The document Solution of Gravitation (Page No - 125) - Physics by Lakhmir Singh, Class 9 Class 9 Notes | EduRev is a part of the Class 9 Course Class 9 Physics Solutions By Lakhmir Singh & Manjit Kaur.

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__Page No -125__

**Question 46:****Explain why, buildings and dams have wide foundations.****Solution :**

The foundations of buildings and dams are laid on a large area of ground so that the weight of the building or dam produces less pressure on the ground and they may not sink into the ground.

**Question 47:****Why does a ship made of iron and steel float in water whereas a small piece of iron sinks in it ?**

The density of iron or steel is much higher than that of water, so an object made of iron or steel (like this car) sinks in water.

**Solution :**

A ship made of iron and steel is a hollow object which contains a lot of air in it. Due to the presence of a lot of air in it, the average density of the ship becomes less than the density of water. Hence a ship floats in water.

On the other hand, a piece of iron is denser than water, so it sinks in water.

**Question 48:**

Why do camels have large flat feet ?

**Solution :**

Camels have large flat feet so that there is a greater area in contact with the sand which produces less pressure on the sand and the camels can move easily on the sand.

**Question 49:****Name these forces :(a) the upward push of water on a submerged object(b) the force which wears away two surfaces as they move over one another(c) the force which pulled the apple off Isaac Newton’s tree.(d) the force which stops you falling through the floor.**

(a) Buoyant force

(b) Force of friction

(c) Gravitational force

(d) Reaction force

**Question 50:****A pressure of 10 Pa acts on an area of 3.0 m ^{2}. What is the force acting on the area ? What force will be exerted by the application of same pressure if the area is made one-third ?**

If the area is made one-third i.e. 1m

If the area is made one-third i.e. 1m^{2}, then the force would be:

**Question 51:****A girl is wearing a pair of flat shoes. She weighs 550 N. The area of contact of one shoe with the ground is 160 cm**^{2}. What pressure will be exerted by the girl on the ground :

(a) if she stands on two feet ?**(b) if she stands on one foot ?****Solution :**

Force, F= 550N

Area of contact of one shoe =160 cm^{2} =160 x 10^{-4}m^{2}

Area of contact with two shoes =160 x 2 =320 cm^{2}=320 x 10^{-4}m^{2}

**Question 52:****Calculate the density of an object of volume 3 m**^{3} and mass 9 kg. State whether this object will float or sink in water. Give reason for your answer.**Solution :**

volume = 3 m^{3}

Mass = 9Kg

and density of water = 1000kg/m^{3 }

The object will float in the water as the density of the object is less than the density of water.

**Question 53:**

An object weighs 500 grams in air. This object is then fully immersed in water. State whether it will weigh less in water or more in water. Give reason for your answer.**Solution :**

The object will weigh less in water because an upward force (buoyant force) equal to the weight of water displaced acts on the object when immersed in water which reduces its weight apparently.

**Question 54:**

(a) Write down an equation that defines density.

(b) 5 kg of material A occupy 20 cm^{3} whereas 20 kg of materia! B occupy 90 cm^{3}. Which has the greater density : A or B ? Support your answer with calculations.

**Solution :**

For material B:

Mass =20kg

Volume =90 cm^{3} = 90x 10^{-6}m^{3}

Density of material A is more than density of material B.

**Question 55:****(a) Define buoyant force. Name two factors on which buoyant force depends.(b) What is the cause of buoyant force ?(c) When a boat is partially immersed in water, it displaces 600 kg of water. How much is the buoyant force acting on the boat in newtons ? (g = 10 m s**

(a) The upward force acting on an object immersed in a liquid is called buoyant force.

Factors affecting buoyant force:

(i) Volume of object immersed in the liquid,

(ii) Density of the liquid.

(b) The cause of buoyant force is the greater upward pressure exerted by water underneath the object..

(c) Mass of water displaced = 600kg

Weight of water displaced, W =m x g

=600 x 10 =6000N

Since, the weight of water displaced by the boat is 6000N, therefore the buoyant force acting on the boat will also be 6000N.

**Question 56:****(a) State the principle of flotation.(b) A floating boat displaces water weighing 6000 newtons.(i) What is the buoyant force on the boat ?(ii) What is the weight of the boat ?**

(a) According to the principle of floatation: An object will float in a liquid if the weight of object is equal to the weight of liquid displaced by it.

Weight of object = Weight of liquid displaced by it.

(b) Weight of water displaced by boat= 6000N

(i) Buoyant force =6000N, as the weight of water displaced is equal to buoyant force.

