Sample Solution Paper 5 - Term- 1 Mathematics, Class 6 Class 6 Notes | EduRev

Mathematics (Maths) Class 6

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Class 6 : Sample Solution Paper 5 - Term- 1 Mathematics, Class 6 Class 6 Notes | EduRev

 Page 1


  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
CBSE Board 
Class VI Mathematics 
Term I 
Sample Paper 5 – Solution 
Time: 2 ½ hours                          Total Marks: 80 
 
Section A 
 
1. Correct Answer: A 
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3 
 
2. Correct Answer: D 
932, 923, 239, 293, 329, 392. 
 
3. Correct Answer: C 
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1 
and 139.  
 
4. Correct Answer: A 
 
 
5. Correct Answer: D 
The HCF of 15 and 27 is 3. Hence,  
 
  
6. Correct Answer: B 
To add 4 on number line, move 4 steps to the right of 0. 
 
7. Correct Answer: D 
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest 
hundreds. 
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its 
nearest hundreds as 200. 
So, the required estimation of the product is 50 × 200 = 10000. 
Page 2


  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
CBSE Board 
Class VI Mathematics 
Term I 
Sample Paper 5 – Solution 
Time: 2 ½ hours                          Total Marks: 80 
 
Section A 
 
1. Correct Answer: A 
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3 
 
2. Correct Answer: D 
932, 923, 239, 293, 329, 392. 
 
3. Correct Answer: C 
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1 
and 139.  
 
4. Correct Answer: A 
 
 
5. Correct Answer: D 
The HCF of 15 and 27 is 3. Hence,  
 
  
6. Correct Answer: B 
To add 4 on number line, move 4 steps to the right of 0. 
 
7. Correct Answer: D 
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest 
hundreds. 
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its 
nearest hundreds as 200. 
So, the required estimation of the product is 50 × 200 = 10000. 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
8. Correct Answer:  A 
 
Thus, 36 = 2 × 2 × 3 × 3 
 
9. Correct Answer: D 
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7 
 
10. Correct Answer: B 
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending, 
it can be seen that they would meet at a point. Hence, they are intersecting lines. 
One and only one line passes through any two given points. 
 
11. Correct Answer: B 
 267 can be estimated as 270. 
 132 can be estimated as 130. 
Thus the required estimated sum = 270 + 130 = 400 
 
12. Correct Answer: B 
 10 = 2 × 5 
 18 = 2 × 3 × 3 
 HCF of 10 and 18 is 2. 
 Thus, 2 is the required number. 
 
Section B 
13. Place value of 9 at the Ten Lakhs place = 9000000 
Place value of 9 at the hundreds place = 900 
Difference = 9000000 – 900 = 8999100 
 
14. The number of vertices in the given shapes: 
i. Sphere : 0 
ii. Cylinder : 0 
Page 3


  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
CBSE Board 
Class VI Mathematics 
Term I 
Sample Paper 5 – Solution 
Time: 2 ½ hours                          Total Marks: 80 
 
Section A 
 
1. Correct Answer: A 
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3 
 
2. Correct Answer: D 
932, 923, 239, 293, 329, 392. 
 
3. Correct Answer: C 
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1 
and 139.  
 
4. Correct Answer: A 
 
 
5. Correct Answer: D 
The HCF of 15 and 27 is 3. Hence,  
 
  
6. Correct Answer: B 
To add 4 on number line, move 4 steps to the right of 0. 
 
7. Correct Answer: D 
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest 
hundreds. 
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its 
nearest hundreds as 200. 
So, the required estimation of the product is 50 × 200 = 10000. 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
8. Correct Answer:  A 
 
Thus, 36 = 2 × 2 × 3 × 3 
 
9. Correct Answer: D 
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7 
 
10. Correct Answer: B 
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending, 
it can be seen that they would meet at a point. Hence, they are intersecting lines. 
One and only one line passes through any two given points. 
 
11. Correct Answer: B 
 267 can be estimated as 270. 
 132 can be estimated as 130. 
Thus the required estimated sum = 270 + 130 = 400 
 
12. Correct Answer: B 
 10 = 2 × 5 
 18 = 2 × 3 × 3 
 HCF of 10 and 18 is 2. 
 Thus, 2 is the required number. 
 
Section B 
13. Place value of 9 at the Ten Lakhs place = 9000000 
Place value of 9 at the hundreds place = 900 
Difference = 9000000 – 900 = 8999100 
 
14. The number of vertices in the given shapes: 
i. Sphere : 0 
ii. Cylinder : 0 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
15. Anna is 7 feet above sea level. She jumps 3 feet down and walks another 2 feet down. 
Total distance travelled downwards = 3 + 2 = 5 feet. 
 
