Any expression containing constants, variables, and the operations like addition, subtraction, etc. is called an algebraic expression.
Examples: 5x, 2x - 3, x2 + 1 etc.
Any mathematical expression equating one algebraic expression to another is called an equation.
Examples: 5x = 25, 2x - 3 = 9, x2 + 1 = 0 etc.
A linear expression is an expression whose highest power of the variable is one only.
Example
2x + 5, 3y etc.
The expressions like x2 + 1, z2 + 2z + 3 are not the linear expressions as their highest power of the variable is greater than 1.
The equation of a straight line is the linear equation. It could be in one variable or two variables.
If there is only one variable in the equation, then it is called a linear equation in one variable.
The general form is
ax + b = c, where a, b and c are real numbers and a ≠ 0.
Example
x + 5 = 10
y – 3 = 19
To find the solution of such equations, bring all quantities with variables on one side of the equation and all the other quantities on the other side. Now, solve the equation to obtain the solution.
Example 1: Solve 2x - 5 = x + 3
Solution: Firstly, we will transpose x from RHS to LHS
2x - 5 - x = 3
Now, we will transpose the integer - 5 from LHS to RHS
2x - x = 3 + 5
On solving,
x = 8
Example 2: Solve 2x + 53 = 263 - x and verify the result.
Solution: Transposing x to the LHS and 53 to the RHS, we get:
2x + x = 263 - 53
So, 3x = 213 = 7
Dividing both sides by 3, we get:
3x3 = 73
⇒ x = 73
Verification:
Substituting the value of x into the LHS and RHS:
LHS = 2x + 53 = 2 × 73 + 53 = 143 + 53 = 193
RHS = 263 - x = 263 - 73 = 193
Since LHS = RHS, the result is correct.
Example 1: x + 7 - 8x3 = 176 - 5x2
Solution: Firstly, we will transpose 5x2 on LHS:
x + 7 - 8x3 + 5x2 = 176
Now, let us transpose 7 from LHS to RHS:
x - 8x3 + 5x2 = 176 - 7
On solving both sides, we get:
5x6 = -256
Thus, x = -5 is the required solution.
Example 2: The denominator of a rational number is greater than its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, the number obtained is 32 . Find the rational number.
Solution: Suppose the numerator of the rational number is x. Hence, its denominator will be x + 8.
The rational number will be xx + 8.
Given, if the numerator is increased by 17 and the denominator is decreased by 1, the number obtained is 32, thus we get:
x + 17 x + 8 -1 = 32
Or, x + 17x + 7 = 32
Multiplying both sides by 2(x + 7), we get:
2(x + 17) = 3(x + 7)
⇒ 2x + 34 = 3x + 21
Transposing 3x on LHS and 34 on RHS, we get:
2x - 3x = 21 - 34
⇒ -x = -13
Dividing by -1 on both sides,
x = 13
x + 8 = 13 + 8 = 21
Thus, the rational number will be 1321.
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