Grade 11 Exam  >  Grade 11 Notes  >  Sample Solution Paper 3: Physics, Class 11

Sample Solution Paper 3: Physics, Class 11 - Grade 11 PDF Download

Download, print and study this document offline
Please wait while the PDF view is loading
 Page 1


  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
CBSE Board 
Class XI Physics 
Sample Paper-3 Solution 
 
 
1. 
Yes. Example is angle      
 
2.  
Motion of a body thrown vertically/obliquely under constant g 
 
3.  
- x-axis         
 
4.  
Work       
 
5.  
Since ? ? ? rF , larger arm means larger r which requires less F for same ? .   
 
6.  
3         
 
7.     
   
 
8.  
No process is possible whose sole result is the absorption of heat from a reservoir and the 
conversion of all of this heat into work. 
 
 
Page 2


  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
CBSE Board 
Class XI Physics 
Sample Paper-3 Solution 
 
 
1. 
Yes. Example is angle      
 
2.  
Motion of a body thrown vertically/obliquely under constant g 
 
3.  
- x-axis         
 
4.  
Work       
 
5.  
Since ? ? ? rF , larger arm means larger r which requires less F for same ? .   
 
6.  
3         
 
7.     
   
 
8.  
No process is possible whose sole result is the absorption of heat from a reservoir and the 
conversion of all of this heat into work. 
 
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
9.  
Systematic Errors Random Errors 
1. Errors in which the deviation 
from true value tends to have 
fixed size and sign.                 
 
2. They can be attributed to a 
fixed cause and can be 
eliminated. 
Deviation from true value is 
irregular in size as well as sign.               
 
Irregular pattern does not allow 
them to be attributed to any fixed 
cause and hence cannot be 
eliminated, only minimized.                                  
 
10.  
For 3 kg: 
    
   
 F – F 32 = m 3a           (i)     
For 2 kg: 
      
  
F 23 = m 2a                                 (ii)  
 
But from Newton’s third law 
 
23 32
FF ??      
Therefore, from (i) and (ii), F – m 2a = m 3a 
 F = (m 2 + m 3)a 
 
2
5
a 1 m/s
5
? ? ? 
Therefore, F 32 = m 2a = 2.1 = 2N      (1/2) 
 
Page 3


  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
CBSE Board 
Class XI Physics 
Sample Paper-3 Solution 
 
 
1. 
Yes. Example is angle      
 
2.  
Motion of a body thrown vertically/obliquely under constant g 
 
3.  
- x-axis         
 
4.  
Work       
 
5.  
Since ? ? ? rF , larger arm means larger r which requires less F for same ? .   
 
6.  
3         
 
7.     
   
 
8.  
No process is possible whose sole result is the absorption of heat from a reservoir and the 
conversion of all of this heat into work. 
 
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
9.  
Systematic Errors Random Errors 
1. Errors in which the deviation 
from true value tends to have 
fixed size and sign.                 
 
2. They can be attributed to a 
fixed cause and can be 
eliminated. 
Deviation from true value is 
irregular in size as well as sign.               
 
Irregular pattern does not allow 
them to be attributed to any fixed 
cause and hence cannot be 
eliminated, only minimized.                                  
 
10.  
For 3 kg: 
    
   
 F – F 32 = m 3a           (i)     
For 2 kg: 
      
  
F 23 = m 2a                                 (ii)  
 
But from Newton’s third law 
 
23 32
FF ??      
Therefore, from (i) and (ii), F – m 2a = m 3a 
 F = (m 2 + m 3)a 
 
2
5
a 1 m/s
5
? ? ? 
Therefore, F 32 = m 2a = 2.1 = 2N      (1/2) 
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
OR 
 
The two ways are: 
1. Friction adjusts its direction to be always opposite to applied force.  
2. Friction adjusts its magnitude up to a certain limit, to be equal to the applied force.  
 
 F ms = ?
s
N = ? ? ? ? ?
s
mg 0.2 2 10 4N   
Since, applied force < F ms, the static friction acting = f s = 2 N. 
 
11.  
We know that 
 p 2mk ?     
??
? ? ? ? ?
??
??
21 11 11
and p' 2mk' 2m k k 2mk p
100 10 10
  
Therefore, 
11
pp
p1
10
p p 10
?
?
??  
 
p
100 10%
p
?
??   
 
12.  
? ? ? rpsin mv       
Direction of ? rp ? direction of     
  
 
 
13.  
Polar satellites - Their orbit is perpendicular to the orbit of geostationary satellites. These 
are used for communication purpose. Also, the height above the Earth’s surface is lower. 
Negative sign of total energy indicates attractive nature of force between the satellite and 
the Earth.     
 
Page 4


  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
CBSE Board 
Class XI Physics 
Sample Paper-3 Solution 
 
 
1. 
Yes. Example is angle      
 
2.  
Motion of a body thrown vertically/obliquely under constant g 
 
3.  
- x-axis         
 
4.  
Work       
 
5.  
Since ? ? ? rF , larger arm means larger r which requires less F for same ? .   
 
6.  
3         
 
7.     
   