 
16. (–13) + (–19) + (+15) + (–10) 
= –13 – 19 + 15 – 10 
= –13 – 19 – 10 + 15 
= –42 + 15 
= –27 
 
17. A 9-digit numeral in Indian system = 94,50,27,983 
In International system, 
945,027,983 - Nine hundred forty five million twenty seven thousand nine hundred 
eighty three. 
 
18. Two lines in the same plane which never intersect are called parallel lines.  
Parallel lines maintain the same distance apart over their entire length. 
 
 
19. Population of the village = 13295 
Increase in population= Average growth – 1 = 399 
Population in the successive year = 13295 + 399 = 13694 
 
20. Prime factorisation of 455 =  5 × 7 × 13 
Therefore, the dimensions of the cuboid are  
5 cm, 7 cm, 13 cm. 
 
 
Page 4


  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
CBSE Board 
Class VI Mathematics 
Term I 
Sample Paper 5 – Solution 
Time: 2 ½ hours                          Total Marks: 80 
 
Section A 
 
1. Correct Answer: A 
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3 
 
2. Correct Answer: D 
932, 923, 239, 293, 329, 392. 
 
3. Correct Answer: C 
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1 
and 139.  
 
4. Correct Answer: A 
 
 
5. Correct Answer: D 
The HCF of 15 and 27 is 3. Hence,  
 
  
6. Correct Answer: B 
To add 4 on number line, move 4 steps to the right of 0. 
 
7. Correct Answer: D 
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest 
hundreds. 
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its 
nearest hundreds as 200. 
So, the required estimation of the product is 50 × 200 = 10000. 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
8. Correct Answer:  A 
 
Thus, 36 = 2 × 2 × 3 × 3 
 
9. Correct Answer: D 
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7 
 
10. Correct Answer: B 
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending, 
it can be seen that they would meet at a point. Hence, they are intersecting lines. 
One and only one line passes through any two given points. 
 
11. Correct Answer: B 
 267 can be estimated as 270. 
 132 can be estimated as 130. 
Thus the required estimated sum = 270 + 130 = 400 
 
12. Correct Answer: B 
 10 = 2 × 5 
 18 = 2 × 3 × 3 
 HCF of 10 and 18 is 2. 
 Thus, 2 is the required number. 
 
Section B 
13. Place value of 9 at the Ten Lakhs place = 9000000 
Place value of 9 at the hundreds place = 900 
Difference = 9000000 – 900 = 8999100 
 
14. The number of vertices in the given shapes: 
i. Sphere : 0 
ii. Cylinder : 0 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
15. Anna is 7 feet above sea level. She jumps 3 feet down and walks another 2 feet down. 
Total distance travelled downwards = 3 + 2 = 5 feet. 
 
 
16. (–13) + (–19) + (+15) + (–10) 
= –13 – 19 + 15 – 10 
= –13 – 19 – 10 + 15 
= –42 + 15 
= –27 
 
17. A 9-digit numeral in Indian system = 94,50,27,983 
In International system, 
945,027,983 - Nine hundred forty five million twenty seven thousand nine hundred 
eighty three. 
 
18. Two lines in the same plane which never intersect are called parallel lines.  
Parallel lines maintain the same distance apart over their entire length. 
 
 
19. Population of the village = 13295 
Increase in population= Average growth – 1 = 399 
Population in the successive year = 13295 + 399 = 13694 
 
20. Prime factorisation of 455 =  5 × 7 × 13 
Therefore, the dimensions of the cuboid are  
5 cm, 7 cm, 13 cm. 
 
 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
21. L.C.M. of 24, 45 and 54 = 2 × 2 × 2 × 3 × 3 × 3 × 5 = 1080 
 
 
 
 
 
 
 
 
22. 
21
53
72
? 
37 7
72
37 2 7 7
7 2 2 7
74 49
14 14
123
14
11
8
14
??
??
??
??
??
?
?
 