(ii) Weight of a floating object = Weight of water displaced by it = 6000N

**Question 58:****(a) Define pressure.(b) What is the relation between pressure, force and area ? ,(c) Calculate the pressure when a force of 200 N is exerted on an area of:(i) 10 m**

(a) Pressure is the force acting perpendicularly on a unit area of the object.

__Page No -126__

**Question 59:****(a) What are fluids ? Name two common fluids.(b) State Archimedes’ principle.(c) When does an object float or sink when placed on the surface of a liquid ?**

(a) Those substances which can flow easily are called fluids. All the liquid and gases are fluids, like water, air etc.

(b) Archimedes’ Principle :

When an object is wholly (or partially) immersed in a liquid, it experiences a buoyant force (or upthrust) which is equal to the weight of liquid displaced by the object.

Buoyant force on an object = weight of liquid displaced by that object

(c) If the buoyant force exerted by the liquid is less than the weight of the object, the object will sink in the liquid. If the buoyant force exerted by the liquid is equal to or greater than the weight of the object, the object will float in the liquid.

**Question 60:****(a) How does a boat float in water ?(b) A piece of steel has a volume of 12 cm ^{3}, and a mass of 96 g. What is its density :(i) in g/cm^{3} ?(ii) in kg/m^{3} ?**

(a) A floating boat displaces water equal to its own weight. This displaced water exerts buoyant force to balance the weight of boat and keep it afloat.

(b) (i) Mass = 96 g

Volume = 12cm

**Question 61:****An elephant weighing 40,000 N stands on one foot of area 1000 cm**^{2} whereas a girl weighing 400 N is standing on one ‘stiletto’ heel of area 1 cm^{2}.

**(a) Which of the two, elephant or girl, exerts a larger force on the ground and by how much ?**

(b) What pressure is exerted on the ground by the elephant standing on one foot ?

(c) What pressure is exerted on the ground by the girl standing on one heel ?

(d) Which of the two exerts larger pressure on the ground : elephant or girl ?**(e) What is the ratio of pressure exerted by the girl to the pressure exerted by the elephant ?****Solution :**

Weight of elephant=40000N

Area of one foot =1000 cm^{2}= 1000 x 10^{-4}m^{2}

Weight of girl=400N

Area of heel of girl =1 cm^{2}=1 x 10^{-4}m^{2}

(a) Elephant has a larger weight of 40000N, therefore, elephant exerts a larger force on the ground. Elephant exerts a larger force on the ground by 40000N – 400 N=39600N.

(b)Weight of elephant = 40000N

Area of one foot =1000cm^{2}= 1000 x 10^{-4}m^{2}

The pressure exerted by girl is 10 times greater than the exerted by the elephant.

__Page No -127__

**Question 72:**

The two equal weights of unequal volumes which are balanced in air, will get imbalanced when they are completely dipped in water because due to their unequal volumes, they will displace unequal volumes of water and hence suffer unequal loss in weight.

**Question 73:**

No, it is not necessary that their weights in air should also be the same. This is because the two bodies have undergone the same loss in weight on completely immersing in water due to their equal volumes and not because of their equal weights, so they may have different weights in air.

**Question 74:**

The body will sink less in water. This is because the density of water is more than that of kerosene due to which water will exert a greater upward buoyant force on the body.

**Question 75:**

The reading on spring balance will be zero. This is because the weight of floating block of wood is fully supported by the liquid in which it is floating and hence it does not exert any force on the spring balance.

**Question 76:**

When a lot of salt is dissolved in water, then the density of salt solution becomes much more than pure water. Due to its much higher density, the salt solution exerts a greater upward buoyant force on the egg making it rise and then float.

**Page No:128**

**Question 77:**

(a) if a cork is placed in water ?

(b) if a piece of heavy metal is placed in it ?

Give reasons for your answer.

The reading of spring balance will not change if a cork is placed in water because cork, being lighter than water, floats in water.

(b)The reading of spring balance will change if a piece of heavy metal is placed in

water because heavy metal being denser than water, sinks in water.

**Question 78:**

Volume of golf ball = rise in water level = 30 cm

**Question 79:**

**A boy gets into a floating boat.**

**What happens to the boat ?****What happens to the weight of water displaced ?****What happens to the buoyant force on the boat ?**

**Solution :**

a) The boat sinks a little more in water, that is, the boat floats lower in water.

b) The weight of water displaced (by the submerged part of the boat) increases.

c) The buoyant force acting on the boat increases.

**Question 80:**

The sheet of tin sinks in water because the density of tin is higher than that of water. When the same sheet of tin is converted into a box or a boat, then due to the trapping of lot of ‘light’ air in the box or boat, the average density of the box or boat made of tin sheet becomes lower than that of water and hence it floats in water.

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