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Specific heat capacity : dia-atomic gas - Kinetic Theory Video Lecture - Class 11
FAQs on Specific heat capacity : dia-atomic gas - Kinetic Theory Video Lecture - Class 11
| 1. What is specific heat capacity? |  |
Ans. Specific heat capacity is the amount of heat energy required to raise the temperature of a substance by one unit per unit mass. It is a property that helps determine how much heat a substance can store or release.
| 2. What is a diatomic gas? | |
Ans. A diatomic gas is a gas composed of molecules that consist of two atoms. Examples of diatomic gases include oxygen (O2), nitrogen (N2), and hydrogen (H2).
| 3. How does kinetic theory explain specific heat capacity of a diatomic gas? | |
Ans. According to the kinetic theory of gases, the specific heat capacity of a diatomic gas can be explained by the motion and collisions of its molecules. When heat is added to a diatomic gas, its molecules gain kinetic energy and move faster. This increased molecular motion leads to more frequent and energetic collisions, resulting in an increase in temperature. The specific heat capacity determines how much heat energy is required to produce a certain temperature change in the gas.
| 4. What factors affect the specific heat capacity of a diatomic gas? | |
Ans. The specific heat capacity of a diatomic gas is influenced by several factors, including the number of atoms in the molecule, the degree of freedom of the molecules, and the intermolecular forces between the molecules. For example, diatomic gases with more complex molecules (e.g., carbon dioxide) have higher specific heat capacities compared to simpler diatomic gases (e.g., oxygen) due to the additional internal degrees of freedom.
| 5. How is the specific heat capacity of a diatomic gas experimentally determined? | |
Ans. The specific heat capacity of a diatomic gas can be determined experimentally using calorimetry. In this method, a known quantity of the gas is subjected to a known amount of heat, and the resulting temperature change is measured. By knowing the mass of the gas and the temperature change, the specific heat capacity can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.
Text Transcript from Video
hello friends this video on kinetic
theory part 25 is brought to you by
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please make sure that you have watched
all the videos from part-time to par
chanting who before going ahead with
path 25
actually the specific heat capacity for
diatomic gases which it means that the
molecules will have rotational degrees
of freedom but they cannot vibrate they
are that is a rigid oscillator digital
oscillator means it can transmit that is
the entire molecule can move from one
point to another it can also rotate but
it cannot vibrate because vibration is
possible only then there is some
flexibility so there should not be any
rigidness for vibration techniques now
in this case we are considering that the
diatomic molecule is rigid so for these
molecules there will be three
translational degree of freedom plus two
rotational degree of freedom right so
there will be total five degrees of
freedom so according to the law of equal
partition of energy each degree of
freedom will contribute 3 by 2 KB into D
energy therefore 5 degrees of freedom
they'll contribute 5 by 2 I'm sorry
this was T 1 by T so this will be 5 by 2
KT into T therefore the internal energy
of one mole of gas that is U will be
equal to 3 by 2 KB in deep into M a that
is 3 by 2 R into T naught 3 by 2 I'm
sorry again it is 5 by 2 so this will be
5 by 2 RT therefore what is cv cv is d
by DT so this will be 5 by 2 I now if CV
is equal to 5 by 2 y what is CP as I
told CP minus CV is equal to I so CP is
CV plus I so that will be 7 by 2 I so
what will be the ratio of the specific
heat capacities that the CP by CV so
that will be equal to 7 by 5 so for a
rigid diatomic gas the ratio of the
specific heat capacities is 7 by a 5 we
just did the same thing there is that
the number of degrees of freedom changed
here now let us calculate the specific
heat capacity for diatomic gases which
are non rigid so long as it means they
will have translational degree of
freedom plus rotational degree of
freedom as well as vibrational mode so
in this case what will how many degrees
of freedom 3d translational degree of
freedom plus 2 rotational degree of
freedom plus vibrational degree of
freedom so what will be the contribution
from each degree of freedom for three