 
23. Subtracting a negative number is the same as adding its positive integer. 
? 7 – (–3) = 7 + 3 = 10 
 
 
 
24. To find the H.C.F of 77, 105 and 231. 
 
77 = 7 × 11 
105 = 3 × 5 × 7 
231 = 3 × 7 × 11 
Hence, H.C.F of 77, 105 and 231 is = 7  
Page 5


  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
CBSE Board 
Class VI Mathematics 
Term I 
Sample Paper 5 – Solution 
Time: 2 ½ hours                          Total Marks: 80 
 
Section A 
 
1. Correct Answer: A 
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3 
 
2. Correct Answer: D 
932, 923, 239, 293, 329, 392. 
 
3. Correct Answer: C 
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1 
and 139.  
 
4. Correct Answer: A 
 
 
5. Correct Answer: D 
The HCF of 15 and 27 is 3. Hence,  
 
  
6. Correct Answer: B 
To add 4 on number line, move 4 steps to the right of 0. 
 
7. Correct Answer: D 
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest 
hundreds. 
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its 
nearest hundreds as 200. 
So, the required estimation of the product is 50 × 200 = 10000. 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
8. Correct Answer:  A 
 
Thus, 36 = 2 × 2 × 3 × 3 
 
9. Correct Answer: D 
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7 
 
10. Correct Answer: B 
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending, 
it can be seen that they would meet at a point. Hence, they are intersecting lines. 
One and only one line passes through any two given points. 
 
11. Correct Answer: B 
 267 can be estimated as 270. 
 132 can be estimated as 130. 
Thus the required estimated sum = 270 + 130 = 400 
 
12. Correct Answer: B 
 10 = 2 × 5 
 18 = 2 × 3 × 3 
 HCF of 10 and 18 is 2. 
 Thus, 2 is the required number. 
 
Section B 
13. Place value of 9 at the Ten Lakhs place = 9000000 
Place value of 9 at the hundreds place = 900 
Difference = 9000000 – 900 = 8999100 
 
14. The number of vertices in the given shapes: 
i. Sphere : 0 
ii. Cylinder : 0 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
15. Anna is 7 feet above sea level. She jumps 3 feet down and walks another 2 feet down. 
Total distance travelled downwards = 3 + 2 = 5 feet. 
 
 
16. (–13) + (–19) + (+15) + (–10) 
= –13 – 19 + 15 – 10 
= –13 – 19 – 10 + 15 
= –42 + 15 
= –27 
 
17. A 9-digit numeral in Indian system = 94,50,27,983 
In International system, 
945,027,983 - Nine hundred forty five million twenty seven thousand nine hundred 
eighty three. 
 
18. Two lines in the same plane which never intersect are called parallel lines.  
Parallel lines maintain the same distance apart over their entire length. 
 
 
19. Population of the village = 13295 
Increase in population= Average growth – 1 = 399 
Population in the successive year = 13295 + 399 = 13694 
 
20. Prime factorisation of 455 =  5 × 7 × 13 
Therefore, the dimensions of the cuboid are  
5 cm, 7 cm, 13 cm. 
 
 
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
21. L.C.M. of 24, 45 and 54 = 2 × 2 × 2 × 3 × 3 × 3 × 5 = 1080 
 
 
 
 
 
 
 
 
22. 
21
53
72
? 
37 7
72
37 2 7 7
7 2 2 7
74 49
14 14
123
14
11
8
14
??
??
??
??
??
?
?
 
 
23. Subtracting a negative number is the same as adding its positive integer. 
? 7 – (–3) = 7 + 3 = 10 
 
 
 
24. To find the H.C.F of 77, 105 and 231. 
 
77 = 7 × 11 
105 = 3 × 5 × 7 
231 = 3 × 7 × 11 
Hence, H.C.F of 77, 105 and 231 is = 7  
  
 
CBSE VI | Mathematics 
 Sample Paper 5 – Solution  
 
     
Section C 
 
25. To solve using number line start with –8, move 12 steps right and then back 2 steps as 
shown below: 
 
 So, we reach at 2, therefore (–8 + 12 – 2) = 2 
 
26. AC, AD, BD, BE and CE are diagonals. 
 
 
 
 
27. Temperature in the morning = –14
o
F 
Drop in temperature is written as –7
o
F 
Temperature at present = –14
o
F + (–7
o
F) = –14
o
F – 7
o
F = –21
o
F 
 
28. Rs. 13550 estimated to nearest thousands = Rs. 14000 
Rs. 26788 estimated to nearest thousands = Rs. 27000 
Total estimated money (to be received) = Rs. (14000 + 27000) = Rs. 41000 
He has to pay Rs. 37000. 
And 41000 > 37000 
Therefore, he will be able to pay to his supplier with the money received. 
 
29. First we find the LCM of 48, 60, 72. 
48 = 2 × 2 × 2 × 2 × 3 
60 = 2 × 2 × 3 × 5 
72 = 2 × 2 × 2 × 3 × 3 
LCM = 2 × 2 × 2 × 2 × 3 × 3 × 5 = 720 
Hence, they will meet after = 2 rounds. 
 
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