 
8.  
No process is possible whose sole result is the absorption of heat from a reservoir and the 
conversion of all of this heat into work. 
 
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
9.  
Systematic Errors Random Errors 
1. Errors in which the deviation 
from true value tends to have 
fixed size and sign.                 
 
2. They can be attributed to a 
fixed cause and can be 
eliminated. 
Deviation from true value is 
irregular in size as well as sign.               
 
Irregular pattern does not allow 
them to be attributed to any fixed 
cause and hence cannot be 
eliminated, only minimized.                                  
 
10.  
For 3 kg: 
    
   
 F – F 32 = m 3a           (i)     
For 2 kg: 
      
  
F 23 = m 2a                                 (ii)  
 
But from Newton’s third law 
 
23 32
FF ??      
Therefore, from (i) and (ii), F – m 2a = m 3a 
 F = (m 2 + m 3)a 
 
2
5
a 1 m/s
5
? ? ? 
Therefore, F 32 = m 2a = 2.1 = 2N      (1/2) 
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
OR 
 
The two ways are: 
1. Friction adjusts its direction to be always opposite to applied force.  
2. Friction adjusts its magnitude up to a certain limit, to be equal to the applied force.  
 
 F ms = ?
s
N = ? ? ? ? ?
s
mg 0.2 2 10 4N   
Since, applied force < F ms, the static friction acting = f s = 2 N. 
 
11.  
We know that 
 p 2mk ?     
??
? ? ? ? ?
??
??
21 11 11
and p' 2mk' 2m k k 2mk p
100 10 10
  
Therefore, 
11
pp
p1
10
p p 10
?
?
??  
 
p
100 10%
p
?
??   
 
12.  
? ? ? rpsin mv       
Direction of ? rp ? direction of     
  
 
 
13.  
Polar satellites - Their orbit is perpendicular to the orbit of geostationary satellites. These 
are used for communication purpose. Also, the height above the Earth’s surface is lower. 
Negative sign of total energy indicates attractive nature of force between the satellite and 
the Earth.     
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
14.  
The stress required to fracture a material whether by compression, tension, or shear is 
called breaking stress.   
Yes, the wire is under stress as its own weight acts as load. 
 
15.  
For adiabatic expression PV
?
 = const.         
Therefore, PV
?
= '' PV
?
 ? 
5/3 5/3 5 5/3
1600 '(8 ) 2 ' V P V PV ??     
Or ??
a
1600
P' 50P
32
        
Therefore, fall in pressure = 1600 – 500 = 1550 P a      
 
16.  
(i) For isothermal expansion ?T = 0, hence ?U = 0   
(ii) For adiabatic expansion ?U = ?Q – ?W = - ?W = -P ?V as ?Q = 0. 
 
17. 
 
 
 
 
?
? ? ? ?
?
A
36 1000
36 km/h 10 m/s
60 60
 
 
AC
54 km/h 15 m/s ? ? ? ? ? 
 
BA B A
15 10 5 m/s ? ? ? ? ? ? ? ?     
 
CA C A
15 ( 10) 25 m/s ? ? ? ? ? ? ? ? ?  
Time taken by C to cover 1 km = ?
1000
40s
25
 
To avoid accident, B should cover 1 km is less than 40s. 
 ??
2
1
s ut at
2
         
2
1
1000 5 40 a.(40)
2
? ? ? ?       
               200 800a ?? 
 800a = 1000 – 200 = 800 
 ? a = 1 m/s
2
      
 
 
 
Page 5


  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
CBSE Board 
Class XI Physics 
Sample Paper-3 Solution 
 
 
1. 
Yes. Example is angle      
 
2.  
Motion of a body thrown vertically/obliquely under constant g 
 
3.  
- x-axis         
 
4.  
Work       
 
5.  
Since ? ? ? rF , larger arm means larger r which requires less F for same ? .   
 
6.  
3         
 
7.     
   
 
8.  
No process is possible whose sole result is the absorption of heat from a reservoir and the 
conversion of all of this heat into work. 
 
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
9.  
Systematic Errors Random Errors 
1. Errors in which the deviation 
from true value tends to have 
fixed size and sign.                 
 
2. They can be attributed to a 
fixed cause and can be 
eliminated. 
Deviation from true value is 
irregular in size as well as sign.               
 
Irregular pattern does not allow 
them to be attributed to any fixed 
cause and hence cannot be 
eliminated, only minimized.                                  
 