rotational degrees of freedom it would
be 3 into 1/2 KB into P similarly for 2
rotational degrees of freedom it should
be 2 into half KB into T for vibrational
degree of freedom this would be KB into
T so what would be the total energy that
is 5 by 2 KB into B plus KB into T that
is equal to 7 by 2 KB into P so this
would be the total internal energy of
one mole of gas so this would be the
total internal energy there are four
waters
this can be written as 7 by 2 RT 7 by 2
r T would be the internal energy for one
mole so what is CB that the specific
heat capacity at constant volume that is
d u by V P which is equal to seven nine
two so what is CP CP is nothing but C 3
+ I so that is equal to so this is 7 by
2 R so this will be 7 by 2 R plus I that
is equal to 9 by 2 R so what would be
the ratio of the specific hints that
this gamma is CP by CV which will be
equal to 9 by 7 thank you please visit
exam fee or comm to watch free
educational videos try 3 online tests
get the best quality study materials
study from the best tutors and mentors
and much more thank you once again
theory part 25 is brought to you by
example.com know who your prom exam
please make sure that you have watched
all the videos from part-time to par
chanting who before going ahead with
path 25
actually the specific heat capacity for
diatomic gases which it means that the
molecules will have rotational degrees
of freedom but they cannot vibrate they
are that is a rigid oscillator digital
oscillator means it can transmit that is
the entire molecule can move from one
point to another it can also rotate but
it cannot vibrate because vibration is
possible only then there is some
flexibility so there should not be any
rigidness for vibration techniques now
in this case we are considering that the
diatomic molecule is rigid so for these
molecules there will be three
translational degree of freedom plus two
rotational degree of freedom right so
there will be total five degrees of
freedom so according to the law of equal
partition of energy each degree of
freedom will contribute 3 by 2 KB into D
energy therefore 5 degrees of freedom
they'll contribute 5 by 2 I'm sorry
this was T 1 by T so this will be 5 by 2
KT into T therefore the internal energy
of one mole of gas that is U will be
equal to 3 by 2 KB in deep into M a that
is 3 by 2 R into T naught 3 by 2 I'm
sorry again it is 5 by 2 so this will be
5 by 2 RT therefore what is cv cv is d
by DT so this will be 5 by 2 I now if CV
is equal to 5 by 2 y what is CP as I
told CP minus CV is equal to I so CP is
CV plus I so that will be 7 by 2 I so
what will be the ratio of the specific
heat capacities that the CP by CV so
that will be equal to 7 by 5 so for a
rigid diatomic gas the ratio of the
specific heat capacities is 7 by a 5 we
just did the same thing there is that
the number of degrees of freedom changed
here now let us calculate the specific
heat capacity for diatomic gases which
are non rigid so long as it means they
will have translational degree of
freedom plus rotational degree of
freedom as well as vibrational mode so
in this case what will how many degrees
of freedom 3d translational degree of
freedom plus 2 rotational degree of
freedom plus vibrational degree of
freedom so what will be the contribution
from each degree of freedom for three
rotational degrees of freedom it would
be 3 into 1/2 KB into P similarly for 2
rotational degrees of freedom it should
be 2 into half KB into T for vibrational
degree of freedom this would be KB into
T so what would be the total energy that
is 5 by 2 KB into B plus KB into T that
is equal to 7 by 2 KB into P so this
would be the total internal energy of
one mole of gas so this would be the
total internal energy there are four
waters
this can be written as 7 by 2 RT 7 by 2
r T would be the internal energy for one
mole so what is CB that the specific
heat capacity at constant volume that is
d u by V P which is equal to seven nine
two so what is CP CP is nothing but C 3
+ I so that is equal to so this is 7 by
2 R so this will be 7 by 2 R plus I that
is equal to 9 by 2 R so what would be
the ratio of the specific hints that
this gamma is CP by CV which will be
equal to 9 by 7 thank you please visit
exam fee or comm to watch free
educational videos try 3 online tests
get the best quality study materials
study from the best tutors and mentors
and much more thank you once again
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Nov 24, 2024 Last updated |
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