Page 1 CBSE VII | Mathematics Sample Paper 4 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 4 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A For example: (a) 56 + 73 = 129 (b) 113 + 82 = 195 2. Correct answer: B A proper fraction is a fraction that represents a part of a whole. 3. Correct answer: B On a number line when we add a positive integer we move to the right Towards or away from origin depends on the number to which it is added. 4. Correct answer: A An improper fraction is a combination of whole and a proper fraction. 5. Correct answer: B Average of both = 60 20 40 2 ? ? 6. Correct answer: B A variable takes on different numerical values; its value is not fixed. Variables are denoted usually by letters of the alphabets, such as x, y, z, l, m, n, p, etc. 7. Correct answer: C Total runs = 36 + 35 + 50 + 46 + 60 + 55 = 282. To find the mean, we find the sum of all the observations and divide it by the number of observations. Therefore, in this case, mean = 282 47 6 ? Page 2 CBSE VII | Mathematics Sample Paper 4 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 4 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A For example: (a) 56 + 73 = 129 (b) 113 + 82 = 195 2. Correct answer: B A proper fraction is a fraction that represents a part of a whole. 3. Correct answer: B On a number line when we add a positive integer we move to the right Towards or away from origin depends on the number to which it is added. 4. Correct answer: A An improper fraction is a combination of whole and a proper fraction. 5. Correct answer: B Average of both = 60 20 40 2 ? ? 6. Correct answer: B A variable takes on different numerical values; its value is not fixed. Variables are denoted usually by letters of the alphabets, such as x, y, z, l, m, n, p, etc. 7. Correct answer: C Total runs = 36 + 35 + 50 + 46 + 60 + 55 = 282. To find the mean, we find the sum of all the observations and divide it by the number of observations. Therefore, in this case, mean = 282 47 6 ? CBSE VII | Mathematics Sample Paper 4 - Solution 8. Correct answer: C an equation is a condition on a variable. The condition is that two expressions should have equal value. Note that at least one of the two expressions must contain the variable. 9. Correct answer: D When the sum of the measures of two angles is 90°, the angles are called complementary angles. 10. Correct answer: B A median connects a vertex of a triangle to the mid-point of the opposite side. 11. Correct answer: D The tests of congruency are SSS SAS AAS,SAA,ASA (all same) 12. Correct answer: A First convert both the distances to the same unit. So, 3 km = 3 × 1000 m = 3000 m. Thus, the required ratio, 3 km : 300 m is 3000 : 300 = 10 : 1. Section B 13. (a) ? ? ? ? ? ? ? ? 8 4 8 4 8 4 8 4 12 4 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? (b) ? ? ? ? ? ? 3 7 19 15 8 9 3 7 19 15 8 9 15 2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? Page 3 CBSE VII | Mathematics Sample Paper 4 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 4 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A For example: (a) 56 + 73 = 129 (b) 113 + 82 = 195 2. Correct answer: B A proper fraction is a fraction that represents a part of a whole. 3. Correct answer: B On a number line when we add a positive integer we move to the right Towards or away from origin depends on the number to which it is added. 4. Correct answer: A An improper fraction is a combination of whole and a proper fraction. 5. Correct answer: B Average of both = 60 20 40 2 ? ? 6. Correct answer: B A variable takes on different numerical values; its value is not fixed. Variables are denoted usually by letters of the alphabets, such as x, y, z, l, m, n, p, etc. 7. Correct answer: C Total runs = 36 + 35 + 50 + 46 + 60 + 55 = 282. To find the mean, we find the sum of all the observations and divide it by the number of observations. Therefore, in this case, mean = 282 47 6 ? CBSE VII | Mathematics Sample Paper 4 - Solution 8. Correct answer: C an equation is a condition on a variable. The condition is that two expressions should have equal value. Note that at least one of the two expressions must contain the variable. 9. Correct answer: D When the sum of the measures of two angles is 90°, the angles are called complementary angles. 10. Correct answer: B A median connects a vertex of a triangle to the mid-point of the opposite side. 11. Correct answer: D The tests of congruency are SSS SAS AAS,SAA,ASA (all same) 12. Correct answer: A First convert both the distances to the same unit. So, 3 km = 3 × 1000 m = 3000 m. Thus, the required ratio, 3 km : 300 m is 3000 : 300 = 10 : 1. Section B 13. (a) ? ? ? ? ? ? ? ? 