10.  
For 3 kg: 
    
   
 F – F 32 = m 3a           (i)     
For 2 kg: 
      
  
F 23 = m 2a                                 (ii)  
 
But from Newton’s third law 
 
23 32
FF ??      
Therefore, from (i) and (ii), F – m 2a = m 3a 
 F = (m 2 + m 3)a 
 
2
5
a 1 m/s
5
? ? ? 
Therefore, F 32 = m 2a = 2.1 = 2N      (1/2) 
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
OR 
 
The two ways are: 
1. Friction adjusts its direction to be always opposite to applied force.  
2. Friction adjusts its magnitude up to a certain limit, to be equal to the applied force.  
 
 F ms = ?
s
N = ? ? ? ? ?
s
mg 0.2 2 10 4N   
Since, applied force < F ms, the static friction acting = f s = 2 N. 
 
11.  
We know that 
 p 2mk ?     
??
? ? ? ? ?
??
??
21 11 11
and p' 2mk' 2m k k 2mk p
100 10 10
  
Therefore, 
11
pp
p1
10
p p 10
?
?
??  
 
p
100 10%
p
?
??   
 
12.  
? ? ? rpsin mv       
Direction of ? rp ? direction of     
  
 
 
13.  
Polar satellites - Their orbit is perpendicular to the orbit of geostationary satellites. These 
are used for communication purpose. Also, the height above the Earth’s surface is lower. 
Negative sign of total energy indicates attractive nature of force between the satellite and 
the Earth.     
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
14.  
The stress required to fracture a material whether by compression, tension, or shear is 
called breaking stress.   
Yes, the wire is under stress as its own weight acts as load. 
 
15.  
For adiabatic expression PV
?
 = const.         
Therefore, PV
?
= '' PV
?
 ? 
5/3 5/3 5 5/3
1600 '(8 ) 2 ' V P V PV ??     
Or ??
a
1600
P' 50P
32
        
Therefore, fall in pressure = 1600 – 500 = 1550 P a      
 
16.  
(i) For isothermal expansion ?T = 0, hence ?U = 0   
(ii) For adiabatic expansion ?U = ?Q – ?W = - ?W = -P ?V as ?Q = 0. 
 
17. 
 
 
 
 
?
? ? ? ?
?
A
36 1000
36 km/h 10 m/s
60 60
 
 
AC
54 km/h 15 m/s ? ? ? ? ? 
 
BA B A
15 10 5 m/s ? ? ? ? ? ? ? ?     
 
CA C A
15 ( 10) 25 m/s ? ? ? ? ? ? ? ? ?  
Time taken by C to cover 1 km = ?
1000
40s
25
 
To avoid accident, B should cover 1 km is less than 40s. 
 ??
2
1
s ut at
2
         
2
1
1000 5 40 a.(40)
2
? ? ? ?       
               200 800a ?? 
 800a = 1000 – 200 = 800 
 ? a = 1 m/s
2
      
 
 
 
  
 
CBSE  | Physics  
Sample Paper 3 Solution 
 
     
18.  
 a = -kx     
 
dv
a kx
dx
? ? ? ?  
 dv kx dx ? ? ? 
Integrating both sides, we get 
 
x
uo
dv kx dx
?
? ? ?
??
       
 
2 2 2
11
( u ) kx
22
? ? ? ?       
or  
2 2 2
11
m( u ) m kx
22
? ? ? ? 
Therefore, loss in K.E. = 
2
1
m kx
2
    
 
19.  
(a) During free fall acceleration of thief = g = acceleration of load   
So that load is unable to apply any force. 
Let the force by load be N. 
 mg – N ? N = 0 = force applied by load on man  
 
(b) Along horizontal direction, ?
? ext
F0 . Net linear momentum is conserved. 
Before firing, the system is at rest.     
Therefore, 0 = 
b b g g
mm ? ? ? 
 
b
gb
g
m
m
? ? ? ?     
So, to conserve linear momentum, the gun recoils. 
 
(c) The sand yields but the cemented floor doesn’t. 
Hence, the time taken by man to come to rest increases in case of sand. 
Since, 
p
F
t
?
?
?
, force on man is less.    
 
20.  
We know that 
 
12
KA(T T )t
Q
x
?
?    
A = area of 6 faces = 6 × (3 × 10
-1
)
2
 = 54 × 10
-3    
 
 m L = 
12
KA(T T )t
x
?
      
or  
12
KA(T T )t
m
xL
?
? 
Read More
Download as PDF
Explore Courses for Grade 11 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Download the FREE EduRev App
Track your progress, build streaks, highlight & save important lessons and more!
Related Searches

past year papers

,

Viva Questions

,

Free

,

Class 11 - Grade 11

,

Previous Year Questions with Solutions

,

shortcuts and tricks

,

Sample Solution Paper 3: Physics

,

Exam

,

Class 11 - Grade 11

,

study material

,

pdf

,

Class 11 - Grade 11

,

Important questions

,

Sample Paper

,

Objective type Questions

,

Semester Notes

,

practice quizzes

,

Sample Solution Paper 3: Physics

,

video lectures

,

Extra Questions

,

MCQs

,

Sample Solution Paper 3: Physics

,

ppt

,

Summary

,

mock tests for examination

;