

21. a.  y + 7
b.
a
23

22. The complete image is as below:

23. (a) Number of students whose favourite colour is blue = 30.
(b) Number of students whose favourite colour is green = 45
Number of students whose favourite colour is red = 25
Thus, required number of students = 45 – 2 5 = 20

24. Speed of the bus = v km per hour
Distance travelled by the bus in 10 hours = 10v km
According to the question,
Distance from Delhi to Mumbai
= Distance travelled by bus in 10 hours + 80 km
= 10v km + 80 km
= (10v + 80) km

Section C

25. Total balls = 55
Blue balls = 25
Remaining balls are = 55 – 25 = 30
Given that remaining balls are in the ratio of 2 : 1.
Let these balls be 2x and 1x respectively.
? 2x + 1x = 30
? 3x = 30 ? x = 10
Thus, number of other two balls are
2x = 2 × 10 = 20 and 1x = 1 × 10 = 10
Ratio of sum of other two balls to the blue balls
30 6
6:5
25 5
? ? ?
Page 5

CBSE VI | Mathematics
Sample Paper 2 – Solution

CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours                          Total Marks: 80

Section A

Decimal number represented by point A on the number line is 1.9

Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1

Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m

Cost of n such books will be 10n.

3 : 4 :: x : 8

3x
48
?
Gives, 4x = 24 ? x = 6

A rectangle has two lines of symmetry.

Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30

CBSE VI | Mathematics
Sample Paper 2 – Solution

The given number 8.6 can be written as

Value at y = 1 is 4(1) + 12 = 16

Alphabet H has 2 lines of symmetry

9 multiplied to k and then 1 is added.

0.1254 < 01257 < 0.1258 < 01259

Section B

13. Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg
Total weight =

Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g

14. This data can be represented in a tabular form as shown below:
Standard VI Girls Boys Total
Div A 10 12 22
Div. B 6 20 26
Div. C 18 12 30
Div. D 16 24 40
Total 50 68 118

CBSE VI | Mathematics
Sample Paper 2 – Solution

15. Let the length of the fourth side be x cm.
Perimeter = 130 cm
30 + 40 + 25 + x = 130 cm
95 + x = 130 cm
x = 130 – 95
x = 35 cm
Therefore, length of the fourth side is 35 cm.

16. Number of ball in smaller boxes = x
Number of balls in the larger box = 2 × number of balls in small Box + balls left over
= 2x + 10

17. Point A represents 0.8
Point B represents 1.3
Point C represents 2.2
Point D represents 2.9

18. Length of rectangular field = 20 m
Breadth of the rectangular field = 15 m
The ratio of the breadth to the length is 15 : 20
Now,
15 15 5 3
15:20 3: 4
20 20 5 4
?
? ? ? ?
?

Thus, the required ratio is 3 : 4.

19. Steps of construction:
1. Draw a line segment AB of any length and mark a point P on it.
2. Taking P as centre and any radius draw two arcs one on left side of P and other
on right side of P, which cut AB at Q and R.
3. Taking Q and R as a centre draw two arcs and let them intersect at S.
4. Join PS.
5. PS is the required perpendicular of AB.

CBSE VI | Mathematics
Sample Paper 2 – Solution

20. Subtract 74.5 from 91

Hence, 16.5 should be added to 74.5 to get 91.

21. a.  y + 7
b.
a
23

22. The complete image is as below:

23. (a) Number of students whose favourite colour is blue = 30.
(b) Number of students whose favourite colour is green = 45
Number of students whose favourite colour is red = 25
Thus, required number of students = 45 – 2 5 = 20

24. Speed of the bus = v km per hour
Distance travelled by the bus in 10 hours = 10v km
According to the question,
Distance from Delhi to Mumbai
= Distance travelled by bus in 10 hours + 80 km
= 10v km + 80 km
= (10v + 80) km

Section C

25. Total balls = 55
Blue balls = 25
Remaining balls are = 55 – 25 = 30
Given that remaining balls are in the ratio of 2 : 1.
Let these balls be 2x and 1x respectively.
? 2x + 1x = 30
? 3x = 30 ? x = 10
Thus, number of other two balls are
2x = 2 × 10 = 20 and 1x = 1 × 10 = 10
Ratio of sum of other two balls to the blue balls
30 6
6:5
25 5
? ? ?

CBSE VI | Mathematics
Sample Paper 2 – Solution

26.
1. Maximum rainfall occurred in city B, i.e., 25 × 10 = 250 cm
2. Minimum rainfall was in city F that is 25 × 1 = 25 cm
3. Difference between rainfalls of city A and F = (7 – 1) × 25 = 150 cm

27.  The steps of construction are as follows:
1. Draw right angle triangle ABC with right angle at B.
2. Construct perpendicular bisectors of sides AB and BC.
3. Let the point of intersection of the perpendiculars be P.
4. By observing this point P lies on hypotenuse AC.

28. Total area of tiles must be equal to the area of the floor of the room.
Length = 15 m  and  Breadth = 16 m
Area of the floor = length × breadth = 15 × 16 = 240 sq. m
Area of one rectangular tile = length × breadth = 1.5 × 1 = 1.5 sq. m
Area of floor 240
Number of tiles required 160
Area of one tile 1.5
? ? ? ?

29. Number of girls in the class = 35
Number of boys in the class = 45
Total number of students = 35 + 45 = 80
Ratio of boys to girls = 45 : 35 = 9 : 7                  (dividing by 5)
Ratio of boys to total number of students = 45 : 80 = 9 : 16

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