8 4 8 4 8 4 8 4 12 4 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? (b) ? ? ? ? ? ? 3 7 19 15 8 9 3 7 19 15 8 9 15 2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? CBSE VII | Mathematics Sample Paper 4 - Solution (c) 23 41 11 23 41 11 7 29 ? ? ? ? ? ? ? ? (d) ? ? ? ? ? ? ? ? 39 24 15 36 52 36 39 24 15 36 52 36 0 20 ? ? ? ? ? ? ? ? ? ? ? ? ?? (e) 231 79 51 399 159 81 101 159 ? ? ? ? ? ? ? ? ? ? 14. The numbers in ascending order are: Team A scored: â€“ 40, 10, 0 Total score = â€“ 40 + 10 + 0 = â€“ 30 Team B scored: 10, 0, â€“ 40 Total score = 10 + 0 + (â€“ 40)= â€“ 30 ? The scores of both teams are equal. Yes, we can add integers in any order. As we had observed that the scores obtained by both teams in successive rounds were numerically equal but different in order, yet total score of both teams were equal. 15. (i) 3 2 5 3 10 3 7 2 5 5 5 5 5 ?? ? ? ? ? ? (ii) ? ? 4 8 7 7 4 8 7 39 7 44 8 8 8 8 8 8 ?? ? ? ? ? ? ? ? Page 4 CBSE VII | Mathematics Sample Paper 4 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 4 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A For example: (a) 56 + 73 = 129 (b) 113 + 82 = 195 2. Correct answer: B A proper fraction is a fraction that represents a part of a whole. 3. Correct answer: B On a number line when we add a positive integer we move to the right Towards or away from origin depends on the number to which it is added. 4. Correct answer: A An improper fraction is a combination of whole and a proper fraction. 5. Correct answer: B Average of both = 60 20 40 2 ? ? 6. Correct answer: B A variable takes on different numerical values; its value is not fixed. Variables are denoted usually by letters of the alphabets, such as x, y, z, l, m, n, p, etc. 7. Correct answer: C Total runs = 36 + 35 + 50 + 46 + 60 + 55 = 282. To find the mean, we find the sum of all the observations and divide it by the number of observations. Therefore, in this case, mean = 282 47 6 ? CBSE VII | Mathematics Sample Paper 4 - Solution 8. Correct answer: C an equation is a condition on a variable. The condition is that two expressions should have equal value. Note that at least one of the two expressions must contain the variable. 9. Correct answer: D When the sum of the measures of two angles is 90°, the angles are called complementary angles. 10. Correct answer: B A median connects a vertex of a triangle to the mid-point of the opposite side. 11. Correct answer: D The tests of congruency are SSS SAS AAS,SAA,ASA (all same) 12. Correct answer: A First convert both the distances to the same unit. So, 3 km = 3 × 1000 m = 3000 m. Thus, the required ratio, 3 km : 300 m is 3000 : 300 = 10 : 1. Section B 13. (a) ? ? ? ? ? ? ? ? 8 4 8 4 8 4 8 4 12 4 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? (b) ? ? ? ? ? ? 3 7 19 15 8 9 3 7 19 15 8 9 15 2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? CBSE VII | Mathematics Sample Paper 4 - Solution (c) 23 41 11 23 41 11 7 29 ? ? ? ? ? ? ? ? (d) ? ? ? ? ? ? ? ? 39 24 15 36 52 36 39 24 15 36 52 36 0 20 ? ? ? ? ? ? ? ? ? ? ? ? ?? (e) 231 79 51 399 159 81 101 159 ? ? ? ? ? ? ? ? ? ? 14. The numbers in ascending order are: Team A scored: â€“ 40, 10, 0 Total score = â€“ 40 + 10 + 0 = â€“ 30 Team B scored: 10, 0, â€“ 40 Total score = 10 + 0 + (â€“ 40)= â€“ 30 ? The scores of both teams are equal. Yes, we can add integers in any order. As we had observed that the scores obtained by both teams in successive rounds were numerically equal but different in order, yet total score of both teams were equal. 15. (i) 3 2 5 3 10 3 7 2 5 5 5 5 5 ?? ? ? ? ? ? (ii) ? ? 4 8 7 7 4 8 7 39 7 44 8 8 8 8 8 8 ?? ? ? ? ? ? ? ? CBSE VII | Mathematics Sample Paper 4 - Solution 16. (i) 3 21 1 74 5 5 5 ? ? ? (ii) 1 4 1 41 3 3 3 ? ? ? 17. We may arrange the marks obtained by group of student in a science test in an ascending order as following â€“39, 48, 56, 75, 76, 81, 85, 85, 90, 95 (i) Highest marks = 95 Lowest marks = 39 (ii) Range = 95 â€“ 39 = 56 (iii) Mean marks = ? ? 85 76 90 85 39 48 56 95 81 75 10 ? ? ? ? ? ? ? ? ? 730 73 10 ?? 