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**Introductory Exercise 16.1**

**Ques 1: Calculate the bulk modulus of air from the following data for a sound wave of wavelength 35 cm travelling in air. The pressure at a point varies between (10 ^{5} ± 14) Pa and the particles of the air vibrate in SHM of amplitude 5.5 × 10^{-6} m.**

Sol:

= 1.4 × 10

Sol:

= 0.0725 m = 7.25 cm

Sol:

= 3.63 × 10

Find the displacement amplitude. Density of air = 1.29 kg/m

Sol:

Now substituting the value, we have

**Introductory Exercise 16.2**

**Ques 1: Calculate the temperature at which the velocity of sound in air is double its velocity at 0°C.Sol: **v ∝ √T

∴

or

= 1092 K = 819°C

Sol:

∴

= 330.17 m/s

= 349.77 m/s

The difference in these two speeds is approximately 20 m/s.

Sol:

∴ B = ρ (fλ)

= (900) (250 × 8)

Sol:

= 315 m/s

**Introductory Exercise 16.3**

**Ques 1: A sound wave in air has a frequency of 300 Hz and a displacement amplitude of 6.0 × 10 -3 mm. For this sound wave calculate the(a) pressure amplitude(b) intensity(c) sound intensity level (in dB)Speed of sound = 344 m/s and density of air = 1.2 kg/m**

= 4.67 Pa

(as B= ρv

= 0.0264 W/m

= 104 dB

Given L

Solving the equation we get,

Sol:

∴

Now

Substituting

We get, L

(a) the intensity of the sound both in W/m

(b) the amplitude of the oscillations if the frequency is 500 Hz. Assume an air density of 1.29 kg/m

Sol:

For finest sound,

= - 3.48 dB

Same formulae can be applied for loudest sound.

∴

For finest sound,

= 1.43 × 10

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