18. Scores of 15 students in mathematics test are â€“ 19, 25, 23, 20, 9, 20, 15, 10, 5, 16, 25, 20, 24, 12, 20 By arranging these scores in an ascending order 5, 9, 10, 12, 15, 16, 19, 20, 20, 20, 20, 23, 24, 25, 25 Mode of a given data is that value of observation which occurs for the most number of times and the median of the given data is the middle observation while the data is arranged in an ascending or descending order. As here are 15 terms in the given data so the median of this data will be 8th observation. Hence, median = 20 Also we may find that 20 occurs 4 times (i.e. maximum number of times). So, mode of this data = 20. Yes, both are same. Page 5 CBSE VII | Mathematics Sample Paper 4 - Solution CBSE Board Class VII Mathematics Term I Sample Paper 4 - Solution Time: 2 ½ hours Total Marks: 80 Section A 1. Correct answer: A For example: (a) 56 + 73 = 129 (b) 113 + 82 = 195 2. Correct answer: B A proper fraction is a fraction that represents a part of a whole. 3. Correct answer: B On a number line when we add a positive integer we move to the right Towards or away from origin depends on the number to which it is added. 4. Correct answer: A An improper fraction is a combination of whole and a proper fraction. 5. Correct answer: B Average of both = 60 20 40 2 ? ? 6. Correct answer: B A variable takes on different numerical values; its value is not fixed. Variables are denoted usually by letters of the alphabets, such as x, y, z, l, m, n, p, etc. 7. Correct answer: C Total runs = 36 + 35 + 50 + 46 + 60 + 55 = 282. To find the mean, we find the sum of all the observations and divide it by the number of observations. Therefore, in this case, mean = 282 47 6 ? CBSE VII | Mathematics Sample Paper 4 - Solution 8. Correct answer: C an equation is a condition on a variable. The condition is that two expressions should have equal value. Note that at least one of the two expressions must contain the variable. 9. Correct answer: D When the sum of the measures of two angles is 90°, the angles are called complementary angles. 10. Correct answer: B A median connects a vertex of a triangle to the mid-point of the opposite side. 11. Correct answer: D The tests of congruency are SSS SAS AAS,SAA,ASA (all same) 12. Correct answer: A First convert both the distances to the same unit. So, 3 km = 3 × 1000 m = 3000 m. Thus, the required ratio, 3 km : 300 m is 3000 : 300 = 10 : 1. Section B 13. (a) ? ? ? ? ? ? ? ? 8 4 8 4 8 4 8 4 12 4 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? (b) ? ? ? ? ? ? 3 7 19 15 8 9 3 7 19 15 8 9 15 2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? CBSE VII | Mathematics Sample Paper 4 - Solution (c) 23 41 11 23 41 11 7 29 ? ? ? ? ? ? ? ? (d) ? ? ? ? ? ? ? ? 39 24 15 36 52 36 39 24 15 36 52 36 0 20 ? ? ? ? ? ? ? ? ? ? ? ? ?? (e) 231 79 51 399 159 81 101 159 ? ? ? ? ? ? ? ? ? ? 14. The numbers in ascending order are: Team A scored: â€“ 40, 10, 0 Total score = â€“ 40 + 10 + 0 = â€“ 30 Team B scored: 10, 0, â€“ 40 Total score = 10 + 0 + (â€“ 40)= â€“ 30 ? The scores of both teams are equal. Yes, we can add integers in any order. As we had observed that the scores obtained by both teams in successive rounds were numerically equal but different in order, yet total score of both teams were equal. 15. (i) 3 2 5 3 10 3 7 2 5 5 5 5 5 ?? ? ? ? ? ? (ii) ? ? 4 8 7 7 4 8 7 39 7 44 8 8 8 8 8 8 ?? ? ? ? ? ? ? ? CBSE VII | Mathematics Sample Paper 4 - Solution 16. (i) 3 21 1 74 5 5 5 ? ? ? (ii) 1 4 1 41 3 3 3 ? ? ? 17. We may arrange the marks obtained by group of student in a science test in an ascending order as following â€“39, 48, 56, 75, 76, 81, 85, 85, 90, 95 (i) Highest marks = 95 Lowest marks = 39 (ii) Range = 95 â€“ 39 = 56 (iii) Mean marks = ? ? 85 76 90 85 39 48 56 95 81 75 10 ? ? ? ? ? ? ? ? ? 730 73 10 ?? 18. Scores of 15 students in mathematics test are â€“ 19, 25, 23, 20, 9, 20, 15, 10, 5, 16, 25, 20, 24, 12, 20 By arranging these scores in an ascending order 5, 9, 10, 12, 15, 16, 19, 20, 20, 20, 20, 23, 24, 25, 25 Mode of a given data is that value of observation which occurs for the most number of times and the median of the given data is the middle observation while the data is arranged in an ascending or descending order. As here are 15 terms in the given data so the median of this data will be 8th observation. Hence, median = 20 Also we may find that 20 occurs 4 times (i.e. maximum number of times). So, mode of this data = 20. Yes, both are same. CBSE VII | Mathematics Sample Paper 4 - Solution 19. (i) 5p + 2 = 17 Put p = 1 in L.H.S (5 × 1) + 2 = 7 ? R.H.S Put p = 2 in L.H.S (5 × 2) + 2 = 10 + 2 = 12 ? R.H.S Put p = 3 in L.H.S (5 × 3) + 2 = 17 = R.H.S Hence p = 3 is a solution of the given equation. (ii) 3m â€“ 14 = 4 Put m = 4, (3 × 4) â€“ 14 = â€“ 2 ? R.H.S Put m = 5 (3 × 5) â€“ 14 = 1 ? R.H.S Put m = 6 (3 × 6) â€“ 14 = 18 â€“ 14 = 4 = R.H.S Hence, m = 6 is a solution of the given equation.Read More